OK so I am retrieving fullname from web page to filter customer list and I am not really sure which part is first name or last name so I need to run a similar query like the one below:
"SELECT sc.*, c.firstname, c.lastname,c.email FROM scoop_customer AS sc LEFT JOIN
customer AS c ON sc.customer_id = c.customer_id WHERE c.firstname + ' ' + c.lastname
LIKE '%".$fullname."%'"
But it doesn't seem working to me even though I tried many times and normally it should have been returning values from DB. Could you please tell me where I am doing wrong?
Try CONCAT
WHERE concat(c.firstname, ' ', c.lastname) LIKE '%".$fullname."%'"
Use CONCAT(c.firstname , ' ' , c.lastname )
CONCAT Would be nice for these operations
Please see the mysql doc
http://dev.mysql.com/doc/refman/5.0/en/string-functions.html#function_concat
"SELECT sc.*, c.firstname, c.lastname,c.email FROM scoop_customer AS sc LEFT JOIN
customer AS c ON sc.customer_id = c.customer_id WHERE CONCAT(c.firstname, ' ', c.lastname) LIKE '%".mysql_real_escape_string($fullname)."%'"
I'd break full name into first and last and do 2 like checks and get rid of the Wildcard % at the beginning of each. The concatenation and the wildcard starting the like is going to break any indexing you may have on the name fields.
Of course if you only have a couple thousand customers in the table the indexing won't mater much, but when you get into the 100,000's you'll feel it!
Asuming that you haven't escaped it previously I have added mysql_real_escape_string.
For the question, the trick is OR, but not CONCAT
".... WHERE c.firstname LIKE '%".mysql_real_escape_string($fullname)."%'
OR c.lastname LIKE '%".mysql_real_escape_string($fullname)."%'"
Related
I met following problem:
I've got table 'students' with columns: 'id_student', 'name' and 'surname'.
Then I got a variable that contains full_name (example: 'James Bond')
I need to make a query that selects 'id_student' where 'name' and 'surname' matches whole name.
I tried to do this in several ways, like:
SELECT id_student FROM students WHERE name+' '+surname LIKE full_name
but it doesn't work. Any idea?
Your code should work in a database where + is used for string concatenation. The LIKE is fine, but = seems sufficient:
SELECT id_student
FROM students
WHERE CONCAT(name, ' ', surname) = full_name;
Note that unexpected characters and small differences in spelling would cause the comparisons to fail.
MySQL does not support string concatenation using plus, at least not by default. Instead, we can use the CONCAT function. The LIKE expression you want here is:
full_name LIKE 'James%Bond'
Here we want any record which starts with James and ends with Bond.
SELECT id_student
FROM students
WHERE full_name LIKE CONCAT(name, '%', surname);
Maybe you should try something like:
SELECT id_student
FROM students
WHERE CONCAT_WS(" ", name, surname)
LIKE full_name
CONCAT_WS or CONCAT is the MySQL function to join strings. The former allows you to define a separator, a space in your case.
If i give hard coded value inside query it works, but not in case of sub query or column given.
Here is small example of issue i am facing :
Following both query is a type of sub query, like its part of another query, so don't think that where is table 'm' and something else, as it is working already.
So, my query like :
1)
SELECT GROUP_CONCAT(CONCAT(a_u.first_name,' ', a_u.last_name)) AS associated_admin_u
FROM users a_u
WHERE a_u.id IN(m.associated_admin)
GROUP
BY m.id
And m.associated_admin will return a quoted string like '1,10' so this will not work because of its a string.
2)
SELECT GROUP_CONCAT(CONCAT(a_u.first_name,' ', a_u.last_name)) AS associated_admin_u
FROM users a_u
WHERE a_u.id IN(1,10)
GROUP
BY m.id
If i write hard code like 1,10 it works, because it is not a string
So first one is not works because that query is part of another query as a sub query.
And i am sure this question couldn't be duplicate as i am facing it like in this way so any help would be appreciate, thanks reader!
Based on your comments, you need something like:
SELECT GROUP_CONCAT(CONCAT(a_u.first_name,' ', a_u.last_name)) AS associated_admin_u
FROM users a_u
WHERE FIND_IN_SET(a_u.id, TRIM(BOTH '\'' FROM m.associated_admin))
GROUP
BY m.id
This will first trim the quotes from m.associated_admin and then use FIND_IN_SET instead of IN so that you can use a string with comma-separated values.
You can just create a subquery in IN for example:
SELECT group_concat(CONCAT(a_u.first_name,' ', a_u.last_name)) AS associated_admin_u
FROM users a_u WHERE a_u.id IN(
SELECT id FROM mytable WHERE id IN(1,10)
) GROUP BY m.id
First off, I'm a beginner at this so please be patient with me. I've tried searching the forums here, and elsewhere and from what I can see I'm doing it right.. but I get an error. to "Check syntax to use near 'LIKE CONCAT(games.tag, ' Special%') AT LINE X". So clearly I'm doing it wrong.. But everything I have found says I've done it right. Someone please help I'm getting frustrated.
SELECT
games.tag,
ribbons.name,
members.username,
members.joined
FROM
member_ribbons
INNER JOIN ribbons
ON member_ribbons.ribbon_id = ribbons.id
INNER JOIN games
ON ribbons.game_id = games.id
INNER JOIN members
ON member_ribbons.member_id = members.id
WHERE games.id = members.primary_game AND discharged='000-00-00' AND ribbons.name = LIKE CONCAT(games.tag, ' Special %');
An Example
ribbons.name will contain "BF4 Special Consideration"
I need to be able to find that specific one.. but the only thing that changes is the first word which is contained in games.tag. The rest of the Query works. Just need to figure out how to get it to do this and I'm good. However Searching google everywhere and here has not shown any examples of how to do this.. Is it even possible? Clearly I'm doing this wrong.
you have extra =
change this
AND ribbons.name = LIKE CONCAT
^----//--no need this
to
AND ribbons.name LIKE CONCAT
I have a situation where lets say i'm trying to get the information about some food. Then I need to display all the information plus all the ingredients in that food.
With my query, i'm getting all the information in an array but only the first ingredient...
myFoodsArr =
[0]
foodDescription = "the description text will be here"
ratingAverage = 0
foodId = 4
ingredient = 1
ingAmount = 2
foodName = "Awesome Food name"
typeOfFood = 6
votes = 0
I would like to get something back like this...
myFoodsArr =
[0]
foodDescription = "the description text will be here"
ratingAverage = 0
foodId = 4
ingArr = {ingredient: 1, ingAmount: 4}, {ingredient: 3, ingAmount: 2}, {ingredient: 5, ingAmount: 1}
foodName = "Awesome Food name"
typeOfFood = 6
votes = 0
This is the query im working with right now. How can I adjust this to return the food ID 4 and then also get ALL the ingredients for that food? All while at the same time doing other things like getting the average rating of that food?
Thanks!
SELECT a.foodId, a.foodName, a.foodDescription, a.typeOfFood, c.ingredient, c.ingAmount, AVG(b.foodRating) AS ratingAverage, COUNT(b.foodId) as tvotes
FROM `foods` a
LEFT JOIN `foods_ratings` b
ON a.foodId = b.foodId
LEFT JOIN `foods_ing` c
ON a.foodId=c.foodId
WHERE a.foodId=4
EDIT:
Catcall introduced this concept of "sub queries" I never heard of, so I'm trying to make that work to see if i can do this in 1 query easily. But i just keep getting a return false. This is what I was trying with no luck..
//I changed some of the column names to help them be more distinct in this example
SELECT a.foodId, a.foodName, a.foodDescription, a.typeOfFood, AVG(b.foodRating) AS ratingAverage, COUNT(b.foodId) as tvotes
FROM foods a
LEFT JOIN foods_ratings b ON a.foodId = b.foodId
LEFT JOIN (SELECT fId, ingredientId, ingAmount
FROM foods_ing
WHERE fId = 4
GROUP BY fId) c ON a.foodId = c.fId
WHERE a.foodId = 4";
EDIT 1 more thing related to ROLANDS GROUP_CONCAT/JSON Idea as a solution 4 this
I'm trying to make sure the JSON string im sending back to my Flash project is ready to be properly parsed Invalid JSON parse input. keeps popping up..
so im thinking i need to properly have all the double quotes in the right places.
But in my MySQL query string, im trying to escape the double quotes, but then it makes my mySQL vars not work, for example...
If i do this..
GROUP_CONCAT('{\"ingredient\":', \"c.ingredient\", ',\"ingAmount\":', \"c.ingAmount\", '}')`
I get this...
{"ingredient":c.ingredient,"ingAmount":c.ingAmount},{"ingredient":c.ingredient,"ingAmount":c.ingAmount},{"ingredient":c.ingredient,"ingAmount":c.ingAmount}
How can i use all the double quotes to make the JSON properly formed without breaking the mysql?
This should do the trick:
SELECT food_ingredients.foodId
, food_ingredients.foodName
, food_ingredients.foodDescription
, food_ingredients.typeOfFood
, food_ingredients.ingredients
, AVG(food_ratings.food_rating) food_rating
, COUNT(food_ratings.foodId) number_of_votes
FROM (
SELECT a.foodId
, a.foodName
, a.foodDescription
, a.typeOfFood
, GROUP_CONCAT(
'{ingredient:', c.ingredient,
, ',ingAmount:', c.ingAmount, '}'
) ingredients
FROM foods a
LEFT JOIN foods_ing c
ON a.foodsId = c.foodsId
WHERE a.foodsId=4
GROUP BY a.foodId
) food_ingredients
LEFT JOIN food_ratings
ON food_ingredients.foodId = food_ratings.foodId
GROUP BY food_ingredients.foodId
Note that the type of query you want to do is not trivial in any SQL-based database.
The main problem is that you have one master (food) with two details (ingredients and ratings). Because those details are not related to each other (other than to the master) they form a cartesian product with each other (bound only by their relationship to the master).
The query above solves that by doing it in 2 steps: first, join to the first detail (ingredients) and aggregate the detail (using group_concat to make one single row of all related ingredient rows), then join that result to the second detail (ratings) and aggregate again.
In the example above, the ingredients are returned in a structured string, exactly like it appeared in your example. If you want to access the data inside PHP, you might consider adding a bit more syntax to make it a valid JSON string so you can decode it into an array using the php function json_decode(): http://www.php.net/manual/en/function.json-decode.php
To do that, simply change the line to:
CONCAT(
'['
, GROUP_CONCAT(
'{"ingredient":', c.ingredient
, ',"ingAmount":', c.ingAmount, '}'
)
, ']'
)
(this assumes ingredient and ingAmount are numeric; if they are strings, you should double quote them, and escape any double quotes that appear within the string values)
The concatenation of ingredients with GROUP_CONCAT can lead to problems if you keep a default setting for the group_concat_max_len server variable. A trivial way to mitigate that problem is to set it to the maximum theoretical size of any result:
SET group_concat_max_len = ##max_allowed_packet;
You can either execute this once after you open the connection to mysql, and it will then be in effect for the duration of that session. Alternatively, if you have the super privilege, you can change the value across the board for the entire MySQL instance:
SET GLOBAL group_concat_max_len = ##max_allowed_packet;
You can also add a line to your my.cnf or my.ini to set group_concat_max_lenght to some arbitrary large enough static value. See http://dev.mysql.com/doc/refman/5.5/en/server-system-variables.html#sysvar_group_concat_max_len
One obvious solution is to actually perform two queries:
1) get the food
SELECT a.foodId, a.foodName, a.foodDescription, a.typeOfFood
FROM `foods` a
WHERE a.foodsId=4
2) get all of its ingredients
SELECT c.ingredient, c.ingAmount
FROM `foods_ing` c
WHERE c.foodsId=4
This approach has the advantage that you don't duplicate data from the "foods" table into the result. The disadvantage is that you have to perform two queries. Actually you have to perform one extra query for each "food", so if you want to have a listing of foods with all their ingredients, you would have to do a query for each of the food record.
Other solutions usually have many disadvantages, one of them is using GROUP_CONCAT function, but it has a tough limit on the length of the returned string.
When you compare MySQL's aggregate functions and GROUP BY behavior to SQL standards, you have to conclude that they're simply broken. You can do what you want in a single query, but instead of joining directly to the table of ratings, you need to join on a query that returns the results of the aggregate functions. Something along these lines should work.
select a.foodId, a.foodName, a.foodDescription, a.typeOfFood,
c.ingredient, c.ingAmount,
b.numRatings, b.avgRating
from foods a
left join (select foodId, count(foodId) numRatings, avg(foodRating) avgRating
from foods_ratings
group by foodId) b on a.foodId = b.foodId
left join foods_ing c on a.foodId = c.foodId
order by a.foodId
I am building a site where candidates can post their resume and employers can post their jobs.
The employers can post a job with multiple qualifications and I saved it in database like this PHP,Javascript,ASP. Now I want admin to be able to select the candidates who are eligible for a post.
I have written the query:
$sql = "
SELECT
cand_f_name,
cand_l_name,
cand_qualification,
cand_phone,
cand_email,
cand_experience_yr,
cand_experience_mn,
cand_message,
cand_id
FROM
tbl_cand_data
WHERE
cand_qualification LIKE '%$emp_q%'
But it is not showing the expected result. I think my condition cand_qualification LIKE '$emp_q' is wrong.
My tbl_cand_data :
If you are doing a LIKE query you should include wildcards, as they will match a string containing, otherwise just do an exact match using =:
// String match
WHERE
cand_qualification LIKE '%emp_q%';
// Exact match
WHERE
cand_qualification = '$emp_q';
// You could try a WHERE IN clause as well
WHERE cand_qualification IN ('$emp_q');
// Values have to be quoted individually
WHERE cand_qualification IN ('BA','BSc','BCom');
// If you have an array you can do this:
$myArray = array('BA', 'BSc', 'BCom');
$emp_q = "'" . implode("','", $myArray) . "'"; //Output 'BA', 'BSc', 'BCom'
I saved it in database like this PHP,Javascript,ASP
That's what you did utterly wrong.
you have to create a related table (that's why our ratabase called relational one!) storing qualifications, and interconnection table, consists of qualifications id linked with candidates ids.
And query them using basic joins.
Note that despite of your current decision, even if you decide to continue with your lame schema, you WILL have to remake it proper way, sooner or later (but sooner will make you less work).
That is the very basics of database architecture and noone can go against it.
SELECT fields FROM tbl_cand_data d, qualification q, qual_cand qc
WHERE q.name = 'ASP' AND q.id=qc.qid AND d.id=qc.did
Like requires percent %
try it