JSON exception in Android - php

Question

I am trying to execute query on database in the localhost and send the JSON object to the client in android. I m not been able to know what is the problem in my code. So some one please help me on this regard.
My php code is the one where i m sending the JSON object.
php code
query executed successfully..
$row=mysql_fetch_array($result1);
$email=$row['EM'];
$pass=$row['PASS'];
$post=array("email"=>$email, "pass"=>$pass);
$posts[] = array("post"=>$post);
//echo "SUCCESS";
header('Content-type: application/json');
echo json_encode(array("posts"=>$posts));
And in android side i ve this code below;
HttpResponse response = doPost(url, kvPairs);
String responseBody=response.toString();
String temp = EntityUtils.toString(response.getEntity());
if (temp.compareTo("SUCCESS")==0)
{
Toast.makeText(this, "Working", Toast.LENGTH_LONG).show();
}
Above part executes ..
Below code throws a JSON exception
JSONObject json = new JSONObject(responseBody);
JSONArray jArray = json.getJSONArray("posts");
no_of_obj=jArray.length();
nemail=new String[no_of_obj];
npass=new String[no_of_obj];
for (int i = 0; i < jArray.length(); i++) {
JSONObject e = jArray.getJSONObject(i);
String s = e.getString("post");
JSONObject jObject = new JSONObject(s);
Toast.makeText(context,jObject.getString("email")+":"+jObject.getString("pass") , duration).show();
nemail[i]=jObject.getString("email");
npass[i]=jObject.getString("pass");
}
In the log cat i can see : The json string must begin with "{"....

Answer 1

Probably you cannot do this
String s = e.getString("post");
because there is no "post" key in the array of Strings you have given,...
Try doing this,
String s = e.has("post")?e.getString("post"):null;
and then on next line keep a null check before Creating JSONObject..

Answer 2

Try this
$posts['data'] = $post;
//echo "SUCCESS";
header('Content-type: application/json');
echo json_encode($posts);