Reverse whole date in php - php

Question

OK,
i was using following code to reverse a date to use in php yesterday.
<?php
$d=date("F j Y");
$d=explode(" ", $d);
$month=$d[0];
$day=$d[1];
$year=$d[2];
<?php for ($i=10; $i>0; $i--)
{
$date=$month."-".$day--."-".$year;
echo $date;
?>
this was working for me till yesterday 31 March Night. but in the morning on april 1 its started printing
April-1-2012
April-0-2012
April--1-2012 April--2-2012
and so on.
this was the bad logic i used to reverse a date. i realized it soon.
i want this like following.
April-1-2012
March-31-2012
March-30-2012
March-29-2012
and so on
so how this could be possible ?
Thanks in advance.
Well, this also a logic that work perfect for me i made after post of question. but i am really thankful for all answers. that also making me many things clear.
<?php
$d=date("F j Y");
for ($i=0; $i>-10; $i--)
{
$date="<br>".date('F-j-Y', strtotime("+$i days"));
echo $date;
}
?>

Answer 1

This is probably the quickest way to do it
for($i=1; $i <= 10; $i++) {
echo date("F j Y", time()-($i*24*60*60)); //Instead of 24*60*60 write 86400 to increase slight performance
}
Demo

Answer 2

To get an incremental decrease:
$date = date("F j Y");
for ($i = 0; $i < 10; ++$i)
{
$dates[] = date("F-j-Y", strtotime($date . ' - ' . $i . ' day'));
}

Answer 3

If you are using PHP5.2, you can use the DateTime Class and the modify method.
http://www.php.net/manual/en/datetime.modify.php
<?php
$date = new DateTime('2006-12-12');
$date->modify('-1 day');
echo $date->format('F-j-Y');
?>
In 5.3, you can use the sub method in the DateTime class: http://www.php.net/manual/en/datetime.sub.php
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P1D'));
echo $date->format('F-j-Y');
?>
So an example, using the PHP 5.2 DateTime class (example here: http://ideone.com/uwkjj):
$date = new DateTime();
echo $date->format('F-j-Y');
for($i = 0; $i < 10; $i++){
$date->modify('-1 day');
echo $date->format('F-j-Y');
}
And here is an example using PHP5.3 DateTime class with the sub method
$date = new DateTime();
echo $date->format('F-j-Y');
for($i = 0; $i < 9; $i++){
$date->sub(new DateInterval('P1D'));
echo $date->format('F-j-Y');
}
There is also an interesting note on the PHP help page for strtotime: http://www.php.net/manual/en/function.strtotime.php that says not to use it for mathematical operations. I wonder what that means. But I guess subtracting 1 day should be fine.
From PHP manual:
Using this function for mathematical operations is not advisable. It
is better to use DateTime::add() and DateTime::sub() in PHP 5.3 and
later, or DateTime::modify() in PHP 5.2.