Combine Multiple rows from mysql array - php

Question

right guys im having trouble with one.
what i want to do is have a variable which is made from a mysql query. the problem i have is that it needs to contain multiple rows from the query and combine them into one.
currently i have
$lender = mysql_query("Select * from lender where reference = '$reference'");
while($lenderrow=mysql_fetch_array($lender)) {
$lender1 = $lenderrow["lender"] . " " . $lenderrow["lenderref"] . " " . "£" . $lenderrow["amount"]
echo '<br />';
}
so basically i want it to take this format if it has multiple rows
blackhorse htfhg125h £250
santander htdhfr58hryf £541
Test 125452asaed2 £760
currently i only get the last result when i echo $lender 1 (obviously because its the last call in the while loop)
Cheers In Advance

Answer 1

You need to use a other array.
<?php
$lender = mysql_query("Select * from lender where reference = '$reference'");
$formated_lender = array();
while ($lenderrow=mysql_fetch_array($lender)) {
$formated_lender = $lenderrow["lender"] . " " . $lenderrow["lenderref"] . " " . "£" .
$lenderrow["amount"];
}
foreach ($formated_lender as $row)
{
echo $row . '<br />';
}
Or, if you would just one variable containing all the row, replace $lende1 = ... by $lender1 .= ...

Answer 2

Just put your echo inside the loop. A loop isn't restricted to one statement.
$lender = mysql_query("Select * from lender where reference = '$reference'");
while($lenderrow = mysql_fetch_array($lender)) {
$result = $lenderrow["lender"] . " " . $lenderrow["lenderref"] . " " . "£" . $lenderrow["amount"];
echo $result . "<br />";
}
If you want it in an array, you can use an empty while loop too:
$lender = mysql_query("Select * from lender where reference = '$reference'");
$results = array();
while($results[] = mysql_fetch_array($lender)); // Empty loop
Also, you might want to be careful about SQL injection if $reference is user-supplied and unescaped.