PHP - "if" in "while" problems to alternate html table rows colour - php

Question

$banana=0;
$view = mysql_query('SELECT ......') or die ('Encountered an error.') ;
while($rows3=mysql_fetch_array($view))
{
$total_price2=$rows3['qty']*$rows3['number'];
$banana = $banana + 1;
if ($total_price2!=0)
{
if ($banana %2 ==0)
{
echo "<tr class=\"alt\">";
}
else
{
echo "<tr>";
}
echo "<td>".$rows3['member']."</td>";
echo "<td>".$rows3['payment']."</td>";
echo "<td>$".number_format($total_price2,2)."</td>";
}
echo "</tr>";
}
Problems:
The "banana" alternates the colour of the table row (class="alt") by using modulus (%) to check if banana is a odd number.
Not Working, I see the browser is self-closing the opening <tr> tag.
eg:
<tr><td>person</td><td>data</td><td>$10.00</td></tr>
<tr class="alt"></tr> (Repeats in this fashion)
UPDATE
I have discovered that the reiterating banana always returns ODD NUMBERS: 1 , 3, 5, etc
MySQL is not running correctly
SELECT table1.member, table1.paid, table1.payment,table2.qty,table3.number FROM table1,table2,table3 WHERE table1.member = table2.member AND table1.payment="fruit"
It is giving me wrong data like so:
person1 $10.00
person1 $0.00
person2 $10.00
person2 $0.00
etc

Answer 1

If all else fails, you could just use CSS:
tr {background-color: blue;}
tr:nth-of-type(2n) {background-color: red;}

Answer 2

Try doing this for a debug first:
echo "<tr class=\"alt\"> ";
My guess is that you have no data contained in your <tr> and is being squished to 0 px tall by your browser.
EDIT: I'm not entirely sure giving a class to your <tr> will filter down into the <td> based on certain browser DOM parsing. Whenever I do a zebra row, I'll assign the class to the <td>. I'm no designer by any standard, though. :)
Humor me and try this please:
$banana=0;
$view = mysql_query('SELECT ......') or die ('Encountered an error.') ;
while($rows3=mysql_fetch_array($view))
{
$total_price2=$rows3['qty']*$rows3['number'];
$banana++;
if ($banana % 2 == 0) {
$td_class = "alt";
} else {
$td_class = "";
}
echo "<tr>";
if ($total_price2!=0) {
echo "<td class='{$td_class}'>".$rows3['member']."</td>";
echo "<td class='{$td_class}'>".$rows3['payment']."</td>";
echo "<td class='{$td_class}'>$".number_format($total_price2,2)."</td>";
}
echo "</tr>";
}

Answer 3

That's not going to work. You're only opening the table row if $total_price2!=0. It seems you should only output the closing </tr> tag inside that IF block.
Try this instead:
<?php
$banana=0;
$view = mysql_query('SELECT ......') or die ('Encountered an error.') ;
while($rows3=mysql_fetch_array($view))
{
$total_price2=$rows3['qty']*$rows3['number'];
if ( !$total_price2)
continue;
$banana = $banana + 1;
if ($banana %2 ==0)
{
echo "<tr class=\"alt\">";
}
else
{
echo "<tr>";
}
echo "<td>".$rows3['member']."</td>";
echo "<td>".$rows3['payment']."</td>";
echo "<td>$".number_format($total_price2,2)."</td>";
echo "</tr>";
}