php echo certain id from database - php

Question

I would like to echo dates 1 by 1 using the id field of the database, how do I call the first id using the code below?
I have a database named dbflagship, table called funds, rows are id date.
I want to use id and date to echo 1 date at a time.
Example: id 1 Date 10/11/2012
<?php echo $row['date_formatted']; ?>

Answer 1

can you please print_r your result array here.
you can use this to print dates as per id.
<?php for($i=0;$i<count($row);$i++){
echo $row[$i]['date_formatted'];
} ?>

Answer 2

Im im right you should try to fetch this in an mysql_fetch_assoc put it in an array. And after wards echo it by using an for loop.
$row = mysql_fetch_assoc("SELECT * FROM table ORDER BY ID DESC");
for($i=0;$
echo $row[$i]['date_formatted'];
}

Answer 3

Try this
<?php
$con = mysql_connect("localhost","peter","abc123");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("my_db", $con);
$result = mysql_query("SELECT * FROM Persons");
while($row = mysql_fetch_array($result))
{
echo "id:" . $row['id'];
$timestamp = strtotime($row['date_formatted']))
echo "Date".date('d/m/Y', $timestamp);
}
mysql_close($con);
?>

Answer 4

Try something like this:
<?php
$con = mysql_connect("localhost","peter","abc123");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("my_db", $con);
$result = mysql_query("SELECT * FROM Persons");
echo "<table border='1'>
<tr>
<th>Firstname</th>
<th>Lastname</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['FirstName'] . "</td>";
echo "<td>" . $row['LastName'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysql_close($con);
?>
more info & source: http://www.w3schools.com/PHP/php_mysql_select.asp
www.w3schools.com is a great place to know