Echo php array value - php

Question

I have the following code that reads the content of a folder
PHP Code:
<?
//PHP SCRIPT: getimages.php
header('content-type: application/x-javascript');
//This function gets the file names of all images in the current directory
//and ouputs them as a JavaScript array
function returnimages($dirname="./images") {
$pattern="(\.jpg$)|(\.png$)|(\.jpeg$)|(\.gif$)"; //valid image extensions
$files = array();
$curimage=0;
if($handle = opendir($dirname)) {
while(false !== ($file = readdir($handle))){
if(eregi($pattern, $file)){ //if this file is a valid image
//Output it as a JavaScript array element
echo 'galleryarray['.$curimage.']="'.$file .'";' . "\n";
$curimage++;
}
}
closedir($handle);
}
sort($files);
return($files);
}
echo 'var galleryarray=new Array();' . "\n"; //Define array in JavaScript
returnimages() //Output the array elements containing the image file names
?>
which spits out this the following code:
var galleryarray = new Array();
galleryarray[0] = "image1.jpg";
galleryarray[1] = "image5.jpg";
galleryarray[2] = "image2.jpg";
galleryarray[3] = "image4.jpg";
galleryarray[4] = "image8.jpg";
galleryarray[5] = "image7.jpg";
galleryarray[6] = "image0.jpg";
galleryarray[7] = "image3.jpg";
galleryarray[8] = "image6.jpg";​
Now in my html file I want to echo something like
<img src="images/image0.jpg" />
<img src="images/image1.jpg"/>
...
...
How can I do that?

Answer 1

foreach($galleryarray as $img) {
echo "<img src='images/$img' />";
}

Answer 2

maybe this help u
$pattern="(\.jpg$)|(\.png$)|(\.jpeg$)|(\.gif$)"; //valid image extensions
if($handle = opendir("./images")) {
while(false !== ($file = readdir($handle))){
if(eregi($pattern, $file)){ ?>
<img src="/images/<?php echo $file; ?>">
<?php
}
}
}

Answer 3

assuming that you want to sort image name by value and then show the images. you first need to sort values by using function "asort"
asort($galleryarray);
foreach ($galleryarray as $key => $val) {
echo "<img src='images/{$val}'/>"
}
if you want to print and array
1) print_r($array); or if you want nicely formatted array then
echo '<pre>'; print_r($array); echo '<pre/>';
2) use var_dump($array) to get more information of the content in the array like datatype and length.
3) you can loop the array using php's foreach(); and get the desired output. more info on foreach in php's documentation website http://in3.php.net/manual/en/control-structures.foreach.php

Answer 4

Try changing the echo line in the function to this:
echo '<img src="images/' . $file . '" />' ;
Hope this will help :)
OR
Outside the function, use it like this:
$images = returnimages(); //will get the array containing the images
foreach($images as $img)
{
echo '<img src="images/' . $img . '" />';
}
Also, you have to include this line inside the if condition in the while loop:
$files[] = $file; //insert the file into the array. This array is what we are going to return from the function
Update
I have tested this code and it's working:
//PHP SCRIPT: getimages.php
header('content-type: application/x-javascript');
function returnimages($dirname="./images") {
$pattern="([^\s]+(\.(?i)(jpg|png|gif|bmp))$)"; // http://www.mkyong.com/regular-expressions/how-to-validate-image-file-extension-with-regular-expression/
$files = array();
if($handle = opendir($dirname)) {
while(false !== ($file = readdir($handle))){
if(preg_match($pattern, $file)){ //if this file is a valid image
$files[] = $file;
}
}
closedir($handle);
}
//sort($files); // http://php.net/manual/en/function.sort.php
natcasesort($files); // case insensitive "natural order" algorithm :: http://php.net/manual/en/function.natcasesort.php
return($files);
}
$images = returnimages(); //will get the array containing the images
foreach($images as $img)
{
echo '<img src="images/' . $img . '" />';
}
In my images folder, I have put 5 files for testing. And upon running it, it would give the following:
<img src="images/a.jpg" />
<img src="images/ba.jpg" />
<img src="images/ca.jpg" />
<img src="images/Copy (3) of a.jpg" />
<img src="images/Copy (4) of a.jpg" />