How to pass options value from each table row? - php

I am creating a table with rows which has options in each cells. The options are received from database table. Since each row has a options cell, I have to receive the value from each row. In select tag, the 'name' is incremented with the rows. But I am only getting the value of the last row.
Attaching the code section here.
for ($i = 1; $i <= $_GET['pno']; $i++) {
echo'<tr>';
echo "<td>$i</td>";
echo '<td><select name="prod_$i">'; echo "prod_$i";
//Query for production table gets processed.
$qry_pr="SELECT * FROM production";
$result_pr=mysql_query($qry_pr);
$rows_pr=mysql_affected_rows($con);
//Production options get filled from the table data.
for($j=0;$j<=$rows_pr;$j++)
{
$res_arr_pr=mysql_fetch_array($result_pr);
echo "<option value=$res_arr_pr[0]>$res_arr_pr[1]</option>";
//$res++;
}
//mysql_close($con);
echo '</select></td>';
echo '<td><select name="prod_mu_$i">';
//Query for measurement_unit table gets processed.
$qry_mu="SELECT * FROM measurement_unit";
$result_mu=mysql_query($qry_mu);
$rows_mu=mysql_affected_rows($con);
//Unit options get filled from the table data
for($k=0;$k<=$rows_mu;$k++)
{
$res_arr_mu=mysql_fetch_array($result_mu);
echo "<option value=$res_arr_mu[0]>$res_arr_mu[1]</option>";
}
echo '</td>';
echo '</tr>'; echo "prod_$i";
}
echo'</table><br>';
Hope I am clear with the query.
Thank you.

You have placed the SQL Query inside the for loop making it heavy. Because it will perform the same query over and over again. If you tweak the code a little you can use perform a single query and use that for all loop iterations.
<?php
//initialize blank
$productions = $measurements = '';
// create the production select box
$qry_pr="SELECT * FROM production";
$result_pr=mysql_query($qry_pr);
if( mysql_num_rows($result_pr) )
{
$productions .= "<select name='prod_%index%'>";
while( $rec_pr = mysql_fetch_row($result_pr) )
{
$productions .= "<option value='{$rec_pr[0]}'>{$rec_pr[1]}</option>";
}
$productions .= "</select>";
}
// create the measurement select box
$qry_mu="SELECT * FROM measurement_unit";
$result_mu=mysql_query($qry_mu);
if( mysql_num_rows($result_mu) )
{
$measurements .= "<select name='prod_mu_%index%'>";
while( $rec_mu = mysql_fetch_array($result_mu) )
{
$measurements .= "<option value='{$rec_mu[0]}'>{$rec_mu[1]}</option>";
}
$measurements .= "</select>";
}
?>
<table>
<?php for($i=1;$i<=$_GET['pno'];$i++): ?>
<tr>
<td><?php echo str_replace('%index%',$i,$productions); ?></td>
<td><?php echo str_replace('%index%',$i,$measurements); ?></td>
</tr>
<?php endfor; ?>
</table>

Change:
echo '<td><select name="prod_$i">'; echo "prod_$i";
to:
echo '<td><select name="prod_' . $i . '[]">'; echo "prod_$i";

mysql_affected_rows will only give you the number of affected rows by the last INSERT, UPDATE, REPLACE or DELETE query. Your performing a SELECT, so the $rows_mu value will be wrong.
Instead of:
$rows_mu=mysql_affected_rows($con);
//Unit options get filled from the table data
for($k=0;$k<=$rows_mu;$k++)
{
$res_arr_mu=mysql_fetch_array($result_mu);
echo "<option value=$res_arr_mu[0]>$res_arr_mu[1]</option>";
}
try this:
//Unit options get filled from the table data
while ($res_arr_mu = mysql_fetch_array($result_mu))
{
echo "<option value=$res_arr_mu[0]>$res_arr_mu[1]</option>";
}

Related

Get the value of the changed select in table

I need to get the values of the selected select
like the orderno of the changed row
The table looks like this
if I change order no 1002 into sold
$query = mysql_query("select * from orders");
while($row = mysql_fetch_assoc($query))
{
echo '<tr>';
echo '<td>'.$row['orderno'].'</td>';
echo '<td>'.$row['total'].'</td>';
echo '<td>';
if($row['status'] == "sold")
{
echo '<select name = "status[]">';
echo '<option value = "sold" selected>Sold</option>';
echo '<option value = "cancelled">Cancelled</option>';
echo '</select>';
}
else
{
echo '<select name = "status[]">';
echo '<option value = "sold">Sold</option>';
echo '<option value = "cancelled" selected>Cancelled</option>';
echo '</select>';
}
echo '</td>
echo </tr>';
}
if(isset($_POST['status']))
{
//sample only
echo "You change orderno ".$orderno_here." with the
total of ".$total_of_order." into ".$selected_status_of_orderno_here;
}
There are many records in the table and the selects are the same
how do I get the values of the selected select
Following your question, whatever i understood, according to that i am supposing you are getting data from form like tags in your page. If that is the case, you know that which value is changed to be reflected in db. So you can get that selected select from this.
you can check the change through this code:
if(isset($_POST['element'])){
//if this block executed, the <element> named element is changed
}
ignore this answer if this is not the case you are using in your code..

do while in do while in php

That loop using do while, and it is working fine but when I add another do while in to this the second do while work but first do while only show one row not all 10 row. My code is below
<?php do { ?>
<tr>
<td><?php echo $row_Recordset1['date']; ?></td>
<?php do { ?>
<td><?php echo $row_Recordset1['nav']; ?></td>
<?php } while ($row_Recordset1= mysql_fetch_assoc($Recordset1)); ?>
</tr>
<?php } while ($row_Recordset1 = mysql_fetch_assoc($Recordset1)); ?>
My date should be displayed once in a row but all the other td will be took from nav;
This is what I want:
------------------------
|2014-02-26|5.5|3.2|3.5|
------------------------
|2014-02-25|3.1|1.2|1.5|
But I'm currently getting:
------------------------
|2014-02-26|5.5|3.2|3.5|
------------------------
You should look at http://php.net/mysql_fetch_assoc
It moves the internal pointer one step ahead, so each time you do mysql_fetch_assoc() you get the next value, hence only your enternal do while is executed. That is, only date from the first row is output, and all other values are output in second do while;
Try this for exercise:
$q = mysql_query("SOME MYSQL QUERY WITH MINIMUM THREE ROWS");
$f = mysql_fetch_assoc($q);
$f = mysql_fetch_assoc($q);
$f = mysql_fetch_assoc($q);
print_r($f);
First of all, please don't bounce in and out of PHP like that...
<?php
do {
echo '<tr>
<td>';
echo $row_Recordset1['date'];
echo '</td>';
do {
echo '<td>';
echo $row_Recordset1['nav'];
echo '</td>';
} while ($row_Recordset1 = mysql_fetch_assoc($Recordset1));
echo '</tr>';
} while ($row_Recordset1 = mysql_fetch_assoc($Recordset1));
?>
Where do you fetch your first $row_Recordset1? Somewhere earlier than this code? You're going to output table cells (<td>) until you run out of rows. I don't think you want that.
Like so:
<?php do { ?>
<tr>
<td><?php echo $row_Recordset1['date']; ?></td>
<td><?php echo $row_Recordset1['nav']; ?></td>
</tr>
<?php } while ($row_Recordset1 = mysql_fetch_assoc($Recordset1)); ?>
Because each time you use mysql_fetch_assoc it does the following
Returns an associative array that corresponds to the fetched row and moves the internal data pointer ahead.
Part of the reason this doesn't work is because you are re-assigning the value of the same variable. If you don't want to lose it then you cannot do it this way. At the very least it is a bad idea if you ever intend to do anything new with the code.
Next, I really recommend you populate an array with the data first before you ever do anything with outputting it. It is a very good idea to separate logic from output.
Your code should look more like this:
<?php
//Assumes you have already connected to a mysqli resource
$conditional_data_filtered = $mysqli->real_escape_string($conditional_data);
$sql = "SELECT date, nav FROM some_table WHERE some_column = '" . $conditional_data_filtered . "'";
if ($result = $mysqli->query($sql)) {
/* fetch associative array */
while ($row = $result->fetch_assoc()) {
$data = array(); //Make sure we start with a fresh array each time.
$data['date'] = $row['date'];
//Now I think you have a bunch of data in the nav you need to loop through
$nav_filtered = $mysqli->real_escape_string($row['nav']);
$subSql = "SELECT some_data FROM navigation WHERE some_identifier = '" . $nav_filtered . "'";
if ($subResult = $mysqli->query($subSql)) {
while ($subRow = $subResult->fetch_assoc()) {
$data['nav'][] = $subRow;
}
}
$rowList[] = $data;
}
/* free result set */
$result->free();
}
foreach ($rowList as $rowData) {
echo "<tr>";
echo "<td>" . $rowData['date'] . "</td>";
foreach ($rowData['nav'] as $navData) {
echo "<td>" . $navData['some_info'] . "</td>";
}
echo "</tr>";
}
?>
Just a note: If you really don't have sub-data and just want to output the next column then you don't need a sub-loop. You just need to echo the contents of the column like you did with the first one. Then you can get rid of the sub-loops I have shown above and just put it within the first loop.

Populate multiple drop-down lists with a single query

I have four drop-down lists that I would like to populate with values from an MSSQL table. All four lists should contain the same values. The query looks like this:
$data = $con->prepare("SELECT ID, Code FROM Table WHERE Code = :value ORDER BY Code");
$input = array('value'=>'value'); //'value' is hardcoded, not a variable
$data->execute($input);
And here is the code for my drop-downs:
<?php
echo "<select name=\"proj1[]\">";
while($row = $data->fetch(PDO::FETCH_BOTH))
{
echo "<option value='".$row['Code']."'>".$row['Code']."</option> ";
}
echo "</select>";
?>
This works fine for one drop-down. If I try to create another one (proj2[], proj3[], proj4[]) and apply the same query, however, the PHP page stops loading at that point and the second drop-down does not populate. The only way I've found around it is to copy the query and change the variables ($data becomes $data2 for proj2[], and so on). I'd really rather not have to write the same query four times. Is there a way around it?
$select = '';
while($row = $data->fetch(PDO::FETCH_BOTH))
{
$select .= "<option value='".$row['Code']."'>".$row['Code']."</option> ";
}
echo "<select name=\"proj1[]\">";
echo $select;
echo "</select>";
echo "<select name=\"proj2[]\">";
echo $select;
echo "</select>";
//etc...
Why not just put all of it in a veriable and then using it 4 times?
Somthing like this:
<?php
while($row = $data->fetch(PDO::FETCH_BOTH))
{
$options .= "<option value='".$row['Code']."'>".$row['Code']."</option> ";
}
for($i = 0; $i <= 4; $i++){
echo "<select name=\"proj1[]\">";
echo $options;
echo "</select>";
}
?>

SQL Image Database assembling rows into HTML cells and rows

I have a database of images which I want to output as a gallery ...
I want to display each image in its own cell <td>image1</td> and limit the number of cells to 7 per row.
<tr>
<td>image1</td><td>image2</td><td>image3</td><td>image4</td><td>image5</td><td>image6</td><td>image7</td>
</tr>
Then a new row would be created and continue to output all the images.
<tr>
<td>image8</td>
and so on ..
I know how to do a query, but I am lost as to how to assemble the rows into the format I am looking for.
Can anyone please help me it would be greatly appreciated. Thanks.
First run your query, then get the mysql_fetch_assoc in a variable. Then echo your beginning tags for the table and tr. Then create a foreach loop of the query assoc, as another variable such as row, and echo $row['image'] in a td. This will add a new td with the image for every entry in the database. Then echo your closing tags for the tr and table.
$query = mysql_query("SELECT image FROM table_name");
$query_a = mysql_fetch_assoc($query);
echo "<table><tr>"
foreach ($query_a as $row)) {
echo "
<td>" . $row['image'] . "</td>
";
}
echo "</tr></table>";
Not tested, but try something like this
<table>
<?php
// make sure there is at least 1 row first
$cnt = 0;
$while($row = mysql_fetch_assoc($query))
{
if(++$cnt == 1) {
echo '<tr>';
} elseif($cnt % 7 == 0) {
echo '</tr><tr>';
}
// show images in <td>'s
echo "<td>" . $row['image']. "</td>";
}
echo '</tr>';
?>
</table>
Keep it simple:
Query the database to get the desired information, loop through the results, construct a new row come each new loop.
$sql = "Select * from table";
mysql_query($sql) or die(mysql_error());
if(mysql_num_rows !=0)
{
// Found at least one record, create table
echo "<table>";
echo "<tr>";
while($row = mysql_fetch_assoc($sql)
{
$cell_count = 0;
// Create a new row for each record found
echo "<td>" . $row['image_column']. "</td>";
$cell_count++;
if($cell_count == 7)
{
echo "</tr>";
echo "<tr>";
$cell_count = 0;
}
}
// Close the table
echo "</tr>";
echo "</table>";
}

PHP function creates tables, how to add database ID as URL parameter?

I have some code that creates a table like this:
for($i=0; $i<$fields_num; $i++)
{
$field = mysql_fetch_field($result);
echo "<td" . $i;
echo "></td>";
}
echo "</tr>\n";
// printing table rows
while($row = mysql_fetch_row($result))
{
echo "<tr>";
// $row is array... foreach( .. ) puts every element
// of $row to $cell variable
$counter = 0;
foreach($row as $cell)
{
if($counter == 0)
{//1st column
echo "<td><strong>" .$cell. "</strong></td>";
}
elseif($counter == 8)
{//7th column
echo "<td><img src=\"http://php.alton.com/image.php/image.jpg?width=100&height=100&cropratio=1:1&image=".$cell."\" /></td>";
}
elseif($counter == 9)
{//eighth column
echo "<td><strong>" .$cell. "</strong></td>";
}
else
echo "<td>$cell</td>";
//inside your default td
$counter++;
}
echo "</tr>\n";
}
I am trying to get the MySQL result from column 0 (ID) and pass this variable into a URL parameter in the result. I want the SQL results in Column 8 to create a link that includes the ID from column 0. For example: "/details.php?ID=43" where the ID comes from the 1st column in the row. Does this make sense?
Your output code is inherently bad since it relies on the order the results are returned in from the database. This may work now, but is an incredibly fragile way of doing things. You should refer to your fields (columns) by name, not by the order they're returned in. You're also needlessly complicating your output code with that inner loop and if…else construct. Try something along these lines:
<?php while ($row = mysql_fetch_assoc($result)) : ?>
<tr>
(substitute 'col1' etc by the actual columns names)
<td><strong><?php echo $row['col1']; ?></strong></td>
<td><?php echo $row['col2']; ?></td>
…
<td>
<img src="http://php.alton.com/image.php/image.jpg?width=100&height=100&cropratio=1:1&image=<?php echo $row['image']; ?>" />
</td>
…
</tr>
<?php endwhile; ?>
I'm not quite sure about your actual question, but approaching your problem like this may answer it already.

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