get multiple checkbox value with select all and update value into database - php

hello friends i m trying to make a inbox system in which we select all checkbox with the help of one checkbox and then through ajax pass the value to all checkbox and update the database. but the problem is that they values and being selected one by one and then forming a array
for eg
fst time 2
second time 2,3
third time 2,3,4
and at the sql query where i am trying to get the list of array and break them so that i can update the value in database its also not happening , can anyone help ?here is what i coded.
to get the value of checkbox
$(function(){
$('.massmsgdelbutton').click(function(){
var val = [];
$('.sltchk:checked').each(function(i){
val[i] = $(this).val();
var dataString = 'massmsgdel='+ val;
if(confirm("Sure you want move all these messages to Trash? There is NO undo!"))
{
$.ajax({
type: "POST",
url: "modules/messages/sql_ex.php",
data: dataString,
cache: false,
success: function(html){
alert(html);
}
});
}
});
});
});
my sql code using expode to explode the array
if(isset($_REQUEST['massmsgdel']))
{
$id=$_REQUEST['massmsgdel'];
$myArray[] = explode(',', $id);
echo $id;
$sql=mysql_query("update message set trash='1' where message_id='$myArray'");
}

Well, there are really two approaches you can use here. From my experience, anyway.
You can either loop through the array(foreach loop) you have and perform an UPDATE each time, something like the following:
$sql=mysql_query("update message set trash='1' where message_id='$messageID'");
Or you could try using the IN SQL Operator(which you can find more info on here), something like so:
$sql=mysql_query("update message set trash='1' where message_id IN ('$messageID1', '$messageID2', '$messageID3', '$messageID4')");
The IN Operator will match the message_id to any of the parameters in the parenthesis.

Does it work?
if(isset($_REQUEST['massmsgdel']))
{
$id=$_REQUEST['massmsgdel'];
$myString = implode(',', $id);
echo $id;
$sql=mysql_query("update message set trash='1' where message_id IN ($myString)");
}

guys i found the solution .
in the jquery i had to use
var dataString = 'massmsgdel='+ val[i];
instead of
var dataString = 'massmsgdel='+ val;
and in sql i had to use
$sql=mysql_query("update message set trash='1' where message_id IN ('$myArray')");
thanks #Frank Allenby for helping me the way out

Related

Increment MySQL value on click with +1

What I have
An url like this: http://localhost:8888/website/?key=ABC
A MySQL table with many rows, one with a key called ABC. I have a button that I want users to click (upvote) the MySQL row corresponding to key=ABC.
In my scripts.js I have this (incomplete?) Ajax code:
function increment() {
$.ajax({
type: 'POST',
url: '../js/ajax.php',
success: function(data) {
alert("function saved: " + data);
}
});
}
And my ajax.php looks like this:
<?php
if (isset($_GET['key']) {
$rowKEYtest = $_GET['key'];
$sql2 = "UPDATE database SET Score = Score + 1 WHERE UniqueKey = '$rowKEYtest'";
$conn->query($sql2);
} else {
echo "lol";
}
?>
It's not updating. I have no idea what to do.
Please have a look in your code, There is 2 mistakes.
1. In your ajax call you are using type: 'POST', you should use GET.
2. You are nor parsing your 'key' param in ajax call.
Actually you are using POST method in ajax but in ajax.php trying to get the value with GET method. second thing you are not passing any param in ajax call.
Hope this will help.

how would I pull the data out of the database and re-check the checkboxes that were originally checked and submitted?

I entered checkbox values into the database using the code below. When a user wants to view the checked boxes at a later time, how would I pull the data out of the database and re-check the checkboxes that were originally checked and submitted?
From the code below the data gets entered like this: DATA1|DATA2|DATA3|
var checkbox_value = "";
$(":checkbox").each(function () {
var ischecked = $(this).is(":checked");
if (ischecked) {
checkbox_value += $(this).val() + "|";
}
});
Now how to I take DATA1|DATA2|DATA3| and re-check the corresponding checkboxes?
Here is how I'm getting other data and re-displaying it from normal input text boxes:
$.ajax({
url: 'ajax/example/example.php',
data: "findval="+carrier+"&column="+column,
dataType: 'json',
success: function(data)
{
var auto_id = data['id'];
var auto_name = data['name'];
var auto_address = data['address'];
var auto_trailer_types = data['trailer_types'];
$('#output_autocomplete_forms').html("<form id='example' class='form-horizontal'><input type='hidden' name='auto_id' id='auto_id' class='form-control' value="+auto_id+">......<div class='form-group'>
<div class='checkbox'><label><input type='checkbox' name='trailer_kinds[]' value='DATA1'>DATA1</label></div>
<div class='checkbox'><label><input type='checkbox' name='trailer_kinds[]' value='DATA2'>DATA2</label></div>
<div class='checkbox'><label><input type='checkbox' name='trailer_kinds[]' value='DATA3'>DATA3</label></div>
var auto_trailer_types = data['trailer_types'];
Now how do I take DATA1|DATA2|DATA3| and re-check the corresponding checkboxes?
So, I am guessing that the string stored in the database is something like 0|0|1|0, and you need to restore the checkboxes to that state.
As has been said, you can use AJAX for that. First, you need a trigger to launch the AJAX routine -- a button click, usually:
<button id="mybutt">Update Checkboxes</button>
Your AJAX routine will look something like this:
var rowID = $(this).closest('tr').attr('id');
alert(rowID); //this datum must allow you to identify the row in the database
$.ajax({
type: 'post',
url: 'another_php_file.php',
data: 'id=' +rowID,
success: function(recd){
var arrCB = recd.split('|');
for (var n=0; n<arrCB.length; n++){
var z = n+1;
$('#cb'+ z).val( arrCB[n] );
}
}
});
another_php_file.php:
<?php
$id = $_POST['id'];
$pseudo_query = "SELECT `field_name` FROM `table_name` WHERE `id` = '$id' ";
echo $pseudo_query_result;
The pseudo_query_result that you echo should be your original 0|0|1|0. The PHP echo sends that datum back to the jQuery AJAX routine's success function. Important: the received data is not available outside that success function. You must do what you want with that data inside the success function, as shown in above example.
In above code, .split() was used to turn the 0|0|1|0 string into an array, and then we use a for loop (or even just manually code each checkbox update individually).
Use ajax to resolve this issue. But before try to encode your php query response in JSON
$.ajax({
url: "test.php" //Your request URI
}).done(function(data) {
//data (you can name it whatever you want) is the data that you get from your request.
//eg. if(data.checkbock){ //do something }
});
More informations here

jquery each loop into a multi array, check for duplicates

I think what I want to do is really simple but can't get it to work. I'm looping through a table and getting some values from the existing rows, that part works. Then I'm using AJAX to try and make a multidimensional array without duplicates but something isn't working. What I really want to do is delete the duplicate part, reorder the array and array_push new values. Here's what I have:
AJAX:
function getData(){
$("#table .mainTR").each(function(){
var key = $(this).find(".key").text();
var sel = $(this).find(".s").val();
var q = $(this).find(".q").val();
$.ajax({
type: "POST",
async: false,
data: {key: key, s: sel, q: q}
});
});
}
PHP:
if(isset($_POST['key'])){
$title = $_POST['key'];
$s = $_POST['s'];
$q = $_POST['q'];
if(!empty($_SESSION['check'])){
foreach ($_SESSION['check'] as $key=>$value){
if(in_array($title, $value)){
unset ($_SESSION['check'][$title]);
$_SESSION['check'] = array_values($_SESSION['check']);
array_push($_SESSION['check'], array("key"=>$title, "s"=>$s, "q"=>$q));
}
}
}else{
$_SESSION['check'] = array(array("key"=>$title, "s"=>$s, "q"=>$q));
}
}
Is there something wrong with the logic? It seems like it should work. The same foreach loop works when trying to delete a table row. It finds the correct KEY and deletes it. Why doesn't it work here?
Here's the answer I got by hours and hours of searching. I avoided using serialize since...well I don't understand how to use it. In JS I'm looping to find values in the table and making an array like this:
function getData(){
var checkArray = new Array();
$("#shopCart .mainTR").each(function(){
var key = $(this).find(".key").text();
var sel = $(this).find(".s").val();
var q = $(this).find(".q").val();
checkArray.push(key);
checkArray.push(sel);
checkArray.push(q);
});
$.ajax({
type: "POST",
data: {ch: checkArray}
});
}
In my PHP is where I found a cool trick. Since I'm controlling the data in the array, I know how many values will be in it. The trick I found is "array_chunk" so for the 3 values I'm doing this:
if(isset($_POST['ch']) && (!empty($_POST['ch']))){
unset($_SESSION['check']);
$_SESSION['check'] = array_chunk($_POST['ch'], 3);
}
So I'm just clearing the session variable and adding the new values. That eliminates all the checking and clearing and all that. I'm sure there are better ways to do this but this method is short and works and that's what I'm looking for. Hope this helps someone!

variable in jquery function is null

I am having a problem with seeing one of my variables on a webpage. Here is what I have so far.
$(document).ready(function() {
$(function() {
$("#CheckID").click(function() {
// submit ajax job and display the result
var id = '$("#ID").val()'
$.ajax({
type: "POST",
url: "test_wID.php",
data: "id",
success: function(data) {
$('#rightselection').html(data)
}
});
});
});
});
This is the jquery function I am using to take an ID entered into a form and use that ID with a bash script.
Here is the php.
<?php
//Get the ID from the HTML form and use it with the check chunk script.
$id = $_POST['ID'];
if (is_null($id)){
echo "$id is null";
}
echo "Selected test Game ID: ".$id;
//print shell_exec('/opt/bin/tester $id');
?>
I commented out the script because the variable is returning null, at this point I am just trying to make sure that I get the ID.
For completeness here is the form I'm using.
print "<p><h3>ID: <input type=\"text\" id=\"ID\" /></h3></p>";
#print "<br>";
print "<p><button id=\"CheckID\">Check ID</button></p>";
When i click the button I get the message in my div that the variable is null. So my question is am I missing something in the declaration? How is it that the var id is null?
Thanks for any help provided.
You should consider changing your jQuery code to:
$.ajax({
type: "POST",
url: "test_wID.php",
data: {id: $("#ID").val()},
success: function(data) {
$('#rightselection').html(data)
}
});
You mixed up strings and variable references at two points.
First, the statement var id = '$("#ID").val()' assigns just a string to your if variable and not the return value of the jQuery call. So just remove the ' here.
Second, the data parameter you're giving to the ajax() call again consists just of a string "id" and not the respective value. Here you need to change to {'id': id}.
So after correcting everything, your code should look like this:
$(document).ready(function() {
$("#CheckID").click(function() {
// submit ajax job and display the result
var id = $("#ID").val();
$.ajax({
type: "POST",
url: "test_wID.php",
data: {'id': id},
success: function(data) {
$('#rightselection').html(data);
}
});
});
});
Sidenote: Try to put all ;, where they belong. This prevents some errors, which can be hard to track!
EDIT
As pointed out in the comment by #FlorianMargaine you only need one wrapper not two around your code.
Firstly, the two following snippets are equivalent:
$(document).ready(function() {
});
// Is equivalent to:
$(function() {
});
So your code does the same as:
$(document).ready(function() {
$(document).ready(function() {
});
});
Plain useless, right?
Secondly, this line is plain wrong:
var id = '$("#ID").val()';
You're passing a string to the id variable. $('#ID').val() is not evaluated. This is the equivalent of doing this in PHP:
$id = '$_POST["id"]';
Which is just wrong, right?
You want this:
var id = $('#ID').val();
By the way, this variable naming could be improved, the same goes for the HTML ID.
Thirdly, you're doing the same mistake in the data option of $.ajax:
data: 'id'
You're just passing a string to the data option. You want the value of the id variable.
Then, if you absolutely want a string, I don't recommend it. jQuery expects a special kind of string. You better pass an object. Like this:
data: {
id: id
}
Do you see why the variable naming is wrong? You can't differentiate the property from the value. If you had done the following:
var idValue = $('#ID').val();
You could use this:
data: {
id: idValue
}
Which is way more readable.
In your $.ajax call you need to do:
data : { id: id }
If you want to pass parameters in an AJAX call you need to pass a string similar to the GET string you see in urls. So something like: d=123&name=test
Change the line
var id = '$("#ID").val()'
To
var id = 'id=' + $("#ID").val();

ajax POST not working, can't figure why

I have a simple AJAX function to send an id of an object to a php page
My function looks like this:
$(function(){
$("a.vote").click(function(){
//get the id
the_id = $(this).attr('id');
alert(the_id);
//ajax post
$.ajax({
type: "POST",
data: "?id="+the_id,
url: "vote.php",
success: function(msg)
{
$("span#message"+the_id).html(msg);
}
});
});
});
My vote.php looks like this:
session_start();
if(isset($_SESSION['user'])) {
// db setup removed
// insert vote into db
$q = "UPDATE votes SET vote = vote + 1 WHERE id = " . $_POST['id'];
mysql_query($q);
echo "You sent " . $_POST['id'];
}
When I execute my AJAX function, it appears that the vote.php is never run
I know that my AJAX function is being called correctly, because alert(the_id); is popping up with the correct ID.
I know my vote.php is functioning correctly because I can run an HTML method="post" with a textbox named "id", and it will update the database correctly.
Can anyone see what's wrong?
Thank you
You're trying to send your variables in the URL, not as POST variables. Should be something like:
$(function(){
$("a.vote").click(function(){
//get the id
var the_id = $(this).attr('id');
alert(the_id);
//ajax post
$.ajax({
type: "POST",
data: {id:the_id},
url: "vote.php",
success: function(msg)
{
$("span#message"+the_id).html(msg);
}
});
});
});
Your data should be as included as an object, not as a string URL. Check out the examples on the jquery API page for more info on this!
The principal thing I see in your code that doesn't look right is data: "?id="+the_id,. The ? is unnecessary, and illogical for a post request. Do the following instead:
data: {
id: the_id
}
This lets jQuery do the URL-encoding for you.
As an additional point, you do $(this).attr(id). This is very inefficient. Do this.id instead, for exactly the same effect hundreds of times quicker at least 20 times quicker.
Your data value shouldn't need a question mark at the beginning.

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