php - preg_replace / backreference - Syntax to extract parts from mail address - php

Question

I do have a var like this:
$mail_from = "Firstname Lastname <email#domain.com>";
I would like to receive either an
array(name=>"firstname lastname", email=>"email#domain.com")
or
the values in two separate vars ($name = "...", $email = "...")
I have been playing around with preg_replace but somehow do not get it done ...
Did extensive search but did not find a way to get this done.
This is the closest I got:
$str = 'My First Name <email#domain.com>';
preg_match('~(?:"([^"]*)")?\s*(.*)~',$str,$var);
print_r($var);
echo "<br>Name: ".$var[0];
echo "<br>Mail: ".$var[2];
How do I get "email#domain.com" into $var['x]?
Thank you.

Answer 1

This works for your example and should always work, when the email is within angle brackets.
$str = 'My First Name <email#domain.com>';
preg_match('~(?:([^<]*?)\s*)?<(.*)>~', $str, $var);
print_r($var);
echo "<br>Name: ".$var[1];
echo "<br>Mail: ".$var[2];
Explanation:
(?:([^<]*?)\s*)? matches optionally everything that is not a < and everything except the trailing whitespace is stored in group 1.
<(.*)> matches something between angle brackets and store it in group 2.

Answer 2

//trythis
$mail_from = "Firstname Lastname <email#domain.com>";
$a = explode("<", $mail_from);
$b=str_replace(">","",$a[1]);
$c=$a[0];
echo $b;
echo $c;

Answer 3

Try this:
(?<=")([^"<>]+?) *<([^<>"]+)>(?=")
Explanation:
<!--
(?<=")([^"<>]+?) *<([^<>"]+)>(?=")
Options: ^ and $ match at line breaks
Assert that the regex below can be matched, with the match ending at this position (positive lookbehind) «(?<=")»
Match the character “"” literally «"»
Match the regular expression below and capture its match into backreference number 1 «([^"<>]+?)»
Match a single character NOT present in the list “"<>” «[^"<>]+?»
Between one and unlimited times, as few times as possible, expanding as needed (lazy) «+?»
Match the character “ ” literally « *»
Between zero and unlimited times, as many times as possible, giving back as needed (greedy) «*»
Match the character “<” literally «<»
Match the regular expression below and capture its match into backreference number 2 «([^<>"]+)»
Match a single character NOT present in the list “<>"” «[^<>"]+»
Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
Match the character “>” literally «>»
Assert that the regex below can be matched, starting at this position (positive lookahead) «(?=")»
Match the character “"” literally «"»
-->
Code:
$result = preg_replace('/(?<=")([^"<>]+?) *<([^<>"]+)>(?=")/m', '<br>Name:$1<br>Mail:$2', $subject);