PHP MySQL Query group by items - php

Question

I'm getting this JSON result from mySQL with the following php query:
/* grab the posts from the db */
$query = "SELECT * FROM ko_timetable";
$result = mysql_query($query,$link) or die('Errant query: '.$query);
/* create one master array of the records */
$posts = array();
if(mysql_num_rows($result)) {
while($post = mysql_fetch_assoc($result)) {
$posts[] = array('post'=>$post);
}
}
JSON Result:
post = {
"CLASS_LEVEL" = "Intro/General";
"CLASS_TYPE" = "Muay Thai";
"DAY_OF_WEEK" = Sunday;
ID = 19;
"ORDER_BY" = 5;
TIME = "1:00pm - 2:30pm";
};
}
{
post = {
"CLASS_LEVEL" = "General/Intermediate/Advanced";
"CLASS_TYPE" = "Muay Thai Spar - Competitive";
"DAY_OF_WEEK" = Sunday;
ID = 27;
"ORDER_BY" = 5;
TIME = "6:00pm - 9:00pm";
};
},
{
post = {
"CLASS_LEVEL" = "Fighters/Advanced/Intermediate";
"CLASS_TYPE" = "Fighters Training";
"DAY_OF_WEEK" = Monday;
ID = 1;
"ORDER_BY" = 1;
TIME = "9:30am - 11:00pm";
};
But how can I change this query to get this result group by "DAY_OF_WEEK". See example below, thanks for your help:
{
Sunday = {
"CLASS_LEVEL" = "Intro/General";
"CLASS_TYPE" = "Muay Thai";
"DAY_OF_WEEK" = Sunday;
ID = 19;
"ORDER_BY" = 5;
TIME = "1:00pm - 2:30pm";
};
{
"CLASS_LEVEL" = "General/Intermediate/Advanced";
"CLASS_TYPE" = "Muay Thai Spar - Competitive";
"DAY_OF_WEEK" = Sunday;
ID = 27;
"ORDER_BY" = 5;
TIME = "6:00pm - 9:00pm";
};
},
{
Monday = {
"CLASS_LEVEL" = "Fighters/Advanced/Intermediate";
"CLASS_TYPE" = "Fighters Training";
"DAY_OF_WEEK" = Monday;
ID = 1;
"ORDER_BY" = 1;
TIME = "9:30am - 11:00pm";
};
Thanks

Answer 1

You can use DAY_OF_WEEK as array index like this,
while($post = mysql_fetch_assoc($result)) {
$posts[$posts["DAY_OF_WEEK"]] = array('post'=>$post);
}
But remember that in the example you have shown the indexes of array are names of the days then the result of previous Sunday will be replaced with this weeks Sunday and so on so forth.
You could also use a count variable to avoid replacing of keys with duplicate names, like this.
$count = 1;
while($post = mysql_fetch_assoc($result)) {
$posts[$posts["DAY_OF_WEEK"].$count] = array('post'=>$post);
$count++;
}

Answer 2

change this:
while($post = mysql_fetch_assoc($result)) {
$posts[ $post['DAY_OF_WEEK'] ] = $post;
}