MySql conditional SQL. Is my scenario possible? - php

Let me set up the situation first.
I have a "users" table with X fields, the fields dont really matter for my question except for "visibility". Visibility is a tinyint and the values mean the following (0 = visible to all, 1 = visible to friends only, and 2 = invisible).
I also have a friends table (id, user_id, target_user_id). user_id is friends with target_user_id. Easy enough so far right?
Here is where it gets sticky. Im writing a PHP API and my class method looks kinda like this:
public function getUsers($requester, $page, $num) {}
the $requester is the user id of the person requesting the users
the $page is the pagination page number
the $num is the number of items per page
What I want to do in SQL is get $num users from the users table if their visibility field is = 0 or 1. If the visibility flag is 1 however, I need to make sure the user id and the $requester are friends in the friends table and only return that user if they are friends.
I thought about using PHP to filter the visibility after I get my results back but the pagination (limit) will be screwed up if I ask for 5 records for example and one or more user has visibility set to 1 and are not friends with the requester. This pretty much has to be done entirely thru sql.
Possible??

Try creating a temp table 'temp' with same structure as users.
select * into temp From users where visibility=0 or visibility=1;
Select * from temp, friends where (temp.visibility=0) or (temp.user_id = friends.target_user_id);
Don't forget to empty the temp table.
I haven't tried the second query yest, let me know what output you got.
select * from users, friends where (users.visibility=0) or (users.visibility=1 and users.user_id = friends.target_user_id);

I think you can use LEFT JOIN for this.. something like
"SELECT *
FROM users t1
LEFT JOIN friends t2 ON t2.user_id=t1.id AND t1.visibility=1
INNER JOIN user t3 ON t3.id=t2.target_user_id
WHERE t1.visibility=0 OR t1.visibility=1
LIMIT ".($page*$num).",".$num

Related

MYSQL Query - Get the users that are not equal to the users I am following

I am trying to get the users I am not following and that isn't equal to me.
So far I have got this query:
SELECT DISTINCT
u.id,
u.username,
u.profileImage,
u.fullname,
u.coverImage,
u.bio,
a.uuid,
a.type
FROM USERS u
JOIN Activity a
WHERE NOT u.id = 145
AND a.id = 145
AND type = 'follow'
145 is the current user.
I store following's in the Activity table, So I Don't want to get the users that are equal to the IdOtherUser in the row where id = 145.
When I follow someone it would be like this:
Id = 145(me)
IdOtherUser = 86(other person I follow, who I don't want to get from USERS table.)
type = 'follow'(type of action)
I am successfully getting all the users that aren't equal to me(145) but cannot seem to get the users that are equal to the people I follow!
Any ideas are much appreciated.
Thanks in advance
fiddle
I want to get the users that is not equal to 123(current user, and the people he is following user(145))
There are various ways to accomplish the expected outcome. They are all based on using a subquery to determine if a user is followed by a given user. You can have this subquery as a derived table (in the from clause), or in a not in() or not exists() operator. I'll show you an example for the not exists() operator because it does not have to pull data from the users table, it merely checks if you have a record corresponding to the where criteria
select *
from users u1
where u1.id<>145 --not me
and not exists (select 1
from activity a
where a.id=145 --users I follow
and a.IdOtherUser=u1.id
and a.type='follow')

Should I have an updated count as part of user table?

Let's imagine I have a databases with two tables, Users and Posts. The first table contains a row for each user, the second table a row for each post that users have written. If I want to display a post count on the users' profiles, which of these two strategies work the best:
Every time a user creates a post I UPDATE the Users table, +1 a field PostCount;
When someone visits the profile I simply run a select statement to get a count of post, for example SELECT COUNT(post_id) FROM Posts WHERE id_user = 100;
In the first case I have to UPDATE a table very often, which it could be bad as I believe a table gets locked when doing the update; in the second case I have to run a count every time the user visits a profile. Which poison is the less bitter? Is there any other way?
I would say that it depends on how many times you will display PostCount, especially for a huge amount of Users. If you are going to display it for 1000+ users on a page that will be called a lot of times, then the first solution should be the best. But you need to do transactions to be sure both tables Posts and Users are updated when adding a new post.
Otherwise, the second solution should be enough, but you should use LEFT OUTER JOIN so that you would get both information from Users and Posts table in only one query. Eg:
SELECT *
FROM Users u
LEFT OUTER JOIN (
SELECT user_id , COUNT(*) AS posts_count
FROM Posts
GROUP BY user_id
) p ON p.user_id = u.id
WHERE u.id = :searched_id
(And anyway you should use a Cache system so that you don't have to do the same SQL query for a same page if shown to several users.)

Showing users who liked an item in an item list

This is an issue that I've deemed impractical to implement but I would like to get some feedback to confirm.
I have a product and users database, where users can like products, the like data is stored in a reference table with just pid and uid.
The client request is to show 3 users who have liked every product in the product listing.
The problem is, its not possible to get this data in one query for the product listing,
How I once implemented and subsequently un-implemented it was to perform a request for the users who have liked the products during the loop through the product list.
ie.
foreach($prods as $row):
$likers = $this->model->get_likers($row->id);
endforeach;
That works, but obviously results in not only super slow product listings, and also creates a big strain on the database/cpu.
The final solution that was implemented was to only show the latest user who has liked it (this can be gotten from a join in the products list query) and have a link showing how many people have liked, and upon clicking on it, opens a ajax list of likers.
So my question is, is there actually a technique to show likers on the product list, or is it simply not possible to execute practically? I notice actually for most social media sites, they do not show all likers on the listings, and do employ the 'click to see likers' method. However, they do show comments per items on the listing, and this is actually involves the same problem doesn't it?
Edit: mock up attached on the desired outcome. there would be 30 products per page.
By reading your comment reply to Alex.Ritna ,yes you can get the x no. of results with per group ,using GROUP_CONCAT() and the SUBSTRING_INDEX() it will show the likers seperated by comma or whatever separator you specified in the query (i have used ||).ORDER BY clause can be used in group_concat function.As there is no schema information is available so i assume you have one product table one user table and a junction table that maintains the relation of user and product.In the substring function i have used x=3
SELECT p.*,
COUNT(*) total_likes,
SUBSTRING_INDEX(
GROUP_CONCAT( CONCAT(u.firstname,' ',u.lastname) ORDER BY some_column DESC SEPARATOR '||'),
'||',3) x_no_of_likers
FROM product p
LEFT JOIN junction_table jt ON(p.id=jt.product_id)
INNER JOIN users u ON(u.id=jt.user_id)
GROUP BY p.id
Fiddle
Now at your application level you just have to loop through the products and split the x_no_of_likers by separator you the likers per product
foreach($prods as $row):
$likers=explode('||',$row['x_no_of_likers']);
$total_likes= $row['total_likes'];
foreach($likers as $user):
....
endforeach;
endforeach;
Note there is a default 1024 character limit set on GROUP_CONCAT() but you can also increase it by following the GROUP_CONCAT() manual
Edit from comments This is another way how to get n results per group, from this you can get all the fields from your user table i have used some variables to get the rank for product group ,used subquery for junction_table to get the rank and in outer select i have filtered records with this rank using HAVING jt.user_rank <=3 so it will give three users records per product ,i have also used subquery for products (SELECT * FROM product LIMIT 30 ) so the first 30 groups will have 3 results for each,for below query limit cannot be used at the end so i have used in the subquery
SELECT p.id,p.title,u.firstname,u.lastname,u.thumbnail,jt.user_rank
FROM
(SELECT * FROM `product` LIMIT 30 ) p
LEFT JOIN
( SELECT j.*,
#current_rank:= CASE WHEN #current_rank = product_id THEN #user_rank:=#user_rank +1 ELSE #user_rank:=1 END user_rank,
#current_rank:=product_id
FROM `junction_table` j ,
(SELECT #user_rank:=0,#current_rank:=0) r
ORDER BY product_id
) jt ON(jt.product_id = p.id)
LEFT JOIN `users` u ON (jt.`user_id` = u.`id`)
HAVING jt.user_rank <=3
ORDER BY p.id
Fiddle n results per group
You should be able to get a list of all users that have liked all products with this sql.
select uid,
count(pid) as liked_products
from product_user
group by uid
having liked_products = (select count(1) from products);
But as data grows this query gets slow. Better then to maintain a table with like counts that is maintained through a trigger or separately. On every like/dislike the counter is updated. This makes it easy to show the number of likes for each product. Then if the actual users that liked that product is wanted do a separate call (on user interaction) that fetches the specific likes for one product). Don't do this for all products on a page until actually requested.
I am assuming the size of both these tables is non-trivially large. You should create a new table (say LastThreeLikes), where the columns would be pid,uid_1,uid_2 and uid_3, indexed by pid. Also, add a column to your product table called numLikes.
For each "like" that you enter into your reference table, create a trigger that also populates this LastThreeLikes table if the numLikes is less than 3. You can choose to randomly update one of the values anyway if you want to show new users once in a while.
While displaying a product, simply fetch the uids from this table and display them back.
Note that you also need to maintain a trigger for the "Unlike" action (if there is any) to re-populate the LastThreeLikes table with a new user id.
Problem
The problem is the volume of data. From the point of view that you need two integer value as a answer you should forget about building a heavy query from your n<->n relations table.
Solution
Generates a storable representation using the file_put_contents() with append option each time a user likes a product. I don't have enough room to write the class in here.
public function export($file);
3D array format
array[product][line][user]
Example:
$likes[1293][1][456]=1;
$likes[82][2][656]=1;
$likes[65][3][456]=1;
.
.
.
Number of users who like this particular product:
$number_users_like_this_product = count($likes[$idProduct]);
All idUser who like this particular product:
$users_like_this_product = count($likes[$idProduct][$n]);
All likes
$all_likes = count($likes);
Deleting a like
This loop will unset the only line where $idProduct and $IdUser you want. Since all the variables are unsigned integer it is very fast.
for($n=1, $n <= count($likes[$idProduct]), $n++)
{
unset($likes[$idProduct][$n][$idUser]);
}
Conclusion
Get all likes will be easy as:
include('likes.php');
P.S If you want to give a try i will be glad to optimize my stuff and share it. I've created the class in 2012.

Simplifing a mysql query

Scenario
I have three elements in this problem. One is an array of ids in this format: (1,3,5,6,8). That array is a list of id of users I want to display. The second element is table that contains user information something simple like: id name surname email. The third element is a second table that contains users configuration. There are two parameters in that last table, one is lid, and the other is usraction (among others, but the important are those two). lid represent a permission type and usraction the value, if the user wants his data to be public there will be a row on that table where lid=3 and usraction="accepted", also I register the datetime of the action every time the user changes this permission, so each time he change it a new row is added, and in order to retrieve the actual state of the permission i have to retrieve the last row for the user an check the value of usraction like this:
SELECT * FROM legallog WHERE uid = '.$user['id'].' AND lid = 3 ORDER BY ABS(`registration` - NOW()) LIMIT 1
Then in php:
if($queryresult && $queryresult[0]['usraction']=='accepted') //display data
The problem
In the scenario id described how im getting the actual state of the permission set by one user at the time, the problem now is I want to sort of clean an array of ids in one or two sql calls. Lets say I want to print the user information of 4 users, one function gives me the ids in this format: (2,6,8,1), but those users may not want to display their information, using the query I showed before I can make a call to the sql server for each user and then generate a new array, if the users who authorize are 1 and 8 the result array will be (8,1).
The think is whit an array of 100 users I will make 100 calls, and I dont want this, is there a way to solve this in one or two querys?
A query such as this gets you the information you want:
select u.*,
(select usraction from configuration c where c.userid = u.userid and c.lid = 3 order by datetime limit 1
) as lastLid3Action
from users u
where u.userid in (1,3,5,6,8)
If you only want "accepted" values, then make this a subquery:
select t.*
from (select u.*,
(select usraction from configuration c where c.userid = u.userid and c.lid = 3 order by datetime limit 1
) as lastLid3Action
from users u
where u.userid in (1,3,5,6,8)
) t
where LastLid3Action = 'Accepted'
As I understand you have two tables in the first table, where the user information is stored; and the second table, where the user permission is stored. And you want to get information from the first table using permission from the second table, then you need this query:
SELECT a.*
FROM first-table-name AS a
RIGHT JOIN second-table-name AS b a.uid = b.lid
WHERE uid in (1,3,5,6,8) AND usraction='accepted'
ORDER BY ABS)
LIMIT 1
You question is somewhat vague, but if you are asking how to select a number of records when you have a list of ids, the answer is:
select column, list, goes, here from tablename
where id in (1,5,8,12,413);
That will get you the values of the columns you list for just the records that match your array of ids.

Using an array in an SQL query

Okay, so I want to have a news feed on my website. I have 3 tables named Users, Follow, and Posts. Basic user data goes into the Users table, who is following who is stored in the Follow table, and whatever the user posts goes into Posts. Now, I know how to select every post from a database table and limit it using the WHERE clause. But how would I write my query to select all all of the posts from only user's they are following, and display them by DESC date? Thanks.
Here's a general layout for you, make three tables like you mentioned, I've outlined below just as an example
[TABLES]
users
followers
posts
In the users table you should have at least columns like userid (auto incremented value / primary key).
The followers table should have something like userid which would match to the users table userid, a followid column which would also have the id # for the follower from the users table.
Then for your posts table you would want to have userid too so when each post is made it would have the id from users table.
Then you would need to do something like:
SELECT p.*
FROM posts AS p
WHERE p.userid IN (SELECT followid FROM followers WHERE userid = ###)
ORDER BY p.date DESC
Now it really depends on how you are getting the users id to figure this out. If your passing the users id using a session after they logged in similar to something like Facebook, then you could change userid = ### to something like userid = ".$_SESSION['userid']." But again it really depends on how you pass the users id but the above should at least get you somewhat started.
Make sure to put indexes on the userid, followid columns so that when the table becomes larger it will do the joins quickly.
An alternative to #Shane's answer is to use the JOIN operator:
'SELECT p.* // I prefer to name all the fields, but for brevity's sake I'll use the shorthand
FROM Posts AS p
INNER JOIN Follow AS f ON p.userid = f.followid
WHERE f.userid = '.$selectedUserID.'
ORDER BY p.date DESC;'
For an inputed User ID ($selectedUserID), it will find all User ID's of the people they follow (matching follow ID to user ID on the Follow x-ref table) and then find their respective posts from the Post table in descending order by date. It will return empty if they do not follow anyone or the people they follow have no posts.
I also hope I do not need to remind you to sanitize your input to the database and escape your output to the web.
Is this what you're looking for?

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