I am trying to retrieve data from this XML style file :
<Product_Group>
<Product_Group_ID>131</Product_Group_ID>
<Product_Group_Title>Thanks for the Memories</Product_Group_Title>
<Products>
<On_Sale_Date>03/01/12 00:00:00.000</On_Sale_Date>
<ISBN>9780007233694</ISBN>
<Title>Thanks for the Memories</Title>
<Format>Paperback</Format>
<Sub_Format/>
<CoverImageURL_Small>http://www.harpercollins.com/harperimages/isbn/small/4/9780007233694.jpg</CoverImageURL_Small>
</Products>
</Product_Group>
I am using following code but this seems to retrieve nothing. any help in fixing this issues would be highly appreciated
$xml = simplexml_load_string($response);
//$xml= $response;
$updates = array();
//loop through all the entry(s) in the feed
for ($i=0; $i<count($xml->Product_Group); $i++)
{
//get the id from entry
$ISBN = $xml->entry[$i]->ISBN;
//get the account link
$Title = $xml->entry[$i]->Title;
//get the tweet
$Product_Group_SEO_Copy = $xml->entry[$i]->Product_Group_SEO_Copy;
}
1) It is not valid XML. What warnings do you see? You'll need to fix them for simplexml_load_string to work properly.
For example, </CoverImageURL_Small> should be <CoverImageURL_Small/>
2) Assuming that Product_Group is not your actual document root (if it is than $xml points to it already and $xml->Product_Group will not work) then you can access each element like
$xml->Product_Group->Products[$i]->ISBN;
3) It's usually simpler to use a foreach loop than a for loop when dealing with simplexml
foreach($xml->Product_Group->Products as $p)
{
$ISBN = $p->ISBN;
//var_dump($ISBN);
}
Related
First, I am pretty clueless with PHP, so be kind! I am working on a site for an SPCA (I'm a Vet and a part time geek). The PHP accesses an xml file from a portal used to administer the shelter and store images, info. The file writes that xml data to JSON and then I use the JSON data in a handlebars template, etc. I am having a problem getting some data from the xml file to outprint to JSON.
The xml file is like this:
</DataFeedAnimal>
<AdditionalPhotoUrls>
<string>doc_73737.jpg</string>
<string>doc_74483.jpg</string>
<string>doc_74484.jpg</string>
</AdditionalPhotoUrls>
<PrimaryPhotoUrl>19427.jpg</PrimaryPhotoUrl>
<Sex>Male</Sex>
<Type>Cat</Type>
<YouTubeVideoUrls>
<string>http://www.youtube.com/watch?v=6EMT2s4n6Xc</string>
</YouTubeVideoUrls>
</DataFeedAnimal>
In the PHP file, written by a friend, the code is below, (just part of it), to access that XML data and write it to JSON:
<?php
$url = "http://eastbayspcapets.shelterbuddy.com/DataFeeds/AnimalsForAdoption.aspx";
if ($_GET["type"] == "found") {
$url = "http://eastbayspcapets.shelterbuddy.com/DataFeeds/foundanimals.aspx";
} else if ($_GET["type"] == "lost") {
$url = "http://eastbayspcapets.shelterbuddy.com/DataFeeds/lostanimals.aspx";
}
$response_xml_data = file_get_contents($url);
$xml = simplexml_load_string($response_xml_data);
$data = array();
foreach($xml->DataFeedAnimal as $animal)
{
$item = array();
$item['sex'] = (string)$animal->Sex;
$item['photo'] = (string)$animal->PrimaryPhotoUrl;
$item['videos'][] = (string)$animal->YouTubeVideoUrls;
$item['photos'][] = (string)$animal->PrimaryPhotoUrl;
foreach($animal->AdditionalPhotoUrls->string as $photo) {
$item['photos'][] = (string)$photo;
}
$item['videos'] = array();
$data[] = $item;
}
echo file_put_contents('../adopt.json', json_encode($data));
echo json_encode($data);
?>
The JSON output works well but I am unable to get 'videos' to write out to the JSON file as the 'photos' do. I just get '/n'!
Since the friend who helped with this is no longer around, I am stuck. I have tried similar code to the foreach statement for photos but am getting nowhere. Any help would be appreciated and the pets would appreciate it as well!
The trick with such implementations is to always look what you have got by dumping data structures to a log file or command line. Then to take a look at the documentation of the data you see. That way you know exactly what data you are working with and how to work with it ;-)
Here it turns out that the video URLs you are interested in are placed inside an object of type SimpleXMLElement with public properties, which is not really surprising if you look at the xml structure. The documentation of class SimpleXMLElement shows the method children() which iterates through all children. Just what we are looking for...
That means a clean implementation to access those sets should go along these lines:
foreach($animal->AdditionalPhotoUrls->children() as $photo) {
$item['photos'][] = (string)$photo;
}
foreach($animal->YouTubeVideoUrls->children() as $video) {
$item['videos'][] = (string)$video;
}
Take a look at this full and working example:
<?php
$response_xml_data = <<< EOT
<DataFeedAnimal>
<AdditionalPhotoUrls>
<string>doc_73737.jpg</string>
<string>doc_74483.jpg</string>
<string>doc_74484.jpg</string>
</AdditionalPhotoUrls>
<PrimaryPhotoUrl>19427.jpg</PrimaryPhotoUrl>
<Sex>Male</Sex>
<Type>Cat</Type>
<YouTubeVideoUrls>
<string>http://www.youtube.com/watch?v=6EMT2s4n6Xc</string>
<string>http://www.youtube.com/watch?v=hgfg83mKFnd</string>
</YouTubeVideoUrls>
</DataFeedAnimal>
EOT;
$animal = simplexml_load_string($response_xml_data);
$item = [];
$item['sex'] = (string)$animal->Sex;
$item['photo'] = (string)$animal->PrimaryPhotoUrl;
$item['photos'][] = (string)$animal->PrimaryPhotoUrl;
foreach($animal->AdditionalPhotoUrls->children() as $photo) {
$item['photos'][] = (string)$photo;
}
$item['videos'] = [];
foreach($animal->YouTubeVideoUrls->children() as $video) {
$item['videos'][] = (string)$video;
}
echo json_encode($item);
The obvious output of this is:
{
"sex":"Male",
"photo":"19427.jpg",
"photos" ["19427.jpg","doc_73737.jpg","doc_74483.jpg","doc_74484.jpg"],
"videos":["http:\/\/www.youtube.com\/watch?v=6EMT2s4n6Xc","http:\/\/www.youtube.com\/watch?v=hgfg83mKFnd"]
}
I would however like to add a short hint:
In m eyes it is questionable to convert such structured information into an associative array. Why? Why not a simple json_encode($animal)? The structure is perfectly fine and should be easy to work with! The output of that would be:
{
"AdditionalPhotoUrls":{
"string":[
"doc_73737.jpg",
"doc_74483.jpg",
"doc_74484.jpg"
]
},
"PrimaryPhotoUrl":"19427.jpg",
"Sex":"Male",
"Type":"Cat",
"YouTubeVideoUrls":{
"string":[
"http:\/\/www.youtube.com\/watch?v=6EMT2s4n6Xc",
"http:\/\/www.youtube.com\/watch?v=hgfg83mKFnd"
]
}
}
That structure describes objects (items with an inner structure, enclosed in json by {...}), not just arbitrary arrays (sets without a structure, enclosed in json by a [...]). Arrays are only used for the two unstructured sets of strings in there: photos and videos. This is much more logical, once you think about it...
Assuming the XML Data and the JSON data are intended to have the same structure. I would take a look at this: PHP convert XML to JSON
You may not need for loops at all.
I need to extract information from an XML Radionomy (radio streaming) containing information of artist, title, cover art, weather etc.
By placing this url in the browser goes all information xml:
http://api.radionomy.com/currentsong.cfm?radiouid=ce5b70e5-dcc3-40a2-81b2-c713a02daf29&apikey=842650d9-c21a-474d-be8f-f44413dfaae2&callmeback=no&type=xml&cover=yes&previ%20ous=no
<tracks>
<radioname>RTFM</radioname>
<rank>2</rank>
<isradionomy>1</isradionomy>
<radurl>http://www.radionomy.com/rtfm</radurl>
<track>
<uniqueid>2905480252</uniqueid>
<title>02-13-2016</title>
<artists>News - US</artists>
<starttime>2016-02-14 00:59:57.177</starttime>
<playduration>121352</playduration>
<current>1</current>
</track>
</tracks>
But to try to get information through php gives me error. I do not know where he might be the problem, see if I can lend a hand.
I'm trying this:
$xml = #simplexml_load_file("
http://api.radionomy.com/currentsong.cfm?radiouid=ce5b70e5-dcc3-40a2-81b2-c713a02daf29&apikey=842650d9-c21a-474d-be8f-f44413dfaae2&callmeback=no&type=xml&cover=yes&previ%20ous=no");
if($xml){
foreach ($xml as $track){
$artiste = $track->artists;
$titre = $track->title;
$pochette = $track->cover;
continue;
}
}else{
echo "error";
}
Warning: Invalid argument supplied for foreach() in...
EDIT:
Noticed more mistakes and provided working code.
Use urlencode to encode your URL string. Use $xml->track to loop track nodes.
And stop using # to see the actual errors. It is really helpful to see errors.
Didn't touch your original code but you can take it from here.
<?php
$xml = simplexml_load_file(urlencode("http://api.radionomy.com/currentsong.cfm?radiouid=ce5b70e5-dcc3-40a2-81b2-c713a02daf29&apikey=842650d9-c21a-474d-be8f-f44413dfaae2&callmeback=no&type=xml&cover=yes&previ%20ous=no"));
if($xml){
foreach ($xml->track as $track){
$artiste = $track->artists;
$titre = $track->title;
$pochette = $track->cover;
continue;
}
} else {
echo "error";
}
I am trying to traverse this xml feed:
http://www.goonersworld.co.uk/forum/feed.php
using this code:
$data = file_get_contents('http://www.goonersworld.co.uk/forum/feed.php');
//$data = str_replace("content:encoded>","content>",$data);
$xml = simplexml_load_string($data,'SimpleXMLElement', LIBXML_NOCDATA);
foreach ($xml->feed->entry as $stories) {
echo $stories->published."<br>";
}
But I'm getting nothing back. To me it looks like $xml->feed->entry->published but am I missing something?
Ok, so I've figured this out. In case it helps anyone else it was a feed generated by PHPBB (Bulletin Board).
The actual structure I was looking for was simply:
foreach ($xml->entry as $stories) {
echo $stories->published."<br>";
}
feed and entry didn't look to be at the same level in the XML formatting but they were :-(
I have a php file setup to pull through ONE XML data feed, What I would like to do is load up to 4 feeds into it and if possible make it select a random item too. Then parse that into an jQuery News Ticker.
My current PHP is as follows...
<?php
$feed = new DOMDocument();
$feed->load('/feed');
$json = array();
$json['title'] = $feed->getElementsByTagName('channel')->item(0)->getElementsByTagName('title')->item(0)->firstChild->nodeValue;
$json['description'] = $feed->getElementsByTagName('channel')->item(0)->getElementsByTagName('description')->item(0)->firstChild->nodeValue;
$json['link'] = $feed->getElementsByTagName('channel')->item(0)->getElementsByTagName('link')->item(0)->firstChild->nodeValue;
$items = $feed->getElementsByTagName('channel')->item(0)->getElementsByTagName('item');
$json['item'] = array();
$i = 0;
foreach($items as $item) {
$title = $item->getElementsByTagName('title')->item(0)->firstChild->nodeValue;
$description = $item->getElementsByTagName('description')->item(0)->firstChild->nodeValue;
$pubDate = $item->getElementsByTagName('pubDate')->item(0)->firstChild->nodeValue;
$guid = $item->getElementsByTagName('guid')->item(0)->firstChild->nodeValue;
$json['item'][$i++]['title'] = $title;
$json['item'][$i++]['description'] = $description;
$json['item'][$i++]['pubdate'] = $pubDate;
$json['item'][$i++]['guid'] = $guid;
echo '<li class="news-item">'.$title.'</li>';
}
//echo json_encode($json);
?>
How can I modify this to load more than one feed into the file?
Thanks in advance
The simplest approach to doing this is wrapping another loop around the code you have. It's not the cleanest way but will probably suffice for the purpose.
In general, IMO, it's always beneficial to learn the basics of the language first. E.g. PHP manual on foreach
This is roughly what the loop needs to look like:
$my_feeds = array("http://.....", "http://.....", "http://.....");
foreach ($my_feeds as $my_feed)
{
// This is where your code starts
$feed = new DOMDocument();
$feed->load($my_feed); <--------------- notice the variable
$json = array();
... and the rest of the code
}
this will walk through all the URLs in $my_feeds, open the RSS source, fetch all the items from it, and output them.
If I'm reading your question right, what you may want to do is turn your code into a function, which you would then run inside a foreach loop for each url (which you could store in an array or other data structure).
Edit: If you don't know much about functions, this tutorial section might help you. http://devzone.zend.com/9/php-101-part-6-functionally-yours/
I have an XML file. I want to save all the data from the XML file to the database
The file structure of XML is like
<STORY>
<BYLINE>abc</BYLINE>
<STORYID>123456</STORYID>
</STORY>
The code for storing data to database that I am using is
$dom = new DOMDOcument();
$dom->loadXML(equitymarketnews/$zname);
$xpath = new DOMXpath($dom);
$res = $xpath->query("//STORY/");
$allres = array();
foreach($res as $node){
$result = array();
$byline = mysql_real_escape_string($node->getElementsByTagName("BYLINE")->item(0)->nodeValue);
$storyid = mysql_real_escape_string($node->getElementsByTagName("STORYID")->item(0)->nodeValue);
}
$sql12="insert into equitymarketnews values('$byline','$storyid')";
mysql_query($sql12);
I am getting nothing in my database. All values are blanks.
Where am I going wrong?
I think something is wrong with this line
$res = $xpath->query("//STORY/");
i want to story the data ie ABC and 12345 FROm XML File To Table in database
I don't really know what your question is but assuming that the code you posted does not work as you aspect, one thing i noticed is the insertion of the record:
$sql12="insert into equitymarketnews values('$byline','$storyid','$pubdate','$author','$cat','$subcat','$titleline','$subtitleline,'$storymain','$flag')";
mysql_query($sql12);
shouldn't it be inside your foreach loop? Otherwise you won't get anything into your database.
In my opinion it should look something like that:
foreach($res as $node){
$result = array();
$byline = mysql_real_escape_string($node->getElementsByTagName("BYLINE")->item(0)->nodeValue);
$storyid = mysql_real_escape_string($node->getElementsByTagName("STORYID")->item(0)->nodeValue);
$sql12="insert into equitymarketnews values('$byline','$storyid')";
mysql_query($sql12);
}
You can actually use mysql client directly for importing XML data. I do not have much experience to provide you with a code sample, but MySQL docs have quite a bit documentation on it.
Essentially, you can do something like this:
LOAD XML LOCAL INFILE 'address.xml' INTO TABLE quitymarketnews ROWS IDENTIFIED BY '<STORY>';