So im working on a friend search function. The search function works great. When you search a name, each individual user pops up in separate div's with there picture and name and a box that says "request". Now what i want to do, is when you click the box itll run some jQuery to request the user, but it seems that jQuery isnt working inside my live loading JS div.
Heres my code:
$(document).ready(function(){
$('.request').mouseover(function() {
$(this).addClass('select');
});
});
$(document).ready(function(){
$('.request').mouseout(function() {
$(this).removeClass('select');
});
});
$(document).ready(function(){
$('.request.select').click(function() {
var name = $(this).attr('href');
$.ajax({
type: "POST",
url: "requestfriend.php",
data: {'name': name}
});
$(".request.select").load('checkmark.php', function(){ });
});
});
And Here is the HTML of the user div.
echo '
<div class="update miniuser" style="margin: 3px; width: 395px;">
<div><img src="http://myurl.com/' . $FRIENDS[$i] . '/user.png" /></div>
<div style="margin-top: 10px;">' . $FRIENDS[$i] . '</div><div class="request" href="' . $FRIENDS[$i] . '">Request</div>
</div></div>';
The add class isnt working. I believe its because its being loading live in the div? thats when i put the document ready functions on them. still no dice.
I'm guessing you want .live(), which adds the function to all elements with that selector, dynamically loaded or no.
$('.request.select').live("click", function() {
var name = $(this).attr('href');
$.ajax({
type: "POST",
url: "requestfriend.php",
data: {'name': name}
});
$(".request.select").load('checkmark.php', function(){ });
});
You're adding the mouseover/out event on document ready. The data you load doesn't get added to the DOM until much later. After you've done your AJAX request and the content is added to the DOM, attach the events.
$('.request').mouseover(function() {
$(this).addClass('select');
});
Means: find all elements with the class request and add a mouseover function. The handler doesn't magically appear on elements you add afterwards.
Related
How can I add toggle function to a div which is populated with ajax response on click. Right now i can achieve the both functions but I need two clicks to get the div displayed after getting populated. Can I get this done at one click (i.e populating the div and adding toggle function)?
Any help would be greatly appreciated.
My code:
$(document).ready(function(){
$(".ex2").on('click', '.spnSelected', function() {
var self = $(this).closest("tr");
var col1_value = self.find(".col1").text();
$.ajax({
type: 'GET',
url: 'reportForm.php',
data: { propid: col1_value },
success: function(response) {
$('#form'+col1_value).html(response);
$('#form'+col1_value).toggle();
}
});
});
});
Second line $(".ex2").on('click', '.spnSelected', function() { change to $("body").on('click', '.ex2 .spnSelected', function() { should work like charm.
in you code you attached event on .ex2 click, so if you adding more .ex2 elements with ajax. you don't have event attached on new elements. when you attact click event on body and then check if .spnSelected clicked this shuld work with new elements.
I've used jQuery to create a page where users can click on a cell in a table that says, "delete," and it will send an ajax request to delete that entry from a database based on the id of the cell and then it will alter the CSS to hide the cell.
I created a test page while I was creating/tweaking the jQuery code. This page works perfectly. Here is the code:
<html>
<head>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
(function( $ ){
$.fn.deleterow = function(event) {
if (!confirm('Are you sure you want to delete this student?')) {
return false;
}
var id = event.target.id;
$.ajax({
url: 'delete.php',
type: 'GET',
data: 'id=' + id,
});
$(this).parent().css('display', 'none');
}
})( jQuery );
});
</script>
</head>
<table border="1">
<tr>
<td>Cell 2, Row 2</td><td onclick="$(this).deleterow(event);" id="13376">delete</td>
</tr>
</table>
<html>
Now I'm working on getting the code to work in the actual page that it's going to be used in. This page has a short form where users can select their name and a date. This form sends an ajax request that returns the results in a div. The data that is returned is a table , and this is where I'm trying to get my function to work. This table has a tablesorter script attached to it and also my function attached to it.
The tablesorter still works fine, but nothing happens when I click the cell with "delete" in it. I used FireBug to look at the issue and it gives me the error, "TypeError: $(...).deleterow is not a function"
Here is the code for the main page where the user submits a form and where the result is loaded in a div:
<html>
<head>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<script type='text/javascript' src='jquery.tablesorter.js'></script>
<script type='text/javascript'>
$(document).ready(function()
{
$('#myTable').tablesorter();
}
);
</script>";
</head>
<body id="my-students">
<?php include 'header.php'; ?>
<?php include 'nav-tutoring.php'; ?>
<div id="content">
This is where you can view students whom you have assigned to tutoring.
<p>
You may change the way each column is sorted by clicking on the column header.
<p>
<b>Select your name and the date to view students you have assigned for that day.</b>
<form> My form is here; removed to make post shorter </form>
<script>
$('#submit').click(function()
{
$.ajax({
type: 'POST',
url: "mystudents.php",
data: $('#name').serialize(),
success: function(data) {
$("#list").empty();
$('#list').append(data);
}
});
return false;
});
</script>
<div id="list"></div>
Here is the code for the page that is inserted into the div underneath the form. This is the page where the tablesorter works, but I cannot get my function to work. I've also made sure that I include these script libraries in the head of the main page where this div is.
<script src='//ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js'></script>
<script type='text/javascript' src='jquery.tablesorter.js'></script>
<script type='text/javascript'>
$(document).ready(function()
{
$('#myTable').tablesorter();
(function($) {
$.fn.deleterow = function(event) {
if (!confirm('Are you sure you want to delete this student?')) {
return false;
}
var id = event.target.id;
$.ajax({
url: 'delete.php',
type: 'GET',
data: 'id=' + id,
});
$(this).parent().css('display', 'none');
}
})(jQuery);
});
</script>
<table id='myTable' class='tablesorter' border="1">
<thead><tr><th>ID Number</th><th>Last</th><th>First</th><th>Tutoring<br>Assignment</th><th>Assigning Teacher</th><th>Delete?</th></tr></thead><tbody>
<?php
while($row = mysql_fetch_array($data)){
echo "<tr><td>".$row['id']. "</td><td>". $row['last']. "</td><td>". $row['first']."</td><td>". $row['assignment']."</td><td>". $row['assignteacher']."</td><td onclick='$(this).deleterow(event);' id='".$row['pk']."'>Delete</td></tr>";
}
?>
</tbody></table>
I've done many searches based on the error I'm getting, but I just can't seem to fix the problem. Any help would be greatly appreciated.
First it makes no sense to include the $.fn.deleterow = function(event) { inside the document.ready. You should move it outside of that method.
Personally I would change the code to not rely on the inline event handlers in the table. You are using jQuery, so utilize it. Use event bubling to your advantage.
Add it to the table level and listen for click events on the td's that have ids.
$("table tbody").on("click", "td[id]", function(e){
if (!confirm('Are you sure you want to delete this student?')) {
return false;
}
var id = this.id;
$.ajax({
url: 'delete.php',
type: 'GET',
data: 'id=' + id,
});
$(this).parent().css('display', 'none');
});
jsFiddle
Test if jQuery loaded in console (check for jQuery variable)...
You should wrap your code this way:
(function( $ ){
$(document).ready(function(){
$.fn.deleterow = function(event) {
if (!confirm('Are you sure you want to delete this student?')) {
return false;
}
var id = event.target.id;
$.ajax({
url: 'delete.php',
type: 'GET',
data: 'id=' + id,
});
$(this).parent().css('display', 'none');
}
});
})( jQuery );
But the most important is check if jQuery are loading correctly and solve it...
Hope it help
try rewriting to a usual javascript function
function deleterow(id) {...}
and in php
echo "<tr><td>".$row['id']. "</td><td>". $row['last']. "</td><td>". $row['first']."</td><td>". $row['assignment']."</td><td>". $row['assignteacher']."</td><td onclick='deleterow(".$row['id']. ")' id='".$row['pk']."'>Delete</td></tr>";
It's due to this:
<td onclick='$(this).deleterow(event);'
JavaScript can't see this as a function due to the enclosing ' '.
What I advise doing is this:
<td class='deleterow'>
then
$(body).on('click', '.deleteRow', function(event) {
$(this).deleterow(event);
});
You'd be better off binding those events using jQuery's handers instead of onclick, which is poor practice. Eg:
$('#myTable').on('click', 'td', function(e) {
$(this).deleterow(e);
});
this is an ajax method that inserts the data into a db and should supposedly display the new content.
<script type = "text/javascript">
$(document).ready(function() {
$('#submit').live('click', function(eve) {
eve.preventDefault() ;
var form_data = {
title: $('#title').val()
};
$.ajax({
url: "http://localhost/ci/index.php/chat/comment",
type: 'POST',
data: form_data,
success: function(msg) {
alert(msg);
}
});
});
});
</script>
However in my /chat/comment, i am loading the view again, i.e, user submits a comment, load the view again and the comment should be there. My response from server is the view's HTML. However the view comes with all the divs and there are many of them. I need to retrieve only part of the div, say, #commentspace from the ajax on success.
Look at the jQuery $.load() function?
Example
Inside "firstpage.html"
$('#content').load('secondpage.html #content');
I have been researching for the last two days, and have found nothing.
structure:
index.php:
<head>
<script type="text/javascript" src="JS/jquery-1.6.2.js"></script>
<script type="text/javascript" src="function.js"></script>
</head>
<body>
<div>
<div>Show</div> *-->if I click this link data loads into DIV below by function.js without reloading*
<div id="producten"></div> *-->testpage.php loads here perfect,
the code of testpage.php makes by while loop other links.
Here I want to click on a link to load next data in div id=information
without reloading the index.php so the data in the first DIV stay visible
and I dont know how to do that*
<div id="information"></div> *-->testpage2.php have to load data from sql in this DIV*
</div>
</body>
function.js:
$(document).ready(function() {
$(".testcat").click(function() {
var testid = $(this).attr("id");
var datastring = 'id='+ testid ;
$.ajax({
type: "POST",
url: "testpage.php",
data: datastring,
cache: false,
success: function(res) {
$('#producten').html("<div class='loading'><img src='IMG/loading.gif' /></div>")
.hide()
.fadeIn(2000, function() {
$('#producten').html(res);
})
}
});
return false;
});
});
testpage.php and testpage2.php are PDO code for sql data.
You'll want to attach your click handlers with on so that dynamically added content still has the same ajax handlers available to them:
Add whatever information is needed to differentiate one click from the next, ie
<a href='...' data-resultdiv='production'
Then, cleaning up your handler a bit: I assume you want the ajax request to go to the href of the link, and that you want to show "loading" immediately (instead of waiting for the request to complete).
Finally, to cancel the anchor's default behavior of browsing to the page referenced by the href, you can return false;
$(document).on("click", "a", function() {
var href = $(this).attr("href");
var successDiv = $(this).data("resultdiv");
$('#' + successDiv).html("<div class='loading'><img src='IMG/loading.gif' /></div>");
$.ajax({
type: "POST",
url: href,
data: datastring,
cache: false,
success: function(res) {
$('#' + successDiv).hide().html(res).fadeIn(2000);
}
}
return false;
});
And of course if you only want this to run for certain anchors, you can put a selector on your call to on
$(document).on("click", "a.someClass", function() {
I have a PHP file, Test.php, and it has two functions:
<?php
echo displayInfo();
echo displayDetails();
?>
JavaScript:
<html>
...
<script type="text/javascript">
$.ajax({
type:'POST',
url: 'display.php',
data:'id='+id ,
success: function(data){
$("#response").html(data);
}
});
</script>
...
<div id="response">
</div>
</html>
It returns the response from jQuery. The response shows as <a href=Another.php?>Link</a>. When I click the Another.php link in test.php, it loads in another window. But I need it to load the same <div> </div> area without changing the content of test.php, since it has displayInfo(), displayDetails(). Or is it possible to load a PHP page inside <div> </div> elements?
How can I tackle this problem?
If I understand correctly, you'd like for the a link to cancel navigation, but fire the AJAX function?
In that case:
$("#mylink").click(function() {
$.ajax({ type: "POST", url: "another.php", data: {id: "somedata"}, function(data) {
$("#response").html(data);
});
return false;
});
Krof is correct,
One possible unwanted behavior of this however is that it will query the data every time the link is clicked. You can set the event to only call the ajax query once by using one.
$("#mylink").one('click', function() {
// ajax call
return false;
});
Don't forget to set href="javascript:{}" in your link so after the event is fired once the link wont do anything;
You could just use MooTools and class Request.HTML.