Paging in php displaying data over multiple pages - php

Question

Hi I am trying to display my users data over pages
Here is my code:
//Run a query to select all the data from the users table
$perpage = 2;
$result = mysql_query("SELECT * FROM users LIMIT $perpage");
It does display this the only two per page but I was wondering how you get page numbers at the bottom that link to your data
here is my updated code
$result = mysql_query("SELECT * FROM users"); // Let's get the query
$nrResults=mysql_num_rows($result); // Count the results
if (($nrResults%$limit)<>0) {
$pmax=floor($nrResults/$limit)+1; // Divide to total result by the number of query
// to display per page($limit) and create a Max page
} else {
$pmax=floor($nrResults/$limit);
}
$result = mysql_query("SELECT * FROM users LIMIT 2 ".(($_GET["page"]-1)*$limit).", $limit");
// generate query considering limit
while($line = mysql_fetch_array( $result ))
{
?>
error
Parse error: syntax error, unexpected $end in E:\xampp\htdocs\Admin.php on line 98

Answer 1

In order to do this you also need to use the offset value in your SQL Statement, so it would be
SELECT * FROM users LIMIT $offset, $perpage
Example:
SELECT * FROM tbl LIMIT 5,10; # Retrieve rows 6-15
Then to get the links to put on the bottom of your page you would want to get a count of the total data, divide the total by the per page value to figure out how many pages you are going to have.
Then set your offset value based on what page the user clicked.
Hope that helps!
Update:
The unexpected end most likely means that you have an extra closing bracket } in your code which is causing the page to end and still has more code after it. Look through your code and match up the brackets to fix that. There are a few other issues in the code sample you pasted.
$result = mysql_query("SELECT * FROM users" ); //Note if you have a very large table you probably want to get the count instead of selecting all of the data...
$nrResults = mysql_num_rows( $result );
if( $_GET['page'] ) {
$page = $_GET['page']
} else {
$page = 1;
}
$per_page = 2;
$offset = ($page - 1) * $per_page; //So that page 1 starts at 0, page 2 starts at 2 etc.
$result = mysql_query("SELECT * FROM users LIMIT $offset,$per_page");
while( $line = mysql_fetch_array( $result ) )
{
//Do whatever you want with each row in here
}
Hope that helps
You can then use the nrResults number to figure out how many pages you are going to have... if you have 10 records and you are displaying 2 per page you would then have 5 pages, so you could print 5 links on the page each with the correct page # in the URL...

Answer 2

Use requests ! http://php.net/manual/en/reserved.variables.request.php
if (((isset($_GET['page'])) AND (is_int($_GET['page']))) {
$perpage = $_GET['page'];
}
$result = mysql_query("SELECT * FROM users LIMIT $perpage");
...
Link http://yourwebsite.com/userlistforexample.php?page=3
or
http://yourwebsite.com/userlistforexample.php?somethingishere=21&page=3