I need to make the HTML table to show an SQL table, but it won't show up.
I have no idea, why it won't show up.
Here's the code.
<h1> <img src="gag3.png" width="454" height="70" alt="Velkommen!"></h1>
<table width="100%" cellspacing="1" cellpadding="1" border="0" summary="">
<tbody>
<?php
$db_host = 'localhost';
$db_user = 'root';
$db_pwd = '';
$database = 'test1';
$table = 'text';
if (!mysql_connect($db_host, $db_user, $db_pwd))
die("Can't connect to database");
if (!mysql_select_db($database))
die("Can't select database");
// sending query
$result = mysql_query("SELECT * FROM {$table}");
if (!$result) {
die("Query to show fields from table failed");
}
$fields_num = mysql_num_fields($result);
// printing table headers
for($i=0; $i<$fields_num; $i++)
{
$field = mysql_fetch_field($result);
}
echo "</tr>\n";
// printing table rows
while($row = mysql_fetch_row($result))
{
echo "<tr>";
// $row is array... foreach( .. ) puts every element
// of $row to $cell variable
foreach($row as $cell)
echo "<td>$cell</td>";
echo "</tr>\n";
}
mysql_free_result($result);
?>
</tbody>
</table>
Now i really want it to show inside the table there, i want it to show the PHP,
You have no opening <tr> in that snippet. Also consider using <th></th> for your table headings. You also need to echo the headings!
// printing table headers
<tr>
for($i=0; $i<$fields_num; $i++)
{
$field = mysql_fetch_field($result);
echo "<th>".$field."</th>
}
echo "</tr>\n";
You also don't need the \n in there; <tr></tr> automatically makes a line break for the next row. I don't know how those affect the HTML; consider removing them if it still doesn't work?
Related
I want to retrieve the values from a database table and show them in a html table in a page.
I already searched for this but I couldn't find the answer, although this surely is something easy (this should be the basics of databases lol). I guess the terms I've searched are misleading.
The database table name is tickets, it has 6 fields right now (submission_id, formID, IP, name, email and message) but should have another field called ticket_number.
How can I get it to show all the values from the db in a html table like this:
<table border="1">
<tr>
<th>Submission ID</th>
<th>Form ID</th>
<th>IP</th>
<th>Name</th>
<th>E-mail</th>
<th>Message</th>
</tr>
<tr>
<td>123456789</td>
<td>12345</td>
<td>123.555.789</td>
<td>John Johnny</td>
<td>johnny#example.com</td>
<td>This is the message John sent you</td>
</tr>
</table>
And then all the other values below 'john'.
Example taken from W3Schools: PHP Select Data from MySQL
<?php
$con=mysqli_connect("example.com","peter","abc123","my_db");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM Persons");
echo "<table border='1'>
<tr>
<th>Firstname</th>
<th>Lastname</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['FirstName'] . "</td>";
echo "<td>" . $row['LastName'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
?>
It's a good place to learn from!
Try this: (Completely Dynamic...)
<?php
$host = "localhost";
$user = "username_here";
$pass = "password_here";
$db_name = "database_name_here";
//create connection
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$connection = mysqli_connect($host, $user, $pass, $db_name);
//get results from database
$result = mysqli_query($connection, "SELECT * FROM products");
$all_property = array(); //declare an array for saving property
//showing property
echo '<table class="data-table">
<tr class="data-heading">'; //initialize table tag
while ($property = mysqli_fetch_field($result)) {
echo '<td>' . $property->name . '</td>'; //get field name for header
$all_property[] = $property->name; //save those to array
}
echo '</tr>'; //end tr tag
//showing all data
while ($row = mysqli_fetch_array($result)) {
echo "<tr>";
foreach ($all_property as $item) {
echo '<td>' . $row[$item] . '</td>'; //get items using property value
}
echo '</tr>';
}
echo "</table>";
Here is an easy way to fetch data from a MySQL database using PDO.
define("DB_HOST", "localhost"); // Using Constants
define("DB_USER", "YourUsername");
define("DB_PASS", "YourPassword");
define("DB_NAME", "Yourdbname");
$dbc = new PDO("mysql:host=".DB_HOST.";dbname=".DB_NAME.";charset-utf8mb4", DB_USER, DB_PASS);
$print = ""; // assign an empty string
$stmt = $dbc->query("SELECT * FROM tableName"); // fetch data
$stmt->setFetchMode(PDO::FETCH_OBJ);
$print .= '<table border="1px">';
$print .= '<tr><th>First name</th>';
$print .= '<th>Last name</th></tr>';
while ($names = $stmt->fetch()) { // loop and display data
$print .= '<tr>';
$print .= "<td>{$names->firstname}</td>";
$print .= "<td>{$names->lastname}</td>";
$print .= '</tr>';
}
$print .= "</table>";
echo $print;
Learn more about PHP and the MySQLi Library at PHP.net.
First, start a connection to the database. Do this by making all the string variables needed in order to connect, adjusting them to fit your environment, then creating a new connection object with new mysqli() and initializing it with the previously made variables as its parameters. Now, check the connection for errors and display a message whether any were found or not. Like this:
<?php
$servername = "localhost";
$username = "root";
$password = "yourPassword";
$database = "world";
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$conn = new mysqli($servername, $username, $password, $database);
echo "Connected successfully<br>";
?>
Next, make a variable that will hold the query as a string, in this case its a select statement with a limit of 100 records to keep the list small. Then, we can execute it by calling the mysqli::query() function from our connection object. Now, it's time to display some data. Start by opening up a <table> tag through echo, then fetch one row at a time in the form of a numerical array with mysqli::fetch_row() which can then be displayed with a simple for loop. mysqli::field_count should be self explanatory. Don't forget to use <td></td> for each value, and also to open and close each row with echo"<tr>" and echo"</tr>. Finally we close the table, and the connection as well with mysqli::close().
<?php
$query = "select * from city limit 100;";
$queryResult = $conn->query($query);
echo "<table>";
while ($queryRow = $queryResult->fetch_row()) {
echo "<tr>";
for($i = 0; $i < $queryResult->field_count; $i++){
echo "<td>$queryRow[$i]</td>";
}
echo "</tr>";
}
echo "</table>";
$conn->close();
?>
First, connect to the database:
$conn=mysql_connect("hostname","username","password");
mysql_select_db("databasename",$conn);
You can use this to display a single record:
For example, if the URL was /index.php?sequence=123, the code below would select from the table, where the sequence = 123.
<?php
$sql="SELECT * from table where sequence = '".$_GET["sequence"]."' ";
$rs=mysql_query($sql,$conn) or die(mysql_error());
$result=mysql_fetch_array($rs);
echo '<table>
<tr>
<td>Forename</td>
<td>Surname</td>
</tr>
<tr>
<td>'.$result["forename"].'</td>
<td>'.$result["surname"].'</td>
</tr>
</table>';
?>
Or, if you want to list all values that match the criteria in a table:
<?php
echo '<table>
<tr>
<td>Forename</td>
<td>Surname</td>
</tr>';
$sql="SELECT * from table where sequence = '".$_GET["sequence"]."' ";
$rs=mysql_query($sql,$conn) or die(mysql_error());
while($result=mysql_fetch_array($rs))
{
echo '<tr>
<td>'.$result["forename"].'</td>
<td>'.$result["surname"].'</td>
</tr>';
}
echo '</table>';
?>
Surely a better solution would by dynamic so that it would work for any query without having to know the column names?
If so, try this (obviously the query should match your database):
// You'll need to put your db connection details in here.
$conn = new mysqli($server_hostname, $server_username, $server_password, $server_database);
// Run the query.
$result = $conn->query("SELECT * FROM table LIMIT 10");
// Get the result in to a more usable format.
$query = array();
while($query[] = mysqli_fetch_assoc($result));
array_pop($query);
// Output a dynamic table of the results with column headings.
echo '<table border="1">';
echo '<tr>';
foreach($query[0] as $key => $value) {
echo '<td>';
echo $key;
echo '</td>';
}
echo '</tr>';
foreach($query as $row) {
echo '<tr>';
foreach($row as $column) {
echo '<td>';
echo $column;
echo '</td>';
}
echo '</tr>';
}
echo '</table>';
Taken from here: https://www.antropy.co.uk/blog/handy-php-snippets/
mysql_connect("localhost","root","");
mysql_select_db("database");
$query=mysql_query("select * from studenti");
$x=#mysql_num_rows($query);
echo "<a href='file.html'>back</a>";
echo "<table>";
$y=mysql_num_fields($query);
echo "<tr>";
for($i=0 ,$i<$y,$i++)
{
$values=mysql_field_name($query,$i);
echo "<th>$values</th>";
}
echo "</tr>";
while(list($p ,$n $your_table_list)=mysql_fetch_row($query))
{
print("<tr>\n".
"<td>$p</td>".
"</tr>/n");
}
?>
<?php
$mysql_hostname = "localhost";
$mysql_user = "ram";
$mysql_password = "ram";
$mysql_database = "mydb";
$bd = mysql_connect($mysql_hostname, $mysql_user, $mysql_password) or die("Oops some thing went wrong");
mysql_select_db($mysql_database, $bd) or die("Oops some thing went wrong");// we are now connected to database
$result = mysql_query("SELECT * FROM users"); // selecting data through mysql_query()
echo '<table border=1px>'; // opening table tag
echo'<th>No</th><th>Username</th><th>Password</th><th>Email</th>'; //table headers
while($data = mysql_fetch_array($result))
{
// we are running a while loop to print all the rows in a table
echo'<tr>'; // printing table row
echo '<td>'.$data['id'].'</td><td>'.$data['username'].'</td><td>'.$data['password'].'</td><td>'.$data['email'].'</td>'; // we are looping all data to be printed till last row in the table
echo'</tr>'; // closing table row
}
echo '</table>'; //closing table tag
?>
it would print the table like this
just read line by line so that you can understand it easily..
OOP Style :
At first connection with database.
<?php
class database
{
public $host = "localhost";
public $user = "root";
public $pass = "";
public $db = "db";
public $link;
public function __construct()
{
$this->connect();
}
private function connect()
{
$this->link = new mysqli($this->host, $this->user, $this->pass, $this->db);
return $this->link;
}
public function select($query)
{
$result = $this->link->query($query) or die($this->link->error.__LINE__);
if($result->num_rows>0)
{
return $result;
}
else
{
return false;
}
}
?>
Then :
<?php
$db = new database();
$query = "select * from data";
$result = $db->select($query);
echo "<table>";
echo "<tr>";
echo "<th>Name </th>";
echo "<th>Roll </th>";
echo "</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td> $row[name]</td>";
echo "<td> $row[roll]</td>";
echo "</tr>";
}
echo "</table>";
?>
I'm new to PHP. I use the code (below) to print a MySQL table as an HTML table.
However my code prints the table headers from the database.
How can I print HTML table header in hard coded format using the <th>header</th> tags and print the all rows from the table?
Thanks!
<?php
$db_host = 'localhost';
$db_user = 'my user';
$db_pwd = 'my pwd';
$database = 'my db';
$table = 'subcontractor';
if (!mysql_connect($db_host, $db_user, $db_pwd))
die("Can't connect to database");
if (!mysql_select_db($database))
die("Can't select database");
// sending query
$result = mysql_query("SELECT * FROM {$table}");
if (!$result) {
die("Query to show fields from table failed");
}
$fields_num = mysql_num_fields($result);
echo "<table class='table table-bordered table-striped mb-none' id='datatable-tabletools' data-swf-path='assets/vendor/jquery-datatables/extras/TableTools/swf/copy_csv_xls_pdf.swf' >";
// printing table headers
echo "<thead>";
for($i=0; $i<$fields_num; $i++)
{
$field = mysql_fetch_field($result);
echo "<th>{$field->name}</th>";
}
echo "</thead>";
// printing table rows
while($row = mysql_fetch_row($result))
{
echo "<tbody>";
echo "<tr>";
echo "</thead>";
// $row is array... foreach( .. ) puts every element
// of $row to $cell variable
foreach($row as $cell)
echo "<td>$cell</td>";
echo "</tr>";
echo "</tbody>";
}
mysql_free_result($result);
?>
Thank you works perfect. Is there a way to make PHP skip a column from the table on the DB? Thanks –
Yes, just change the Query
$result = mysql_query("SELECT * FROM {$table}");
for example by
$result = mysql_query("SELECT `name`,`email`,`address` FROM {$table}");
You can change the headers by removing these lines of code.
for($i=0; $i<$fields_num; $i++)
{
$field = mysql_fetch_field($result);
echo "<th>{$field->name}</th>";
}
Replace the above lines for example by:
echo "<thead>";
echo "<th>My Header 1</th>";
echo "<th>My Header 2</th>";
echo "</thead>";
I want to retrieve the values from a database table and show them in a html table in a page.
I already searched for this but I couldn't find the answer, although this surely is something easy (this should be the basics of databases lol). I guess the terms I've searched are misleading.
The database table name is tickets, it has 6 fields right now (submission_id, formID, IP, name, email and message) but should have another field called ticket_number.
How can I get it to show all the values from the db in a html table like this:
<table border="1">
<tr>
<th>Submission ID</th>
<th>Form ID</th>
<th>IP</th>
<th>Name</th>
<th>E-mail</th>
<th>Message</th>
</tr>
<tr>
<td>123456789</td>
<td>12345</td>
<td>123.555.789</td>
<td>John Johnny</td>
<td>johnny#example.com</td>
<td>This is the message John sent you</td>
</tr>
</table>
And then all the other values below 'john'.
Example taken from W3Schools: PHP Select Data from MySQL
<?php
$con=mysqli_connect("example.com","peter","abc123","my_db");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM Persons");
echo "<table border='1'>
<tr>
<th>Firstname</th>
<th>Lastname</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['FirstName'] . "</td>";
echo "<td>" . $row['LastName'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
?>
It's a good place to learn from!
Try this: (Completely Dynamic...)
<?php
$host = "localhost";
$user = "username_here";
$pass = "password_here";
$db_name = "database_name_here";
//create connection
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$connection = mysqli_connect($host, $user, $pass, $db_name);
//get results from database
$result = mysqli_query($connection, "SELECT * FROM products");
$all_property = array(); //declare an array for saving property
//showing property
echo '<table class="data-table">
<tr class="data-heading">'; //initialize table tag
while ($property = mysqli_fetch_field($result)) {
echo '<td>' . $property->name . '</td>'; //get field name for header
$all_property[] = $property->name; //save those to array
}
echo '</tr>'; //end tr tag
//showing all data
while ($row = mysqli_fetch_array($result)) {
echo "<tr>";
foreach ($all_property as $item) {
echo '<td>' . $row[$item] . '</td>'; //get items using property value
}
echo '</tr>';
}
echo "</table>";
Here is an easy way to fetch data from a MySQL database using PDO.
define("DB_HOST", "localhost"); // Using Constants
define("DB_USER", "YourUsername");
define("DB_PASS", "YourPassword");
define("DB_NAME", "Yourdbname");
$dbc = new PDO("mysql:host=".DB_HOST.";dbname=".DB_NAME.";charset-utf8mb4", DB_USER, DB_PASS);
$print = ""; // assign an empty string
$stmt = $dbc->query("SELECT * FROM tableName"); // fetch data
$stmt->setFetchMode(PDO::FETCH_OBJ);
$print .= '<table border="1px">';
$print .= '<tr><th>First name</th>';
$print .= '<th>Last name</th></tr>';
while ($names = $stmt->fetch()) { // loop and display data
$print .= '<tr>';
$print .= "<td>{$names->firstname}</td>";
$print .= "<td>{$names->lastname}</td>";
$print .= '</tr>';
}
$print .= "</table>";
echo $print;
Learn more about PHP and the MySQLi Library at PHP.net.
First, start a connection to the database. Do this by making all the string variables needed in order to connect, adjusting them to fit your environment, then creating a new connection object with new mysqli() and initializing it with the previously made variables as its parameters. Now, check the connection for errors and display a message whether any were found or not. Like this:
<?php
$servername = "localhost";
$username = "root";
$password = "yourPassword";
$database = "world";
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$conn = new mysqli($servername, $username, $password, $database);
echo "Connected successfully<br>";
?>
Next, make a variable that will hold the query as a string, in this case its a select statement with a limit of 100 records to keep the list small. Then, we can execute it by calling the mysqli::query() function from our connection object. Now, it's time to display some data. Start by opening up a <table> tag through echo, then fetch one row at a time in the form of a numerical array with mysqli::fetch_row() which can then be displayed with a simple for loop. mysqli::field_count should be self explanatory. Don't forget to use <td></td> for each value, and also to open and close each row with echo"<tr>" and echo"</tr>. Finally we close the table, and the connection as well with mysqli::close().
<?php
$query = "select * from city limit 100;";
$queryResult = $conn->query($query);
echo "<table>";
while ($queryRow = $queryResult->fetch_row()) {
echo "<tr>";
for($i = 0; $i < $queryResult->field_count; $i++){
echo "<td>$queryRow[$i]</td>";
}
echo "</tr>";
}
echo "</table>";
$conn->close();
?>
First, connect to the database:
$conn=mysql_connect("hostname","username","password");
mysql_select_db("databasename",$conn);
You can use this to display a single record:
For example, if the URL was /index.php?sequence=123, the code below would select from the table, where the sequence = 123.
<?php
$sql="SELECT * from table where sequence = '".$_GET["sequence"]."' ";
$rs=mysql_query($sql,$conn) or die(mysql_error());
$result=mysql_fetch_array($rs);
echo '<table>
<tr>
<td>Forename</td>
<td>Surname</td>
</tr>
<tr>
<td>'.$result["forename"].'</td>
<td>'.$result["surname"].'</td>
</tr>
</table>';
?>
Or, if you want to list all values that match the criteria in a table:
<?php
echo '<table>
<tr>
<td>Forename</td>
<td>Surname</td>
</tr>';
$sql="SELECT * from table where sequence = '".$_GET["sequence"]."' ";
$rs=mysql_query($sql,$conn) or die(mysql_error());
while($result=mysql_fetch_array($rs))
{
echo '<tr>
<td>'.$result["forename"].'</td>
<td>'.$result["surname"].'</td>
</tr>';
}
echo '</table>';
?>
Surely a better solution would by dynamic so that it would work for any query without having to know the column names?
If so, try this (obviously the query should match your database):
// You'll need to put your db connection details in here.
$conn = new mysqli($server_hostname, $server_username, $server_password, $server_database);
// Run the query.
$result = $conn->query("SELECT * FROM table LIMIT 10");
// Get the result in to a more usable format.
$query = array();
while($query[] = mysqli_fetch_assoc($result));
array_pop($query);
// Output a dynamic table of the results with column headings.
echo '<table border="1">';
echo '<tr>';
foreach($query[0] as $key => $value) {
echo '<td>';
echo $key;
echo '</td>';
}
echo '</tr>';
foreach($query as $row) {
echo '<tr>';
foreach($row as $column) {
echo '<td>';
echo $column;
echo '</td>';
}
echo '</tr>';
}
echo '</table>';
Taken from here: https://www.antropy.co.uk/blog/handy-php-snippets/
mysql_connect("localhost","root","");
mysql_select_db("database");
$query=mysql_query("select * from studenti");
$x=#mysql_num_rows($query);
echo "<a href='file.html'>back</a>";
echo "<table>";
$y=mysql_num_fields($query);
echo "<tr>";
for($i=0 ,$i<$y,$i++)
{
$values=mysql_field_name($query,$i);
echo "<th>$values</th>";
}
echo "</tr>";
while(list($p ,$n $your_table_list)=mysql_fetch_row($query))
{
print("<tr>\n".
"<td>$p</td>".
"</tr>/n");
}
?>
<?php
$mysql_hostname = "localhost";
$mysql_user = "ram";
$mysql_password = "ram";
$mysql_database = "mydb";
$bd = mysql_connect($mysql_hostname, $mysql_user, $mysql_password) or die("Oops some thing went wrong");
mysql_select_db($mysql_database, $bd) or die("Oops some thing went wrong");// we are now connected to database
$result = mysql_query("SELECT * FROM users"); // selecting data through mysql_query()
echo '<table border=1px>'; // opening table tag
echo'<th>No</th><th>Username</th><th>Password</th><th>Email</th>'; //table headers
while($data = mysql_fetch_array($result))
{
// we are running a while loop to print all the rows in a table
echo'<tr>'; // printing table row
echo '<td>'.$data['id'].'</td><td>'.$data['username'].'</td><td>'.$data['password'].'</td><td>'.$data['email'].'</td>'; // we are looping all data to be printed till last row in the table
echo'</tr>'; // closing table row
}
echo '</table>'; //closing table tag
?>
it would print the table like this
just read line by line so that you can understand it easily..
OOP Style :
At first connection with database.
<?php
class database
{
public $host = "localhost";
public $user = "root";
public $pass = "";
public $db = "db";
public $link;
public function __construct()
{
$this->connect();
}
private function connect()
{
$this->link = new mysqli($this->host, $this->user, $this->pass, $this->db);
return $this->link;
}
public function select($query)
{
$result = $this->link->query($query) or die($this->link->error.__LINE__);
if($result->num_rows>0)
{
return $result;
}
else
{
return false;
}
}
?>
Then :
<?php
$db = new database();
$query = "select * from data";
$result = $db->select($query);
echo "<table>";
echo "<tr>";
echo "<th>Name </th>";
echo "<th>Roll </th>";
echo "</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td> $row[name]</td>";
echo "<td> $row[roll]</td>";
echo "</tr>";
}
echo "</table>";
?>
I am trying to display a table containing data from my db in a php page.
No problems at all.
When I try to use css to make the table better looking the browser gives me simply a blank page.
Here's my code...
If I delete the id=csstest part after opening the table tag everything works, as soon as I add id=csstest I get a blank page...
What am I doing wrong?
<?php
include 'config.php';
if (!mysql_connect($db_host, $db_user, $db_pwd))
die("Can't connect to db");
if (!mysql_select_db($database))
die("Can't select db");
// sending query
$result = mysql_query("SELECT data, cur_timestamp FROM {$table}");
if (!$result) {
die("Check your SQL query");
}
$fields_num = mysql_num_fields($result);
echo "<h1>Tabella: {$table}</h1>";
echo "<table id="csstest"><tr>";
// printing table headers
for($i=0; $i<$fields_num; $i++)
{
$field = mysql_fetch_field($result);
echo "<td>{$field->name}</td>";
}
echo "</tr>\n";
// printing table rows
while($row = mysql_fetch_row($result))
{
echo "<tr>";
// $row is array... foreach( .. ) puts every element
// of $row to $cell variable
foreach($row as $cell)
echo "<td>$cell</td>";
echo "</tr>\n";
}
mysql_free_result($result);
mysql_close($result);
?>
</table>
Change the following statement:
echo "<table id="csstest"><tr>";
to this:
echo "<table id=\"csstest\"><tr>";
you need to add slashes before your double quotes:
echo "<table id=\"csstest\"><tr>";
echo "<table id="csstest"><tr>";
above code generates parse error and your error reporting is off so it just showing blank page
try on of the below method
echo "<table id='csstest'><tr>";
echo '<table id="csstest"><tr>';
echo "<table id=\"csstest\"><tr>";
I'm using PHP to display what is in my MYsql database in a table. I would like to add a delete button buy I don't know how. I would like the delete button right after the last column. Here is my code.
<?php
$db_host = 'localhost';
$db_user = 'root';
$db_pwd = '';
$database = 'coins_gage';
$table = 'coins';
if (!mysql_connect($db_host, $db_user, $db_pwd))
die("Can't connect to database");
if (!mysql_select_db($database))
die("Can't select database");
// sending query
$result = mysql_query("SELECT * FROM {$table}");
if (!$result) {
die("Query to show fields from table failed");
}
$fields_num = mysql_num_fields($result);
echo "<h1>Table: {$table}</h1>";
echo "<table border='1'><tr>";
// printing table headers
for($i=0; $i<$fields_num; $i++)
{
$field = mysql_fetch_field($result);
echo "<td>{$field->name}</td>";
}
echo "</tr>\n";
// printing table rows
while($row = mysql_fetch_row($result))
{
echo "<tr>";
// $row is array... foreach( .. ) puts every element
// of $row to $cell variable
foreach($row as $cell)
echo "<td>$cell</td>";
echo "</tr>\n";
}
mysql_free_result($result);
?>
You have to do several things here to make the interface user friendly and perform your task. If I summarize the steps you have to do is like this.
1) Make sure you keep your table inside a form with POST method. And add following kind of hidden elements just before close the FORM tag.
<input type="hidden" name="hidDelete" id="hidDelete" value="" />
2) Add a column header to the table by modifying this section.
// printing table headers
for($i=0; $i<$fields_num; $i++)
{
$field = mysql_fetch_field($result);
echo "<td>{$field->name}</td>";
}
echo "<td>Delete</td>";
echo "</tr>\n";
3) Add the delete button to all the rows.
foreach($row as $cell)
echo "<td>$cell</td>";
echo "<td><input type=\"button\" value=\"Delete\" onclick=\"deleteThis({$field->id})\" /></td>"
echo "</tr>\n";
4) The create a javascript function to make the delete request. Before you post data you have to set a hidden value. If you use javascript library like jquery this will be much easier. Since I don't know which library you are using I will explain in pure javascript.
<script type="text/javascript">
function deleteThis(id)
{
document.getElementById("hidDelete").value = id;
document.yourFormName.submit();
}
</script>
5) Once you get the post request to your page, Make the deletion before you do select queries.
if(isset($_POST["hidDelete"]) $_POST["hidDelete"] != "")
{
$rowID = $_POST["hidDelete"];
// Write your delete queries
}