Count function() - php

Question

I have these two table with some data sample in them. I would like to to pull out number of classifieds in each category. I gave it a try, and I got (2) in each one which is not correct. So hopefully someone will help me with this.
CREATE TABLE IF NOT EXISTS `categories` (
`id` int(255) NOT NULL AUTO_INCREMENT,
`name` text COLLATE utf8_unicode_ci NOT NULL,
`subcategory_id` int(2) NOT NULL DEFAULT '0',
`parent_id` int(255) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=27 ;
--
-- Dumping data for table `categories`
--
INSERT INTO `categories` (`id`, `name`, `subcategory_id`, `parent_id`) VALUES
(1, 'Announcements', 0, 0),
(2, 'Employment', 0, 0),
(3, 'Items For Sale', 0, 0),
(4, 'Services', 0, 0),
(5, 'Garage Sales', 0, 0),
(6, 'Automobiles', 0, 0),
(7, 'Announcement1', 1, 1),
(8, 'Announcement2', 1, 1),
--
-- Table structure for table `classifieds`
--
CREATE TABLE IF NOT EXISTS `classifieds` (
`classified_id` int(255) NOT NULL AUTO_INCREMENT,
`title` text COLLATE utf8_unicode_ci NOT NULL,
`description` text COLLATE utf8_unicode_ci NOT NULL,
`category_id` int(10) NOT NULL,
`name` text COLLATE utf8_unicode_ci NOT NULL,
`authorized` int(10) NOT NULL DEFAULT '0',
PRIMARY KEY (`adid`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=177 ;
--
-- Dumping data for table `classifieds`
--
INSERT INTO `classifieds` (`classified_id`, `title`, `description`, `category_id`, `name`, `authorized`) VALUES
(1, 'Test Classified', 'Here is the First Test classified listing.', 1, 1);
INSERT INTO `classifieds` (`classified_id`, `title`, `description`, `category_id`, `name`, `authorized`) VALUES
(2, 'GMC For Sell', 'Looks like new 1979 GMC.', 6, 1);
here
$query = "SELECT category_id, COUNT(title) FROM classifieds GROUP BY category_id";
$result = mysql_query($query) or die(mysql_error());
$row = mysql_fetch_array($result)
$num_items_in_category = $row['COUNT(title)'];
echo "<><a href='category-".$row['id'].".php' >".$row['name'].$num_items_in_category."</a></li>";
Thanks

Answer 1

Change the SQL a bit, and loop through the results?
$query = "SELECT c.id, c.name,
COUNT(cl.category_id) AS num_items_in_category
FROM category_id c
LEFT JOIN aclassifieds cl ON cl.category_id=c.id
GROUP BY c.id";
$result = mysql_query($query) or die(mysql_error());
while ($row = mysql_fetch_array($result)) {
echo "<li><a href='category-".$row['id'].".php' >".$row['name'].$row['num_items_in_category']."</."</a></li>";
}

Answer 2

Just in case someone else wants to benefit my this:
enter $query = "SELECT c.id, c.name,
COUNT(cl.title) AS num_items_in_category
FROM categories c
LEFT JOIN classifieds cl ON cl.category_id=c.id
GROUP BY c.id";
$result = mysql_query($query) or die(mysql_error());
while ($row = mysql_fetch_array($result)) {
echo "".$row['name'].$row['num_items_in_category']."";
}
here
Thanks