PostgreSQL Database - Inner Join Query Error - php

With the help of this community, I was able to produce a query using an inner join which I thought would work for what I'm trying to do. Unfortunately, when I attempted to run the query found below, I received the following error:
ERROR: table name "bue" specified more than once
From what I've read on Google, some people have said that the "FROM bue" is not needed, but when I removed this, I got another error found below:
ERROR: syntax error at or near "INNER" at character 98
I'd very much appreciate your assistance in troubleshooting this. Thank you so very much.
Query:
UPDATE
bue
SET
rgn_no = chapterassociation.rgn_no,
chp_cd = chapterassociation.chp_cd
FROM
bue
INNER JOIN
chapterassociation
ON bue.work_state = chapterassociation.work_state
AND bue.bgu_cd = chapterassociation.bgu_cd
WHERE
bue.mbr_no IS NULL AND bue.chp_cd IS NULL

In PostgreSQL, specifying the table to be updated needs to be done only in the UPDATE clause, e.g. UPDATE bue. The FROM clause is only for additional tables referenced in the query. (If you were doing a self-join on bue, you would mention it again in the FROM clause, but you aren't in this case.)
The second error you get is likely just a simple syntax error. The other tricky thing is that JOIN/ON syntax doesn't fit in the FROM clause, so you have to move the join conditions to the WHERE clause. Try something like:
UPDATE
bue
SET
rgn_no = chapterassociation.rgn_no,
chp_cd = chapterassociation.chp_cd
FROM
chapterassociation
WHERE
bue.mbr_no IS NULL AND bue.chp_cd IS NULL
AND bue.work_state = chapterassociation.work_state
AND bue.bgu_cd = chapterassociation.bgu_cd
See http://www.postgresql.org/docs/current/interactive/sql-update.html.
(N.B. At least I don't know how to put JOIN/ON into an UPDATE statement... I could be missing something.)

Related

How to optimize long query that displays thousands of data

I have almost thousands of data to display for my reports and it makes my browser lags due to the heavy data. I think that my query is the real problem. How can I optimized my query? is there something that I should add in my query?
I am using Xampp which supports PHP7.
SELECT
`payroll_billed_units`.`allotment_code`,
`payroll_billed_units`.`category_name`,
`payroll_billed_units`.`ntp_number`,
`payroll_billed_units`.`activity`,
`payroll_billed_units`.`regular_labor`,
`payroll_sub`.`block_number`,
(SELECT
GROUP_CONCAT(DISTINCT `lot_number` SEPARATOR ', ')
FROM
`payroll_billed_units` `lot_numbers`
WHERE
`lot_numbers`.`allotment_code` = `payroll_billed_units`.`allotment_code`
AND `lot_numbers`.`category_name` = `payroll_billed_units`.`category_name`
AND `lot_numbers`.`ntp_number` = `payroll_billed_units`.`ntp_number`
AND `lot_numbers`.`activity` = `payroll_billed_units`.`activity`) AS `lot_numbers`,
(SELECT
COUNT(`billed`.`ntp_id`)
FROM
`regular_ntp` `billed`
WHERE
`billed`.`allotment_code` = `payroll_billed_units`.`allotment_code`
AND `billed`.`category_name` = `payroll_billed_units`.`category_name`
AND `billed`.`ntp_number` = `payroll_billed_units`.`ntp_number`
AND `billed`.`activity` = `payroll_billed_units`.`activity`) AS `billed`,
(SELECT
COUNT(`approved`.`id`)
FROM
`payroll_billed_units` `approved`
WHERE
`approved`.`allotment_code` = `payroll_billed_units`.`allotment_code`
AND `approved`.`category_name` = `payroll_billed_units`.`category_name`
AND `approved`.`ntp_number` = `payroll_billed_units`.`ntp_number`
AND `approved`.`activity` = `payroll_billed_units`.`activity`) AS `approved`
FROM
`payroll_billed_units`
JOIN payroll_transaction ON payroll_billed_units.billing_number =
payroll_transaction.billing_number
JOIN payroll_sub ON payroll_transaction.billing_number =
payroll_sub.billing_number
WHERE payroll_billed_units.billing_date = '2019-02-13'
AND payroll_transaction.contractor_name = 'Roy Codal' GROUP BY allotment_code, category_name, activity
I was expecting that it will load or display all my data.
The biggest problem are the dependendt sub-selects, they are responsible for a bad performance. A sub-select will be executed for EVERY ROW of the outer query. And if you cascade subs-selects, you'll quickly have a query run forever.
If any of the parts would yield only 5 resultsets, 3 sub-select would mean that the database has to run 625 queries (5^4)!
Use JOINs.
Several of your tables need this 'composite' index:
INDEX(allotment_code, category_name, ntp_number, activity) -- in any order
payroll_transaction needs INDEX(contractor_name), though it may not get used.
payroll_billed_units needs INDEX(billing_date), though it may not get used.
For further discussion, please provide SHOW CREATE TABLE for each table and EXPLAIN SELECT ...
Use simply COUNT(*) instead of COUNT(foo). The latter checks the column for being not-NULL before including it. This is usually not needed. The reader is confused by thinking that there might be NULLs.
Your GROUP BY is improper because it is missing ntp_number. Read about the sql_mode of ONLY_FULL_GROUP_BY. I bring this up because you can almost get rid of some of those subqueries.
Another issue... Because of the "inflate-deflate" nature of JOIN with GROUP BY, the numbers may be inflated. I recommend you manually check the values of the COUNTs.

Mysql Server timing out on specific locate queries

Im programming a search with ZF3 and the DB module.
Everytime i use more than 1 short keyword - like "49" and "am" or "1" and "is" i get this error:
Statement could not be executed (HY000 - 2006 - MySQL server has gone away)
Using longer keywords works perfectly fine as long as i dont use 2 or more short keywords.
The problem only occurs on the live server its working fine on the local test server.
The project table has ~2200 rows with all kind of data the project_search table has 17000 rows with multiple entries for each project , each looking like:
id, projectid, searchtext
The searchtext Column is fulltext. Here the relevant part of the php code:
$sql = new Sql($this->db);
$select = $sql->select(['p'=>'projects']);
if(isset($filter['search'])) {
$keywords = preg_split('/\s+/', trim($filter['search']));
$join = $sql->select('project_search');
$join->columns(['projectid' => new Expression('DISTINCT(projectid)')]);
$join->group("projectid");
foreach($keywords as $keyword) {
$join->having(["LOCATE('$keyword', GROUP_CONCAT(searchtext))"]);
}
$select->join(
["m" => $join],
"m.projectid = p.id",
['projectid'],
\Zend\Db\Sql\Select::JOIN_RIGHT
);
}
Here the resulting Query:
SELECT p.*, m.projectid
FROM projects AS p
INNER JOIN (
SELECT projectid
FROM project_search
GROUP BY projectid
HAVING LOCATE('am', GROUP_CONCAT(searchtext))
AND LOCATE('49', GROUP_CONCAT(searchtext))
) AS m
ON m.projectid = p.id
GROUP BY p.id
ORDER BY createdAt DESC
I rewrote the query using "MATCH(searchtext) AGAINST('$keyword)" and "searchtext LIKE '%keyword%' with the same result.
The problem seems to be with the live mysql server how can i debug this ?
[EDIT]
After noticing that the error only occured in a special view which had other search related queries - each using multiple joins (1 join / keyword) - i merged those queries and the error was gone. The amount of queries seemed to kill the server.
Try refactoring your inner query like so.
SELECT a.projectid
FROM (
SELECT DISTINCT projectid
FROM projectsearch
WHERE searchtext LIKE '%am%'
) a
JOIN (
SELECT DISTINCT projectid
FROM projectsearch
WHERE searchtext LIKE '%49%'
) b ON a.projectid = b.projectid
It should give you back the same set of projectid values as your inner query. It gives each projectid value that has matching searchtext for both search terms, even if those terms show up in different rows of project_search. That's what your query does by searching GROUP_CONCAT() output.
Try creating an index on (searchtext, projectid). The use of column LIKE '%sample' means you won't be able to random-access that index, but the two queries in the join may still be able to scan the index, which is faster than scanning the table. To add that index use this command.
ALTER TABLE project_search ADD INDEX project_search_text (searchtext, projectid);
Try to do this in a MySQL client program (phpmyadmin for example) rather than directly from your php program.
Then, using the MySQL client, test the inner query. See how long it takes. Use EXPLAIN SELECT .... to get an explanation of how MySQL is handling the query.
It's possible your short keywords are returning a ridiculously high number of matches, and somehow overwhelming your system. In that case you can put a LIMIT 1000 clause or some such thing at the end of your inner query. That's not likely, though. 17 kilorows is not a large number.
If that doesn't help your production MySQL server is likely misconfigured or corrupt. If I were you I would call your hosting service tech support, somehow get past the front-line support agent (who won't know anything except "reboot your computer" and other such foolishness), and tell them the exact times you got the "gone away" message. They'll be able to check the logs.
Pro tip: I'm sure you know the pitfalls of using LIKE '%text%' as a search term. It's not scalable because it's not sargable: it can't random access an index. If you can possibly redesign your system, it's worth your time and effort.
You could TRY / CATCH to check if you get a more concrete error:
BEGIN TRY
BEGIN TRANSACTION
--Insert Your Queries Here--
COMMIT
END TRY
BEGIN CATCH
DECLARE #ErrorMessage NVARCHAR(4000);
DECLARE #ErrorSeverity INT;
DECLARE #ErrorState INT;
SELECT
#ErrorMessage = ERROR_MESSAGE(),
#ErrorSeverity = ERROR_SEVERITY(),
#ErrorState = ERROR_STATE();
IF ##TRANCOUNT > 0
ROLLBACK
RAISERROR (#ErrorMessage, -- Message text.
#ErrorSeverity, -- Severity.
#ErrorState -- State.
);
END CATCH
Although because you are talking about short words and fulltext it seems to me it must be related to StopWords.
Try running this query from both your dev server and production server and check if there are any differences:
SELECT * FROM INFORMATION_SCHEMA.INNODB_FT_DEFAULT_STOPWORD;
Also check in my.ini (if that is the config file) text file if these are set to:
ft_stopword_file = ""
ft_min_word_len = 1
As stated in my EDIT the problem wasnt the query from the original Question, but some other queries using the search - parameter as well. Every query had a part like follows :
if(isset($filter['search'])) {
$keywords = preg_split('/\s+/', trim($filter['search']));
$field = 1;
foreach($keywords as $keyword) {
$join = $sql->select('project_search');
$join->columns(["pid$field" => 'projectid']);
$join->where(["LOCATE('$keyword', searchtext)"]);
$join->group("projectid");
$select->join(
["m$field" => $join],
"m$field.pid$field = p.id"
);
$field++;
}
}
This resulted in alot of queries with alot of resultrows killing the mysql server eventually. I merged those Queries into the first and the error was gone.

MySQL query into Code Igniter Active Directory format?

I'm trying to get mysql query into Code Igniter's Active Record syntax but am having a bit of a hard time.
The query is as a result of this question: Multiple mysql ORDER BY's for multidimensional ordering/grouping
I've attempted to format the query myself, have tackled a couple of errors, but am unsure how to progress. I had to add in the get_compiled_select() function to DB_active_rec.php myself and change the _reset_select() from protected to public to get it to run at all.
The suggested query is:
select
t.id,
t.group,
t.date,
t.comlete
from
YourTable t
left join
(select
m.group,
min(m.date) as mindate,
min(t.complete) as groupcomplete
from
YourTable m) mt on mt.group = t.group
order by
coalesce(mt.groupcomplete, t.complete),
coalesce(mt.mindate, t.date),
t.group,
t.complete,
t.date
My translation looks like this (note that there's a 'where' clause not in the original, and that 'date' is actually 'due'):
// Sub query
$this->db->select('m.group, min(m.due) as mindate, min(t.complete) as groupcomplete');
$this->db->from('task m');
$this->db->where('property', $property);
$subquery = $this->db->get_compiled_select();
$this->db->_reset_select();
// Main query
$this->db->select('*');
$this->db->where('property', $property);
$this->db->from('task t');
$this->db->join('($subquery) mt','mt.group = t.group');
$this->db->order_by('coalesce(mt.groupcomplete, t.complete)');
$this->db->order_by('coalesce(mt.mindate, t.due)');
$this->db->order_by('t.group');
$this->db->order_by('t.complete');
$this->db->order_by('t.due');
$query = $this -> db -> get();
// Return
return $query->result();
Unfortunately this is just throwing an error:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'mt ON `mt`.`group` = `t`.`group` WHERE `property` = '7' ORDER BY coalesce(mt.gr' at line 3
The query as reported by CI looks like:
SELECT * FROM (`task` t) JOIN ($subquery) mt ON `mt`.`group` = `t`.`group` WHERE `property` = '7' ORDER BY coalesce(mt.groupcomplete, `t`.`complete)`, coalesce(mt.mindate, `t`.`date)`, `t`.`due`, `t`.`complete`, `t`.`date`
Anyone able to lend some advice as to how to get this formatted correctly? My mysql skills are, unfortunately, pretty bare, so this is pushing my abilities. Much of the approach of my translation is from answers on Stack Overflow, as I have no experience combining queries in this way (with the subquery).
The problem (or 'one of the problems') is here:
$this->db->join('($subquery) mt','mt.group = t.group');
You use single quotes, so the variable $subquery doesn't get expanded.
This can also be seen in the query that is outputted by CodeIgniter.
When you have multiple order by statements u separate them by comma like this
$this->db->order_by('coalesce(mt.groupcomplete, t.complete), coalesce(mt.mindate, t.date), t.due, t.complete, t.date');

Propel ORM - Joining unrelated tables

How does this SQL statement translate into Propel (1.6.3)?
SELECT * FROM table_a JOIN table_b
With tableA and tableB sharing no Foreign Keys and having no relationships defined.
TableAQuery::create()->join('tableB')
doesn't work since Propel complains with an error:
"Fatal error: Uncaught exception 'PropelException' with message 'Unknown relation TableB on the TableA table'
Thanks very much in advance for any help and hints! This is my first post here and I hope I haven't done anything wrong yet :-) (I've searched thoroughly before I posted!)
You could also use "addJoin" like this:
TableAQuery::create()
->addJoin(TableAPeer::ThisCOLUMN, TableBPeer::ThatCOLUMN, Criteria::INNER_JOIN); //Can also be left/right
The third argument also takes left and right join.
And, instead of the usual "filterByXXX()"
->filterByOtherColumn(value)
you'd use "add()", like this:
->add(TableAPeer::OtherCOLUMN, value)
You can work around this limitation by using raw SQL syntax. For instance:
$con = Propel::getConnection(SomePeer::DATABASE_NAME);
$query = 'SELECT * FROM `table_a` JOIN `table_b` LIMIT 10';
$stmt = $con->prepare($query);
if($stmt->execute()) {
$res = $stmt->fetchAll();
var_dump($res);
}
Note #1: These kind of joins can become very big and quickly exhaust the allowed memory size. That's why I've added a LIMIT.
Note #2: The output isn't very clean, arrays of both numeric and associative keys. Maybe there are ways to improve this.

Using JOIN in NotORM

Been trying the following code
$notorm->table()->select("table.*, table2.column, table2.table3.column2");
from http://sql-cross-queries.freexit.eu/dibi/notorm to create a JOIN statement, but to no avail. Am I missing out on anything?
I have reports(timestamp, incident_id, location id), incident(incident_id, incident_desc, location_id), and location(location_id, location_name). I am trying to get timestamp, incident_name, and location_name by joining reports, incident, and location. So I used the following statement:
$notorm->reports()->select("reports.*, incident.incident_id, incident.location.location_id");
but it's not returning anything. The following statement, though:
$notorm->reports()->select("reports.*");
returns reports.
Try this, not 100% sure but worth a try.
$notorm->reports()->join("reports", "LEFT JOIN incident ON reports.incident_id = incident.incident_id")
->join("reports", "LEFT JOIN location ON reports.location_id = location.location_id")
->select("reports.timestamp, incident.incident_desc, location.location_name");
in your table definition, there must be a field name table2_id present

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