I have the following variable in Javascript. I want to know how to pass this data to a PHP so that I can display the contents of the data once redirected.
postData = {
'dates_ranges': datesAndRanges,
'action':'build',
'output_type': output_type,
'form_html': formHtml,
'width': formBuilder.width(),
'rules':validationRules,
'theme': theme,
};
Use JQuery post method to pass data to PHP file:
$.post("/path/to/script.php", postData, function(result) {
// work with result
});
In PHP use $_POST global to get the variables:
print $_POST['dates_ranges'];
print $_POST['action'];
// ...
using jquery it goes easy & clean like this:
$.post('script.php', postData, function(response){
// process/display the server response
});
you can use:
$.post("YOUR_URL", postData, function(response) {
// handle with response
});
OR:
$.ajax({
url: YOUR_URL,
data: postData,
type: 'post',
success: function(response) {
// handle with response
}
});
And In your PHP file:
if(isset($_POST) && !empty($_POST)) {
$d = $_POST;
echo $d['date_range']; // and so more
}
Related
I need to pass a json object from JS to PHP, and it will pass, but the result is an empty array.
Ajax request in 'adopt.php':
var info = JSON.stringify(filteredArray);
$.ajax({
type: 'POST',
url: 'ajax.php',
data: {'info': info},
success: function(data){
console.log(data);
}
});
ajax.php code:
if(isset($_POST['info'])){
$_SESSION['array'] = $_POST['info'];
}
back in adopt.php, later:
if(isset($_SESSION['array'])){
$arr = $_SESSION['array'];
echo "console.log('information: ' + $arr);";
}
in both of the console.logs, it returns an empty object. Does anybody know what could be causing this? (i've tried just passing the json without stringifying it, but it throws a jquery error whenever i do this.)
Try below code i think you miss return ajax response
adopt.php
<script>
var info = JSON.stringify(filteredArray);
$.ajax({
type: 'POST',
url: 'ajax.php',
data: {info: info},
success: function(data){
console.log(data);
}
});
</script>
ajax.php
if (isset($_POST['info'])) {
$_SESSION['array'] = $_POST['info'];
echo json_encode(["result" => "success"]);
}
To get the response data from PHP, you need to echo your data to return it to the browser.
In your ajax.php:
if (isset($_POST['info'])) {
$_SESSION['array'] = $_POST['info'];
echo json_encode(['result' => $_SESSION['array']]);
}
Your ajax.php is not returning any data.To get data at the time of success you need to echo the data you want to display on success of your ajax.
I've tried to go to php file using jquery.
Here is my code.
This is index.php
$.post('test.php',data,function(json){},'json');
This is test.php
//set session variable from passed data
$_SESSION['data1'] = $_POST['data1'];
<script>
window.open('test1.php','_blank');
</script>
This is test1.php
echo $_SESSION['data1'];
But this code is not working.
I want to pass data from index.php to test1.php.
How can I do this? I don't want to use GET method because of too long url.
Anyhelp would be appreciate.
I am not quite clear from you explanation right now. But I am here trying to resolve you problem as you can use the jquery post method as follows :
$.post('test1.php',{param1:value1,param2=value2,...},function(data){
//Here you can take action as per data return from the page or can add simple action like redirecting or other
});
Here is a simple example of register :
$.post('', $("#register_form").serialize(), function(data) {
if (data === '1') {
bootbox.alert("You have registered successfully.", function() {
document.location.href = base_url + '';
});
} else if (data === '0') {
bootbox.alert("Error submitting records");
} else {
bootbox.alert(data);
}
$("#user_register_button").button("reset");
});
Try this:
$.ajax({
url: 'test.php',
type: 'POST',
data: {
myData : 'somevalue'
},
success: function(response){ // response from test.php
// do your stuff here
}
});
test.php
$myData = $_REQUEST['myData'];
// do your stuff here
I like use jQuery post a url like this.
$('form').on('submit', function(e) {
e.preventDefault();
var $this = $(this);
$.ajax({
url: $this.attr('action'),
method: $this.attr('method'),
data: $this.serializeArray(),
success: function(response) {
console.log(response);
}
})
});
I you a beginner, you can reference this project
php-and-jQuery-messageBoard
I'm working on a project coding PHP-AJAX-Jquery and JSON and need to send the information of a form that has three input fields to a php file that will store the info of the three fields in the database.
my problem is that I need(I have because of project spec) to use Jquery-AJAX and JSON and I think I'm passing in a malformed JSON string to the PHP file, this is the js that is supposed to handle the call:
$(document).ready(function(){
$('#ID_formulario').on('submit',function(e) {
e.preventDefault();
var nombre = $('input#ID_nombre');
var email = $('input#ID_email');
if(validaForm(nombre, email)){
var url = $(this).attr('action');
var data = $(this).serializeArray();
var type = $(this).attr('method');
alert(data);
$.ajax({
url:url,
data:data,
type:type,
cache: false,
contentType: "application/x-www-form-urlencoded",
dataType: 'json',
beforeSend: function () {
$("#flash").show();
$("#flash").fadeIn(400).html('<img src="imagen.gif" align="absmiddle"> <span class="loading">Realizando peticion...</span>');
},
error: function(){
alert("error petición ajax");
},
success: function(datos){
$('#result').empty().html(respuesta). fadeIn('slow').delay(5000).fadeOut();
$('#ID_formulario')[0].reset();
$('input#ID_nombre').focus();
$("#flash").hide();
//$("#display").after(html);
//$("#result").append(data);
}
});
}
});
});
my questions are: how to send the info of the three fields in a valid JSON format to the php file? is there any jquery function that helps? or is serializeArray() enough?
It's okay to use success: function(datos) or should I replace it to .done(function)) ?
thanks in advance.
You dont need to send anything as JSON to PHP. Just send it with type: POST and read it in PHP. Then return it as JSON to read in Javascript. You just read the $_POST in PHP. I believe you've mistaken your project specs and you need to RETURN data from PHP as JSON.
This is one of my projects:
$("document").ready(function(){
$(".js-ajax-php-json").submit(function(){
var data = {
"action": "product"
};
data = $(this).serialize() + "&" + $.param(data);
$.ajax({
type: "POST",
dataType: "json",
url: "response.php",
data: data,
success: function(data) {
$(".the-return").html(
// Read returned JSON. Exammple
"<div class='data-row'><strong>TYPE</strong> " + data["title"]+ "</div>";
);
}
});
return false;
});
});
In PHP you take the POST and read data.
response.php
if (is_ajax()) {
if (isset($_POST["action"]) && !empty($_POST["action"])) { //Checks if action value exists
$action = $_POST["action"];
switch($action) { //Switch case for value of action
case "product": sendValues();
break;
}
}
}
// Function to check if the request is an AJAX request
function is_ajax() {
return isset($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest';
}
// Do everything with $_POST's here
function sendValues(){
$return = $_POST;
$return["title"] = 'Something';
$return["json"] = json_encode($return);
echo json_encode($return); // Return JSON formatted data to Javascript.
}
I have this ajax code
$.ajax(
{
type: "POST",
url: "getData.php",
data: ValueToPass,
cache: false,
success: function(html)
{
LastDiv.after(html);
}
});
I am new with this Ajax thing.
This code is to load getData.php file and send variables through type POST.
The variables are in this var ValueToPass = "lastid="+LastId+"&br="+br;.
Other thing this code does is return the getData.php's HTML after loading.
Probably with this. success: function(html)
How can I return this $br variable from getData.php after loading, so I can use it again through the next cycle. Cuz what happens here is that I can put the variable in the getData.php with the Ajax and working with it, but when the file getData.php is loaded, outside this file, the variable is not known(not declared). And I'm losing the counting :S
I want to return the HTML and the variable.
You can return json data in your php file like
$response = array ('br'=> $br, 'html'=> $html);
echo json_encode($response);
Here both html and data are returned.
And this to use it in your ajax callback :
success: function(data)
{
br = data.br;
LastDiv.after(data.html);
}
I'd consider setting a Session variable with the value from the $br variable passed via AJAX. Then when you call getData.php from another file or location, you can use the Session variable since session variables retain their value anywhere in the session.
You can try this to get the data from your `getData.php' :
$.ajax(
{
type: "POST",
url: "getData.php",
data: { ValueToPass: ValueToPass},
cache: false,
success: function(data)
{
LastDiv.html(data);
}
});
and in your getData.php you have to pass ValueToPass
maybe like this:
$ValueToPass = mysqli_real_escape_string($db, $_POST['ValueToPass']);
If I understand your question correctly, and if you want to return the $br variable then include it in a JSON object in the successs callback function. So, something like this (I'm not familiar enough with PHP so my PHP syntax might be incorrect):
// create JSON object
<?php
$result = array('br' => $br, 'html' => 'htmlContent);
echo json_encode($result);
?>
// return JSON object
$.ajax(
{
type: "POST",
url: "getData.php",
data: ValueToPass,
cache: false,
success: function(result)
{
var $br = result.br;
LastDiv.after(result.html);
}
});
I have checked around, but can't seem to figure out how this is done.
I would like to send form data to PHP to have it processed and inserted into a database (this is working).
Then I would like to send a variable ($selected_moid) back from PHP to a JavaScript function (the same one if possible) so that it can be used again.
function submit_data() {
"use strict";
$.post('insert.php', $('#formName').formSerialize());
$.get('add_host.cgi?moid='.$selected_moid.');
}
Here is my latest attempt, but still getting errors:
PHP:
$get_moid = "
SELECT ID FROM nagios.view_all_monitored_objects
WHERE CoID='$company'
AND MoTypeID='$type'
AND MoName='$name'
AND DNS='$name.$selected_shortname.mon'
AND IP='$ip'
";
while($MonitoredObjectID = mysql_fetch_row($get_moid)){
//Sets MonitoredObjectID for added/edited device.
$Response = $MonitoredObjectID;
if ($logon_choice = '1') {
$Response = $Response'&'$logon_id;
$Response = $Response'&'$logon_pwd;
}
}
echo json_encode($response);
JS:
function submit_data(action, formName) {
"use strict";
$.ajax({
cache: false,
type: 'POST',
url: 'library/plugins/' + action + '.php',
data: $('#' + formName).serialize(),
success: function (response) {
// PROCESS DATA HERE
var resp = $.parseJSON(response);
$.get('/nagios/cgi-bin/add_host.cgi', {moid: resp });
alert('success!');
},
error: function (response) {
//PROCESS HERE FOR FAILURE
alert('failure 'response);
}
});
}
I am going out on a limb on this since your question is not 100% clear. First of all, Javascript AJAX calls are asynchronous, meaning both the $.get and $.post will be call almost simultaneously.
If you are trying to get the response from one and using it in a second call, then you need to nest them in the success function. Since you are using jQuery, take a look at their API to see the arguments your AJAX call can handle (http://api.jquery.com/jQuery.post/)
$.post('insert.php', $('#formName').formSerialize(),function(data){
$.get('add_host.cgi?moid='+data);
});
In your PHP script, after you have updated the database and everything, just echo the data want. Javascript will take the text and put it in the data variable in the success function.
You need to use a callback function to get the returned value.
function submit_data(action, formName) {
"use strict";
$.post('insert.php', $('#' + formName).formSerialize(), function (selected_moid) {
$.get('add_host.cgi', {moid: selected_moid });
});
}
$("ID OF THE SUBMIT BUTTON").click(function() {
$.ajax({
cache: false,
type: 'POST',
url: 'FILE IN HERE FOR PROCESSING',
data: $("ID HERE OF THE FORM").serialize(),
success: function(data) {
// PROCESS DATA HERE
},
error: function(data) {
//PROCESS HERE FOR FAILURE
}
});
return false; //This stops the Button from Actually Preforming
});
Now for the Php
<?php
start_session(); <-- This will make it share the same Session Princables
//error check and soforth use $_POST[] to get everything
$Response = array('success'=>true, 'VAR'=>'DATA'); <--- Success
$Response = array('success'=>false, 'VAR'=>'DATA'); <--- fails
echo json_encode($Response);
?>
I forgot to Mention, this is using JavaScript/jQuery, and ajax to do this.
Example of this as a Function
Var Form_Data = THIS IS THE DATA OF THE FORM;
function YOUR FUNCTION HERE(VARS HERE) {
$.ajax({
cache: false,
type: 'POST',
url: 'FILE IN HERE FOR PROCESSING',
data:Form_Data.serialize(),
success: function(data) {
// PROCESS DATA HERE
},
error: function(data) {
//PROCESS HERE FOR FAILURE
}
});
}
Now you could use this as the Button Click which would also function :3