How can I convert the time zone of a date string in php without changing the default time zone. I want to convert it locally to display only. The php time zone settting should not be modified.
EDIT:
My source time is a UTC string, I want to convert it to a different format, retaining the time zone as UTC, but php is converting it to local timezone.
The code I used was:
date('Y-m-d H:i::s',strtotime($time_str));
How do I retain timezone?
$src_tz = new DateTimeZone('America/Chicago');
$dest_tz = new DateTimeZone('America/New_York');
$dt = new DateTime("2000-01-01 12:00:00", $src_tz);
$dt->setTimeZone($dest_tz);
echo $dt->format('Y-m-d H:i:s');
Note that if the source time is UTC, you can change the one line to this:
$dt = new DateTime("2000-01-01 12:00:00 UTC");
Edit: Looks like you want to go to UTC. In that case, just use "UTC" as the parameter to the $dest_tz constructor, and use the original block of code. (And of course, you can omit the $src_tz parameter if it is the same as the default time zone.)
Related
I have a Laravel-based app that is used by people from various parts of the US.
I am capturing a timestamp in Javascript when the user takes a specific action, and then I am submitting that timestamp as form data, for the Laravel/PHP to process.
The timestamp that I am capture in Javascript is in typical "YYYY-MM-DD HH:MM:SS" format.
I have the timezone the user is in stored in a database.
I basically want to take that timestamp, and convert it to UTC time, so that all timestamps in the database are UTC.
That is where I am struggling.
I have the following PHP code:
$defaultTime = request('submitted-time-stamp'); //In this case, we'll say 2022-12-21 12:01:01
$defaultTZ = $user->time_zone; //Translates to America/Denver
$utcTime = new DateTime($defaultTime);
$convertedTime = $utcTime1->setTimeZone(new DateTimeZone('UTC'));
$formattedTime = $convertedTime->format("Y-m-d H:i:s");
echo $formattedTime;
This code – it isn't producing any errors per sé... but it is showing the wrong time. It's showing the time that it went in as, not the time converted to UTC.
Basically, if I submit "2022-12-21 12:01:01" as the time, the converted time SHOULD be "2022-12-21 19:01:01", but it's still just echoing out "2022-12-21 12:01:01".
What am I missing here?
setTimezone() changes the timezone of the object from whatever default it was created with. I.e., it means, "convert from the existing timezone to this new timezone." It does not mean, "interpret the time as if it were in this timezone." If the original string didn't contain some sort of timezone identifier, then that default is whatever your PHP config says.
$when = new DateTime('2022-12-21 12:01:01');
echo $when->getTimeZone()->getName();
This will be the same as:
echo date_default_timezone_get();
Which is probably not what you want unless all your users are in the same timezone as your server.
In order to create a DateTime object in a specific known timezone that is not the same as your server's default, you'll need one of two things -- either a timezone representation in the input string:
$when = new DateTime('2022-12-21 12:01:01 America/New_York');
Or an explicit default timezone passed as a second parameter to the DateTime constructor:
$userDefaultTzStr = 'America/New_York'; // read this value from the database
$defaultTz = new DateTimeZone($userDefaultTzStr);
$when = new DateTime('2022-12-21 12:01:01', $defaultTz);
This latter method is (probably) preferred. If the input string contains any sort of timezone identifier, that will be used and the second parameter will be ignored. But if the input string does not contain any sort of timezone identifier, then the string will be interpreted as if it were in the indicated timezone.
Using Carbon it's very trivial.
use Carbon\Carbon;
$date = Carbon::create(request('submitted-time-stamp'), $user->time_zone);
$date->tz('UTC');
echo $date->format('Y-m-d H:i:s');
It should be the same thing with Laravel's Date facade.
use Illuminate\Support\Facades\Date;
$date = Date::create(request('submitted-time-stamp'), $user->time_zone);
$date->tz('UTC');
echo $date->format('Y-m-d H:i:s');
I am working on a project and I am having an issue formatting an epoch time to a human readable time.
I have the following epoch time 1428512160 and when I put this through epochconverter.com I get the human time of 08/04/2015 17:56:00 GMT+1:00 DST as expected.
I then use the following code in order to perform the conversion from the epoch time to a human date time.
$dt = new DateTime($supportDetails["Reported"]);
$reportedTimeString = $dt->format('d-m-Y H:i:s');
$supportDetails[Reported] is the epoch time (I've printed it so I know it's correct).
The result I get back however is 08-04-2160 14:28:51.
You need to add an # for the timestamp in the DateTime class, like this:
$dt = new DateTime("#" . $supportDetails["Reported"]);
//^ See here
You can also see this in the manual. And a quote from there:
Unix Timestamp "#" "-"? [0-9]+ "#1215282385"
Also note that the current timezone is getting ignored, which you can also see in the manual:
Note:
The $timezone parameter and the current timezone are ignored when the $time parameter either is a UNIX timestamp (e.g. #946684800) or specifies a timezone (e.g. 2010-01-28T15:00:00+02:00).
Printing date and time is correct.
Its based on what GMT you have set in your PHP.
If you printing with GMT you will get required result.
Try the following code:
$reportedTimeString = date("d-m-Y H:i:s", $supportDetails["Reported"]);
Or the following:
$date = new DateTime();
$date->setTimestamp($supportDetails["Reported"]);
$reportedTimeString = $date->format("d-m-Y H:i:s");
The problem I see is with your formatting.
If you look at PHP's date function you can see that you just need to write each portion of the desired date & time into a string.
The following formatting gives the same output you were looking for:
$dt = new DateTime($supportDetails["Reported"]);
$reportedTimeString = $dt->format('d/m/Y H:i:s \G\M\TP T');
I am trying to have a line of code added to an html document that is preceded by the time. I want the time zone to be relative to me, however I cannot change it from the default UTC. I have changed in the php.ini file to PST as well as using date_default_timezone_set('America/Los_Angeles'); and yet it still prints the time 7 hours ahead of my timezone. Heres the code that deals with the time:
session_start();
if(isset($_SESSION['name']))
{
date_default_timezone_set('America/Los_Angeles');
$msg = $_POST['text'];
$fo = fopen("log.html", 'a');
fwrite($fo, "<div class=msgln>(".date("g:i A").") <b style=color:red;>".$_SESSION['name']."</b>: ".stripslashes(htmlspecialchars($msg))."<br></div>
");
fclose($fo);
}
Servers should be set to UTC, and you should not be looking to change the default. Instead, what you want to do is create a DateTime object based on the time, then convert it to the timezone you want, and display.
$now = new DateTime();
$now->setTimezone(new DateTimeZone('America/Los_Angeles'));
echo $now->format('g:i A');
I don't know if your format string is valid or not, but the format method is suppossed to be compatible with that accepted by the date() function you were using in your original example.
First make sure you're using a valued timezone. You can find a list of supported timezones in the PHP docs.
The second problem is using date() without specifying the timestamp. This defaults to the timestamp produced by time() which (based on a comment in the documentation) is UTC time. You'll either have to use strftime() or manually subtract the difference from UTC.
If you use 'etc/GMT' you can set the dateTime object to the desired time zone like so:
$dtz = new DateTimeZone('etc/GMT-10');
$dt = new DateTime(date("Y-m-d h:i A"), $dtz);
$date = gmdate("Y-m-d h:i A", $dt->format('U'));
I am working on an iPhone app where I am getting date and time(separate) from user and submitting it to my php web service. php web service is then supposed to take this date and time and save it to utc timezone. I have read that I will also require local timezone in php file to convert it to utc. I am getting 'Asia/Kolkata (IST) offset 1980' as my timezone value in my iPhone application and can send it to php file. Now how will I convert date, time and timezone to utc date.
I have to convert the date to utc format so that I can query my table to get me data which is not past local time.
Thanks in advance
Regards
Pankaj
Use setTimeZone to convert the timezone from whatever the user sends to UTC:
$utz = new DateTimeZone($input['timezone']);
$udt = new DateTime($input['date'].' '.$input['time'], $utz);
$udt->setTimezone(new DateTimeZone('UTC'));
echo $input['date'].' '.$input['time'].' '.$input['timezone'].' is '.$udt->format('Y-m-d H:i:s')." UTC\n";
check out PHP DateTime();
Essentially you'll want to handle it somewhat like below.
$date = new DateTime($dateFromiPhone);
$date->setTimeZone(new DateTimeZone("UTC"));
And then use $date->format(); to format for your desired usage
I have a date stored in a database in this format:
2011-02-23 13:00:00
I need to return it in ISO8601 format, but it needs to be set to a specific time zone (which is not necessarily the time zone of the server.) What I want to return is this:
2011-02-23T13:00:00-0600
Using this code:
echo date(DATE_ISO8601, strtotime("2011-02-23 13:00:00"));
I get this:
2011-02-23T13:00:00+0000
Is there any way to reset the time zone in the date or strtotime function, or do I need to strip off the 5 rightmost characters and concatenate the desired timezone stamp to the remaining date/time?
EDITED TO ADD:
Although I did accept the solution below of using new DateTime and setting new DateTimeZone, I found an easier way if you don't need to keep resetting the time zone:
date_default_timezone_set('America/Chicago');
$startTime = date(DATE_ISO8601, strtotime("2011-02-23 13:00:00"));
You could use the DateTime class. Datetime objects can be initialized with a specific time zone, and easily transposed to others.
Modified from the manual:
$date = new DateTime('2011-02-23 13:00:00', new DateTimeZone('Pacific/Nauru'));
echo $date->format('c') . "\n";
$date->setTimezone( new DateTimeZone('Europe/Berlin'));
echo $date->format('c') . "\n";