How to echo out the values individually of this array?
Array ( [0] => 20120514 [1] => My Event 3 )
so
echo $value[0]; etc
I have this so far:
foreach (json_decode($json_data_string, true) as $item) {
$eventDate = trim($item['date']);
// positive limit
$myarray = (explode(',', $eventDate, 2));
foreach ($myarray as $value) {
echo $value;
}
This echo's out the whole string no as an array. and if i do this?
echo $value[0};
Then I only get 2 characters of it??
The print_r :
Array ( [0] => 20120430 [1] => My Event 1 )
foreach ($array as $key => $val) {
echo $val;
}
Here is a simple routine for an array of primitive elements:
for ($i = 0; $i < count($mySimpleArray); $i++)
{
echo $mySimpleArray[$i] . "\n";
}
you need the set key and value in foreach loop for that:
foreach($item AS $key -> $value) {
echo $value;
}
this should do the trick :)
The problem here is in your explode statement
//$item['date'] presumably = 20120514. Do a print of this
$eventDate = trim($item['date']);
//This explodes on , but there is no , in $eventDate
//You also have a limit of 2 set in the below explode statement
$myarray = (explode(',', $eventDate, 2));
//$myarray is currently = to '20'
foreach ($myarray as $value) {
//Now you are iterating through a string
echo $value;
}
Try changing your initial $item['date'] to be 2012,04,30 if that's what you're trying to do. Otherwise I'm not entirely sure what you're trying to print.
var_dump($value)
it solved my problem, hope yours too.
Related
i dont want to echo the last two values in an associative array, couldn's figure it out, please help.
foreach($_POST as $key => $value){
echo $value;
}
This echoes all the values, i want to echo all but the last 2.
Just count the loops and dont print the value in the last two loops.
$i = 0;
foreach($_POST as $key => $value) {
$i++;
if($i != count($_POST) && $i != count($_POST)-1) {
echo $value;
}
}
It should work to slice the array before you loop it.
<?php
$newArray = array_slice( $_POST, 0, count($_POST)-2);
foreach( $newArray AS $key => $value ) {
echo $value;
}
If you want to keep your $key value, then set the 4th parameter to true to "preserve keys":
http://php.net/manual/en/function.array-slice.php
Maybe this is just an exercise, but I do want to note, in addition, that relying on the exact order of your POST'd elements sounds like a bad design idea that could lead to future problems.
I'd rather do this:
$a = array('a' => 'q','s' => 'w','d' => 'e','f' => 'r');
$arr_count = count($a) - 2;
$i = 1;
foreach($a as $k => $val){
echo $k.' - '.$val.PHP_EOL;
if ($i == $arr_count) break;
$i++;
}
Another alternative solution:
<?php
$tot=count($_POST)-2;
while ($tot--) {
// you can also retrieve the key using key($_POST);
echo current($_POST);
next($_POST);
}
Driving me crazy but here goes:
$cat=2,3,4
$test = print_r(explode(',', $cat), true);
echo ''.$test.'';
foreach ($test as $key => $val) {
echo "$key => $val <br>";
}
What I'm hoping to get:
2
3
4
I'm trying to use a string of numbers obtained from another code to build an array, and then show each value on separate lines. What am I doing wrong?
You shouldn't assign print_r() to $test variable... It's a debugging function for printing purposes..
You should write your code like this..
$cat='2,3,4';
foreach(explode(',',$cat) as $v)
{
echo $v."<br>";
}
This should be either:
$test = explode(',', $cat);
or:
print_r(explode(',', $cat), true);
<?php
$cat='2,3,4';
$array = explode(',', $cat);
$test = print_r($array, true);
echo ''.$test.'';
foreach ($array as $key => $val) {
echo "$key => $val <br>";
}
$test is string. You need array for foreach statement.
Try with this:
<?php
$cat = "2,3,4"; // This is a string separated with commas.
$test = explode(',', $cat); // This assign every number to an array item. The print_r() function is not necesary here.
foreach ($test as $value) {
echo $value. "<br />\n";
}
?>
THIS WILL PRODUCE:
2
3
4
Explanation about your errors:
$cat= '2,3,4'; <- ** Missing quotes **
$test = print_r(explode(',', $cat), true); <- **print_r is not needed here **
echo ''.$test.'';
foreach ($test as $key => $val) { <- Not using it propperly
echo "$key => $val ";
}
You miss ; in $cat variable declaration. Use the following code.
$cat=2,3,4;
$test = explode(',', $cat);
foreach ($test as $key => $val) {
echo $val."<br>";
}
I have an associative array in a foreach like this:
foreach ($mArray as $aValue) {
foreach ($aValue as $key => $value) {
echo $html->find($key,$value)
}
}
It gives me this output:
bobby
johnny
Now I would like to get the last character which is y so I did:
echo substr($TheString, -1);
But this gives me: yy because its a multi-dimensional array so it gives me the last characters in each array. What can I do to get the last character on the page y (..and delete it)?
$last_char = '';
foreach ($mArray as $aValue) {
foreach ($aValue as $key => $value) {
if(substr($html->find($key,$value), -1) == 'y'){
$last_char = $html->find($key,$value);
}
}
}
echo $last_char;
This seems to work for me
echo substr_replace($TheString,"",-3);
Try This :
echo substr($TheString, -1, 1);
OR replace a string Removing y
$s="abcdey";
$m=substr($s,0,-1);
echo substr_replace($s,$m,0)
Try This :
$array = array(
"foo" => "jonny",
"bar" => "monny",
);
$i=0;
$con=count($array);
foreach($array as $key => $value)
{
$i++;
if($i==$con)
{
$s=$value;
$m=substr($value,0,-1);
$value=substr_replace($s,$m,0);
echo "Removed Y from array of last item =".$m."</br>";
}
echo $value."</br>";
}
I have an array called $topProductIdResults and it looks like the following:
Array ( [11497522] => 2 )
The keys are prodcuct ID's and the value is the number of 5 star ratings that the product has recieved.
I want it to echo out this data using a loop. However I can't work our how to echo out both the key and value. Sometimes there will be several product ID's and number pairs in this array. Please let me know where I'm going wrong. My code so far is:
foreach ($topProductIdResults as $prod) {
echo $prod[0];
echo $prod[1];
}
which just echo's 22 at the moment. I want it to echo 11497522 2
foreach ($topProductIdResults as $key => $value) {
echo $key;
echo $value;
}
Try this :
foreach ($topProductIdResults as $key=>$prod) {
echo $key;
echo $prod;
}
Ref: http://php.net/manual/en/control-structures.foreach.php
If you just have a single dimensional array with key and value Array ( [11497522] => 2 ) , then you can use this :
$array = array(11497522=>2);
$key = key($array);
$value = $array[$key];
Use this
foreach ($topProductIdResults as $key => $value)
{
echo $key;
echo $value;
}
Try this
foreach ($topProductIdResults as $prodid => $prod) {
echo $prod[0];
echo $prod[1];
}
Why does this yield this:
foreach( $store as $key => $value){
$value = $value.".txt.gz";
}
unset($value);
print_r ($store);
Array
(
[1] => 101Phones - Product Catalog TXT
[2] => 1-800-FLORALS - Product Catalog 1
)
I am trying to get 101Phones - Product Catalog TXT.txt.gz
Thoughts on whats going on?
EDIT: Alright I found the solution...my variables in my array had values I couldn't see...doing
$output = preg_replace('/[^(\x20-\x7F)]*/','', $output);
echo($output);
Cleaned it up and made it work properly
The doc http://php.net/manual/en/control-structures.foreach.php clearly states why you have a problem:
"In order to be able to directly modify array elements within the loop precede $value with &. In that case the value will be assigned by reference."
<?php
$arr = array(1, 2, 3, 4);
foreach ($arr as &$value) {
$value = $value * 2;
}
// $arr is now array(2, 4, 6, 8)
unset($value); // break the reference with the last element
?>
Referencing $value is only possible if the iterated array can be referenced (i.e. if it is a variable). The following code won't work:
<?php
/** this won't work **/
foreach (array(1, 2, 3, 4) as &$value) {
$value = $value * 2;
}
?>
Try
foreach( $store as $key => $value){
$store[$key] = $value.".txt.gz";
}
The $value variable in the array is temporary, it does not refer to the entry in the array.
If you want to change the original array entry, use a reference:
foreach ($store as $key => &$value) {
// ^ reference
$value .= '.txt.gz';
}
You are rewriting the value within the loop, and not the key reference in your array.
Try
$store[$key] = $value.".txt.gz";
pass $value as a reference:
foreach( $store as $key => &$value){
$value = $value.".txt.gz";
}
Try
$catalog = array();
foreach( $store as $key => $value){
$catalog[] = $value.".txt.gz";
}
print_r ($catalog);
OR
foreach( $store as $key => $value){
$store[$key] = $value.".txt.gz";
}
print_r ($store);
Depends on what you want to achieve
Thanks
:)
I believe this is what you want to do:
foreach( $store as $key => $value){
$store[$key] = $value.".txt.gz";
}
unset($value);
print_r ($store);
How about array map:
$func = function($value) { return $value . ".txt.gz"; };
print_r(array_map($func, $store));
foreach(array_container as & array_value)
Is the way to modify array element value inside foreach loop.