Jquery: If form is blank load this query - php

Question

I've got some JQuery which monitors a form. Basically, for every keyup it will call a php file to search the database.
$(document).ready(function() {
$("#faq_search_input").watermark("Begin Typing to Search");
$("#faq_search_input").keyup(function() {
var faq_search_input = $(this).val();
var dataString = 'keyword='+ faq_search_input;
if (faq_search_input.length > 2) {
$.ajax({
type: "GET",
url: "core/functions/searchdata.php",
data: dataString,
beforeSend: function() {
$('input#faq_search_input').addClass('loading');
},
success: function(server_response) {
$('#searchresultdata').empty();
$('#searchresultdata').append(server_response);
$('span#faq_category_title').html(faq_search_input);
}
});
}
return false;
});
});
This works fine, however it filters the results in #searchresultdata depending on the query. The only thing is, if nothing is in the form, I want it to load everything - the user should not have to click the form to do this, therefore a .blur would not work.
The PHP file is simply:
if(isset($_GET['keyword'])){}

Answer 1

you should handle a [*] search on your server
$query = "SELECT Image, Manufacturer, Model FROM Device_tbl WHERE Manufacturer LIKE '%$keyword%' OR Model LIKE '%$keyword%";
if ($keyword=='*') $query = "SELECT Image, Manufacturer, Model FROM Device_tbl";
$(document).ready(function() {
$("#faq_search_input").watermark("Begin Typing to Search");
$("#faq_search_input").keyup(function() {
var faq_search_input = $(this).val();
if (faq_search_input =='') faq_search_input ='*';
var dataString = 'keyword='+ faq_search_input;
if (faq_search_input.length > 2 || faq_search_input=='*') {
$.ajax({
type: "GET",
url: "core/functions/searchdata.php",
data: dataString,
beforeSend: function() {
$('input#faq_search_input').addClass('loading');
},
success: function(server_response) {
$('#searchresultdata').empty();
$('#searchresultdata').append(server_response);
$('span#faq_category_title').html(faq_search_input);
}
});
}
return false;
});
$("#faq_search_input").trigger('keyup');
});

Answer 2

If you're loading all results initially, then could you not just store this in a JavaScript array and filter the results with JavaScript? This would save you a HTTP request on every key press, which can only be good for speed and resource usage of your site.
EDIT: Sample.
<?php
$sql = "SELECT `title` FROM `your_table`";
$res = mysql_query($sql);
$rows = array();
while ($row = mysql_fetch_assoc($res)) {
$rows[] = $row['title'];
}
echo '<script>var data = ' . json_encode($rows) . ';</script>';
?>
<form method="post" action="">
<fieldset>
<input type="text" name="search" id="faq_search_input" />
</fieldset>
</form>
<script>
// I presume you're using jQuery
var searchInput = $('#faq_search_input');
var searchResults = $('#searchresultdata');
var tmpArray = data;
// add all results to results div
$.each(data, function(key, val) {
searchResults.append('<li>' + val + '</li>');
});
searchInput.attr('placeholder', 'Begin typing to search');
searchInput.keyup(function() {
// hide any <li> in your #searchresultdata that don't match input
});
</script>
I don't know what is in your serverresponse variable, so I can only guess what gets put into the searchresultdata <div>. You'll also need to modify the SQL query to match your table and column names.
Contents of searchdata.php
$query = "SELECT Image, Manufacturer, Model FROM Device_tbl WHERE Manufacturer LIKE '%$keyword%' OR Model LIKE '%$keyword%'";
if ($keyword=='*') $query = "SELECT Image, Manufacturer, Model FROM Device_tbl";
$result=mysql_query($query, $database_connection) or die(mysql_error());
if($result){
if(mysql_affected_rows($database_connection)!=0){
while($row = mysql_fetch_object($result)){
?>
<div class="hold-cont">
<div class="holder">
<div class="image-hold" >
<img class="image-icon" src="<? echo $deviceimg.($row->Image); ?>"/>
</div>
</div>
<div class="device-name devicename-txt"><? echo($row->Manufacturer. ' ' .$row->Model); ?></div>
</div>
<?
}
}else {
echo 'No Results for :"'.$_GET['keyword'].'"';
}
}
}else {
echo 'Parameter Missing';
}