I am analyzing images and need a fast clustering algorithm which searches for the center of the biggest center.
A sample data set might look like this:
$x = array(6,9,7,0,0,0,4,0,0,6,6,3);
As you see there are 3 clusters in the array.
The result I am looking for is the array position of the center of the cluster with the highest sum.
In the example above this would be 1 as $x[1] is the center of the biggest cluster 6+9+7(=22).
Any ideas?
Whichever way you go, you'll have to walk through the array at least once. The following algorithm does this in one pass without any additional sorting/searching - although I admit that it still may not be the most efficient one. Note that if the biggest cluster has an even number of elements, then it'll return the "lower" mid-point (e.g. for a cluster with indices 0, 1, 2, 3 it will return 1) - this can be easily adjusted in the last line of computation ($mid = ...).
$input = array(6,9,7,0,0,0,4,0,0,6,6,3);
$clust = array(0, 0, 0);
$st = -1;
$sum = 0;
for($i=0; $i<count($input); $i++) {
if($input[$i] == 0) {
if($i == 0) {
continue;
}
elseif($input[$i - 1] == 0) {
continue;
}
else {
if($clust[2] < $sum) {
$clust = array($st, $i - 1, $sum);
}
}
}
else {
if($i == 0 || $input[$i - 1] == 0) {
$st = $i;
$sum = 0;
}
$sum += $input[$i];
}
}
if(end($input) != 0 && $clust[2] < $sum) {
$clust = array($st, $i - 1, $sum);
}
if($clust[2] > 0) {
$mid = (int)(($clust[1] - $clust[0]) / 2);
echo $clust[0] ."->". $mid ."->" . $clust[1] ." = ". $clust[2];
}
else {
echo "No clusters found";
}
Related
This code is working fine when the array length is 8 or 10 only. When we are checking this same code for more than 10 array length.it get loading not showing the results.
How do reduce my code. If you have algorithm please share. Please help me.
This program working flow:
$allowed_per_room_accommodation =[2,3,6,5,3,5,2,5,4];
$allowed_per_room_price =[10,30,60,40,30,50,20,60,80];
$search_accommodation = 10;
i am get subsets = [5,5],[5,3,2],[6,4],[6,2,2],[5,2,3],[3,2,5]
Show lowest price room and then equal of 10 accommodation; output like as [5,3,2];
<?php
$dp=array(array());
$GLOBALS['final']=[];
$GLOBALS['room_key']=[];
function display($v,$room_key)
{
$GLOBALS['final'][] = $v;
$GLOBALS['room_key'][] = $room_key;
}
function printSubsetsRec($arr, $i, $sum, $p,$dp,$room_key='')
{
// If we reached end and sum is non-zero. We print
// p[] only if arr[0] is equal to sun OR dp[0][sum]
// is true.
if ($i == 0 && $sum != 0 && $dp[0][$sum]) {
array_push($p,$arr[$i]);
array_push($room_key,$i);
display($p,$room_key);
return $p;
}
// If $sum becomes 0
if ($i == 0 && $sum == 0) {
display($p,$room_key);
return $p;
}
// If given sum can be achieved after ignoring
// current element.
if (isset($dp[$i-1][$sum])) {
// Create a new vector to store path
// if(!is_array(#$b))
// $b = array();
$b = $p;
printSubsetsRec($arr, $i-1, $sum, $b,$dp,$room_key);
}
// If given $sum can be achieved after considering
// current element.
if ($sum >= $arr[$i] && isset($dp[$i-1][$sum-$arr[$i]]))
{
if(!is_array($p))
$p = array();
if(!is_array($room_key))
$room_key = array();
array_push($p,$arr[$i]);
array_push($room_key,$i);
printSubsetsRec($arr, $i-1, $sum-$arr[$i], $p,$dp,$room_key);
}
}
// Prints all subsets of arr[0..n-1] with sum 0.
function printAllSubsets($arr, $n, $sum,$get=[])
{
if ($n == 0 || $sum < 0)
return;
// Sum 0 can always be achieved with 0 elements
// $dp = new bool*[$n];
$dp = array();
for ($i=0; $i<$n; ++$i)
{
// $dp[$i][$sum + 1]=true;
$dp[$i][0] = true;
}
// Sum arr[0] can be achieved with single element
if ($arr[0] <= $sum)
$dp[0][$arr[0]] = true;
// Fill rest of the entries in dp[][]
for ($i = 1; $i < $n; ++$i) {
for ($j = 0; $j < $sum + 1; ++$j) {
// echo $i.'d'.$j.'.ds';
$dp[$i][$j] = ($arr[$i] <= $j) ? (isset($dp[$i-1][$j])?$dp[$i-1][$j]:false) | (isset($dp[$i-1][$j-$arr[$i]])?($dp[$i-1][$j-$arr[$i]]):false) : (isset($dp[$i - 1][$j])?($dp[$i - 1][$j]):false);
}
}
if (isset($dp[$n-1][$sum]) == false) {
return "There are no subsets with";
}
$p;
printSubsetsRec($arr, $n-1, $sum, $p='',$dp);
}
$blockSize = array('2','3','6','5','3','5','2','5','4');
$blockvalue = array('10','30','60','40','30','50','20','60','80');
$blockname = array("map","compass","water","sandwich","glucose","tin","banana","apple","cheese");
$processSize = 10;
$m = count($blockSize);
$n = count($processSize);
// sum of sets in array
printAllSubsets($blockSize, $m, $processSize);
$final_subset_room = '';
$final_set_room_keys = '';
$final_set_room =[];
if($GLOBALS['room_key']){
foreach ($GLOBALS['room_key'] as $set_rooms_key => $set_rooms) {
$tot = 0;
foreach ($set_rooms as $set_rooms) {
$tot += $blockvalue[$set_rooms];
}
$final_set_room[$set_rooms_key] = $tot;
}
asort($final_set_room);
$final_set_room_first_key = key($final_set_room);
$final_all_room['set_room_keys'] = $GLOBALS['room_key'][$final_set_room_first_key];
$final_all_room_price['set_room_price'] = $final_set_room[$final_set_room_first_key];
}
if(isset($final_all_room_price)){
asort($final_all_room_price);
$final_all_room_first_key = key($final_all_room_price);
foreach ($final_all_room['set_room_keys'] as $key_room) {
echo $blockname[$key_room].'---'. $blockvalue[$key_room];
echo '<br>';
}
}
else
echo 'No Results';
?>
I'm assuming your task is, given a list rooms, each with the amount of people it can accommodate and the price, to accommodate 10 people (or any other quantity).
This problem is similar to 0-1 knapsack problem which is solvable in polynomial time. In knapsack problem one aims to maximize the price, here we aim to minimize it. Another thing that is different from classic knapsack problem is that full room cost is charged even if the room is not completely occupied. It may reduce the effectiveness of the algorithm proposed at Wikipedia. Anyway, the implementation isn't going to be straightforward if you have never worked with dynamic programming before.
If you want to know more, CLRS book on algorithms discusses dynamic programming in Chapter 15, and knapsack problem in Chapter 16. In the latter chapter they also prove that 0-1 knapsack problem doesn't have trivial greedy solution.
I have two sorted arrays:
$idProducts = [2,9,25,666,1001,1002,1005,2546...n]; //almost 55.000 values
$someIds = [1,9,11,12,99,111,855...n]; //almost 2.500 values
I try make a new array from intersection of idProducts and $someIds.
I applied 3 search algorithms: linear, binary, interpolar searching, but only linear and binary algorithm work properly:
foreach($someIds as $id){
if(interpolation_search($idProducts, $id) >=0){
$newArray[]=$id;
}
}
function interpolation_search($list, $x)
{
$l = 0;
$r = count($list) - 1;
while ($l <= $r) {
if ($list[$l] == $list[$r]) {
if ($list[$l] == $x) {
return $l;
} else {
// not found
return -1;
}
}
$k = ($x - $list[$l])/($list[$r] - $list[$l]);
// not found
if ($k < 0 || $k > 1) {
return -1;
}
$mid = round($l + $k*($r - $l));
if ($x < $list[$mid]) {
$r = $mid - 1;
} else if ($x > $list[$mid]) {
$l = $mid + 1;
} else {
// success!
return $mid;
}
// not found
return -1;
}
}
Anyway the best solution was:
$idProducts = array_flip($idProducts);
foreach ($someIds as $id){
if (isset($idProducts [$id])===true){
$newArray[]=$id;
}
}
But i want know why interpolation doesnt work properly in my case and in which case we can implement interpolation algorithm searching.
Thank you.
I challenged myself to improve my skills by doing some individual projects and for now I am stuck with the 2048.
I have the text file which stores the present values of the game.
128 64 32 16 32 8 8 8 16 4 4 4 8 2 2 2
<?php
$logs = file("logs-2048.txt");
if ($_SERVER["REQUEST_METHOD"] == "POST") {
file_put_contents('logs-2048.txt', '');
$tableValues = [];
$arrayLine = explode(" ", $logs[0]);
for($g=0; $g<4; $g++) {
$newLine = [];
for($h=0; $h<4; $h++) {
array_push($newLine, htmlspecialchars($arrayLine[$g*4+$h]));
}
array_push($tableValues, $newLine);
}
$direction = $_POST["action-joueur"];
$string = "";
if($direction == "^") {
for($g = 0; $g < 3; $g++) {
for ($h = 0; $h < 4; $h++) {
for ($i = 0; $i < 3; $i++) {
if ($tableValues[$i][$h] == $tableValues[$i+1][$h] || $tableValues[$i][$h] == 0) {
$tableValues[$i][$h] += $tableValues[$i+1][$h];
$tableValues[$i+1][$h] = 0;
}
}
}
}
} else if ($direction == "v") {
//Almost simillar stuff as for ^
} else if ($direction == "<") {
//Almost similar stuff as for ^
} else if ($direction == ">") {
//Almost similar stuff as for ^
}
$arrayEmpty = [];
for($g = 0; $g < 4; $g++) {
for($h = 0; $h < 4; $h++) {
if($tableValues[$g][$h] == 0) {
array_push($arrayEmpty, [$g, $h]);
}
}
}
$findRand = mt_rand(0, count($arrayEmpty)-1);
$tableValues[$arrayEmpty[$findRand][0]][$arrayEmpty[$findRand][1]] = 2;
for($g = 0; $g < 4; $g++) {
for ($h = 0; $h < 4; $h++) {
$string = $string.$tableValues[$g][$h]." ";
}
}
file_put_contents("logs-2048.txt", $string);
}
?>
The first loop is to parse the array that I take from the file, and convert it to a 2 dimensional array(table).
The problem is in the next 4 nested loops which does the summing, I can't figure how can I do other way then just use another loop(first one for each nested loop) which goes 3 times back if some numbers were stuck somewhere adding themselves (EX. 2 2 2 2 in first column => 4 2 2 0 => 4 4 0 0 => 8 0 0 0).
I am 100% sure that the algorithms for summing is terribly inefficient, but I can't figure out what solution I can provide to make it faster and more intuitive, then have 4 for's... I tried also to look at different resources on internet but it's pretty messed up for me because I am starting with php.
Yes, I know that php isn't the best way to do, I'll do myself with
Javascript, but I need it for learning, any ideas or tips to improve the algorithm will be greatly appreciated.
I have the following code:
for($a=1; $a<strlen($string); $a++){
for($b=1; $a+$b<strlen($string); $b++){
for($c=1; $a+$b+$c<strlen($string); $c++){
for($d=1; $a+$b+$c+$d<strlen($string); $d++){
$tempString = substr_replace($string, ".", $a, 0);
$tempString = substr_replace($tempString, ".", $a+$b+1, 0);
$tempString = substr_replace($tempString, ".", $a+$b+$c+2, 0);
$tempString = substr_replace($tempString, ".", $a+$b+$c+$d+3, 0);
echo $tempString."</br>";
}
}
}
}
What it does is to make all possible combinatons of a string with several dots.
Example:
t.est123
te.st123
tes.t123
...
test12.3
Then, I add one more dot:
t.e.st123
t.es.t123
...
test1.2.3
Doing the way I'm doing now, I need to create lots and lots of for loops, each for a determined number of dots. I don't know how I can turn that example into a functon or other easier way of doing this.
Your problem is a combination problem. Note: I'm not a math freak, I only researched this information because of interest.
http://en.wikipedia.org/wiki/Combination#Number_of_k-combinations
Also known as n choose k. The Binomial coefficient is a function which gives you the number of combinations.
A function I found here: Calculate value of n choose k
function choose($n, $k) {
if ($k == 0) {return 1;}
return($n * choose($n - 1, $k - 1)) / $k;
}
// 6 positions between characters (test123), 4 dots
echo choose(6, 4); // 15 combinations
To get all combinations you also have to choose between different algorithms.
Good post: https://stackoverflow.com/a/127856/1948627
UPDATE:
I found a site with an algorithm in different programming languages. (But not PHP)
I've converted it to PHP:
function bitprint($u){
$s= [];
for($n= 0;$u > 0;++$n, $u>>= 1) {
if(($u & 1) > 0) $s[] = $n;
}
return $s;
}
function bitcount($u){
for($n= 0;$u > 0;++$n, $u&= ($u - 1));
return $n;
}
function comb($c, $n){
$s= [];
for($u= 0;$u < 1 << $n;$u++) {
if(bitcount($u) == $c) $s[] = bitprint($u);
}
return $s;
}
echo '<pre>';
print_r(comb(4, 6));
It outputs an array with all combinations (positions between the chars).
The next step is to replace the string with the dots:
$string = 'test123';
$sign = '.';
$combs = comb(4, 6);
// get all combinations (Th3lmuu90)
/*
$combs = [];
for($i=0; $i<strlen($string); $i++){
$combs = array_merge($combs, comb($i, strlen($string)-1));
}
*/
foreach ($combs as $comb) {
$a = $string;
for ($i = count($comb) - 1; $i >= 0; $i--) {
$a = substr_replace($a, $sign, $comb[$i] + 1, 0);
}
echo $a.'<br>';
}
// output:
t.e.s.t.123
t.e.s.t1.23
t.e.st.1.23
t.es.t.1.23
te.s.t.1.23
t.e.s.t12.3
t.e.st.12.3
t.es.t.12.3
te.s.t.12.3
t.e.st1.2.3
t.es.t1.2.3
te.s.t1.2.3
t.est.1.2.3
te.st.1.2.3
tes.t.1.2.3
This is quite an unusual question, but I can't help but try to wrap around what you are tying to do. My guess is that you want to see how many combinations of a string there are with a dot moving between characters, finally coming to rest right before the last character.
My understanding is you want a count and a printout of string similar to what you see here:
t.est
te.st
tes.t
t.es.t
te.s.t
t.e.s.t
count: 6
To facilitate this functionality I came up with a class, this way you could port it to other parts of code and it can handle multiple strings. The caveat here is the strings must be at least two characters and not contain a period. Here is the code for the class:
class DotCombos
{
public $combos;
private function combos($string)
{
$rebuilt = "";
$characters = str_split($string);
foreach($characters as $index => $char) {
if($index == 0 || $index == count($characters)) {
continue;
} else if(isset($characters[$index]) && $characters[$index] == ".") {
break;
} else {
$rebuilt = substr($string, 0, $index) . "." . substr($string, $index);
print("$rebuilt\n");
$this->combos++;
}
}
return $rebuilt;
}
public function allCombos($string)
{
if(strlen($string) < 2) {
return null;
}
$this->combos = 0;
for($i = 0; $i < count(str_split($string)) - 1; $i++) {
$string = $this->combos($string);
}
}
}
To make use of the class you would do this:
$combos = new DotCombos();
$combos->allCombos("test123");
print("Count: $combos->combos");
The output would be:
t.est123
te.st123
tes.t123
test.123
test1.23
test12.3
t.est12.3
te.st12.3
tes.t12.3
test.12.3
test1.2.3
t.est1.2.3
te.st1.2.3
tes.t1.2.3
test.1.2.3
t.est.1.2.3
te.st.1.2.3
tes.t.1.2.3
t.es.t.1.2.3
te.s.t.1.2.3
t.e.s.t.1.2.3
Count: 21
Hope that is what you are looking for (or at least helps)....
I'm trying to program my own Sine function implementation for fun but I keep getting :
Fatal error: Maximum execution time of 30 seconds exceeded
I have a small HTML form where you can enter the "x" value of Sin(x) your looking for and the number of "iterations" you want to calculate (precision of your value), the rest is PhP.
The maths are based of the "Series definition" of Sine on Wikipedia :
--> http://en.wikipedia.org/wiki/Sine#Series_definition
Here's my code :
<?php
function factorial($int) {
if($int<2)return 1;
for($f=2;$int-1>1;$f*=$int--);
return $f;
};
if(isset($_POST["x"]) && isset($_POST["iterations"])) {
$x = $_POST["x"];
$iterations = $_POST["iterations"];
}
else {
$error = "You forgot to enter the 'x' or the number of iterations you want.";
global $error;
}
if(isset($x) && is_numeric($x) && isset($iterations) && is_numeric($iterations)) {
$x = floatval($x);
$iterations = floatval($iterations);
for($i = 0; $i <= ($iterations-1); $i++) {
if($i%2 == 0) {
$operator = 1;
global $operator;
}
else {
$operator = -1;
global $operator;
}
}
for($k = 1; $k <= (($iterations-(1/2))*2); $k+2) {
$k = $k;
global $k;
}
function sinus($x, $iterations) {
if($x == 0 OR ($x%180) == 0) {
return 0;
}
else {
while($iterations != 0) {
$result = $result+(((pow($x, $k))/(factorial($k)))*$operator);
$iterations = $iterations-1;
return $result;
}
}
}
$result = sinus($x, $iterations);
global $result;
}
else if(!isset($x) OR !isset($iterations)) {
$error = "You forgot to enter the 'x' or the number of iterations you want.";
global $error;
}
else if(isset($x) && !is_numeric($x)&& isset($iterations) && is_numeric($iterations)) {
$error = "Not a valid number.";
global $error;
}
?>
My mistake probably comes from an infinite loop at this line :
$result = $result+(((pow($x, $k))/(factorial($k)))*$operator);
but I don't know how to solve the problem.
What I'm tring to do at this line is to calculate :
((pow($x, $k)) / (factorial($k)) + (((pow($x, $k))/(factorial($k)) * ($operator)
iterating :
+ (((pow($x, $k))/(factorial($k)) * $operator)
an "$iterations" amount of times with "$i"'s and "$k"'s values changing accordingly.
I'm really stuck here ! A bit of help would be needed. Thank you in advance !
Btw : The factorial function is not mine. I found it in a PhP.net comment and apparently it's the optimal factorial function.
Why are you computing the 'operator' and power 'k' out side the sinus function.
sin expansion looks like = x - x^2/2! + x^3/3! ....
something like this.
Also remember iteration is integer so apply intval on it and not floatval.
Also study in net how to use global. Anyway you do not need global because your 'operator' and power 'k' computation will be within sinus function.
Best of luck.
That factorial function is hardly optimal—for speed, though it is not bad. At least it does not recurse. It is simple and correct though. The major aspect of the timeout is that you are calling it a lot. One technique for improving its performance is to remember, in a local array, the values for factorial previously computed. Or just compute them all once.
There are many bits of your code which could endure improvement:
This statement:
while($iterations != 0)
What if $iterations is entered as 0.1? Or negative. That would cause an infinite loop. You can make the program more resistant to bad input with
while ($iterations > 0)
The formula for computing a sine uses the odd numbers: 1, 3, 5, 7; not every integer
There are easier ways to compute the alternating sign.
Excess complication of arithmetic expressions.
return $result is within the loop, terminating it early.
Here is a tested, working program which has adjustments for all these issues:
<?php
// precompute the factorial values
global $factorials;
$factorials = array();
foreach (range (0, 170) as $j)
if ($j < 2)
$factorials [$j] = 1;
else $factorials [$j] = $factorials [$j-1] * $j;
function sinus($x, $iterations)
{
global $factorials;
$sign = 1;
for ($j = 1, $result = 0; $j < $iterations * 2; $j += 2)
{
$result += pow($x, $j) / $factorials[$j] * $sign;
$sign = - $sign;
}
return $result;
}
// test program to prove functionality
$pi = 3.14159265358979323846264338327950288419716939937510582097494459230781640628620;
$x_vals = array (0, $pi/4, $pi/2, $pi, $pi * 3/2, 2 * $pi);
foreach ($x_vals as $x)
{
$y = sinus ($x, 20);
echo "sinus($x) = $y\n";
}
?>
Output:
sinus(0) = 0
sinus(0.78539816339745) = 0.70710678118655
sinus(1.5707963267949) = 1
sinus(3.1415926535898) = 3.4586691443274E-16
sinus(4.7123889803847) = -1
sinus(6.2831853071796) = 8.9457384260403E-15
By the way, this executes very quickly: 32 milliseconds for this output.