How do I combine two statement will be one query? - php

Question

Here an example queries to get two type of icons..
$fetchIcon = array();
$queryIcon = $db->query("SELECT * FROM icon_code WHERE icon_type = 'icon'");
while ($fIcon = $db->fetch_assoc($queryIcon)) {
$fetchIcon[] = $fIcon;
}
$fetchOther = array();
$queryOther = $db->query("SELECT * FROM icon_code WHERE icon_type = 'other'");
while ($fOther = $db->fetch_assoc($queryOther)) {
$fetchOther[] = $fOther;
}
Then I use foreach to show an ouput on the same page.
foreach ($fetchIcon as $Icon) {
echo $Icon['IconName']; // select option for Icon
}
foreach ($fetchOther as $Other) {
echo $Other['IconName']; // select option for other icon
}
Question :
How do I combine the two statement will be one query?

Answer 1

SELECT * FROM icon_code
WHERE icon_type = 'icon'
or icon_type = 'other'
ORDER BY icon_type
or
SELECT * FROM icon_code
WHERE icon_type in ('icon', 'other')
ORDER BY icon_type
The order byis optional to get the order by type.

Answer 2

SELECT *
FROM icon_code
WHERE icon_type IN ('icon', 'other')
and then
$fetchIcon = array();
$fetchOther = array();
while($row = mysql_fetch_assoc($result)) {
switch($row['icon_type']) {
case 'icon':
$fetchIcon[] = $row;
break;
case 'other':
default:
$fetchOther[] = $row;
}
}

Answer 3

I would suggest using the IN function:
$queryOther = $db->query("SELECT * FROM icon_code WHERE icon_type IN ('other', 'icon'");