I have this block of code
public function onlyLetters($string) {
if(preg_match("/[a-zA-Z]/", $string)) {
return true;
} else {
return false;
}
}
but it always returns false, what would the reason be?
Your string most likely doesn't contain what you expect, and doesn't have a single upper or lower case a-z letter.
OR - you aren't handling the return value correctly
If you check these assumptions, you'll probably solve it yourself :)
Related
I'm trying to check for if a string contains any blacklisted words from an array of string.
This is my current code - the focus is efficiency, string from list may be empty, the string we search in is never empty:
public static function includes_from_array($stringArray, $searchInMe, $offset=0) : bool {
// if not array just check if $stringArray exists in our $searchInMe string.
if(!is_array($stringArray)) {
return strpos($stringArray, $searchInMe) !== false;
}
foreach($stringArray as $query) {
if ($query === '') {
continue;
}
else if(strpos($searchInMe, strtolower($query), $offset) !== false) {
return true;
}
}
return false;
}
Is there a way to shorten the code quickly without harming efficiency or even improving it?
The code was written as it is currently to be able to retrieve the position if required (changing from true or false to pos returned in check), however it is not required in the shortened version.
Thanks!
As per my understanding you soul purpose is to check any bad word is present in sentence or URL and if present then return Boolean true.
Kindly try like this:
<?php
function includes_from_array($stringArray, $searchInMe){
if(is_array($stringArray)){
foreach($stringArray as $arr){
if(strpos($searchInMe,$arr) !== false){
return true;
}
}
}else{
if(strpos($searchInMe,$stringArray) !== false){
return true;
}
}
return false;
}
Sample Output : https://3v4l.org/3Pefn
I am using 2 regex functions here and I wanna make another function which returns false when the 2 regex are both false and if not, then true.
The problem here is when I wanna use the 2 regex functions in the third one, I have to give them parameters, which is not necessary I think, because the third function will only return a simple true or false. I get an undefined variable whenever I give parameters to the 2 regex functions in the 3rd one.
I tried using global variables which works but since its a bad practice I am looking for a better solution.
Code:
function regex1($input)
{
$regex= "/^[A-Za-z0-9 ]*$/";
if (!preg_match($regex, $input))
{
return false;
}
else
{
return true;
}
}
function regex2($input)
{
$regex= "/^[A-Za-z0-9 ]*$/";
if (!preg_match($regex, $input))
{
return false;
}
else
{
return true;
}
}
function checkBoth()
{
if (regex1($input) === false || regex2($input) === false)
{
return false;
}
else
{
return true;
}
}
EDIT:
The checkBoth function I am using in my other file like this together with the other 2 regex functions:
if (!regex1($input))
{
// show error at the same time
}
if (!regex2($input))
{
// show error at the same time
}
if(checkBoth())
{
// success
}
function regex2($input,$secondVar=false)
{....
Later in code in place where you need just add:
if($secondVar !== false){
// do whatever...
}
If you can't user "false" you can just empty string '' or any other value that will not appear there.
I have the following function to do a "exact match" of a pattern($searchPat)
in a sentence ($sourceStr)
function isUsed($sourceStr, $searchPat) {
if (strpos($sourceStr, $searchPat) !== false) {
return true;
} else {
return false;
}
}
However, this doesn't do an exact match. I changed the function as follows but this doesn't even execute.
function isUsed($sourceStr, $searchPat) {
if (preg_match("~\b[$sourceStr]\b~", $searchPat)) {
return true;
} else {
return false;
}
}
How could I do an exact match please?
The [] is a character class. That lists characters you want to allow, for example [aeiou] would allow a vowel. Your variables are also in the inverted order, pattern first, then string to match against. Try this:
function isUsed($sourceStr, $searchPat) {
if (preg_match("~\b$searchPat\b~", $sourceStr)) {
return true;
} else {
return false;
}
}
Additional notes, this is case sensitive, so Be won't match be. If the values you are passing in are going to have special characters the preg_quote function should be used, preg_quote($variable, '~'). You also may want to concatenate the variable so it is clear that that is a variable and not part of the regex. The $ in regex means the end of the string.
Try This.
function isUsed($sourceStr, $searchPat) {
if (preg_match("/\b".preg_quote($sourceStr)."\b/i", $searchPat)) {
return true;
} else {
return false;
}
}
Please try "preg_match" for matches.
$string = 'test';
if ( preg_match("~\btest\b~",$string) )
echo "matched";
else
echo "no match";
Or try like this
if(stripos($text,$word) !== false)
echo "no match";
else
echo "match";
You can try this one:
function isUsed($string_to_search, $source_String) {
if (preg_match("/$string_to_search/", $source_String)) {
return true;
} else {
return false;
}
}
You can change according to your need.
Case insensitive: preg_match("/$string_to_search/i", $source_String)
Boundry condition: preg_match("/\b$string_to_search\b/i", $source_String)
Special characters: if you have any special characters in your string for your safe side replace it with '\special_character'
My pattern matching expression is like this i want to check and return error message.
public function checkthe($str)
{
if(preg_match('/^\(?[+]?[0-9]{3,4}[-. ]?[0-9]{8,10}$/', $str)==TRUE)
{
return true;
}
else
{
$this->form_validation->set_message('checkthe', 'The %s should be in format XXX-XXXXXXXX');
return false;
}
}
I need display error if other than + / and 0-9 in the string
If that is indeed the case your regex code should be:
public function checkthe($str) {
return preg_match('~^[+/0-9]+$~', $str);
}
Though it is always better to include your sample inputs.
Can any one help me to write a preg_match rules to detect whether an input string is a unicode code character?
Here is the list of characters:
http://www.utf8-chartable.de/unicode-utf8-table.pl?start=9728&number=128&utf8=string-literal
I want to write a methods to detect whether the input string is a emoticons
function detectEmoticons($input) {
if (preg_match("/REGEX/", $input)) {
return TRUE;
} else {
return FALSE;
}
}
If the input is a string like "\xe2\x98\x80" or "\xe2\x98\x81"... etc (all the chacracter available in the list http://www.utf8-chartable.de/unicode-utf8-table.pl?start=9728&number=128&utf8=string-literal) then it should return
TRUE
Thanks in Advance,
Uttam
First, use the u modifier if you want your regular expression to work with unicode. Second, use a character class for all characters in the range [\x{2600}-\x{267F}] (i.e. U+2600 to U+267F). Now you can write your function as:
function detectEmoticons($input){
if(preg_match("/[\x{2600}-\x{267F}]/u", $input)){
return TRUE;
}
else{
return FALSE;
}
}
For match Unicode characters in a Regular expressions you must add the u Modifier
Example:
function detectEmoticons($input) {
if (preg_match("/REGEX/u", $input)) {
return TRUE;
} else {
return FALSE;
}
}
If you must retrieve one of the set you could pass the character range like
/[\x{START}-\x{END}]/u
Or check all characters with the mb_strpos function
Example
function detectEmoticons($input) {
$characters = array("\xe2", "\x98", ...);
foreach ($characters as $v) {
if (mb_strpos($input, $v) !== false)
return true;
}
return false;
}
You can find the documentation here:
http://ch1.php.net/manual/en/reference.pcre.pattern.modifiers.php
http://ch2.php.net/manual/en/function.mb-strpos.php
try this
preg_match("/\\[a-zA-Z0-9_-]{1,}\\[a-zA-Z0-9_-]{1,}\\[a-zA-Z0-9_-]{3}/", $input);
Use preg_replace to scape
preg_replace("/\\[a-zA-Z0-9_-]{1,}\\[a-zA-Z0-9_-]{1,}\\[a-zA-Z0-9_-]{3}/",'', $input);