I'm making a supplies requisition form where the user can request supplies. I did this tutorial that allowed me to dynamically add form elements. I was able to produce duplicates of Stock_No, Quantity_Available and Quantity text fields and an Item_Name dropdown list. How am I suppose to insert the values that the user inputs in the dynamically added form elements?
Each dynamically added form element should be using array syntax for the name of each field. Then when the form is submitted your PHP script should be receiving array values for each item. At that point you just need to loop through the arrays to add them to the database.
Basic Example:
$item_names = $_POST['item_names'];
$item_prices = $_POST['item_prices'];
$item_qty = $_POST['item_qty'];
$num_items = count($item_names);
for ($i = 0; $i < $num_items; $i++)
{
// Create your SQL
}
Related
I am trying to insert the data of text area of tabs in MYSQL using PHP. I am able to insert the data of only predefined tab but I am not able to insert the data of newly created tabs when user clicks on ADD TAB button and create his own tab.
Any ideas how it can be done?
here is my HTML output: http://jsfiddle.net/HMv9S/1/
I have tried this MySQL code for inserting the data and successfully can insert the data of predefined tab:
<?php
if ($_POST['submit'])
{
$con=mysqli_connect("localhost","root","","my_db");
$texts=array($_POST['txt']);
foreach($texts as $value)
{
$allTextArea = implode(",", $value);
$text = mysql_real_escape_string($allTextArea);
$query= "INSERT INTO Sections(data) VALUES('$text')";
mysqli_query($con,$query);
}
}
?>
You should name the textarea as an array like txt[] instead of txt. Now on form submit you will get all the textarea values.
if ($_POST['submit']){
$allTextArea = $_POST['txt'];
print_r($allTextArea);
}
Input elements attribute name must be unique (semantically also id). Then iterate through possible keys received in $_POST.
In single form you are creating multiple input elements (in your case <textarea>) with same name attribute. in $_POST, values are sent in format 'key' => value with input element attribute name as key. All your textareas has 'txt' as name.
okay, im new in this site also new in php and can't get the logic on this,
i have a product page that shows the name, quantity and an add to cart button in each row of product
i made this just cutted of some code
while($showProducts = mysql_fetch_array($products))
{
$currenQuantity = $showProducts['current_quantity'];
$prodid = $showProducts['product_id'];
echo"<select name='quan'>";
for ($x=0;$x<=$currenQuantity;$x++)
{
if($currenQuantity != 0)
{
echo "<option value=$x> $x </option>";
}
}
echo"</select><br/>";
}
now the problem is every time i tried to get the value by using $_POST['quan'] the value that i always get is the default value 1 even i select a different value of quantity of a certain product, and i'm blanked with ideas.
You can't use the same name for an input/select field in a form.
You have to specify a diffrent name or create an indexed array:
<select name="quan[$prodid]">
You can acces it via
$_POST['quan'][$prodid]
Just a wild guess: has each of your product rows a select named 'quan'?
Then you're getting the last select named 'quan' in your POST data.
Prefix each of the quantities selects with name of the product, or some kind of a (scrambled) id.
Additionally:
If you don't want to have a 0 in your select, don't start the for loop with 0
for ($x=1;$x<=$currenQuantity;$x++)
if the current quantity is 0, the for loop doesn't get executed.
If you have more selectboxes with the same name (quan) in one form, you are getting value of the last one.
You should change the selectbox definition to:
echo"<select name='quan[" . $prodid . "]'>";
then you can access the values using:
$_POST["quan"][$some_product_id]
$_POST["quan"][$another_product_id]
The title is so general mainly because I don't know what should be the appropriate title for it. Let me just explain the situation:
Say that I have two textboxes named LastName0 and FirstName0 and a button called addMore. When I click addMore, another two textboxes will be created through JavaScript. These textboxes will be named LastName1 and FirstName1. When I click the addMore button again, another two textboxes button will be created and named LastName2 and FirstName2 respectively. This will go on as long as the addMore button is clicked. Also, a button named deleteThis will be created alongside the textboxes. This simply deletes the created textboxes when clicked.
I also initialized a variable called counter. Every time the addMore button is clicked, the counter goes up by 1, and whenever the deleteThis button is clicked, the counter decreases by 1. The value of the counter is stored in a hidden input type.
When the user submits the form, I get the value of the counter and create a For loop to get all the values of the textboxes in the form. Here is the sample code:
//Suppose that the user decides to add 2 more textboxes. Now we have the following:
// LastName0 FirstName0
// LastName1 FirstName1
// LastName2 FirstName2
$ctr = $_POST['counter']; //the counter == 3
for ($x = 0; $x < $ctr; $ctr++)
{
$lastname = $_POST["LastName$x"];
$firstname = $_POST["FirstName$x"];
//This will get the values of LastName0,1,2 and FirstName0,1,2
//code to save to database…
}
On the code above, if the value of counter is equal to 3, then the values of textboxes LastName0,1,2 and FirstName0,1,2 will be saved. Now here is the problem: If the user decided to delete LastName1 and FirstName1, the For loop will not be able to iterate properly:
$ctr = $_POST['counter']; //the counter == 2
for ($x = 0; $x < $ctr; $ctr++)
{
//Only LastName0 and FirstName0 will be saved.
$lastname = $_POST["LastName$x"];
$firstname = $_POST["FirstName$x"];
//code to save to database…
}
Someone told me to use the "push and pop" concept to solve this problem, but I am not really sure on how to apply it here. So if anyone can tell me how to apply it, it'll be grand.
Add your input text boxes with name as array ie, <input type="text" name="FirstName[]" />
In php you can fetch them as a array. ie,
foreach($_POST["FirstName"] as $k=>$val){
echo $val; // give you first name
echo $_POST["LastName"][$k]; // will give you last ame
}
In this case even if one set of field is removed in HTML will not affect the php code.
One solution would be to use the isset function like this:
$ctr = $_POST['counter'];
for ($x = 0; $x < $ctr; $ctr++)
{
isset($_POST["LastName$x"])?$lastname = $_POST["LastName$x"]:;
isset($_POST["FirstName$x"])?$firstname = $_POST["FirstName$x"]:;
}
If it is possible, instead of using LastNameN and FirstNameN names try using LastName[N] and FirstName[N], this way the result is an array and you can iterate through it with a foreach, meaning you will not need the counter and the index of the value will not be important:
foreach ($_POST["LastName"] as $i=>$lastname) {
if (!isset($_POST["FirstName"][$i])) {
// This should only happen if someone messes with the client side before posting
throw new Exception("Last name input does not have a related First name input");
}
$firstname = $_POST["FirstName"][$i];
}
If not, then you may have to use your $counter in a different way
$current = 0;
while ($counter) { // Stop only when i found all
if (isset($_POST["LastName$current"]) {
$counter--; // Found one
$lastname = $_POST["LastName$current"];
$firstname = $_POST["FirstName$current"];
}
$current++;
}
A better way to solve this would be to use arrays for Firstname and Lastname. Instead of calling them Lastname0 and Firstname0, then Lastname1 and Firstname1, call them all Lastname[] and Firstname[]. Give them ID's of Lastname0 and Firstname0 and so on for the delete function, but keep the names as arrays.
When the form is submitted use the following:
foreach($_POST['Lastname'] as $i => $lastname) {
$firstname = $_POST['Firstname'][$i]
//... code to save into the database here
}
Be warned though that in IE if you have an empty field it will not be submitted, so if Lastname0 has a value, but Firstname0 does not, then $_POST['Firstname'][0] will in fact contain the value of Firstname1 (assuming it has a value in it). To get around this you can use javascript to check if a field is empty when submitting the form, and if so put the word EMPTY in it.
Do not use counter if not required
A much easier way is to add array name when admore clicked.
Give a name like first_name[] in textbox
if you create form like that you can use foreach through $_POST['first_name']
try var_dump($_POST) in you php code to see how things goes on.
Inside your for loop, maybe you could try...
if ((isset($_POST["LastName$x"])) && (isset($_POST["FirstName$x"]))){
$lastname = $_POST["LastName$x"];
$firstname = $_POST["FirstName$x"];
//code to save to database…
}
This will check if the variables exists before you try to do anything with them.
Hello i want any checkbox i am gonna check, to stay checked after pagination.
here is the code:
foreach($test as $string){
$queryForArray = "SELECT p_fname,p_id FROM personnel WHERE p_id = " .$string["p_id"]. " ;" ;
$resultForArray = mysql_query($queryForArray, $con);
$rowfForArray = mysql_fetch_array($resultForArray);
?>
<td id="<?php echo $rowfForArray["p_id"]?>" onclick="setStyles(this.id)" ><?php echo $rowfForArray["p_fname"]?></td>
<td><input id="<?php echo $rowfForArray["p_id"]?>" class="remember_cb" type="checkbox" name="how_hear[]" value="<?php echo $rowfForArray["p_fname"]?>"
<?php foreach($_POST['how_hear'] as $_SESSION){echo (( $rowfForArray["p_fname"] == $_SESSION) ? ('checked="checked"') : ('')); } ?>/></td>
</tr>
<tr>
I am geting the data from a search result i have in the same page , and then i have each result with a checkbox , so that i can check the "persons" i need for $_Session use.
The only think i want is the checkbox's to stay checked after pagination and before i submit the form!(if needed i can post the pagination code, but he is 100% correct)
In the checkbox tag use the ternary operation, without that foreach inside him:
<input [...] value="<?php echo $rowfForArray["p_fname"]?>" <?php $rowfForArray["valueToCompareIfTrue"] ? "checked='checked'" : ''; ?> />
because the input already is inside of 'for' loop, then each time of the loop will create a new checkbox wich will verify if need to being check or not.
I hope I have helped you.
A few ways to tackle this:
(Straight up PHP): Each page needs to be a seperate form then, and your "next" button/link needs to submit the form everytime they click next. The submit data should then get pushed to your $_SESSION var. The data can then be extracted and used to repopulate the form if they navigate backwards as well. Just takes some clever usage of setting the URL with the proper $_GET variables for the form.
(HTML5): This will rely more on JavaScript, but basically you get rid of pagination and then just break the entire data set into div chunks which you can hide/reveal with JavaScript+CSS or use a library like JQuery.
(AJAX): Add event listeners to the checkboxes so that when a button is checked an asynchronous call is made back to a PHP script and the $_SESSION variable is updated accordingly. Again, this one depends on how comfortable you are with JavaScript.
Just keep in mind that PHP = ServerSide & JavaScript = ClientSide. While you can hack some PHP together to handle "clientside" stuff, its usually ugly and convoluted...
I did it without touching the database...
The checkbox fields are a php collection "cbgroup[]".
I then made a hidden text box with all the values which equal the primary keys of the selectable items mirroring the checkboxes. This way, I can iterate through the fake checkboxes on the current page and uncheck the checkboxes by ID that exist on the current page only. If the user does a search of items and the table changes, the selectable items remain! (until they destroy the session)
I POST the pagination instead of GET.
After the user selects their items, the page is POSTED and I read in the hidden text field for all the checkbox IDs that exist on that current page. Because PhP only tells you which ones are checked from the actual checkboxes, I clear only the ones from the session array that exist on the POSTED page from this text box value. So, if the user selected items ID 2, 4, 5 previously, but the current page has IDs 7,19, and 22, only 7, 19, and 22 are cleared from the SESSION array.
I then repopulate the array with any previously checked items 7, 19, or 22 (if checked) and append it to the SESSION array along with 2, 4, and 5 (if checked)
After they page through all the items and made their final selection, I then post their final selections to the database. This way, they can venture off to other pages, perhaps even adding an item to the dB, return to the item selection page and all their selections are still intact! Without writing to the database in some temp table every page iteration!
First, go through all the checkboxes and clear the array of these values
This will only clear the checkboxes from the current page, not any previously checked items from any other page.
if (array_key_exists('currentids', $_POST)) {
$currentids = $_POST['currentids'];
if (isset($_SESSION['materials']) ) {
if ($_SESSION['materials'] != "") {
$text = $_SESSION['materials'];
$delimiter=',';
$itemList = explode($delimiter, $text);
$removeItems = explode($delimiter, $currentids);
foreach ($removeItems as $key => $del_val) {
//echo "<br>del_val: ".$del_val." - key: ".$key."<br>";
// Rip through all possibilities of Item IDs from the current page
if(($key = array_search($del_val, $itemList)) !== false) {
unset($itemList[$key]);
//echo "<br>removed ".$del_val;
}
// If you know you only have one line to remove, you can decomment the next line, to stop looping
//break;
}
// Leaves the previous paged screen's selections intact
$newSessionItems = implode(",", $itemList);
$_SESSION['materials'] = $newSessionItems;
}
}
}
Now that we have the previous screens' checked values and have cleared the current checkboxes from the SESSION array, let's now write in what the user selected, because they could have UNselected something, or all.
Check which checkboxes were checked
if (array_key_exists('cbgroup', $_POST)) {
if(sizeof($_POST['cbgroup'])) {
$materials = $_POST['cbgroup'];
$N = count($materials);
for($i=0; $i < $N; $i++)
{
$sessionval = ",".$materials[$i];
$_SESSION['materials'] = $_SESSION['materials'].$sessionval;
}
} //end size of
} // key exists
Now we have all the items that could possibly be checked, but there may be duplicates because the user may have paged back and forth
This reads the entire collection of IDs and removes duplicates, if there are any.
if (isset($_SESSION['materials']) ) {
if ($_SESSION['materials'] != "") {
$text = $_SESSION['materials'];
$delimiter=',';
$itemList = explode($delimiter, $text);
$filtered = array();
foreach ($itemList as $key => $value){
if(in_array($value, $filtered)){
continue;
}
array_push($filtered, $value);
}
$uniqueitemschecked = count($filtered);
$_SESSION['materials'] = null;
for($i=0; $i < $uniqueitemschecked; $i++) {
$_SESSION['materials'] = $_SESSION['materials'].",".$filtered[$i];
}
}
}
$_SESSION['materials'] is a collection of all the checkboxes that the user selected (on every paged screen) and contains the primary_key values from the database table. Now all you need to do is rip through the SESSION collection and read\write to the materials table (or whatever) and select/update by primary_key
Typical form...
<form name="materials_form" method="post" action="thispage.php">
Need this somewhere: tracks the current page, and so when you post, it goes to the right page back or forth
<input id="_page" name="page" value="<?php echo $page ?> ">
if ($page < $counter - 1)
$pagination.= " next »";
else
$pagination.= "<span class=\"disabled\"> next »</span>";
$pagination.= "</div>\n";
Read from your database and populate your table
When you build the form, use something like this to apply the "checked" value of it equals one in the SESSION array
echo "<input type='checkbox' name='cbgroup[]' value='$row[0]'";
if (isset($filtered)) {
$uniqueitemschecked = count($filtered);
for($i=0; $i < $uniqueitemschecked; $i++) {
if ($row[0] == $filtered[$i]) {
echo " checked ";
}
}
}
While you're building the HTML table in the WHILE loop... use this. It will append all the select IDs to a comma separated text value after the loop
...
$allcheckboxids = "";
while ($row = $result->fetch_row()) {
$allcheckboxids = $allcheckboxids.$row[0].",";
...
}
After the loop, write out the hidden text field
echo "<input type='hidden' name='currentids' value='$allcheckboxids'>";
I am dynamically creating forms based on values in a database. Each form element corresponds to a specific database entry, which includes the name, label, type, and (depending upon the type) possible values to be displayed with the form element.
The name value for each form element is set to the identity column value of the corresponding database entry.
I'm running into a problem when I am working with checkboxes, though. I'm trying to retrieve the array of selected values, but I am unable to retrieve more than one. I believe that this is because I am not properly setting the checkbox names to an array, but I am not certain.
Here is where I am generating the checkbox tags:
$answers = explode(',',$answerKey);
for($i=0; $i < count($answers); $i++) {
$questionTag .= "<INPUT TYPE='checkbox' name='$id' value='$answers[$i]' />$answers[$i]";
}
Yet when I post back my results, the results of $_POST["$id"] only returns the last value in the checkbox list.
Any suggestions would be appreciated!
$questionTag .= "<INPUT TYPE='checkbox' name='".$id."[]' value='$answers[$i]' />$answers[$i]";