loading rss feed into php - php

Question

What's the best way to load an RSS feed into a PHP feed?
I also want to handle the media:content problems to display a image.
At this moment I have the following code but I don't know if this is the best.
<?php
$rss = new DOMDocument();
$rss->load('http://www.hln.be/rss.xml');
$feed = array();
foreach ($rss->getElementsByTagName('item') as $node) {
$item = array (
'title' => $node->getElementsByTagName('title')->item(0)->nodeValue,
'desc' => $node->getElementsByTagName('description')->item(0)->nodeValue,
'link' => $node->getElementsByTagName('link')->item(0)->nodeValue,
'date' => $node->getElementsByTagName('pubDate')->item(0)->nodeValue,
'media' => $node->getElementsByTagName('media:content url')->item(0)->nodeValue,
);
array_push($feed, $item);
}
$limit = 20;
for($x=0;$x<$limit;$x++) {
$title = str_replace(' & ', ' & ', $feed[$x]['title']);
$link = $feed[$x]['link'];
$description = $feed[$x]['desc'];
$date = date('l F d, Y', strtotime($feed[$x]['date']));
$image = $feed[$x]['media'];
echo '<p><strong>'.$title.'</strong><br />';
echo '<small><em>Posted on '.$date.'</em></small></p>';
echo '<p>'.$description.'</p>';
echo '<img src="' . $image . '"/>';
}
?>

Answer 1

Check this:
<?php
$feed = simplexml_load_file('http://www.hln.be/rss.xml');
foreach ($feed->channel->item as $item) {
$title = (string) $item->title;
$description = (string) $item->description;
print '<div>';
printf(
'<h2>%s</h2><p>%s</p>',
$title,
$description
);
if ($media = $item->children('media', TRUE)) {
if ($media->content->thumbnail) {
$attributes = $media->content->thumbnail->attributes();
$imgsrc = (string)$attributes['url'];
printf('<div><img src="%s" alt="" /></div>', $imgsrc);
}
}
echo '</div>';
}
?>

Answer 2

You can try this:
<?php
$feed = simplexml_load_file('http://www.hln.be/rss.xml');
print_r($feed);
?>
This gives you object/array structure which you can use directly instead of communicating with additional layer(i.e. DOM) on top of the data.