How to show selected cells of a table? - php

I have a table which show data from mysql database in HTML table like this:
then I want to show like this with checkboxes:
after that user select some rows and submit then the selected rows shown in the next page so how could it be done in php with HTML.


This will get you started:
<table>
<?php
while($r = mysql_fetch_array($q)) {
?>
<tr>
<td><?php echo $r['s_no']; ?></td>
<td><?php echo $r['name']; ?></td>
<td><input type="checkbox" name="selected_s_no[]" value="<?php echo $r['s_no']; ?>" /></td>
</tr>
<?php
}
?>
</table>
On the submitted page there will be an array you can access with the selected s_no values
print_r($_REQUEST['selected_s_no'])


<table>
<?php
while($r = mysql_fetch_array($q)) {
?>
<tr>
<td><?php echo $r['s_no']; ?></td>
<td><?php echo $r['name']; ?></td>
<td><input type="checkbox" name="selected_s_no[]" value="<?php echo $r['s_no']; ?>" /></td>
</tr>
<?php
}
?>
</table>
on submitting page you can use foreach with selected values
foreach($_POST['selected_s_no'] as $value)
{
//show data according to selected checkbox
}

Related

php - mysql update inside a loop using checkbox

I'm trying to update all selected fields in the database using check box. This is the code that I've done, but it only updates the last record I choose from the checkbox list.
<tbody>
<?php while($row = mysqli_fetch_array($queryEmail)):?>
<tr>
<td><input type="checkbox" name="formDoor[]" value=<?php echo $row['id'];?>>
</td>
<td><?php echo $row['name'];?></td>
<td><?php echo $row['hour'];?></td>
</tr>
<?php endwhile;?>
</tbody>
<?php
$hor = $_POST['hours']; //input value i want to update in selected id's
foreach ($_POST['formDoor'] as $entry){
$sql = "UPDATE hora SET hour='$hor' WHERE id = $entry";
}
?>

Try this You are forget to execute mysqli_query() on loop
<tbody>
<?php while($row = mysqli_fetch_array($queryEmail)):?>
<tr>
<td>
<input type="checkbox" name="formDoor[]" value=<?php echo $row['id'];?>>
</td>
<td><?php echo $row['name'];?></td>
<td><?php echo $row['hour'];?></td>
</tr>
<?php endwhile;?>
</tbody>
<?php
$hor = $_POST['hours']; //input value i want to update in selected id's
foreach ($_POST['formDoor'] as $entry){
$sql = mysqli_query($con,"UPDATE hora SET hour='$hor' WHERE id = $entry");
}
?>

Is there a way I could store id of my button used in a table?

<?php
while($row = mysqli_fetch_array($results)){
?>
<tbody>
<tr>
<td> <?php echo $row['Product_ID'] ?></td>
<td> <?php echo $row['Product_Name'] ?></td>
<td> <?php echo $row['Product_Price'] ?></td>
<td> <?php echo $row['Product_Stock'] ?></td>
<td> <button type="submit" name="add" id="<?php $row['Product_ID'] ?>" onclick="func(<?php $row['Product_ID'] ?>)"> Add </button></td>
</tr>
<?php } ?>`
<script type="text/javascript" method="post">
function func(id){
window.alert(id);
};
</script>
Is there a way I could store id of my button named add?
I've to store multiple product ids and use them in a receipt that would be generated using product ids. the method of the form is POST but I don't know how to get the id

Replace this
func(<?php $row['Product_ID'] ?>)
With This
func(<?php echo $row['Product_ID']; ?>)

HTML Checkbox cannot be checked

I have some checkbox in a table that contains the id of that row item. I want to allow the user to select multiple rows. However, I can't seem to check the checkbox on Chrome. I loaded the site up on my mobile and it works. I have tried to insert an onclick but it doesn't seem like the checkbox is registering any clicks to it as well. Please help.
The table
<?php echo form_open_multipart('Events/Two/Search');?>
<table class="table">
<thead>
<tr class="text-left">
<td></td>
<td>Name</td>
<td>Email</td>
<td>Phone Number</td>
<td>Address</td>
</tr>
</thead>
<tbody>
<?php
if(!empty($datatable)){
foreach ($datatable as $data){
?>
<tr>
<td><input type="checkbox" name="id[]" value="<?php echo $data->id; ?>"/></td>
<td><?php echo $data->first_name." ".$data->last_name; ?></td>
<td><?php echo $data->email; ?></td>
<td><?php echo $data->phone_number; ?></td>
<td><?php echo $data->address;?></td>
</tr>
<?php
}
}
?>
</tbody>
</table>
<?php echo form_close(); ?>
EDIT: I have cleared my cache and cookies as well. It works on the mobile but not on chrome for some reason.
EDIT 2 : It works on Safari
EDIT 3 : If I place a checkbox on another place, I can check it. Just not in the table

<tbody>
<?php
if(!empty($datatable)){
foreach ($datatable->result() as $data){
?>
<tr>
<td><input type="checkbox" name="id[]" value="<?php echo $data->id; ?>"/></td>
<td><?php echo $data->first_name." ".$data->last_name; ?></td>
<td><?php echo $data->email; ?></td>
<td><?php echo $data->phone_number; ?></td>
<td><?php echo $data->address;?></td>
</tr>
<?php
}
}
?>
</tbody>
</table>
First Your query is not working it seems so please preview this code the use jquery append to add more row if you need help on that code will be below
Jquery on click ADD/REMOVE ROW please Visit the link below
https://jsfiddle.net/susanadhikary/omngzss8/8/

Cannot connect rows in html with php (logical error display)

The html table rows aren't displayed properly. I want to combine the two while loops in the table row but sadly the Update and Delete button are not arranged properly.
here's my code I used two queries that's why it has two while loops
$sql_sel=mysql_query("SELECT students.stud_id, students.fname, students.lname, students.gender, subjects.sub_code, subjects.subject_name FROM students, enrollments, subjects WHERE students.stud_id = enrollments.stud_id and subjects.sub_code = enrollments.sub_code");
$sql_sel1=mysql_query("SElECT * FROM enrollments");
while($row=mysql_fetch_array($sql_sel)) //for the first query
{
$i++;
$color=($i%2==0)?"lightblue":"white";
?>
<tr bgcolor="<?php echo $color?>">
<td><?php echo $i;?></td>
<td><?php echo $row['stud_id'];?></td>
<td><?php echo $row['fname']." ".$row['lname'];?></td>
<td><?php echo $row['gender'];?></td>
<td><?php echo $row['sub_code'];?></td>
<td><?php echo $row['subject_name'];?></td>
<?php
while($row=mysql_fetch_array($sql_sel1)) //for the second query
{ <!-------The Update and Delete Button are not displayed properly------>
?>
<td align="center"><img src="picture/update.png" /></td>
<td align="center"><img src="picture/delete.png" /></td>
<?php
}
?>
</tr>
<?php
}
?>
Here is the visual scenario of the problem:
The desired output must be like this:

In table header use colspan='4' for the last column.
Also be sure that you fill the table with empty columns, where you don't have information to fill with.
Edit 1:
Sorry, I haven't seen what's really the problem was. Here should be the working code:
while($row=mysql_fetch_array($sql_sel))
{
$i++;
$color=($i%2==0)?"lightblue":"white";
?>
<tr bgcolor="<?php echo $color?>">
<td><?php echo $i;?></td>
<td><?php echo $row['stud_id'];?></td>
<td><?php echo $row['fname']." ".$row['lname'];?></td>
<td><?php echo $row['gender'];?></td>
<td><?php echo $row['sub_code'];?></td>
<td><?php echo $row['subject_name'];?></td>
<!-- You were already in a while loop -->
<td align="center"><img src="picture/update.png" /></td>
<td align="center"><img src="picture/delete.png" /></td>
</tr>
<?php
}
?>
As you can see you were already in a while loop, and the second one was unnecesary.
Edit 2:
There is a single SQL query now:
<?php
// UPDATED SQL QUERY
$sql_sel = mysql_query("SELECT students.stud_id, students.fname, students.lname, students.gender, subjects.sub_code, subjects.subject_name, enrollments.enroll_num
FROM students, enrollments, subjects
WHERE students.stud_id = enrollments.stud_id and subjects.sub_code = enrollments.sub_code");
while($row = mysql_fetch_array($sql_sel)){
$i++;
$color=($i%2==0)?"lightblue":"white";
?>
<tr bgcolor="<?php echo $color?>">
<td><?php echo $i;?></td>
<td><?php echo $row['stud_id'];?></td>
<td><?php echo $row['fname']." ".$row['lname'];?></td>
<td><?php echo $row['gender'];?></td>
<td><?php echo $row['sub_code'];?></td>
<td><?php echo $row['subject_name'];?></td>
<td align="center"><img src="picture/update.png" /></td>
<td align="center"><img src="picture/delete.png" /></td>
</tr>
<?php
}
?>
Why it didn't worked?
You were reading the whole informations for every student. Then you were reading the whole informations in enrollments table.
You started writing the first row with student information, and inside it you told the server to start writing all the information he had regarding enrollments (without even be linked to that student's id).
When the server reached the second row, all the information available for enrollments were depleted.
Now you have them linked in your first query. Please ask in comments if you need further explanations.

Try this,
$sql= "SELECT sts.stud_id, sts.fname, sts.lname, sts.gender, sub.sub_code, sub.subject_name, ets.enroll_num
FROM students sts
JOIN enrollements ets ON(sts.stud_id = ets.stud_id)
JOIN subjects sub ON (sub.sub_code = ets.sub_code)
GROUP BY sts.stud_id, sub.sub_code";
$sql_sel=mysql_query($sql);
while($row=mysql_fetch_array($sql_sel)) //for the first query
{
$i++;
$color=($i%2==0)?"lightblue":"white";
?>
<tr bgcolor="<?php echo $color?>">
<td><?php echo $i;?></td>
<td><?php echo $row['stud_id'];?></td>
<td><?php echo $row['fname']." ".$row['lname'];?></td>
<td><?php echo $row['gender'];?></td>
<td><?php echo $row['sub_code'];?></td>
<td><?php echo $row['subject_name'];?></td>
<td align="center"><img src="picture/update.png" /></td>
<td align="center"><img src="picture/delete.png" /></td>
</tr>
<?php
}
?>
I have added enroll_num column in select, And you dont need two queries for this. One query with proper join will be fine.

PHP table data filtering

I want to filter data in the table use dropdown menu (e.g. filter by name so i can see all data with name 'Jane'). I don't want to move to another page (use ajax or anything else if can). Any idea what must i do ?
This is the dropdown menu and table code :
<!-- Dropdown menu -->
<div class="col-md-2">
<select class="form-control selectpicker">
<option value="">Name</option>
<?php
// print all name value from $administratorProvider
foreach($administratorProvider as $administrator){
?>
<option value="<?php $administrator->first_name ?>"><?php echo $administrator->first_name; ?></option>
<?php
}
?>
</select>
</div>
<table>
<!-- Table heading -->
<thead>
<tr>
<th class="center">No.</th>
<th>Name</th>
<th>Email</th>
<th>Join</th>
<th>Last Login</th>
</tr>
</thead>
<!-- Table body -->
<tbody>
<?php
$i=1;
foreach ($dataProvider as $data){
?>
<tr>
<div>
<td class="center"><?php echo $i; ?></td>
<td><?php echo $data->name; ?></td>
<td><?php echo $data->email; ?></td>
<td><?php echo $data->join; ?></td>
<td><?php echo $data->last_login; ?></td>
</div>
</tr>
<?php $i++; } ?>
</tbody>
<!-- // Table body END -->
</table>
Thanks for any advice.
Regards

You can use jQuery to achieve this effect quite easily. Make two files:
1) One that includes the table.
2) One that has the select tag that will reload the first file upon change of the <select> tag.
Let's call the first file select.php
<script>
// Load the div with the contents of the table.php file with no GET parameter
$('div').load('table.php');
$('select').change(function() {
var name = $(this).val();
var data = 'name='+ name;
// Make sure that the table's contents don't change if the first option tag
// is selected.
if(name != '') {
$('div').load('table.php', data);
}
});
</script>
<div class="col-md-2">
<select class="form-control selectpicker">
<option value="">Name</option>
<?php
// print all name value from $administratorProvider
foreach($administratorProvider as $administrator){
?>
<option value="<?php $administrator->first_name ?>"><?php echo $administrator->first_name; ?></option>
<?php
}
?>
</select>
</div>
File two can be called table.php
$sql = "SELECT * FROM table WHERE name = '".$name."'";
$query = mysql_query($sql)or die(mysql_error());
$num = mysql_num_rows($query);
$i = 0;
while($row = mysql_fetch_array($query)) {
// Save your info as variables
$name[$i] = $row['name'];
$email[$i] = $row['email'];
$join[$i] = $row['join'];
$login[$i] = $row['last_login'];
}
?>
<div>
<table>
<thead>
<tr>
<th class="center">No.</th>
<th>Name</th>
<th>Email</th>
<th>Join</th>
<th>Last Login</th>
</tr>
</thead>
<tbody>
<?php
for($i=0;$i<$num;$i++) {
?>
<tr>
<div>
<td class="center"><?php echo $i; ?></td>
<td><?php echo $name[$i]; ?></td>
<td><?php echo $email[$i]; ?></td>
<td><?php echo $join[$i]; ?></td>
<td><?php echo $login[$i]; ?></td>
</div>
</tr>
<?php
}
?>
</tbody>
</table>
</div>
Upon change of the select tag, the second file will be loaded with the value of the selected option tag sent to that file as a GET variable. You might wanna take the SQL part with a grain of salt as I'm not sure how you're fetching your relevant data.

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