I want to count the number of positive, neutral, negative feedbacks.
I have those 3 queries that look very much alike. Is there a way I can put all this into one query? Or is it the most concise way of doing it?
Thanks in advance, regards.
$total_positive_seller = mysql_num_rows(mysql_query("SELECT id FROM feedback
WHERE seller='$user' AND feedback='positive'"));
$total_neutral_seller = mysql_num_rows(mysql_query("SELECT id FROM feedback
WHERE seller='$user' AND feedback='neutral'"));
$total_negative_seller = mysql_num_rows(mysql_query("SELECT id FROM feedback
WHERE seller='$user' AND feedback='negative'"));
If you just want to count appearances, your use of mysql_num_rows is rather inefficient. It would be better to use the count(*) functionality of MySQL like in the following query:
SELECT feedback, count(*) AS `count`
FROM feedback
WHERE seller='$user'
GROUP BY feedback
This gives you something that should look like the following
feedback | count
----------------
positive | 12
neutral | 8
negative | 3
You can afterwards parse this like any other query-result in a row-wise fashion.
EDIT
If you want to address each entry seperatly in your following code you can use something like the following. After this code you can reference all entries, e.g., by $result['positive'].
$qres = mysql_query( 'SELECT ...' );
$result = array();
while( $row = mysql_fetch_array( $qres ) ) {
$result[ $row['feedback' ] ] = $row['count'];
}
Related
I am trying to use the selected id's as an array a other statement. It seems it is not counting all the result as it is much lower that it is.. I have tried to find my answer on google but none of the options are working for me or i do not know how to use them in my case. There are no errors and i have error log on!
Here is my code, what am i doing wrong?
$counttheid = array();
$stmt3 = $mysqli->prepare("SELECT
id
FROM account
WHERE level <= '5' AND door = ? AND `group_name` = ? AND betaald = 'Yes'");
$stmt3->bind_param("ss",$usernamesession,$groupname);
$stmt3->execute();
$result3 = $stmt3->get_result(); //only works when nd_mysli is set on the server!
while ($rowid = $result3->fetch_assoc())
{
$counttheid[] = $rowid['id'];
$countid = implode(',', $counttheid);
}
$sql = "SELECT SUM(mobcash) AS totalcash FROM account WHERE id IN (?)
";
$stmt = $mysqli->prepare($sql);
$stmt->bind_param("s",$countid);
$stmt->execute();
$stmt->bind_result($row['totalcash']);
while($stmt->fetch()) $sumcash = $row['totalcash'];
//echo print_r($counttheid);
//echo implode(',', $counttheid);
echo $sumcash;
I am no profesional developer just started learning this, any help is welcome!
Since you have edited the question, my original answer is no longer relevant.
I suggest for you to simplify your two queries into a single query. In your first query you select a bunch of ids and in the second query you sum a different value from the same table using the ids. You can just to that in one query:
SELECT SUM(mobcash) AS totalcash
FROM account
WHERE level <= '5'
AND door = ?
AND `group_name` = ?
AND betaald = 'Yes';
Original answer
You use $result->fetch_all(MYSQLI_ASSOC), meaning each row from the result set will be an associative array with the column names as the keys and the cell values as values. That is also the case, if you only select one column.
That means for this example table
id | name | balance
----+------+---------
1 | acc1 | 12.34
2 | acc2 | 1.23
your variable $dataid will have the following value (for the simplified query SELECT id FROM account):
$dataid = [
[
"id": 1
],
[
"id": 2
]
];
To get more familiar with PHP, you could write some foreach loops yourself, but you can also use the built-in PHP function array_column (php.net: array_column):
$ids = array_column($dataids, "id");
From an SQL perspective I would also suggest for you to learn about nested queries, since you could avoid this PHP logic altogether.
i want to count the different rows in CodeIgniter...
I have a table like this
NAME | ZIPCODE
Mike | 12345
Marc | 51233
TEST | 12345
Now i want a Result of "2" cause there 2 different Zipcodes.
I tried so much, but dont get this :(
$this->db->select('zipcode, count(*)');
$getAll = $this->db->get('ads');
echo $getAll->num_rows();
but dont get result of or anything... idk how i can make this.
Please help
//EDIT:
Okay i found it. Sorry for Question. Here is the Answer
$this->db->distinct();
$this->db->select('zipcode');
$getAll = $this->db->get('ads');
echo $getAll->num_rows();
you can use this:
$query = $this->db->query('select count(1) as x from your_table_name group by zipcode');
$row= $query->row();
$x = $row->x;
You could use group_by() in your query as follows.
$this->db->select('zipcode', 'count(*) as totalcount');
$this->db->group_by('zipcode');
$this->db->get('ads');
By the way, before it is mentioned, I am well aware I should be using mysqli. Thanks in advance.
This is my code:
$q5 = "select listingid FROM userlisting WHERE userid = '$_SESSION[UserID]'";
$r5 = mysql_query($q5) or die(mysql_error());
$a5 = mysql_fetch_array($r5);
The userlisting table is a 'lookup' table and has two columns:
userid and listingid
It has a many to many relationship. In other words, there could be one userid attached (associated) to multiple listingids and thus having multiple rows in that table.
e.g.
userid|listingid
1|1
1|2
1|3
2|1
etc
To keep things simple: What I want to do is check the following:
$a5['listingid'] == $_GET['id']
And if it is True I will display information and if it is False the information will not be displayed.
So on the page mywebsite.com there will be an id as so, mywebsite.com?id=[id here]. I am trying to see if the user $_SESSION[UserID] has an entry in userlisting table that matches the id of the page (well, it is a property website and the id is that of the property listing).
At the moment the code I have above just searches/checks for the first row for that userid only. In the example I gave above that would be listingid ='1' It is not seeing that row 2 and 3 also have entries in them too, listingid = '2' and '3' respectively. So on mywebsite.com?id=1 it is true, but on ?id=2 and id=3 it is coming up false, but userid = 1 has three rows with entries 1, 2 and 3.
I have been trying to find a solution for a while and I am starting to feel frustrated now. I would much appreciate it if someone could come up with a quick solution for me.
You can check both on SQL with some clause like
WHERE userid=XX AND listingid=XX
And remember to escape the get parameter ;)
PS: You can use too a while for iterate the mysql_fetch_row and search if anyone is correct. Something like:
$correct_check = false;
while($a5 = mysql_fetch_array($r5)) {
if($a5['listingid'] == $_GET['id']) $correct_check = true;
}
if($correct_check) ....
else ....
Try something like this
$page_id = $_GET['id'];
$q5 = "select listingid FROM userlisting WHERE userid = '$_SESSION[UserID]' and listingid = '$page_id' ";
$res = mysql_qury($result);
$num_rows = $mysql_num_rows($res);
if($num_rows > 0)
//your ok code
else
//fail message
When I want to find out how many shoes Alfred has, I always count the rows in the table "usershoes" where the userid matches Alfred's
But since I switched to PDO, and select row count is not simple or bulletproof/consistent, I'm reconsidering my methods
Maybe I should instead keep an int field "shoes" directly in table "users", keep number of shoes there, and then increase/decrease that number for that user along the way? Feels not right..
If anyone has a solid method for simple row counting on an existing select query, without extra query, let me know
Try something like this
SELECT COUNT(*) FROM usershoes
WHERE userid="theIdOfTheUser";
I could not get count(fetchColumn()) or fetchColumn() to work correctly (outputted 1 when 0 was the real number)
So now I'm using this, and it works:
$sql = 'SELECT COUNT(*) as numrows, shoecolor FROM usershoes WHERE userid = ?'
$STH = $conn->prepare($sql);
$STH->execute(array($someuseridvar));
And then:
$row = $STH->fetch();
if ($row['numrows'] > 0) {
// at least one row was found, do something
}
With MySQL, you can use FOUND_ROWS():
$db = new PDO(DSN...);
$db->setAttribute(array(PDO::MYSQL_USE_BUFFERED_QUERY=>TRUE));
$rs = $db->query('SELECT SQL_CALC_FOUND_ROWS * FROM table LIMIT 5,15');
$rs1 = $db->query('SELECT FOUND_ROWS()');
$rowCount = (int) $rs1->fetchColumn();
$rowCount will contain the total number of rows, not 15.
Taken from:
http://php.net/manual/en/pdostatement.rowcount.php#83586
I have the following query.
$query_assignments = "SELECT * FROM tb_scheduler_assignments
WHERE company_id = '".$company_id."' OR
dept_id = '".$dept_id."' OR
user_id = '".$user_id."' ORDER BY
due_date GROUP BY purchase_id";
What I'd like is a single query solution that would keep the results for user_id over dept_id and dept_id over company_id.
For example:
if the same purchase_id occurs for
rows that were gotten via dept_id and
user_id, then I only want the result
for the user_id;
if the same purchase_id occurs for
rows that were gotten via company_id
and user_id, then I only want the
result for the user_id
First, you're interpolating variables in your SQL, which suggests you might be vulnerable to SQL injection. Just to make sure. PHP should offer prepared statements, or some escaping function.
Second, your SQL statement won't compile because you're using GROUP BY a but selecting * which includes at least three more columns.
Third, it sounds like you're misunderstanding SQL in thinking that it might, in a query such as you're trying to formulate (without UNION ALL), retrieve duplicate rows, i.e. the same row multiple times because it matches multiple criteria. This is not so.
The "single query" solution that I was looking for doesn't seem to exist, or if it does, it would be way slower than just handling all the sorting in php.
So, I ran 3 separate queries, put each of them into arrays, and then in order to put them all into a final array with the hierarchy that I needed, I did the loops below to see if the purchaseID existed for the levels up the hierarchy. If it didn't, then I put it in to the array.
$finalArray = array();
foreach ($companyArray as $purchaseID => $companyData) {
if (empty($deptArray[$purchaseID]) && empty($userArray[$purchaseID])) {
$finalArray[] = $companyData;
}
}
foreach ($deptArray as $purchaseID => $deptData) {
if (empty($userArray[$purchaseID])) {
$finalArray[] = $deptData;
}
}
foreach ($userArray as $purchaseID => $userData) {
$finalArray[] = $userData;
}
Then I can sort that array however I want and loop through that to echo what I need to.
Not sure if that's the best way, but it worked well and is lightning fast for me.
$query_assignments = "SELECT *,
IF(user_id = {$user_id}, 30,
IF(dept_id = {$dept_id}, 20,
IF(company_id = {$company_id}, 10, 0)
)
) as priority
FROM tb_scheduler_assignments
WHERE company_id = {$company_id} OR
dept_id = {$dept_id} OR
user_id = {$user_id}
GROUP BY purchase_id
ORDER BY due_date, priority DESC";
You can make a virtual field with the if statement.
user_id: 30 pts
dept_id: 20 pts
company_id: 10 pts
else: 0 pts
WARNING: can not be Indexed!
Syntax FIX: GROUP BY and ORDER BY reordered