While loop within a while loop - php

Question

I have one table which contains events and dates, and another which contains the guestlist for each of these nights. I can print the nights like so:
$day = date("l");
$date = getFullDateString($day);
$result = mysql_query("SELECT * FROM nights WHERE day = '$day' AND promoter = 'blah'") or die(mysql_error);
while ($row = mysql_fetch_array($result)) {
echo "<h2>";
echo $row[name];
echo " (";
echo getFullDateString($row[day]);
echo ")</h2>";
}
The problem is that for each of these events I want the guestlist to be printed below it. I've tried putting another while loop inside, but even the test echo doesn't work.
$result2 = mysql_query("SELECT DISTINCT guest FROM guestlists WHERE night = '$row[name]' AND date = 'getFullDateString($row[day])'") or die(mysql_error ());
while($row2 = mysql_fetch_array($result2)) {
echo $row2[0];
echo "test";
echo "<br />";
}
Essentially I want the following:
Event 1
Name 1
Name 2
Name 3
Event 2
Name 1
Name 2
Name 3

Answer 1

You have a method inside the query string which won't be run.
Try:
$sql = "SELECT DISTINCT guest FROM guestlists WHERE night = '".$row['name']."' AND `date` = '".getFullDateString($row['day'])."'"
Also, date is a reserved word in MySQL and should be encapsulated within backticks or changed to something else.
Additionally, the mysql_ functions are being deprecated and it is recommended to replace them with PDO or MySQLi.

Answer 2

Take a look at Complex (curly) syntax for string parsing to learn the proper way to embed your variables in the string.

Answer 3

Try this...
$result = mysql_query("SELECT * FROM nights WHERE day = '".$day."' AND promoter = 'blah'") or die(mysql_error);
while ($row = mysql_fetch_array($result)) {
echo "<h2>".$row[cname]."</h2>";
$result2 = mysql_query("SELECT DISTINCT guest FROM guestlists WHERE night = '$row[name]' AND date = '".getFullDateString($row[day])."'") or die(mysql_error);
while ($row2 = mysql_fetch_array($result2))
{
echo $row2[cname];
}
}