Display image using absolute path - php

Question

I am using uploadify to upload img to server at the time of upload i saved absolute path to the data base its like:
/var/www/html/workbench/photogallery/uploads/logo2.jpg
now I want to display the same in browser the following method does not work
<div id="photos">
<h3>Photo title</h3>
<P class="like">Like </P>
<p class="date">date </p>
<p class="pclear" />
<div id="image">
<img src="<?php echo $result_set['path']; ?>" />
</div>
<p class="about">about image goes here</p>
</div>
above code doesn't work. when I edit the path manually to uploads/logo2.jpg it works perfectly
how can I resolve this problem?

Answer 1

You need to use an url, not a path.
This:
/var/www/html/workbench/photogallery/uploads/logo2.jpg
is a physical path, the address on that server where the image is found. You need to use an url available for your visitors. I guess that you have a name mapped to that server (something like localhost or www.example.com).
From the structure I guess that your url would be something like
http://www.example.com/photogallery/uploads/logo2.jpg
where www.example.com is the base url you are using to get to that application

Answer 2

Try this:
<img src="/photogallery/uploads/<?php echo basename($result_set['path']) ?>" />

Answer 3

Try this it works for me and keeps the location of the images hidden from the browser.
<img src='fake.php' style='max-width:90px;'/>
Create a file called fake.php as follows
<?php
$thePic = "/var/www/html/workbench/photogallery/uploads/logo2.jpg";
$image = imagecreatefromjpeg($thePic);
// Output image and free up the memory
header("Content-type: image/jpeg");
imagejpeg($image);
imagedestroy($image);
?>
You can adjust the code in the fake.php file to retrieve the location of $thePic from posted data or database, etc.