Online SQL work with local page but not online page - php

I created a page in PHP
The database is connected online, so when I run the site local / but the sql database connected online
everything works good. But as soon as I run the page Online, and tries to do anything with the database it says
The website encountered an error while retrieving http://www..... It
may be down for maintenance or configured incorrectly.
So I understands that something is wrong, but I cant seem to understand why I can upload things to my SQL database when I drive the page localy.
Any tips on what I should be thinking on ?
I Will add my upload.php file
the thing is that even if i delete my include('/core/inc/init.inc.php'); file.
Its still get the same error. so its must be something with my query's ?
This is my code.
<?php
// Connects to your Database
include('/core/inc/init.inc.php');
if($_FILES['file_name'])) {
$file_name = mysql_real_escape_string($_FILES['file_name']['name']);
//Writes the information to the database
mysql_query("INSERT INTO `files` (`file_name`) VALUES ('$file_name')") ;
move_uploaded_file($_FILES['file_name']['tmp_name'], "core/files/{$_FILES['file_name']['name']}");
}
// sid antal
$page = ($_GET['page'])) ? (int)$_GET['page'] : 1;
//Retrieves data from MySQL
$data = mysql_query("SELECT * FROM files") or die(mysql_error());
//Puts it into an array
$files = mysql_query("SELECT * FROM files") or die(mysql_error());
/*pagination */
$per_page = 5;
$pages_query = mysql_query("SELECT COUNT('user_id') FROM files");
$pages = ceil(mysql_result($pages_query, 0) /$per_page);
$page = ($_GET['page'])) ? (int)$_GET['page'] : 1;
$start = ($page - 1) * $per_page;
/*pagination */
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>Pixeltouch</title>
<link rel="stylesheet" type="text/css" href="ext/style.css" />
</head>
<body>
<div id="page-wrap">
<div id="main-content">
<br/>
<?php include_once('template/head.inc.php');
?>
<div id="menu">
<?php include_once('template/nav.inc.php');
?>
</div>
<!-- SKRIVBOX-->
<div>
<form enctype="multipart/form-data" action="" method="post">
<p>
<input type="file" name="file_name" /><br/>
</p>
<p>
<input type="submit" value="Add" />
</p>
</form>
<!-- Listan -->
</div>
<!--Pagination-->
<?php
$data = mysql_query("SELECT * FROM files LIMIT $start, $per_page")
or die(mysql_error());
echo "<table border cellpadding=1>";
while($info = mysql_fetch_array( $data ))
{ ?><?php
echo "<tr>";
// echo "<td>".$info['user_id'] . "</td> ";
echo "<td>".$info['user_name'] . "</td> ";
echo "<td>".$info['file_name'] . "</td> ";
?>
<td> <?php echo $info['file_name']; ?></td>
<?php
echo "<td>".date('d/m/Y') . "</td>" ;
}
echo "</tr>";
echo "</table>";
if($pages >= 1 && $page <=$pages){
for ($x = 1; $x<=$pages; $x++){
echo ($x == $page) ? '<strong>' .$x. ' </strong>' : '' .$x. ' ';
}
}
?>
<!--Pagination-->
<!--PAGINATION-->
<!-- SKRIVBOX END-->
</div>
<?php include_once('template/foot.inc.php');
?>
</div>
</body>
</html>
Init.inc.php file
<?php
session_start();
mysql_connect("server", "username", "password") or die(mysql_error()) ;
mysql_select_db("pixeltouch2") or die(mysql_error()) ;
$path = dirname(__FILE__);
include("{$path}/user.inc.php");
?>
<!--Registration/Login (START)-->
<?php
$exceptions = array('register', 'login', 'user_list', 'profile', 'edit_profile');
$page = substr(end(explode('/', $_SERVER['SCRIPT_NAME'])), 0, -4);
if(in_array($page, $exceptions) == false){
if (isset($_SESSION['username']) == false){
header('Location: login.php');
die();
}
}
?>
<!--Registration/Login (END)-->
<!--User Profile (START)-->
<?php
$_SESSION['uid'] = 1;
?>
<!--User Profile (END)-->


Make sure you have something like this:
mysql_connect($server, $username, $password)
in your /core/inc/init.inc.php.


Well this is the error message i get Can't connect to local MySQL server through socket '/var/run/mysqld/mysqld.sock' (2) – Felipe Otarola 1 hour ago
Felipe try start/restart your mysql server:
sudo service mysql start // ubuntu
sudo service mysqld start // centos
EDIT 1
Try this:
if ($_SERVER['HTTP_HOST'] != 'localhost') // running in remote server
$server = 'localhost';
else // running locally
$server = 'your-online-database-server-address';
mysql_connect($server, "username", "password") or die(mysql_error());

Related

link to mysql single record from search with pagination

I am trying to link through to the single row record information in my mysql database from my search using php/ajax_pagination and the code that I am trying to get to work is:
<div id="posts_content">
<?php
//Include pagination class file
include('Pagination.php');
//Include database configuration file
include('dbConfig.php');
$limit = 3;
//get number of rows
$queryNum = $db->query("SELECT COUNT(*) as postNum FROM posts");
$resultNum = $queryNum->fetch_assoc();
$rowCount = $resultNum['postNum'];
//initialize pagination class
$pagConfig = array(
'totalRows' => $rowCount,
'perPage' => $limit,
'link_func' => 'searchFilter'
);
$pagination = new Pagination($pagConfig);
//get rows
$query = $db->query("SELECT * FROM posts ORDER BY id DESC LIMIT $limit");
if($query->num_rows > 0){ ?>
<div class="posts_list">
<?php
while($row = $query->fetch_assoc()){
$postID = $row['id'];
?>
<div class="list_item"><h2><?php echo $row["title"]; ?></h2></div>
<?php } ?>
</div>
<?php echo $pagination->createLinks(); ?>
<?php } ?>
</div>
There is obviously something wrong with my href link:
<h2><?php echo $row["title"]; ?></h2>
OR my file.php page:
<?php
// GET ID FROM THE URL
$id = $_GET['id'];
?>
<!DOCTYPE HTML>
<html lang="en">
<head>
<title>Ajax Pagination with Search and Filter in PHP</title>
<link href='style.css' rel='stylesheet' type='text/css'>
<script src="jquery.min.js"></script>
<script type="text/javascript"></script>
</head>
<body>
<?php
$sql =mysql_query("select * from posts where id='".$id."'");
while($row = mysql_fetch_array($sql)){
?>
<tr>
<th>title:</th>
<th>created:</th>
<th>modified:</th>
<th>statusr:</th>
</tr>
<tr>
<td><?=$row['title']?></td>
<td><?=$row['created']?></td>
<td><?=$row['modified']?></td>
<td><?=$row['status']?></td>
</tr>
<?php
}
?>
But I cannot understand why as everything else seems to be working fine, maybe I have been looking at this to long and missed something blatently obvious... but any help would be greatly appreciated.

Use Below Code:
<div class="list_item"><h2><?php echo $row["title"]; ?></h2></div>

What's wrong with this simple php code querying a database and displaying results?

This is simply additional functionality for an assignment where I have created a water level monitor device. All I want the web page to do is display a couple of SQL results. However, none of the PHP in the page seems to run at all. I have tested the SQL statements and they work fine so it is definitely my PHP. Any help would be appreciated, cheers!
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns='http://www.w3.org/1999/xhtml' xml:lang='cs' lang='cs'>
<head>
<meta http-equiv="content-type" content="text/html; charset=UTF-8" />
<meta http-equiv='Content-Language' content='cs' />
<link rel="stylesheet" href="styl.css" type="text/css" />
<title>Flood Detector</title>
<?php
error_reporting(E_ALL); ini_set('display_errors', 1);
$con=mysqli_connect("");
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
?>
</head>
<body>
<div id="header">
<h2>Flood Detector</h2>
<ul id="menu-top">
<li>Home</li>
<li>Records</li>
</ul>
</div>
<div id="contain">
<div id="left">
<h1>Welcome</h1>
<p> Your water levels are currently <?php
$sql = "SELECT BODY FROM sms ORDER BY ID DESC LIMIT 1";
$result = mysqli_query($con, $sql)
or die(mysqli_error($con));
while($row = mysqli_fetch_array($result)){
print_r($row);
?></p>
<br>
<br>
<p> Your water has reached dangerous levels <?php
if ($dangerresult = mysqli_query($con, "SELECT * FROM sms WHERE BODY = ' warning'")) {
$count = mysqli_num_rows($dangerresult);
echo $count;
}
?>
times
</p>
</div>
<div class="cleaner"></div>
</div>
</body>
</html>

Firstly, you need to pass DB connection to your queries.
You also have a space in ' warning' so that may cause problems; remove it 'warning' if you're not getting results with my answer/code below.
$sql = "SELECT BODY FROM sms ORDER BY ID DESC LIMIT 1";
$result = mysqli_query($con,$sql);
echo $result;
Sidenote: I don't know why you're doing echo $result; so you may need to elaborate on that.
Or try something like:
while($row = mysqli_fetch_array($result))
{
echo "Your water levels are currently " . $row['BODY'];
echo "<br>";
}
and $mysqli_query that is a function not a variable.
In regards to mysqli_num_rows(), try using it this way, since you want to check if num_rows() does return a value as per the word you're looking for, being "warning".
$dangerresult = mysqli_query($con, "SELECT * FROM sms WHERE BODY = ' warning'");
$count = mysqli_num_rows($dangerresult);
if($count > 0){
echo $count;
}
else{
echo "Empty.";
}
Edit:
Or try:
$dangerresult = mysqli_query($con, "SELECT * FROM sms WHERE BODY = 'warning'");
$count = mysqli_num_rows($dangerresult);
if($count > 0){
echo $count;
}
else{
echo "Empty.";
}
while($row = mysqli_fetch_array($dangerresult))
{
echo "Your water levels are currently " . $row['BODY'];
echo "<br>";
}
Also add or die(mysqli_error($con)) to all the mysqli_query() and error reporting.
Plus, in regards to SQL injection, use mysqli with prepared statements, or PDO with prepared statements, they're much safer.

There's many problems with that code.
First, you need to pass your $con arround, the mysqli_query function needs to know what connection you're referring to, check the manual page for mysqli_query().
Then there's also the line if ($dangerresult = $mysqli_query(..., where you're referring to mysqli_query as a variable.
Also,
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
Is lacking a closing bracket, so the rest of the script is only executed in case of error (and it's a syntax error too).

You did not use mysqli_select_db and mysqli_fetch_array function to fetch data. Please try this :
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns='http://www.w3.org/1999/xhtml' xml:lang='cs' lang='cs'>
<head>
<meta http-equiv="content-type" content="text/html; charset=UTF-8" />
<meta http-equiv='Content-Language' content='cs' />
<link rel="stylesheet" href="styl.css" type="text/css" />
<title>Flood Detector</title>
<?php
$con=mysqli_connect("*****************","*********","********","***********");
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
?>
</head>
<body>
<div id="header">
<h2>Flood Detector</h2>
<ul id="menu-top">
<li>Home</li>
<li>Records</li>
</ul>
</div>
<div id="contain">
<div id="left">
<h1>Welcome</h1>
<p> Your water levels are currently <?php
$sql = "SELECT BODY FROM sms ORDER BY ID DESC LIMIT 1";
$result = mysqli_query($sql);
//echo $result;
while($row = mysqli_fetch_array($result)){
print_r($row);
}
?></p>
<br>
<br>
<p> Your water has reached dangerous levels <?php
if ($dangerresult = mysqli_query("SELECT * FROM sms WHERE BODY = ' warning'")) {
$count = mysqli_num_rows($dangerresult);
echo $count;
}
?>
times
</p>
</div>
<div class="cleaner"></div>
</div>
</body>
</html>

PHP and HTML not updating the page with onchange

So basically I have a page built with php inline with html. When I select a new option from my dropdown or enter a new value in a text box I need it to change. I had this working when I was echoing all my HTML in php (noobish mistake I know) but now that I attempted to clean it up it seems to have stop working. Also all my database connections are working just fine so Im not sure whats going on. Full code listed below. Thanks for any help at all and please remember I am a bit new to this.
<!doctype html>
<html lang="en">
<head>
<meta charset="utf-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge,chrome=1">
<title>Megapixel Calculator</title>
<meta name="Megapixel Calculator" content="">
<meta name="Matthew Stair" content="">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<link rel="stylesheet" href="style.css">
</head>
<body style="background:#99CCFF;overflow:hidden;">
<?php
$host = "localhost";
$username = "root";
$pass = "";
$database = "database_camcalc";
$conn = mysql_connect($host, $username, $pass) or die (mysql_error());
mysql_select_db($database, $conn);
$query = "SELECT camera FROM camlist";
$result = mysql_query($query) or die (mysql_error());
if (isset($_POST['cameraDD']))
{
$camSelect = $_POST['cameraDD'];
}else{
$camSelect = 'SNV-5200';
}
$horiQuery = mysql_query("SELECT hori FROM camlist WHERE camera = '$camSelect'");
if (!$horiQuery) {
die("Failed: " . mysql_error());
}
$hori = mysql_fetch_row($horiQuery);
$sensorSize = mysql_query("SELECT sensor_size FROM camlist WHERE camera = '$camSelect'");
if (!$sensorSize) {
die("Failed: " . mysql_error());
}
$sensorQuery = mysql_query("SELECT camlist.width FROM camlist WHERE camlist.camera = '$camSelect'");
$sensorRow = mysql_fetch_array($sensorQuery);
$sensorWidth = floatval($sensorRow['width']);
if(isset($_POST['horizontalFOV'])){
if($_POST['horizontalFOV'] != 0){
$horiFOV = $_POST['horizontalFOV'];
}else{
$horiFOV = 20;
}
}else{
$horiFOV = 20;
}
if(isset($_POST['distToObj'])){
if($_POST['distToObj'] != 0){
$distObj = $_POST['distToObj'];
}else{
$distObj = 35;
}
}else{
$distObj = 35;
}
$lensCalc = ($distObj / $horiFOV) * $sensorWidth;
$lensCalcFix = number_format($lensCalc);
$ppfCalc = $hori[0] / $horiFOV;
?>
<div style="width:1000px; margin:auto;">
<div style="width:50%;float:left;">
<div style="float:left; width:100%;">
<?php
print("Select Camera: <select name='cameraDD' value='$camSelect' onchange='this.form.submit()'>");
while($row = mysql_fetch_assoc($result)) {
if($row['camera'] == $camSelect)
print("\r\n<option selected='selected' value='{$row['camera']}'>{$row['camera']}</option>");
else
print("\r\n<option value='{$row['camera']}'>{$row['camera']}</option>");
}
?>
</select>
</div>
<div style="float:left;width:50%;">
Lens Focal Length: <?php print("$lensCalcFix"); ?> MM
</div>
<div style="float:left;width:50%;">
<?php
print("Horizontal Field of View: <input style='width:50px;' type='text' name='horizontalFOV' value='$horiFOV' onchange='this.form.submit()'>");
?>
</div>
<img style="width:100%" src="/images/example.gif" alt="Example of horizontal field of view and distance to object">
<div>
<?php
print("Distance to Object: <input style='width:50px;' type='text' name='distToObj' value='$distObj' onchange='this.form.submit()'> Feet");
?>
</div>
</div>
<div style="width:40%;float:left;margin-left:10px;">
<div>
<?php
echo 'Pixels per Foot: ',
round($ppfCalc),
' PPF';
?>
</div
<div>
<?php
if ($ppfCalc < 19){
echo "<p style ='font-weight:bold;'>Level of detail: Too Low</p>";
echo "<img src='images/noimg.gif' alt='Pixel Per Foot Too Low'>";
}elseif ($ppfCalc >= 19 and $ppfCalc <=39){
echo "<p style ='font-weight:bold;'>Level of detail: Observation</p>";
echo "<img src='images/20ppf.gif' alt='Observation Level'>";
}elseif ($ppfCalc >=40 and $ppfCalc <=59){
echo "<p style ='font-weight:bold;'>Level of detail: Forensic Review</p>";
echo "<img src='images/40ppf.gif' alt='Forensic Review Level'>";
}elseif ($ppfCalc >=60 and $ppfCalc <=79){
echo "<p style ='font-weight:bold;'>Level of detail: Identification</p>";
echo "<img src='images/75ppf.gif' alt='Identification Level'>";
}elseif ($ppfCalc >=80){
echo "<p style ='font-weight:bold;'>Level of detail: Fine</p>";
echo "<img src='images/100ppf.gif' alt='Fine Level'>";
}
?>
<div style="width:300px;">
<p style="text-decoration:underline;font-weight:bold;">Observation (General Security) = 20 PPF</p>
<p> Allows for recognition of male/female, color of clothes, approximate height, color of skin, etc...</p>
<p style="text-decoration:underline;font-weight:bold;">Forensic Review (forensic detail)= 40 PPF</p>
<p>Allows for basic identification of forensic details</p>
<p style="text-decoration:underline;font-weight:bold;">Identification (high detail)= 60 PPF</p>
<p>Allows for facial recognition, point-of-sale tracking, etc...</p>
<p style="text-decoration:underline;font-weight:bold;">Fine = 80 PPF</p>
<p>Allows for detailed facial recognition such as license plate number, scars, birth marks, eye color, tattoos, etc...</p>
</div>
</div>
</div>
</div>
</body>
</html>

How to increase the pagination speed

In my project I have done a pagination using PHP, I have done it as follows:
Each buttons(NEXT PAGE and PREVIOUS PAGE) are hyperlinks which links to the same page with passing a GET variable (PAGENUMBER). For each page change, there are scripts for
connect to DB .
query for the data for the specified page.
close the
DB connection. displays the data.
The problem is that it is working slowly. Is there any alternative method for each time connect to db and query for the data and close db connection.
Also During the pagination I want to reload only the datas from DB and all other contents in page remains the same and dont want to reload. How to achieve this?
The script is given below
<?php
require_once("./include/membersite_config.php"); //include files for login system
if($fgmembersite->CheckLogin())
{
$login=true;
}
else
{
$login=false;
}
require_once("db.php");
$con=connect(); //connect to db and select the db
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<HTML>
<HEAD>
<TITLE> Gallery </TITLE>
<META name="generator" content="Adobe Photoshop(R) CS Web Photo Gallery">
<META http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<link href="images/galleryStyle.css" rel="stylesheet" type="text/css">
<link rel="STYLESHEET" type="text/css" href="style/new.css" />
</HEAD>
<body marginheight=0 marginwidth=0 leftmargin=0 topmargin=0>
<table><tr>
<?php
//////////////////DISPLAYING IMAGE THUNBNAILS//////////////////////
$query="SELECT COUNT(*) FROM gallery ";
$res = query($query);
$raw=mysql_fetch_array($res);
$imagecount=$raw[0];
if($imagecount==0) { die ("No images found"); }
$pagecount=ceil($imagecount/15);
$page = isset($_GET['page']) ? mysql_real_escape_string($_GET['page']) : 1;
if (isset($_GET['page']))
{
if (!(ctype_digit($_GET['page']) and $_GET['page']>0 and $_GET['page']<=$pagecount))
{
die ("You are not autorised to viw this page");
}
}
$start= ($page*15)-15;
$query = "SELECT * FROM gallery ORDER BY imageid DESC LIMIT $start , 15";
$res = query($query);
$count= mysql_num_rows($res);
$index=0;
for($i=1;$i<=3;$i++)
{
?>
<TR>
<?php
for($j=1;$j<=5;$j++)
{
if(!$raw=mysql_fetch_array($res)) {break;}
$index++;
$imageid=$raw['imageid'];
$thumbpath= $raw['thumbpath'];
$largepath=$raw['largepath'];
$caption=$raw['caption'];
?>
<A name=1 href="image.php?imageid=<?php echo $imageid ?>&imageindex=<?php echo ((($page-1)*15)+$index-1) ; ?> "><IMG border=0 src="<?php echo $thumbpath; ?>" height="75" width="75" alt="<?php echo $caption ?>" title="<?php echo $caption ?>" ></A><BR>
<?php
echo "<a href='delete.php?delete=yes&imageid=".$imageid.'&page='.$page."'>Delete </a>"
echo "<a href='replace.php?update=yes&imageid=".$imageid.'&page='.$page."'>Replace </a>"
?>
</table>
</td>
<?php } ?>
</TR>
<?php
}
if ($page!=1)
{
?>
<td width=17><IMG SRC="images/previous.gif" BORDER=0></td>
<?php } ?>
<td align=middle class="pagenums"><?php echo "page ".$page." of ".$pagecount ?></td>
<?php
if ($page!=$pagecount)
{
?>
<td align=right width=17><img border=0 src="images/next.gif"></td>
<?php } ?>
</table>
</body>
</html>

There are lot much options available
go with javascript pagination
ajax pagination
try to reduce pagination code(optimized code)

You do not need to connect/close db for each page change

use the ajax script for connecting and getting database values with reloading the current page you can do it -- -- -- --- -- -- try ajax

Set Page Title using PHP

I wish to set the title of my webpage to Ultan.me - Whatever the post title. I want it to display the post title. The posts are submitted to a MySQL database and the title row is called "title". Any help is appreciated with this small question.
Update:
Here is the page itself now but it doesn't display the title. Should I open the php document and connect to my database somewhere different to it's current locations?
The Code (The only necessary piece is the beginning):
<html>
<head>
<meta name="keywords" content="Mac user Ultan Casey TheCompuGeeks UltanKC">
<title>Ultan.me - <?echo $title;?></title>
<link rel="stylesheet" href="css/styles.css" type="text/css" />
<script type="text/javascript"
src="http://ajax.googleapis.com/ajax/libs/jquery/1.2.6/jquery.min.js"></script>
<script type="text/javascript"
src="js/jquery.labelify.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$(":text").labelify();
});
</script>
<style>
a {text-decoration:none}
</style>
</head>
<body>
<div id="main">
<!-- Menu Start -->
<div id="menu">
<ul>
<li>home</li>
<li>about me</li>
<li>archives</li>
<li>contact</li>
<li>gallery</li>
</ul>
</div>
<!-- Menu End -->
<img src="images/banner.png" />
<div id="content">
<div id="posts">
<?php
mysql_connect ('localhost', 'root', 'root') ;
mysql_select_db ('ultankc');
if (!isset($_GET['id']) || !is_numeric($_GET['id'])) {
die("Invalid ID specified.");
}
$id = (int)$_GET['id'];
$sql = "SELECT * FROM php_blog WHERE id='$id' LIMIT 1";
$result = mysql_query($sql) or print ("Can't select entry from table php_blog.<br />" . $sql . "<br />" . mysql_error());
while($row = mysql_fetch_array($result)) {
$date = date("l F d Y", $row['timestamp']);
$title = stripslashes($row['title']);
$entry = stripslashes($row['entry']);
$get_categories = mysql_query("SELECT * FROM php_blog_categories WHERE `category_id` = $row[category]");
$category = mysql_fetch_array($get_categories);
?>
<p><?php echo "<p id='post-title'><strong>" . $title . "</strong></p>"; ?><br /><br />
<div id="entry"><?php echo $entry; ?>
</div><br /><br />
<p id="date">Posted in <?php echo $category['category_name']; ?> on <?php echo $date; ?></p>
</p>
<h2 id="share-title">Share This Post</h2>
<div id="social-share">
<li id="link-right"><a href="http://twitter.com/home?status=
I just read <?php echo $title; ?> at http://ultan.me/post.php?id=<?php echo $id; ?>"><center>Twitter</center></a></li>
<li id="link-left"><center>Digg</center></li>
<br>
<li id="link-right"><center>Facebook</center></li>
<li id="link-left"><a href="http://www.google.com/buzz/post?url=http://ultan.me/post.php?id=<?php echo $id; ?>
"><center>Google Buzz</center></a></li>
<div class="clr"></div>
</div>
<h2 id="comments-title">Comments</h2>
<div id="comment-list">
<?php
}
$commenttimestamp = strtotime("now");
$sql = "SELECT * FROM php_blog_comments WHERE entry='$id' ORDER BY timestamp";
$result = mysql_query ($sql) or print ("Can't select comments from table php_blog_comments.<br />" . $sql . "<br />" . mysql_error());
while($row = mysql_fetch_array($result)) {
$timestamp = date("l F d Y", $row['timestamp']);
printf("<div class='comment-ind'><p id='comments'><a id='username' href=\"%s\">%s</a> %s</p>", stripslashes($row['url']), stripslashes($row['name']), $timestamp);
print("<p class='comments'>" . stripslashes($row['comment']) . "</p><div class='clr'><br></div></div>");
}
?>
<div class="clr"></div>
<form id="commentform" method="post" action="process.php">
<p><input type="hidden" name="entry" id="entry" value="<?php echo $id; ?>" />
<input type="hidden" name="timestamp" id="timestamp" value="<?php echo $commenttimestamp; ?>">
<input type="text" name="name" id="name" title="Name (required)" /><br />
<input type="text" name="email" id="email" title="Mail (will not be published) (required)" /><br />
<input type="text" name="url" id="url" title="Website" value="http://" /><br />
<br />
<textarea title="Your Comment Goes Here" name="comment" id="comment"></textarea></p>
<p><input type="submit" name="submit_comment" id="submit_comment" value="Add Comment" /></p>
</form>
</div>
<div id="pages">
<?php
$total_results = mysql_fetch_array(mysql_query("SELECT COUNT(*) AS num FROM php_blog"));
$total_pages = ceil($total_results['num'] / $blog_postnumber);
if ($page > 1) {
$prev = ($page - 1);
echo "<< Newer ";
}
for($i = 1; $i <= $total_pages; $i++) {
if ($page == $i) {
echo "$i ";
}
else {
echo "$i ";
}
}
if ($page < $total_pages) {
$next = ($page + 1);
echo "Older >>";
}
?>
</div>
</div>
</div>
<!-- Sidebar Start -->
<div class="sidebar">
<!-- Item 1 -->
<div id="side-item">
<h2>
<a href="http://www.dailybooth.com/UltanCasey">
<img src="images/db-icon.jpg">Dailybooth
</a></h2>
<div id="side-item-content">
<center>
<img src="http://dailybooth.com/UltanCasey/latest/medium.jpg" />
</center>
</div>
</div>
<!-- Item 2 -->
<div id="side-item">
<h2><img src="images/connect.jpg" />Connect</h2>
</div>
<div id="side-item-content">
<div class="tweet-title"><p>Latest Tweet:</p></div>
<div id="tweet">
<?php
function getTwitterStatus($userid){
$url = "http://twitter.com/statuses/user_timeline/$userid.xml?count=1";
function auto_link_twitter ($text)
{
// properly formatted URLs
$urls = "/(((http[s]?:\/\/)|(www\.))?(([a-z][-a-z0-9]+\.)?[a-z][-a-z0-9]+\.[a-z]+(\.[a-z]{2,2})?)\/?[a-z0-9._\/~#&=;%+?-]+[a-z0-9\/#=?]{1,1})/is";
$text = preg_replace($urls, " <a href='$1'>$1</a>", $text);
// URLs without protocols
$text = preg_replace("/href=\"www/", "href=\"http://www", $text);
// Twitter usernames
$twitter = "/#([A-Za-z0-9_]+)/is";
$text = preg_replace ($twitter, " <a href='http://twitter.com/$1'>#$1</a>", $text);
// Twitter hashtags
$hashtag = "/#([A-Aa-z0-9_-]+)/is";
$text = preg_replace ($hashtag, " <a href='http://hashtags.org/$1'>#$1</a>", $text);
return $text;
}
$xml = simplexml_load_file($url) or die("could not connect");
foreach($xml->status as $status){
$text = $status->text;
}
echo auto_link_twitter ($text);
}
getTwitterStatus("UltanKC");
?>
</div>
<br>
<ul>
<li id="social">YouTube</li>
<li id="social">Twitter</li>
<li id="social">LastFM</li>
<li id="social">Email</li>
</ul>
</div>
<!-- Item 2 End-->
<div id="side-item">
<h2><img src="images/archive.jpg" />Archives</h2>
</div>
<div id="archive-side">
<?php
mysql_connect ('localhost', 'root', 'root') ;
mysql_select_db ('ultankc');
$result = mysql_query("SELECT FROM_UNIXTIME(timestamp, '%Y') AS get_year, COUNT(*) AS entries FROM php_blog GROUP BY get_year");
while ($row = mysql_fetch_array($result)) {
$get_year = $row['get_year'];
$entries = $row['entries'];
echo "<li id='tag'>Entries from " . $get_year . " (" . $entries . ")<br /></li>";
}
$result1 = mysql_query("SELECT * FROM php_blog_categories ORDER BY category_name ASC");
while($row = mysql_fetch_array($result1)) {
$result2 = mysql_query("SELECT COUNT(`id`) AS entries FROM php_blog WHERE category = $row[category_id]");
$num_entries = mysql_fetch_array($result2);
echo '<li id="tag">' . $row['category_name'] . ' (' . $num_entries['entries'] . ')</li>';
}
?>
</div>
</div>
<div class="clr" />
</div>
<!-- Sidebar End -->
<div id="footer">
<p> © Ultan Casey 2010</p>
<p style="margin-top: -18px; float:right">Home | About Me | Email Me</p>
</div>
</div>
</div>
</body>
</html>
?>

Here's the method I use (for similar things, not just title):
<?
ob_start (); // Buffer output
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en">
<head>
<title><!--TITLE--></title>
</head>
<body>
<?
$pageTitle = 'Title of Page'; // Call this in your pages' files to define the page title
?>
</body>
</html>
<?
$pageContents = ob_get_contents (); // Get all the page's HTML into a string
ob_end_clean (); // Wipe the buffer
// Replace <!--TITLE--> with $pageTitle variable contents, and print the HTML
echo str_replace ('<!--TITLE-->', $pageTitle, $pageContents);
?>
PHP usually works be executing any bits of code and printing all output directly to the browser. If you say "echo 'Some text here.';", that string will get sent the browser and is emptied from memory.
What output buffering does is say "Print all output to a buffer. Hold onto it. Don't send ANYTHING to the browser until I tell you to."
So what this does is it buffers all your pages' HTML into the buffer, then at the very end, after the tag, it uses ob_get_contents () to get the contents of the buffer (which is usually all your page's HTML source code which would have been sent the browser already) and puts that into a string.
ob_end_clean () empties the buffer and frees some memory. We don't need the source code anymore because we just stored it in $pageContents.
Then, lastly, I do a simple find & replace on your page's source code ($pageContents) for any instances of '' and replace them to whatever the $pageTitle variable was set to. Of course, it will then replace <title><!--TITLE--></title> with Your Page's Title. After that, I echo the $pageContents, just like the browser would have.
It effectively holds onto output so you can manipulate it before sending it to the browser.
Hopefully my comments are clear enough.
Look up ob_start () in the php manual ( http://php.net/ob_start ) if you want to know exactly how that works (and you should) :)

You parse the field from the database as usual.
Then let's say you put it in a variable called $title, you just
<html>
<head>
<title>Ultan.me - <?php echo htmlspecialchars($title);?></title>
</head>
EDIT:
I see your problem. You have to set $title BEFORE using it. That is, you should query the database before <title>...

header.php has the title tag set to <title>%TITLE%</title>; the "%" are important since hardly anyone types %TITLE% so u can use that for str_replace() later. then, you use output buffer like so
<?php
ob_start();
include("header.php");
$buffer=ob_get_contents();
ob_end_clean();
$buffer=str_replace("%TITLE%","NEW TITLE",$buffer);
echo $buffer;
?>
For more reference, click PHP - how to change title of the page AFTER including header.php?

What about using something like:
<?php
$page_title = "Your page tile";
include("navigation.php"); // if required
echo("<title>$page_title</title>");
?>

Move the data retrieval at the top of the script, and after that use:
<title>Ultan.me - <?php echo htmlspecialchars($title, ENT_QUOTES, 'UTF-8'); ?></title>

You need to set the value of $title before echoing it.
Also, you should really sanitize any data before using it in queries as this is a security risk

create a new page php and add this code:
<?php
function ch_title($title){
$output = ob_get_contents();
if ( ob_get_length() > 0) { ob_end_clean(); }
$patterns = array("/<title>(.*?)<\/title>/");
$replacements = array("<title>$title</title>");
$output = preg_replace($patterns, $replacements,$output);
echo $output;
}
?>
in <head> add code: <?php require 'page.php' ?> and on each page you call the function ch_title('my title');

The problem is that $title is being referenced on line 5 before it's being assigned on line 58. Rearranging your code isn't easy, because the data is both retrieved and output at the same time. Just to test, how does something like this work?
Because you're only retrieving one row, you don't need to use a while loop, but I left it with hopes that it'll make it easier for you to relate to your current code. All I've done is removed the actual output from your data retrieval, and added variables for category and category name which are then referred to as usual later on. Also, I haven't tested this. :)

It'll be tricky to rearrange your code to make this work, but I'll try :)
So, put this at the top of your code:
<?php require_once('mysql.php'); ?>
The top of the file should look like:
<?php require_once('mysql.php'); ?>
<html>
<head>
<meta name="keywords" content="Mac user Ultan Casey TheCompuGeeks UltanKC">
<title>Ultan.me - <?php echo htmlspecialchars($title); ?> </title>
Then, create a file called mysql.php in the same directory that the file which contains the code you quoted is in.
Put this is mysql.php:
<?php
mysql_connect ('localhost', 'root', 'root');
mysql_select_db ('ultankc');
if (!isset($_GET['id']) || !is_numeric($_GET['id'])) {
die("Invalid ID specified.");
}
$id = (int)$_GET['id'];
$sql = "SELECT * FROM php_blog WHERE id='$id' LIMIT 1";
$result = mysql_query($sql) or print ("Can't select entry from table php_blog.<br />" . $sql . "<br />" . mysql_error());
$res = mysql_fetch_assoc($result);
$date = date("l F d Y", $res['timestamp']);
$title = $res['title'];
$entry = $res['entry'];
$get_categories = mysql_query("SELECT * FROM php_blog_categories WHERE `category_id` = $res['category']");
$category = mysql_fetch_array($get_categories);
?>
Well, hope that helped :)

I know this is an old post but having read this I think this solution is much simpler (though technically it solves the problem with Javascript not PHP).
<html>
<head>
<title>Ultan.me - Unset</title>
<script type="text/javascript">
function setTitle( text ) {
document.title = text;
}
</script>
<!-- other head info -->
</head>
<?php
// Make the call to the DB to get the title text. See OP post for example
$title_text = "Ultan.me - DB Title";
// Use body onload to set the title of the page
print "<body onload=\"setTitle( '$title_text' )\" >";
// Rest of your code here
print "<p>Either use php to print stuff</p>";
?>
<p>or just drop in and out of php</p>
<?php
// close the html page
print "</body></html>";
?>

Simply add $title variable before require function
<?php
$title = "Your title goes here";
require("header.php");
?>
header.php
<title><?php echo $title; ?></title>

<?php echo APP_TITLE?> - <?php echo $page_title;?>
this should work fine for you

if you want to current script filename as your title tag
include the function in your project
function setTitle($requestUri)
{
$explodeRequestUri = explode("/", $requestUri);
$currentFileName = end($explodeRequestUri);
$withoutExt = preg_replace('/\\.[^.\\s]{3,4}$/', '', $currentFileName);
$explodeCurrentFileName = explode("-", $withoutExt);
foreach ($explodeCurrentFileName as $curFileValue)
{
$fileArrayName[] = ucfirst($curFileValue);
}
echo implode(" ", $fileArrayName);
}
and in your html include the function script
and replace your title tag with this
<title>Your Project Name -
<?php setTitle($_SERVER['REQUEST_URI']); ?>
</title>
it works on php7 and above but i dont have any idea about php 5.*
Hope it helps

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