Read the latest number from loop - php

Question

How can I read the latest number from the following code
<table width="100" border="1" >
<tr align="center" bgcolor="#999999" >
<td >NO</td>
<td >Name</td>
<td >PBSID</td>
</tr>
$query ="select * from stock ";
$hasil = mysql_query($query);
$no=0;
while ($row = mysql_fetch_array($hasil))
{
$no++;
if($x != $row[pbsid] )
{
$no=1;
echo "<tr bgcolor=#CCCCCC>
<td colspan=4 ><b> GROUP $row[pbsid]</b></td>
</tr>";
}
$mo=count($no);
echo "<tr><td>$no </td><td> $row[bnama]</td><td>$row[pbsid] </td></tr>";
$x = $row["pbsid"];
}
The result:
===========
NO | NAME | GROUP
---------------------------------------
===========
GROUP 1
---------------------------------------
===========
1 | A | 1
2 | B | 1
3 | C | 1
4 | D | 1
---------------------------------------
===========
GROUP 2
---------------------------------------
===========
1 | A | 2
2 | B | 2
3 | C | 2
I want to show the latest GROUP number, Group 1=4 and Group 2=3, can anyone help me with this?

Answer 1

Try this query:
SELECT s.*, c.count
FROM stock AS s
LEFT JOIN ( SELECT pbsid, COUNT(1) AS `count` FROM stock GROUP BY pbsid ) AS c
ON s.pbsid = c.pbsid
Now you will have the count for each group, which is what it seems you really want.
If you'd prefer to do all the work in PHP for some reason, you could do it like this:
<table width="100" border="1" >
<tr align="center" bgcolor="#999999" >
<td >NO</td>
<td >Name</td>
<td >PBSID</td>
</tr>
$query ="select * from stock ";
$hasil = mysql_query($query);
$no=0;
$counts = array(); // make an array of counts for each group, keyed by pbsid
$rows = array(); // put all the data from SQL into an array
while ($row = mysql_fetch_array($hasil))
{
$rows[] = $row;
if (!isset($counts[$row[pbsid]]))
{
$counts[$row[pbsid]] = 0; // initialize it to 0
}
$counts[$row[pbsid]]++; // increment for each occurrence of a pbsid
}
foreach ($rows as $row)
{
$no++;
if($x != $row[pbsid] )
{
$no=1;
echo "<tr bgcolor=#CCCCCC>
<td colspan=4 ><b> GROUP $row[pbsid]</b> Count = " . $counts[$row[pbsid]] . " </td>
</tr>";
}
$mo=count($no);
echo "<tr><td>$no </td><td> $row[bnama]</td><td>$row[pbsid] </td></tr>";
$x = $row["pbsid"];
}
Although, I think it's much simpler to just have this information calculated in your query.

Answer 2

This would work
$query ="select * from stock ";
$hasil = mysql_query($query);
$no=0;
$latest = array();
while ($row = mysql_fetch_array($hasil))
{
$no++;
if($x != $row[pbsid] ){
$no=1;
echo "<tr bgcolor=#CCCCCC>
<td colspan=4 ><b> GROUP $row[pbsid]</b></td>
</tr>";
}
$mo=count($no);
echo "<tr><td>$no </td><td> $row[bnama]</td><td>$row[pbsid] </td></tr>";
$x = $row["pbsid"];
$key = 'Group'.$row['pbsid'];
$latest[$key] = $no;
}
print_r($latest);

Answer 3

<table width="100" border="1" >
<tr align="center" bgcolor="#999999" >
<td >NO</td>
<td >Name</td>
<td >PBSID</td>
</tr>
$last_no = array();
$query ="select * from stock ";
$hasil = mysql_query($query);
$no=0;
while ($row = mysql_fetch_array($hasil))
{
$no++;
if($x != $row[pbsid] ){
$no=1;
echo "<tr bgcolor=#CCCCCC>
<td colspan=4 ><b> GROUP $row[pbsid]</b></td>
</tr>";
}
$mo=count($no);
echo "<tr><td>$no </td><td> $row[bnama]</td><td>$row[pbsid] </td></tr>";
$x = $row["pbsid"];
$last_no[] = $no;
}
print_r($last_no);

Answer 4

Change your query $query ="select MAX(no),bnama, pbsid from yourtablename GROUP BY pbsid ";