To upload a image in MySql database via php - php

Question

I am currently working on a website that needs to upload the images of different products by its users. I am implementing it by using MySql database via php.
My code for a basic form for taking input from users is:
<form enctype="multipart/form-data" action="testimage1.php" method="post" name="changer">
<input name="MAX_FILE_SIZE" value="102400" type="hidden">
<input name="image" accept="image/jpeg" type="file">
<input value="Submit" type="submit">
</form>
My database table is:
mysql> CREATE TABLE tbl_images (
> id tinyint(3) unsigned NOT NULL auto_increment,
> image blob NOT NULL,
> PRIMARY KEY (id)
> );
testimage1.php has the following code:-
$username = "root";
$password = "";
$host = "localhost";
$database = "thinstrokes";
$link = mysql_connect($host, $username, $password);
if (!$link) {
die('Could not connect: ' . mysql_error());
}
// Select your database
mysql_select_db ($database);
if (isset($_FILES['image']) && $_FILES['image']['size'] > 0) {
// Temporary file name stored on the server
$tmpName = $_FILES['image']['tmp_name'];
// Read the file
$fp = fopen($tmpName, 'r');
$data = fread($fp, filesize($tmpName));
$data = addslashes($data);
fclose($fp);
// Create the query and insert
// into our database.
$query = "INSERT INTO tbl_images ";
$query .= "(image) VALUES ('$data')";
$results = mysql_query($query, $link) or die(mysql_error());
// Print results
print "Thank you, your file has been uploaded.";
}
else {
print "No image selected/uploaded";
}
On submitting the form I am getting an error: No image selected/uploaded
I am not getting the error... and I've already asked for this before as:
mysql error during inserting a image in mysql database
How can I insert an image in a MySQL database using PHP?
But until now I am not successful in storing the image in the database.

Answer 1

Your script is working just fine, This is what I test:
<?
if (isset($_FILES['image']) && $_FILES['image']['size'] > 0) {
// Temporary file name stored on the server
$tmpName = $_FILES['image']['tmp_name'];
// Read the file
$fp = fopen($tmpName, 'r');
$data = fread($fp, filesize($tmpName));
$data = addslashes($data);
fclose($fp);
// Create the query and insert
// Print results
print "Thank you, your file has been uploaded.";
}
else {
print "No image selected/uploaded";
}
?>
<form enctype="multipart/form-data" action="" method="post" name="changer">
<input name="MAX_FILE_SIZE" value="102400" type="hidden">
<input name="image" accept="image/jpeg" type="file">
<input value="Submit" type="submit">
</form>
And it works just fine, if you want to see it in action I can send you the link.
It must be something else that is ruining your code (*note that I removed the DB queries to avoid getting mysql errors but the script was working even with them there.

Answer 2

//Here is the solution for your problem
<form enctype="multipart/form-data" action="" method="post" name="changer">
<input name="MAX_FILE_SIZE" value="102400" type="hidden">
<input name="image" accept="image/jpeg" type="file">
<input value="Submit" type="submit">
</form>
<?php
// connection to database
include 'includes/connection.php';
?>
<?php
if (isset($_FILES['image']) && $_FILES['image']['size'] > 0) {
// Temporary file name stored on the server
$tmpName = $_FILES['image']['tmp_name'];
// Read the file
$fp = fopen($tmpName, 'r');
$data = fread($fp, filesize($tmpName));
$data = addslashes($data);
fclose($fp);
$result = mysql_query("INSERT INTO image (image)VALUES ( '$data')", $connection);
if(!$result)
{
die("Database query failed: ". mysql_error());
}
// Print results
print "Thank you, your file has been uploaded.";
}
else
{
print "No image selected/uploaded";
}
?>
<?php
//close connection
include 'includes/close.php';
?>