Sort array by other one - PHP - php

Question

Ive got 2 arrays, first one contains values of objects, and second one contains their IDs.
In this form:
$values[0] applies to $ids[0]
$values[1] applies to $ids[1]
I need to sort first array (using sort() ) from lowest to highest (values are ints) - That's not problem.
Problem is, that When I sort array with values, I will lost ID of that value.
My question is: How to make that
If $values[0] turns to $values[5], automatically turn $ids[0] to $ids[5]
Thanks
Update:
Content of $values and $ids:
$values[0] = 1.5;
$values[1] = 2.4;
$values[2] = 15.7;
$values[3] = 11.7;
$values[4] = 4.8;
$values[5] = 0.4;
$ids[0] = 1;
$ids[1] = 2;
$ids[2] = 3;
$ids[3] = 4;
$ids[4] = 5;
$ids[5] = 6;

Answer 1

Combine the arrays first, then sort by key:
$newArr = array_combine($ids, $values);
ksort($newArr);

Answer 2

It sounds like you're looking for array_combine():
Example
<?php
$ids = array(2, 1, 3); // IDs
$values = array(a, b, c); // Values
$array = array_combine($ids, $values); // Combine arrays as ID => Value
ksort($arrays); // Sort new array
print_r($array); // Echo array
Output
Array
(
1 => b,
2 => a,
3 => c,
)

Answer 3

Follow the code below... have not tested it ... but it must work.... Easy to understand..
<?php
$count = count($values);
for($i = 0; $i<$count; $i++)
{
if($i == 0)
{
$sort1 = $values[$i];
$sort2 = $ids[$i];
$temp = 0;
}
if($sort1 > $values[$i])
{
$sort1 = $values[$i];
$sort2 = $ids[$i];
$temp_val = $values[$temp];
$temp_id = $ids[$temp];
$values['temp'] = $values[$i];
$ids['temp'] = $ids[$i];
$temp = $i;
$values[$i] = $temp_val;
$ids[$i] = $temp_id;
}
}
?>