PHP get element using a known attribute - php

Question

So lets say I have:
<?php
$template = '<img src="{image}" editable="all image_all" />';
$template .= '<div>';
$template .= '<img src="{image}" editable="yes" />';
$template .= '</div>';
?>
Now what I would like is to make the script go through all the elements containing the {image} src and checking to see if any of them have the
editable="all"
attribute.
If so: get the second editable attribute e.g.
image_all
And include that into the src.

Answer 1

This task can be simplified with the use of a library suggested on comments, Simple HTML DOM Parser:
It is as easy as this:
$images = array(); //an array for your images with {image} in src
$html = "...";
foreach($html->find('img') as $element)
if($element->src == '{image}') {
//add to the collection
$images[] = $element;
}
//Also you can compare for the editable attribute same way as above.
}

Answer 2

if you want to get second editable attr and save it in an array like $src so check this code:
$content=new DOMDocument();
$content->loadHTML($template);
$elements=simplexml_import_dom($content);
$images=$elements->xpath('//img');
foreach ($images as $img) {
if(preg_match('/all /i', $img['editable']))
$src[]=substr($img['editable'],4) ;
}
print_r($src);
will output:
Array ( [0] => image_all )

Answer 3

Try this,
include('simple_html_dom.php');
$html = str_get_html('<div><img src="{image}" editable="all image_all" /><img src="{image}" editable="yes" /></div>');
$second_args= array();
foreach($html->find('img[src="{image}"]') as $element){
$editables = explode(' ',$element->editable);
if($editables[0] === "all"){
$second_args[] = $editables[1];
}
}
print_r($second_args);