how doHow do we do
select table.value as table_value from table in codeigniter?
The AS part doesnt work because when i try to access the value,
this doesnt work:
$qry_inp = 'select table.value as table_value from table '
$query = $this->db->query($qry_inp);
echo $query->row('table_value ');// this will be empty, but it shouldn`t be
doesn`t matter if its in AR or simple query
Pretty simple thing.
$this->db->select('COLUMN_ACTUAL_NAME as `COLUMN_NAME_YOU_WANT_TO_SHOW`');
i'm joining two tables in which column names are same so i separate both tables columns by using as keyword , this is how you can use AS in codeigniter
$this->db->select("departments.name AS 'dname'");
$this->db->select('positions.name');
Where is that behaviour documented? row doesn't take a column name as a parameter; it optionally takes a row number, and that's it. Access it like any other field:
echo $query->row()->table_value;
Related
I have two tables user_master and user_teams with common field user_name.
I want to join the table and get the team value group by teams
tried as
$filter_teams = DB::table('user_teams')
->join('user_master','user_master.user_name','=','user_teams.user_name')
->whereIn('user_master.geo',$geo)
->groupBy('user_teams.team')
->pluck('user_teams.team')
->toArray();
by may values are duplicating.I'm using postgresql
since you didn't determine select fields ... the default will be '*'
this is why you are getting duplicated fields ...
just add :
->select('user_teams.team')
and i think that all.
i recommend not using group without aggregation ....
so my advice your query to like this:
$filter_teams = DB::table('user_teams')
->join('user_master','user_master.user_name','=','user_teams.user_name')
->whereIn('user_master.geo',$geo)
->select('user_teams.team')->distinct()
->pluck('user_teams.team')
->toArray();
I have a table names and in that table there is a field info data is like this:
ID info
1 'alpha,romeo,ciera,delta'
2 'testing,temp,total'
I am trying to create a select query.
select * from names where info like '%$var%'
$var is data from php.
Problem is i want exact match. If i use above query and in $var if
data is rome then it also return row of romeo.
one more example-
data in table is testing,temp,total
user input data is test then it also return testing
i tried
select * from names where info like '$var%'
and
select * from names where info like '%$var'
but it didn't return data as i expected.
Please advise how can i achieve this.
Note- : This is an example i am not using mysql as its depreciated. I am using mysqli
Append , at begin and end of your target search string.
And then make sure your source string also has those ,
SQL Fiddle Demo
select *
from names
where concat( ',', info , ',') like
concat( '%,', $var, ',%')
The problem is this wont use any index. You should go for FULL TEXT search
Problem is i want exact match. If i use above query and in $var if data is rome then it also return row of romeo.
Don't use the LIKE operator, use exact match operator =
select * from names where info = '$var'
Use , in your query to use it as a delimiter and use multiple conditions to account for the "edge cases".
SELECT *
FROM names
WHERE
info LIKE '%,$var,%' OR
info LIKE '$var,%' OR
info LIKE '%,$var' OR
info = '$var'
If you have rows with info column:
alpha,romeo,ciera,delta
testing,temp,total
rome
foo,test,bar
berlin,paris,madrid,london,rome
venice,milano,rome,firence
black,crome
rome,fome,mome,kome,kome
Query with $var as "rome" will select:
rome
berlin,paris,madrid,london,rome
venice,milano,rome,firence
rome,fome,mome,kome,kome
But not:
alpha,romeo,ciera,delta
black,crome
I've this code:
public function getAllAccess(){
$this->db->select('accesscode');
$this->db->where(array('chain_code' => '123');
$this->db->order_by('dateandtime', 'desc');
$this->db->limit($this->config->item('access_limit'));
return $this->db->get('accesstable')->result();
}
I need to join it with another table (codenamed table), I've to tell it this. Not really a literal query but what I want to achieve:
SELECT * accesscode, dateandtime FROM access table WHERE chain_code = '123' AND codenames.accselect_lista != 0
So basically accesstable has a column code which is a number, let us say 33, this number is also present in the codenames table; in this last table there is a field accselect_lista.
So I have to select only the accselect_lista != 0 and from there get the corrisponding accesstable rows where codenames are the ones selected in the codenames.
Looking for this?
SELECT *
FROM access_table a INNER JOIN codenames c ON
a.chain_code = c.chain_code
WHERE a.chain_code = '123' AND
c.accselect_lista != 0
It will bring up all columns from both tables for the specified criteria. The table and column names need to be exact, obviously.
Good start! But I think you might be getting a few techniques mixed up here.
Firstly, there are two main ways to run multiple where queries. You can use an associative array (like you've started to do there).
$this->db->where(array('accesstable.chain_code' => '123', 'codenames.accselect_lista !=' => 0));
Note that I've appended the table name to each column. Also notice that you can add alternative operators if you include them in the same block as the column name.
Alternatively you can give each their own line. I prefer this method because I think its a bit easier to read. Both will accomplish the same thing.
$this->db->where('accesstable.chain_code', '123');
$this->db->where('codenames.accselect_lista !=', 0);
Active record will format the query with 'and' etc on its own.
The easiest way to add the join is to use from with join.
$this->db->from('accesstable');
$this->db->join('codenames', 'codenames.accselect_lista = accesstable.code');
When using from, you don't need to include the table name in get, so to run the query you can now just use something like:
$query = $this->db->get();
return $query->result();
Check out Codeigniter's Active Record documentation if you haven't already, it goes into a lot more detail with lots of examples.
I have a simple left join query.
SELECT e.employee_id as employee
, e.badge_id as badge
, e.first_nm as first
, e.last_nm as last
, e.work_phone as work_ph
, e.mobile_phone as mobile_ph
, e.manager_id as man_id
, e.title_id as titl_id
, e.username as user
, e.start_dt as start
, m.employee_id as memp_id
, m.last_nm as m_last
, m.first_nm as m_first
, t.title_nm as titl_nm
FROM employee e
left join employee m
on e.manager_id = m.employee_id
left join title t
on e.title_id = t.title_id
WHERE e.employee_id = 1
If I use column aliases as I have done above, the query works fine. If I do not use aliases, however, some values do not get returned. For example, the following returns a space if I do not give the column an alias.
e.first_nm as first //returns "Robert"
e.first_nm //returns ""
e.first_nm as first_nm //returns "" (alias matches column name)
In this same query,
e.middle_nm //will return "P"
regardless of whether it has an alias or not. I'm baffled.
I have given my tables aliases and I have used the table alias in the column names so there shouldn't be any ambiguous column names.
Any thoughts would be appreciated.
Thanks,
Rob
You have two columns with same name as first_nm and problably the PDO don´t know what return to your code then return simple "". Although they are in diferent tables when came to a record they have the same name... you see the problem?
You have two columns with same name as first_nm and mysql knows how to return them all right, and then return simple "first_nm" for both. And then PDO have to assign them to array members, making field names as array keys. There is only one way, like this
$row['first_nm'] = first col;
$row['first_nm'] = second col;
If you try to see into $row, how many entries you will find?
So, you either have to use FETCH_ROW or give your fields distinct names. It's neither mysql nor PDO to blame - it's just how the things work.
first of all, that's what I'm trying to do:
In one of my classes in the library I want to count the total amount of rows of a search result. The class uses a select object set by the appendant model of the search result. My problem is now, this select() has already set the requested columns by from(), but to simply count the rows I just want to select the id, because the website has to to be performant. I can't simply change the values of the object, because I'm using it in the library and the variables are protected. Unfortunately, Zend has no function for the mySql count command and I don't want to use static mySql code, because it could be, that we switch our database system in the future.
Now here's my question:
Is there any possibility by Zend_Select how I could change the selected columns?
Try this:
$select->reset(Zend_Db_Select::COLUMNS)
->from('thetable', 'COUNT(*)');
replacing the 'thetable' with the correct table name.
This is from a project and isn't tested, but one of these should work.
$select->from(array("table_name" => "table_name"), array("my_col" => "COUNT(id)"));
OR
$select->from(array("table_name"), array("my_col" => "COUNT(id)"));
This is the same as
SELECT COUNT(id) as my_col FROM table_name
Hope that helps
Jake
This one didn't work for me (I needed to select only from one joined table):
$select->reset(Zend_Db_Select::COLUMNS)
->from('thetable', 'COUNT(*)');
Maybe because I had some joins. But nevertheless, here's the solution: to use reset() and then columns():
$select->setIntegrityCheck(false)
->from(['t1' => 'table1'])
->join(['t2' => 't2'], 't1.id = t2.t1_id')
->reset(Zend_Db_Select::COLUMNS)
->columns('t1.*');
Just FYI, the version of Zend Framework is 1.12
To use a mysql command in a select, you need to use Zend_Db_Expr:
$select = $this->select()
->from('myTable', new Zend_Db_Expr('COUNT(id) as count'));
echo $select; //SELECT COUNT(id) as count FROM myTable;