My PHP form will not send to multiple users - php

Question

Hi I have a php form that works perfectly when it sends an email to one person but when I add another email address it doesn't send an email to either address. I have been looking on php sites but can't see why my form is now refusing to email once the second email address is added.
<?php
function isRequestSet( $name ) {
if ( isset ( $_REQUEST[$name] ) ) {
return ( $_REQUEST[$name] != "" ) ;
}
return false;
}
$name = "";
if ( isRequestSet('name' ) ) {
$name = $_REQUEST['name'];
}
$number = "";
if ( isRequestSet('number') ) {
$number = $_REQUEST['number'];
}
$email = "";
if ( isRequestSet( 'email' ) ) {
$email = $_REQUEST['email'];
}
$postcode = "";
if ( isRequestSet('postcode' ) ) {
$location = $_REQEUST['postcode'];
}
$how_did_you_hear_about_us = array();
if ( isset( $_REQUEST['how_did_you_hear_about_us'] ) ) {
$how_did_you_hear_about_us = $_REQUEST['how_did_you_hear_about_us'];
}
$message = "";
if ( isRequestSet('message' ) ) {
$location = $_REQEUST['message'];
}
$apartment_price_range = array();
if ( isset( $_REQUEST['apartment_price_range'] ) ) {
$apartment_price_range = $_REQUEST['apartment_price_range'];
}
$url = "";{
$url = $_REQUEST['url'];
}
$property = "";{
$property = $_REQUEST['property'];
}
if ( ($name !="") && ($number != "") && ($email != "") && ($isspam !="yes") ) {
$to = 'name#email.com,name#email2.com';
$from = $to;
$headers = 'From: ' . $to . "\n" .
'Reply-To: ' . $to . "\n";
$vars = array( 'name' , 'number' , 'email' , 'postcode' , 'message' ) ;
$message = "-----------\n" ;
foreach ( $vars as $v ) {
$value = $_REQUEST[$v];
$message .= "$v:\t$value\n";
}
$message .= "-----------\n" ;
$message .= "\nHow did you hear about apartments?:\n" ;
foreach ( $how_did_you_hear_about_us as $how_did_you_hear_about_us ) {
$message .= "$how_did_you_hear_about_us\n" ;
}
$message .= "-----------\n" ;
$message .= "\nApartment price range:\n" ;
foreach ( $apartment_price_range as $apartment_price_range ) {
$message .= "$apartment_price_range\n" ;
}
$subject = "From: $name <$email>";
mail( $to , $subject , $message , $headers, "-f $from" );
$confirm = true;
//redirect to the 'thank you' page
header("Location:http://website.com/file/thankyou.php");
} else {
$confirm = false;
}
?>

Answer 1

Most likely it is because you use multiple addresses for From and Reply-to fields:
$to = 'name#email.com,name#email2.com';
$from = $to;
Change it to use either first email or something like your-service-name#you-domain-name.com

Answer 2

Use only one address for From and Reply-To.
$from = 'me#my-domain.com';
$headers = 'From: ' . $from . "\n" .
'Reply-To: ' . $from . "\n";

Answer 3

"In the line below you should break the $to field into an array.
mail( $to , $subject , $message , $headers, "-f $from" );
For example
$address_array = split(",", $to);
foreach($address_array as $address)
{
mail( $address, $subject , $message , $headers, "-f $from" );
}
This allows for you $to string to contain as many emails as desired.
N.b if you wish to skip the split line just store the $to as an array
$to = array("name#email.com","name#email2.com");

Answer 4

make your email part into a function.
will much more easier for you to pass the email address.
function email_to_user($email_address){
$to = $email_address;
<rest of the codes>
}
and you can easily pass the email address
email_to_user(name1#mail.com);
email_to_user(name2#mail.com);