PHP Similar Words using soundex with array - php

Question

I am creating a findSpellings function that has two parameters $word and $allWords. $allwords is an array that has mis-spellings of words that could sound similar to the $word variable. What I am trying to accomplish is to print out all words that are similar to the $word based on the soundex function. I am having trouble printing out the array with words. My function that I have is below. Any help would be greatly appreciated:
<?php
$word = 'stupid';
$allwords = array(
'stupid',
'stu and pid',
'hello',
'foobar',
'stpid',
'supid',
'stuuupid',
'sstuuupiiid',
);
function findSpellings($word, $allWords){
while(list($id, $str) = each($allwords)){
$soundex_code = soundex($str);
if (soundex($word) == $soundex_code){
//print '"' . $word . '" sounds like ' . $str;
return $word;
return $allwords;
}
else {
return false;
}
}
}
print_r(findSpellings($word, $allWords));
?>

Answer 1

if (soundex($word) == $soundex_code){
//print '"' . $word . '" sounds like ' . $str;
return $word;
return $allwords;
}
You can't have 2 returns, the first return will exit the code.
You could just do something like this:
if (soundex($word) == $soundex_code){
//print '"' . $word . '" sounds like ' . $str;
$array = array('word' => $word, 'allWords' => $allWords);
return $array;
}
And then just retrieve the values out of $array like so:
$filledArray = findSpellings($word, $allWords);
echo "You typed".$filledArray['word'][0]."<br/>";
echo "Were you looking for one of the following words?<br/>";
foreach($filledArray['allWords'] as $value)
{
echo $value;
}