I'm trying to use strlen or something like that to count multiple set of characters
in a string.
Here's the database string
xa1xb2xcxd3xe4xcxa5xb6xcxd7xe8xcxa9xb10xcxd11xe12xcxa13xb14xc
I get the string from the database and i want to count the number of
"xa" "xb" "xd" and "xe" that the string contains.
I Guess i could count first xa then xb then xd then xe with strlen and then adding the numbers but isn't there an easier way?
Please help!
Are you open to preg_match_all solution?
echo preg_match_all('/x(a|b|d|e)/', $message, $matches)
From the docs:
Returns the number of full pattern matches (which might be zero), or
FALSE if an error occurred.
Although this returns the aggregated number of xa,xb,xd and xe, not the individual ones
If you need to get individual ones, you need one more step with array_count_values:
$sums = array_count_values($matches[0]);
print_r($sums);
Try this one.
$string ="xa1xb2xcxd3xe4xcxa5xb6xcxd7xe8xcxa9xb10xcxd11xe12xcxa13xb14xc";
echo substr_count($string, 'xa')."<br>";
echo substr_count($string, 'xb')."<br>";
echo substr_count($string, 'xc')."<br>";
echo substr_count($string, 'xd')."<br>";
http://php.net/manual/en/function.substr-count.php
$text = "xa1xb2xcxd3xe4xcxa5xb6xcxd7xe8xcxa9xb10xcxd11xe12xcxa13xb14xc";
echo substr_count($text, 'xa');
echo substr_count($text, 'xb');
echo substr_count($text, 'xd');
Related
I have a question about a String i want to count all the characters in the string. Like if i have a string
"Hello world & good morning. The date is 18.05.2016"
You can use explode() to convert string into array and then use count() function to count length of array.
echo count(explode(' ', "Hello world & good morning. The date is 18.05.2016"))
You can try this code.
<?php
$file = "C:\Users\singh\Desktop\Talkative Challenge\base_example.txt";
$document = file_get_contents($file);
$return_array = preg_split("/[\s,]+/",$document);
echo count($return_array);
echo $document;
?>
Hopefully it will be working fine.
The 3rd parameter of str_word_count allows you to set additional characters to be counted as words:
str_word_count($document, 0, '&.0..9');
&.0..9 means it will consider &, ., and range from 0 to 9.
You can count the spaces with substr_count and add one.
echo substr_count($str, " ")+1;
// 9
https://3v4l.org/oJJkt
I'm trying to read a number in a link in php. But I'm not sure how to do it.
http://example.com/Productdetail.asp?SID=72&ProductID=8640
How can I read the number 8640 without reading 72 at the same time.
ProductID= <- it will always be there.
SID=X <- this one will be there sometimes and left out on other pages. and the number can change between 1-999,
Is there a way to say ProductID= "read the next 4 numbers and save in string"
Thanks
you can get this output by using explode()
$link='http://example.com/Productdetail.asp?SID=72&ProductID=8640';
$links=explode('ProductID=',$link);
echo $link[1]; //this is your number
Simple use
echo $_GET['ProductID'];//8640
You can use preg_match as
$str = "http://example.com/Productdetail.asp?SID=72&ProductID=8640";
preg_match('/&ProductID=(\d+)?/',$str,$match);
echo $match[1];
Or you can simply use parse_str as
$str = "http://example.com/Productdetail.asp?SID=72&ProductID=8640";
parse_str($str,$res);
echo $res['ProductID'];
You can use:
strpos to get the ProductID=
's index
substr to get the string from ProductID= until the end of the string
str_replace to replace the ProductID= part
<?php
$str = "http://example.com/Productdetail.asp?SID=72&ProductID=8640";
echo str_replace("ProductID=", "", substr($str, strpos($str, "ProductID=")));
?>
I have a string that looks something like this:
abc-def-ghi-jkl-mno-pqr-stu-vwx-yz I'd like to get the content BEFORE the 4th dash, so effectively, I'd like to get abc-def-ghi-jkl assigned to a new string, then I'd like to get mno assigned to a different string.
How could I go about doing this? I tried using explode but that changed it to an array and I didn't want to do it that way.
Try this:
$n = 4; //nth dash
$str = 'abc-def-ghi-jkl-mno-pqr-stu-vwx-yz';
$pieces = explode('-', $str);
$part1 = implode('-', array_slice($pieces, 0, $n));
$part2 = $pieces[$n];
echo $part1; //abc-def-ghi-jkl
echo $part2; //mno
See demo
http://php.net/manual/en/function.array-slice.php
http://php.net/manual/en/function.explode.php
http://php.net/manual/en/function.implode.php
Can you add your source code? I done this one before but I cant remember the exact source code I used. But I am pretty sure I used explode and you can't avoid using array.
EDIT: Mark M answer is right.
you could try using substr as another possible solution
http://php.net/manual/en/function.substr.php
If I see where you are trying to get with this you could also go onto substr_replace
I guess an alternative to explode would be to find the position of the 4th - in the string and then get a substring from the start of the string up to that character.
You can find the position using a loop with the method explained at find the second occurrence of a char in a string php and then use substr(string,0,pos) to get the substring.
$string = "abc-def-ghi-jkl-mno-pqr-stu-vwx-yz";
$pos = -1;
for($i=0;$i<4;$i++)
$pos = strpos($string, '-', $pos+1);
echo substr($string, 0, $pos);
Code isn't tested but the process is easy to understand. You start at the first character (0), find a - and on the next loop you start at that position +1. The loop repeats it for a set number of times and then you get the substring from the start to that last - you found.
I want to exclude a specific number like 4800 from a string of numbers like 569048004801.
I'm using php for this and the method preg_match_all some pattern's examples I have tried :
/([^4])([^8])([^0])([^0])/i
/([^4800])/i
If you just want to see if a string contain 4800, you don't need regular expressions :
<?php
$string = '569048004801';
if(strpos($string,'4800') === false){
echo '4800 was not found in the string';
}
else{
echo '4800 was found in the string';
}
More information about strpos in the documentation here
If you mean you simply want to remove 4800 from a string, this is easier with a str_replace:
$str = '569048004801';
$str = str_replace('4800', '', $str);
On the other hand, if you mean you want to know if a particular string of digits contains 4800, this will test that for you:
$str = '569048004801';
if (preg_match_all('/4800/', $str) > 0) {
echo 'String contains 4800.';
} else {
echo 'String does not contain 4800.';
}
/([^4])([^8])([^0])([^0])/i
This actually says, a sequence of four characters that is not "4800". Close.
/([^4800])/i
This actually says, a single character that is not '4', '8', or '0'.
Assuming you mean to capture a number that doesn't contain "4800" in it, I think you might want
/(?!\d*4800)\d+/i
This says, check first that we're not looking at a string of numbers with "4800" somewhere, and provided this is the case, capture the string of numbers. It's called a "negative lookahead assertion".
$vari = "testing 245";
$numb = 0..9;
$numb_pos = strpos($vari,$numb);
echo substr($vari,0,$numb_pos);
The $numb is numbers from 0 to 9
Where am I wrong here, all I need to echo is testing
You want to cut out the numbers from a string?
$string = preg_replace('/(\d+)/', '', 'String with 1234 numbers');
Use a regular expression to strip numeric characters from your string.
or, use a regular expression to find the first instance of one either way...
Your code won't work as-is, as it'll fail if the number if the first character in the string. (You need to check $numb_pos !== false prior to the substr.)
Irrespective, if you just want to check for the existance of a number in a string, something like the following would probably be more efficient.
$digitMatched = preg_match('/\\d/im', $vari);