PHP preg match? - php

Question

Okay, let's say this is a line
v1=something;v2=something2;
how to get v1 value (something) starting from = and break at ; and same to be done with v2 by calling it (v1)
function getVal($name){
// some code to start grabbing from = and end by ;
}
when i call
getVal("v1");
it should return "something"

Answer 1

This will work
v1=([^;]*)
The match will be in group 1
Just replace v1 in the regex with the key you want to lookup
if (preg_match('/v1=([^;]*)/', $subject, $regs)) {
$result = $regs[1];
} else {
$result = "";
}

Answer 2

If I understand your question, then I think this is what you are looking for:
$line = "v1=something;v2=something2;";
function getVal($name, $line){
preg_match('/'.$name.'=([^;]*)/', $line, $matches);
return $matches[1];
}
echo getVal("v1", $line);

Answer 3

v(?:\d*)=(\w;+)
That will match all v (with digits or no digits after it) and then the match group will be after the = sign. It is group 1.

Answer 4

You are obliged to sent the line to your function (or you can be dirty and use it as global).
So, your function can be something like that :
<?php
function getVal($name, $line){
// some code to start grabbing from = and end by ;
preg_match('#;?' . $name . '=([^;]+);?#', $line, $aMatches);
if(isset($aMatches[1])) {
return $aMatches[1];
}
return false;
}
$line = 'v1=something;v2=something2';
$v1 = getVal('v1',$line);
echo $v1;
?>

Answer 5

Use this Function:
function getVal($name, $line){
preg_match("/{$name}=(.+);(v(\d+)=|$)/U", $line, $matches);
$matches = $matches[0];
$matches = preg_replace("/{$name}=/","",$matches);
$matches = preg_replace("/;v(\d+)=/","",$matches);
return $matches;
}
this will give you exact answer.
Tested and working.:)