Array Rand Not Working with MySQL Fetch Array - php

I wrote a PHP script that retrieves values from a MySQL Query. I used mysql_fetch_array to add the results to an array. I am trying to select a random value from the array, however array_rand doesn't seem to work. My code is below:
<?php
session_start();
ob_start();
require_once 'includes/db_connection.php';
require_once 'includes/contest.php';
require_once 'includes/survey.php';
require_once 'includes/poll.php';
require_once 'includes/clients.php';
require_once 'includes/user.php';
//Select All Entries from Contest and Save as Array
//Select
mysql_connect(localhost,s2ktest_s2kuser, Bc33iyZYQWgUmguBehPI);
$dbname = 's2ktest_s2k';
mysql_select_db($dbname);
$contestid = 20;
$query = "SELECT UserID FROM Contest_Entered WHERE ContestID = $contestid";
//Save Result
$result = mysql_query($query) or die(mysql_error());
//Save All Contest Entries in Array
$entries = mysql_fetch_array($result) or die(mysql_error());
//Output all Rows
//While Each Entry in the Array is a Value
while($entries = mysql_fetch_array($result))
{
echo $entries;
echo "</br>";
}
echo array_rand($entries);
//mysql_free_result($result);
?>

Maybe because you don't have any array...
The while is only generating one row at the time.
while($entries = mysql_fetch_array($result))
{
echo $entries;
$arr[] = $entries;
echo "</br>";
}
echo array_rand($arr);

mysql_fetch_array() retrieves only one row at a time. First, load the whole result set into an array using the [] append syntax, then fetch randomly from that.
$all_entries = array();
// Using MYSQL_NUM to retrieve only numeric keys
// by default, mysql_fetch_array() gets both numeric and associative keys
while($entries = mysql_fetch_array($result, MYSQL_NUM))
{
// Append all rows onto an array, only a sinlge value so you get a 1D array
$all_entries[] = $entries[0];
}
// Then call array_rand() against $all_entries
echo array_rand($all_entries);
Disclaimer:
Start thinking about migrating away from the old mysql_*() functions to a modern API supporting prepared statements. PDO is excellent and portable between RDBMS, while MySQLi is a good alternative as well.

That's because you're changing the value of $entries from an array to a string when you start the loop. Try echoing array_rand($entries) before the loop instead.
However, if you are instead trying to retrieve a random row from a table (rather than a random column from a row, as your code appears to do) use ORDER BY RAND() in your query. It's unclear what you're going for.
Good luck!

Related

PHP MySQL Database - All rows into Multi-Dimensional Array

It's been a long while since I touched PHP so, I just need a refresher of sorts.
I have an HTML form that captures several lines of data (dataA, dataB, dataC & dataD) and inserts them into a database table (dataAll). I will be entering rows upon rows of data into "dataAll". What I'm looking to do is create a display.php page, where the code will take all of the data and place each cell into an array, or the row of an array, for example:
new Array = [["dataA", "dataA", "dataA", "dataA", "dataA"],
["dataB", "dataB", "dataB", "dataB", "dataB"],
["dataC", "dataC", "dataC", "dataC", "dataC"],
["dataD", "dataD", "dataD", "dataD", "dataD"]];
But I cannot remember the syntax on how to perform this task. Any help would be greatly appreciated.
The database is named 'compdata', the table is 'dataAll', and each row is 'dataA', 'dataB', 'dataC', 'dataD'.
Please let me know if I need to supply more information.
Since you asked for All rows, so the simple code for query is written below:
<?php
//after connection to mysql db using mysql_connect()
$sql = "Select dataA, dataB, dataC, dataD from `compdata`.`dataAll`" ;
$result = mysql_query($sql) ;
if(mysql_num_rows($result) > 0 ){
while($row = mysql_fetch_array($result)){
$dataArray[] = $row ;
}
}
echo '<pre>';
print_r($dataArray) ;//you got the desired 2D array with all results
?>
Assuming you are used to the old mysql_xxx functions:
$data = array ();
$result = mysql_query ('select * from dataAll');
while ($row = mysql_fetch_array ($restult, MYSQL_ASSOC))
$data [] = $row;
Result:
$data = array (
0=>array ('col_1'=>'dataA', 'col_2'=>dataB...),
1=>array ('col_1'=>'dataA', 'col_2'=>dataB...)
);
If you only want the numbers and not the column names, use MYSQL_NUM.
However, mysql functions are being replaced with the more generic PDO object so you might want to look into that.
$stmt = $pdo->query ('select * from dataAll');
$result = $pdo->fetchAll (PDO::FETCH_ASSOC); // Or PDO::FECTCH_NUM
Same results as above.

How do I insert values into an multidimensional-array, then show them?

I'm fairly new to php, and I don't know how to work with arrays very well. Here's the deal, I want to add into a multidimensional array three or more values I obtain from my database, then I want to sort them based on the timestamp (one of the values). After that, I want to show all of the sorted values. I can't seem to do this, here's the code
$queryWaitingPatients = 'SELECT ArrivalTime, TargetTime, Order, Classification FROM exams WHERE (CurrentState = "Pending")';
$results = mysql_query($queryWaitingPatients) or die(mysql_error());
if (mysql_num_rows($results) == 0) {
echo '<p>There\'s currently no patient on the waiting list.</p>';
return;
}
while ($rows = mysql_fetch_array($results)) {
extract($rows);
//now is the part that I don't know, putting the values into an array
}
// I'm also not sure how to sort this according to my $TargetTime
asort($sortedTimes);
//the other part I don't know, showing the values,
Thanks for the help!
Well, let's look at your code. First, you have a query that's returning a result set. I don't recommend using mysql_fetch_array because it's not only deprecated (use mysqli functions instead) but it tends to lend itself to bad code. It's hard to figure out what you're referencing when all your keys are numbers. So I recommend mysqli_fetch_assoc (be sure you're fully switched to the mysqli functions first, like mysql_connect and mysqli_query)
Second, I really dislike using extract. We need to work with the array directly. Here's how we do this
$myarray = array();
while ($rows = mysqlI_fetch_assoc($results)) {
$myarray[] = $rows;
}
echo $myarray[0]['ArrivalTime'];
So let's go over this. First, we're building an array of arrays. So we initialize our overall array. Then we want to push the rows onto this array. That's what $myarray[] does. Finally, the array we're pushing is associative, meaning all the keys of the row match up with the field names of your query.
Now, the sorting really needs to be done in your query. So let's tweak your query
$queryWaitingPatients = 'SELECT ArrivalTime, TargetTime, `Order`, Classification
FROM exams
WHERE CurrentState = "Pending"
ORDER BY TargetTime';
This way, when your PHP runs, your database now churns them out in the correct order for your array. No sorting code needed.
$arr = array();
while ($rows = mysql_fetch_array($results)) {
array_push ($arr, $row);
}
print_r($arr);
<?php
$queryWaitingPatients = ' SELECT ArrivalTime, TargetTime, Order, Classification, CurrentState
FROM exams
WHERE CurrentState = "Pending"
ORDER BY TargetTime ';
$results = mysql_query($queryWaitingPatients) or die(mysql_error());
if ($results -> num_rows < 1)
{
echo '<p>There\'s currently no patient on the waiting list.</p>';
}
else
{
while ($rows = mysqli_fetch_array($results))
{
$arrivaltime = $row['ArrivalTime'];
$targettime = $row['targettime'];
$order = $row['Order'];
$classification = $row['Classification'];
echo "Arrival: ".$arrivaltime."--Target time: ".$targettime."--Order: ".$order."--Classification: ".$classification;
}
}
echo "Done!";
//or you could put it in a json array and pass it to client side.
?>

How to select multiple rows from mysql with one query and use them in php

I currently have a database like the picture below.
Where there is a query that selects the rows with number1 equaling 1. When using
mysql_fetch_assoc()
in php I am only given the first is there any way to get the second? Like through a dimesional array like
array['number2'][2]
or something similar
Use repeated calls to mysql_fetch_assoc. It's documented right in the PHP manual.
http://php.net/manual/function.mysql-fetch-assoc.php
// While a row of data exists, put that row in $row as an associative array
// Note: If you're expecting just one row, no need to use a loop
// Note: If you put extract($row); inside the following loop, you'll
// then create $userid, $fullname, and $userstatus
while ($row = mysql_fetch_assoc($result)) {
echo $row["userid"];
echo $row["fullname"];
echo $row["userstatus"];
}
If you need to, you can use this to build up a multidimensional array for consumption in other parts of your script.
$Query="select SubCode,SubLongName from subjects where sem=1";
$Subject=mysqli_query($con,$Query);
$i=-1;
while($row = mysqli_fetch_array($Subject))
{
$i++;
$SubjectCode[$i]['SubCode']=$row['SubCode'];
$SubjectCode[$i]['SubLongName']=$row['SubLongName'];
}
Here the while loop will fetch each row.All the columns of the row will be stored in $row variable(array),but when the next iteration happens it will be lost.So we copy the contents of array $row into a multidimensional array called $SubjectCode.contents of each row will be stored in first index of that array.This can be later reused in our script.
(I 'am new to PHP,so if anybody came across this who knows a better way please mention it along with a comment with my name so that I can learn new.)
This is another easy way
$sql_shakil ="SELECT app_id, doctor_id FROM patients WHERE doctor_id = 201 ORDER BY ABS(app_id) ASC";
if ($result = $con->query($sql_shakil)) {
while ($row = $result->fetch_assoc()) {
printf ("%s (%s)\n", $row["app_id"], $row["doctor_id"]);
}
Demo Link
It looks like the complete solution has not been suggested yet
$Query="select SubCode,SubLongName from subjects where sem=1";
$Subject=mysqli_query($con,$Query);
$Rows = array ();
while($row = mysqli_fetch_array($Subject))
{
$Rows [] = $row;
}
The $Rows [] = $row appends the row to the array. The result is a multidimensional array of all rows.

Unexpected result in mysql_fetch_array

I am using a complex join statement to get data from my 'items' table where 'column1' is equal to the value of table2.ID
This is in a mysql_query() statement, and it should return 3 rows.
Now my understanding is that by using
$array=mysql_fetch_array($queryresult);
I can then loop through each 'row' using a
foreach($array as $output) {
echo $output['ID'];
}
This is however not returning what i want. Using print_r on $output is outputting non-sensical information.
So, yes it is ver much back to basics, but obviously i have missed the point.
You need to use while loop:
while($row = mysql_fetch_array($queryresult)){
// handle each row
}
This is how I do it. This is by far not the end all solution... Just an example of how I do it.
$result = mysql_query($query, $dbconnect) or trigger_error("SQL", E_USER_ERROR);
$i = 0;
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
echo $row["questionId"];
echo $row["questionText"];
echo $row["questionReview"];
$i++;
}
http://php.net/manual/en/function.mysql-fetch-array.php
$array has a single row in it when you get to the loop, so when you say $output['ID'] you are one level deeper than you are expecting, walking through the columns instead of each row. When the ids don't exist or are translating to integers, thats where the nonsense comes in.
Use while($row = mysql_fetch_array($queryresult)) to walk through each row in the result set, then access the column values from $row['id'], $row['name'], etc. It will return false when there are no more rows.
The result will always be a single flat array with a single row per index id, regardless of the join dimensions.

Disappear the arrays generated with mysql_fetch_array() after use?

I have a typical database query:
$query = mysql_query('SELECT titulo,referencia FROM cursos WHERE tipo=1 AND estado=1');
and I can convert it in an array and print the data:
while ($results=mysql_fetch_array($query)): ?>
echo $results['referencia'];
// and so...
endwhile;
but in some cases I need to print the same data in another part of the web page, but the $results array seems to be empty (I use var_dump($results) and I get bool(false)). I plan to use what I learned reading Create PHP array from MySQL column, but not supposed to mysql_fetch_array() creates an array? So, what happen?
Tae, the reason that your $result is false at the end of the while loop is that mysql_fetch_array returns false when it reaches the end of the query set. (See the PHP Docs on the subject) When you reach the end of the query set $results is set to false and the while loop is exited. If you want to save the arrays (database row results) for later, then do as Chacha102 suggests and store each row as it is pulled from the database.
$data = array();
while($results = mysql_fetch_array($query)) {
$data[] = $results;
}
foreach ($data as $result_row) {
echo $result_row['referencia'];
... etc.
}
Try this
while($results = mysql_fetch_array($query))
{
$data[] = $results;
}
Now, all of your results are in $data, and you can do whatever you want from there.
As Anthony said, you might want to make sure that data is actually being retrieved from the query. Check if any results are being returned by echo mysql_num_rows($query). That should give you the number of rows you got

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