See this code:
<?php
$a = rand(1, 10000000000);
$b = "abcdefghi";
?>
How can I insert $b into a random position of $a?
Assuming "casual" means random:
<?php
$a = rand(1, 10000000000);
$b = "abcdefghi";
//get a random position in a
$randPos = rand(0,strlen($a));
//insert $b in $a
$c = substr($a, 0, $randPos).$b.substr($a, $randPos);
var_dump($c);
?>
above code working: http://codepad.org/VCNBAYt1
Edit: had the vars backwards. I read "insert a into b,
I guess you could by treating $a as a string and concatenating it with $b:
$a = rand(1, 1000000);
$b= "abcd";
$pos = rand(0, strlen($a));
$a = substr($a, 0, $pos).$b.substr($a, $pos, strlen($a)-$pos);
and the results:
a=525019
pos=4
a=5250abcd19
a=128715
pos=5
a=12871abcd5
You should put {$b} on top of {$a} so that you can insert it to {$b}..
eg:
<?php
$b = "abcdefghi";
$a = rand(1, 10000000000);
$a .= $b;
echo $a;
?>
Sth like this :
<?php
$position = GetRandomPosition(); // you will have to implement this function
if($position >= strlen($a) - 1) {
$a .= $b;
} else {
$str = str_split($a, $position);
$a = $str[0] . $b . implode(array_diff($str, array($str[0])));
}
?>
Cast $a to string, then use strlen to get the length of $a. Use rand, with with the length of $a as the maximum, to get a random position within $a. Then use substr_replace to insert $b into $a at the position you've just randomized.
Related
Here is my situation, let's say i have two variables:
$a = "Peter";
$b = "tall";
Then, i can combine this by
$c = " $a is very $b ";
which give me the string : "Peter is very tall"
However, if i have another variable $e passed to my function, and the string is " $a is very $b "
then, i print out $e, it just show me " $a is very $b ";
What i expected is "Peter is very tall", because $e is equal to $c.
This is the whole logic flow:
$e = " $a is very $b ";
getMsg($e);
function getMsg($e){
$a = "Peter";
$b = "tall";
$c = " $a is very $b ";
echo $c //Peter is very tall
echo $e //$a is very $b
}
How can i achieve this function?
You could use sprintf sprintf documentation. The %s symbols are string tokens that get substituted in the format string (the 1st param to sprintf).
$e = "%s is very %s";
getMsg($e);
function getMsg($e){
$a = "Peter";
$b = "tall";
echo sprintf($e, $a, $b);
}
Or a less coupled version of the getMsg() function:
function getMsg($msg,$name,$is){
echo sprintf($msg, $name, $is);
}
getMsg("%s is very %s", "Peter", "tall");
Please try this code. I hope this is what you want.
<?php
// Your code here!
$a = "Peter";
$b = "tall";
$e = $a."is very".$b;
getMsg($e,$a,$b);
function getMsg($e,$a,$b)
{
$c = $a."is very".$b;
echo $c;
echo $e;
}
?>
Try this. It should work fine. You need to Define $a and $b outside the function.
function getString($a,$b,$e){
$c = " $a is very $b ";
echo $c;
echo '<br/>'.$e;
}
$a = "Peter";
$b = "tall";
$e = " $a is very $b ";
$response = getString($a,$b,$e);
OUTPUT :
Peter is very tall
Peter is very tall
How check in PHP is my string $a at postion $i is string $b
$a = "Ha me duck who,garage?!"
$b = "duck"
$i = 7;
echo function($a,$b,$i); // will return true, but for other $i false
Since you want to check at multiple occurrences, this soln makes a substring at expected index (with length of needle) and checks if the strings match.
<? php
$a = "Ha me duck who,garage, duck?!";
$b = "duck";
$i = 23;
var_dump(chk($a, $b, $i));
function chk($a, $b, $i) {
return substr($a, $i, strlen($b)) === $b;
}
I have the following script
$a = 434343434343;
$b = $a *3;
$c = $a * 6;
print $a;
print $b;
print $c;
I want all three variables to be returned using the number_format($var) syntax. The three vars are being printed in various parts of an html template. What is the best way to do this for all three vars at once? Should I add these vars to an array and number_format the array?
The best that I can come up with is the following:
$a = 434343434343;
$b = $a *3;
$c = $a * 6;
$a = number_format($a);
$b = number_format($b);
$c = number_format($c);
print $a;
print $b;
print $c;
Is that preferred?
Put those numbers inside an array and format the array, it's faster.
$numbers = array();
$numbers['a'] = 434343434343;
$numbers['b'] = $numbers['a'] * 3;
$numbers['c'] = $numbers['a'] * 6;
foreach($numbers as $key => $val)
{
$numbers[$key] = number_format($val);
}
by the way, if you NEED the values as variables, you can extract them:
extract($numbers); //creates the variables $a, $b, $c
echo $a;
echo $b;
echo $c;
You can see it in action right here.
Seems I found a much better solution.
$a = number_format(434343434343);
$b = number_format($a *3);
$c = number_format($a * 6);
//$a = number_format($a);
//$b = number_format($b);
//$c = number_format($c);
//output
print $a;
print $b;
print $c;
function a(&$c, &$d){
$c = &$d;
}
$a = 1;
$b = 2;
a($a, $b);
echo $a;
output is 1,but shouldn't it be outputting 2 as $c is referencing $d. $c and $a reference to the same value,then $c refer to the value of $d which refer to $b so ultimately $a should refer to $b, isn't it correct?
For the operation you seek you must remove the ampersand reference used within the function a.
Example
function swap (&$one, &$two) {
$tmp = $one; // One is stored temporarily
$one = $two; // Two is stored in One
$two = $tmp; // Temporary data retrieved and stored in two
unset($tmp); // Temporary variable destroyed
}
// Set the variables
$a = 1;
$b = 2;
echo $a . " - " . $b . "<br />"; // See output as: 1 - 2
swap($a, $b);
echo $a . " - " . $b; // See output as: 2 - 1
in line
$c = &$d;
$a is referring to the address of $b but not to $b, then you can try this:
<?php
function foo(&$c, &$d){
$c = $d;
}
$a = 1;
$b = 2;
foo($a, $b);
echo $a;
?>
Adding a string with a variable $a = 'ABC-01-222222'; with $b = 1; and it should give $a = 'ABC-01-222223'
You can use explode() to split the value of $a into three parts. Then add $b to the third item of the array, and then re-join the parts using implode():
$a = 'ABC-01-222222';
$b = 1;
$parts = explode('-', $a);
$parts[2] += $b;
$a = implode('-', $parts);
echo $a;