I want to use jQuery to pull information from my database when I click a button.
i've managed to get console.log to display the following
[Object { id="16", user_to="Obadiah Stane", user_delivery_add1="The Lanesborough"}]
But I cant figure out how to pull each value for use in a Form.
Could someone help?
jQuery
$.post('/assets/inc/get-delivery-details.php', qString, function (data) {
console.log(data);
var json = $.parseJSON(data);
$('.addAddressDialog').html(json);
}, "json");
PHP
$q = "SELECT * FROM tbl_user_delivery WHERE id = '$selectedID'";
$sql = mysql_query($q);
$results = array();
while($row = mysql_fetch_array($sql))
{
$results[] = array(
'id' => $row['id'],
'user_to' => $row['user_to'],
'user_delivery_add1' => $row['user_delivery_add1']
);
}
echo json_encode($results);
$.post('/assets/inc/get-delivery-details.php', qString, function (data) {
//var json = $.parseJSON(data); // don't need this line, because you've
// already set dataType json as fourth
// arguments of $.post()
// To get values
alert(data[0].id);
alert(data[0].user_to); // so on
// To set above values to a form fields
// just an example, don't know your form markup
$('input[name=id]').val(data[0].id); // so on
}, "json");
$('.addAddressDialog').html(json.id); will output 16 in your example.
After parsing the variable json, it becomes an object.
Related
When call php from jquery via ajax ,have any response .I changed the dataTypeand put jsoninstead html.I´m thinking the issue is that,for the ajax call never trigger the php code,it seems $_POST['retriveForm'] never carries a value.
PHP:
if(isset($_POST["retriveForm"])) {
$data_json =array();
$id = $_POST['retriveForm'];
$sql = "SELECT * FROM mytable WHERE Id = $id";
while ($row = mysqli_fetch_array($db->consulta($sql)) {
$data_json = array('item1' => $row['item1'],'item2' => $row['item2']) ;
}
$data_json['item_array'] = call_a_function_return_array();//this works
echo json_encode($data_json);
}
and jQuery :
$(document.body).on('click', '.edit', function() {
var id = $(this).data('id');
$.ajax({
type: "POST",
url: "is_the_same_page.php",
data: {
retriveForm: id
},
dataType: "json",
success: function(response) {
$('#myForm').find('input').eq(1).val(response.item1);
}
});
});
Code is all in the same page if that may be important.
Since the AJAX code is in the same script, make sure you don't output any of the normal HTML in this case. Your PHP code should be at the very beginning of the script, before any HTML is output. And you should exit the script after echoing the JSON. Otherwise your JSON will be mixed together with HTML, and jQuery won't be able to parse the response.
Also, you're not correctly adding to $data_json in your loop. You're overwriting the variable each time instead of pushing onto it.
<?php
// code here to set up database connection
if(isset($_POST["retriveForm"])) {
$data_json =array();
$id = $_POST['retriveForm'];
$sql = "SELECT * FROM mytable WHERE Id = $id";
while ($row = mysqli_fetch_array($db->consulta($sql)) {
$data_json[] = array('item1' => $row['item1'],'item2' => $row['item2']) ;
}
$data_json['item_array'] = call_a_function_return_array();//this works
echo json_encode($data_json);
exit();
}
?>
<html>
<head>
...
Then in the success function, you'll need to index the elements of response, since it's an array, not a single object.
I'm creating my project using OOP. I need to pass all the values inserted in the database in the form of array. And it's a multidimensional array. SO when I pass now via ajax as a 'text' datatype it displays array in console.log(). But I'm unsure if this is the correct way and how to display the value in a table form in jquery.
Below are the functions where the values returned to the object in another page.
public function selectType()
{
$sql="SELECT * FROM car_type";
$stmt =connection::$pdo->prepare($sql);
$stmt->execute();
$carType=array();
while($row = $stmt->fetch())
{
array_push($carType,$row['car_type']);
}
return $carType;
}
public function selectMaker()
{
$sql="SELECT * FROM car_maker";
$stmt =connection::$pdo->prepare($sql);
$stmt->execute();
$carMaker=array();
while($row = $stmt->fetch())
{
array_push($carMaker,$row['car_maker']);
}
return $carMaker;
}
ANd this is how I'm fetching the values to be passed to another page to be displayed to the user.
$setting = new setting($car_type,$car_maker,$rental_type,$rental);
//$setting->connection;
$setting->addCarType();
$setting->addCarMaker();
$setting->addRentalBy();
$carType=$setting->selectType();
$carMaker=$setting->selectMaker();
$json=array();
array_push($json,array("type"=>$carType,"maker"=>$carMaker));
echo $json;
Finally ajax to fetch and display data
$("#submit").on("click",function()
{
$("#set_setting").submit(function(){
data = $(this).serialize()
$.ajax({
type: "POST",
dataType: "html",
url: "submit_setting.php", //Relative or absolute path to response.php file
data: data,
success: function(data) {
//hide the form
$("#set_setting").slideUp("slow");
//show the result
for (i = 0; i < data.length; i++) {
console.log(data);//outputs array
$(".the-return").html(data);
}
}
});
return false;
});
});
You need to pass array as JSON and post it using name value pairs.
var data = {a:{'foo':'bar'},b:{'this':'that'}};
$.ajax({ url : '/',
type : 'POST',
data : {'data':JSON.stringify(data)},
success : function(){ }
});
And in backend (PHP):
$data = json_decode($_POST['data']);
print_r($data);
// Result:
// Array( "a" => Array("foo"=> "bar"), "b" => Array("that" => "this"))
I am using a jquery ajax get method to fetch information from the server however I am having trouble parsing the information so that I may use it. My website has a gallery of products that will filter its items based on category.
Here is the jQuery ajax function:
$('.category').click(function() {
var category;
if ($(this).hasClass('Shirts')) {
category = 'shirts';
}
if ($(this).hasClass('Hats')) {
category = 'hats';
}
if ($(this).hasClass('Acc')) {
category = 'acc';
}
$.ajax({
type: 'GET',
url: 'galleryfetch.php',
data: { 'category' : category },
dataType: 'json',
success: function(data) {
arr = $.parseJSON(data);
alert(arr);
}
});
});
This is the php script that the information is posted to:
<?php
if ($_SERVER['REQUEST_METHOD'] == 'GET') {
$category = $_GET['category'];
$conn = mysqli_connect('localhost', '*****', '*****', 'clothing');
$rows = mysqli_query($conn, "SELECT * FROM products WHERE category = '".$category."'");
while ($row = mysqli_fetch_array($rows)) {
$arr[] = $row;
}
echo json_encode(array('data' => $arr));
}
I using the alert in the success function to see if the information is passed succesfully but at the moment there is no alert and i get an:
Unexpected token o error.
I'm not sure if I'm parsing the information correctly or if Im not correctly using JSON
tl;dr: $.parseJSON(data); should be removed.
Your server is returning JSON (but claiming it is sending HTML, you should have header("Content-Type: application/json")).
You have told jQuery to ignore the claim that it is HTML and parse it as JSON. (This would be redundant if you fixed the above problem)
dataType: 'json',
The parsed data is passed to your success function.
You then pass that data to JSON.parse so it gets converted to a string (which will look something like [ [Object object], ... and is not valid JSON) and then errors.
Remove:
arr = $.parseJSON(data);
And just work with data.
I have a table that has sortable rows. The table is generated from a mysql database that has a field called "displayorder" that oders the table. When the user drags and drops rows, I want to use AJAX to submit those changes to the database whenever a user drops a row.
Currently, I can see the console.log() output from the success part of the AJAX call, and when i output the data there (order) it looks great, like this:
["order_1=1", "order_2=2", "order_4=3", "order_3=4"]
But according to Firebug, all that's getting passed in the $_POST is "undeclared".
How do I access that order variable from my indexpage_order.php file?
I have this jquery code:
<script>
$(document).ready(function() {
var fixHelper = function(e, tr) {
var $originals = tr.children();
var $helper = tr.clone();
$helper.children().each(function(index)
{
$(this).width($originals.eq(index).width())
});
return $helper;
};
var sortable = $("#sort tbody").sortable({
helper: fixHelper,
stop: function(event, ui) {
//create an array with the new order
order = $(this).find('input').map(function(index, obj) {
var input = $(obj);
input.val(index + 1);
return input.attr('id') + '=' + (index + 1);
});
$.ajax({
type: 'POST',
url: 'indexpage_order.php',
data: order,
error: function() {
console.log("Theres an error with AJAX");
},
success: function(order) {
console.log("Saved.");
console.log(order);
}
});
return false;
}
});
});
</script>
indexpage_order.php contains:
if(isset($_POST) ) {
while ( list($key, $value) = each($_POST) ) {
$id = trim($key,'order_'); //trim off order_
$sqlCommand =
"UPDATE indexpage
SET displayorder = '".$value."'
WHERE id = '".$id."'";
$query = mysqli_query($myConnection,$sqlCommand) or die (mysqli_error($myConnection));
$row = mysqli_fetch_array($query);
}
}
You can simply rewrite the js code that are generating the data for POST.
order = {}
$(this).find('input').map(function(index, obj)
{
return order[this.id] = index;
}
)
Rest should work in PHP.
Try $_REQUEST instead of $_POST on the PHP file for POST method with ajax.
convert the js array order to json object as ajax data needs to be in json using JSON.stringify. hence, it needs to be data:JSON.stringify(order), in the ajax function.
Or, use json_encode like this data: <?php echo json_encode(order); ?>, in the ajax function
order is an array. Convert the order to query string like this in your ajax script,
data: order.join('&'),
It looks like your sending your order in a JavaScript array
And when it arrives at your PHP, its unreadable.
If its an object look into the json_decode function.
If its an array, serialize the data before it goes, then unserialize on the php side.
PHP is unable to understand JavaScript array or objects unless they are encoded/serialized correctly.
I'm using php to return an array of data, with the command json_encode(). I want to also send some other data after I send this array. I'm using the jquery library. My php code is as follows:
<?php
//// Query
$sql = "SELECT gtn FROM $table WHERE gid < 10";
//// Open connection
$con = pg_connect("host=12.12.2.2 port=5434 dbname=spatial_data user=postgres password=****");
if (!$con){echo 'error connecting'; die; }
//// Run query
$query = pg_query($con, $sql);
$arrayData = array(); // Store results from query in arrays
//// Parse results
while($r = pg_fetch_row($query)) {
$arrayData[] = $r[0];
}
echo json_encode($arrayData);
//// Return metadata about calculation
//echo "$('#messages').html('Result returned for New York')";
//// close connection
pg_close($con);
?>
This php is responding to a jquery post command:
$.ajax({
type: "POST",
url: "/php/array_test_v3.php",
data:{vertices: pointlist},
success: function(arrayData){
//console.log(arrayData[0])
for(i=0;i<arrayData.length; i++){
setGeoJson(arrayData[i]);
}
},
dataType:'json'
});
This is a spatial database, and when I query the information, I also want to return some other values. For example, if the area is New York, I want to return an array of data and also the string New York. At the moment the line echo "$('#messages').html('Result returned for New York')"; just appends to the array of information. Is there a way that I can escape from the array, or do I need to have a separate post function to get this information.
Instead of echo json_encode($arrayData);, just fetch the meta data and then do:
echo json_encode(array(
'data' => $arrayData,
'meta' => $metaData
));
And then in JQuery:
success: function(result){
for(i=0;i<result.data.length; i++){
setGeoJson(result.data[i]);
}
// do something with result.meta
},
assuming you are using php.
make the array like this below
while($r = pg_fetch_row($query)) {
$arrayData[] = array('gtn'=>$r[0],'someotherkey'=>'someothervalue','anotherkey'=>'anothevalue');
}
echo json_encode($arrayData);
now in jquery you can do this
$.ajax({
type: "POST",
url: "/php/array_test_v3.php",
data:{vertices: pointlist},
success: function(arrayData){
$.each(arrayData,function(index,value){
setGeoJson(value.gtn);
$('#messages').html(value.someotherkey);
})
},
dataType:'json'
});
like this you can append or do any thing you like..