I have a page where I search for the books that an author wrote (really basic search based on an assignment I had 2 months ago). I choose the author from a dropdown box and after I press the "Submit" button the results should appear.
Here is the page's code:
<?php
include ("includes/connections.php");
if($_POST)
{
if (!isset($_POST["authors"])){
header("Location: searchAuthor.php");
exit;
}
foreach ($_POST["authors"] as $author)
{
?????????
}
}
?>
<?php include ("includes/connections.php");
function dropdown($intIdField, $strfNameField, $strlNameField, $strTableName, $strOrderField, $strNameOrdinal, $strMethod="asc") {
echo "<select name=\"{$strNameOrdinal}[]\">\n";
echo "<option value=\"NULL\">Select Value</option>\n";
$strQuery = "SELECT $intIdField, $strfNameField, $strlNameField
FROM $strTableName
ORDER BY $strOrderField $strMethod";
$rsrcResult = mysql_query($strQuery) or die(mysql_error());
while($arrayRow = mysql_fetch_assoc($rsrcResult)) {
$strA = $arrayRow["$intIdField"];
$strB = $arrayRow["$strlNameField"] . " " . $arrayRow["$strfNameField"];
echo "<option value=\"$strA\">$strB</option>\n";
}
echo "</select>";
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Add Book Information</title>
<link href="back.css" rel="stylesheet" type="text/css" />
</head>
<body>
<h1>Search for Books of an Author</h1><table width="528" border="0" align="center">
<tr>
<td width="480"><span id="tip">*Hitting the "Search books of Author" button without filling the fields with an asterisk will just reset the form</span></td>
</tr>
</table>
<form method="post" action="<?php echo $_SERVER['PHP_SELF'];?>" id="formBook">
<table width="563" border="0" align="center">
<tr>
<td style="text-align: right"><label for="authors">Select an Author*:</label></td>
<td><?php dropdown("author_ID", "author_firstname", "author_lastname", "author", "author_lastname", "authors"); ?></td>
</tr>
<tr>
<td> </td>
<td> </td>
</tr>
<tr>
<td> </td>
<td><input type="submit" name="submit" id="submit" value="Search books of Author" /></td>
</tr>
<tr>
<td><div align="left"><img src="images/buttonleft.png" alt="previous" width="70" height="70" usemap="#Previous" border="0"></div></td>
<td><div align="right"><img src="images/buttonright.png" alt="next" width="70" height="70" usemap="#Next" border="0">
<map name="Previous">
<area shape="circle" coords="35,35,33" href="addSubject.php">
</map>
<map name="Next">
<area shape="circle" coords="35,35,33" href="addEdition.php">
</map>
</div></td>
</tr>
</table>
</form>
</body>
</html>
As you can see I have everything inside a table (convenient for small stuff like this). I want when I press the submit button, the author that was chosen to be inputed in a method which will display the results from the query. The query will be executed in the foreach where the ?????? are. Then I want the result of the query to be used to display inside my table (by adding more rows and inserting one result in each row through a php function) the results.
Is there a way to do that just with php? I don't know how to use Javascript just php and html. Even if I have to insert the result of the query in another page and display everything there I'm ok with that.
I haven't written the query just yet.
Actually the foreach is there to put in a single variable each book the author has written.
Here's an example. Queries/fields are bogus.
<?php
if (isset($_POST['Submit'])) {
$strQuery = "SELECT 'field1', 'field2', 'field3'
FROM $strTableName
ORDER BY $strOrderField $strMethod";
$rsrcResult = mysql_query($strQuery) or die(mysql_error());
?>
<table>
<td> HEADER 1 </td> <td> HEADER 2 </td> <td> HEADER 3 </td>
<?php
while ($row = mysql_fetch_array($rsrcResult) {
echo "<tr><td>".$row['field1']."</td><td>".$row['field2']."</td><td>".$row['field3']."</td>";
}
?>
</table>
Related
This is very quick.
I have a form that when submitted should add user input into my DB. I have had a similar form working well but for some reason this one is not working.
Please excuse my sloppy code but here is the whole page. For some reason 'observation' will not take the user input and display it on the next page (showOne.php). The next page simply shows a blank space for observation and I checked the DB and there was nothing in the observation field of course.
Is it something simple that I can't see? I've been at this for days since it is identical to another form I have that works well on another page.
Thank you for any insight.
<?php
//including the database connection file
include("config.php");
$activePage = "start.php";
if(isset($_POST['update'])) {
$id = $_POST['id'];
$observation = $_POST['observation'];
$result = mysqli_query($mysqli, "UPDATE tasks SET observation='$observation' WHERE id=$id");
header("Location: showOne.php?id=$id");
}
//getting id from url
$id = $_GET['id'];
//selecting data associated with this particular id
$result2 = mysqli_query($mysqli, "SELECT * FROM users WHERE id=$id ORDER BY id ASC");
$result = mysqli_query($mysqli, "SELECT * FROM tasks ORDER BY taskNumber ASC");
include_once "nav.php";
?>
<!doctype html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>Pathfinder - A User Testing Dashboard</title>
<meta name="description" content="Pathfinder - A User Testing Dashboard">
<meta name="author" content="James Stables - Thurs April 13th 2017">
<link rel="stylesheet" href="core.css">
<link href="https://fonts.googleapis.com/css?family=Open+Sans:400,600,700" rel="stylesheet">
<!--[if lt IE 9]>
<script src="https://cdnjs.cloudflare.com/ajax/libs/html5shiv/3.7.3/html5shiv.js"> </script>
<![endif]-->
<script src="http://code.jquery.com/jquery-latest.min.js" type="text/javascript"></script>
</head>
<body>
<header>
<h1 class="logo"><img src="images/logo.png">Pathfinder</h1>
<h4>User Testing Dashboard</h4>
</header>
<section class="nonav">
<div class="showAllUsers">
<table border='0'>
<tr>
<?php while($res = mysqli_fetch_array($result2))
{ ?>
<td class="widthHundred no-border left"><h2><?php echo $res['nameFirst']; ?></h2></td>
<?php } ?>
</tr>
</table>
<table border='0'>
<thead>
<tr>
<th>Image</th>
<th>Category</th>
<th>Task Number</th>
<th>Task Name</th>
<th>Observation</th>
<td> </td>
<td> </td>
<td> </td>
</tr>
</thead>
<tbody>
<form name="start" method="post" action="start.php" enctype="multipart/form-data">
<tr>
<td><a href="<?php echo $res['$image'];?>" data-lightbox="example-1" data-title="Task Number <?php echo $res['taskNumber'];?>">
<img id="imageResize" src="<?php echo $res['image'];?>" /></a></td>
<td><?php echo $res['category'];?></td>
<td><?php echo $res['taskNumber'];?></td>
<td><?php echo $res['taskName'];?></td>
<td><input type="text" name="observation" value="<?php echo $res['observation'];?>"></td>
<td> </td>
<td> </td>
<td> </td>
<?php } ?>
</tr>
<tr>
<td> </td>
<td> </td>
<td> </td>
<td> </td>
<td> </td>
<td> </td>
<td><input type="hidden" name="id" value="<?php echo $_GET['id'];?>"><input type="submit" class="buttonUpdate right" name="update" value="Update"></td>
<td><a class="buttonCancel right" href="tasks.php" onClick="return confirm('Cancel and go back?')">Cancel</a></td>
</tr>
</form>
</tbody>
</table>
</div>
</section>
<script src="js/lightbox-plus-jquery.min.js"></script>
<script>
lightbox.option({
'resizeDuration': 200,
'showImageNumberLabel': false,
'fitImagesInViewport': true
})
</script>
</body>
</html>
I want to update record in php using GET method but whenever i click on "update button" it does not change anything and just refresh the page.and data remains the same.Here are the codes. Kindly tell me where i m doing it wrong. Thanks
<?php
include_once"dbconfig.php";
if(isset($_GET['edit']))
{
$id=$_GET['edit'];
echo $id;
$sql_query="SELECT * FROM users WHERE user_id='$id' ";
$result_set=mysql_query($sql_query);
$fetched_row=mysql_fetch_array($result_set);
}
if(isset($_POST['btn-update']))
{
// variables for input data
$first_name=$_POST['first_name'];
$last_name=$_POST['last_name'];
$city_name=$_POST['city_name'];
//sql query to update into database
$sql_query="UPDATE users SET first_name='$first_name',last_name='$last_name',user_city='$city_name' WHERE user_id='$id' ";
mysql_query($sql_query);
//if(!$sql_query)
//die('data can not update'.mysql_error());
//else
//echo 'data updated successfully';
}
?>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html;charset=utf-8" />
<link rel="stylesheet" href="style.css" type="text/css" />
</head>
<body>
<center>
<form method="post">
<table align="center">
<tr>
<td><input type="text" name="first_name" placeholder="First Name" value="<?php echo $fetched_row['first_name']; ?>"required /> </td>
</tr>
<tr>
<td><input type="text" name="last_name" placeholder="Last Name" value="<?php echo $fetched_row['last_name']; ?>" required /> </td>
</tr>
<tr>
<td><input type="text" name="city_name" placeholder="City" value="<?php echo $fetched_row['user_city']; ?>" required /> </td>
</tr>
<tr>
<td>
<button type="submit" name="btn-update"><strong>UPDATE</strong></button>
</td>
</tr>
</table>
</form>
</center>
</body>
</html>
Second File
<?php
include_once"dbconfig.php";
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8"/>
<title>CRUD Operations With php and MySql </title>
<link rel="stylesheet" href="style.css" type="text/css"/>
</head>
<body>
<center>
<div id="body">
<div id="content">
<table align="center">
<table align="center">
<tr>
<th colspan="9">Add data Here ! </th>
</tr>
<tr>
<th colspan="2">FirstName </th>
<th colspan="8">LastName</th>
<th colspan="4">CityName </th>
<th>Operations</th>
<!--<th colspan="2">Operations</th> -->
</tr>
<?php
$sql_query="SELECT * FROM users";
$result_set=mysql_query($sql_query);
while($row=mysql_fetch_row($result_set))
{
?>
<tr>
<td><?php echo $row[0]; ?> </td>
<td colspan="4"><?php echo $row[1]; ?></td>
<td colspan="6"><?php echo $row[2];?></td>
<td colspan="4"><?php echo $row[3];?></td>
<td> <a href='edit_data.php?edit=$row[0]'>EDIT</a> </td>
<!--<td align="center"><a href="javascript edt_id('<//?php echo $row[0]; ?><img src="b_edit.png" align="EDIT" /></a></td>
<td align="center"><a href="javascript:delete_id('<//?php echo $row[0];?><img src="b_drop.png" align="DELETE" /></a></td>
</tr> -->
<?php
}
?>
</table>
</div>
</div>
</center>
</body>
</html>
Change
mysql_query($sql_query);
To
mysql_query($sql_query) or die (mysql_error()) ;
You're not sending the id (the form action property is missing
I want to create a crf form for my university project .
i created course table i select some data from course but where student click the completed course and next click .then next page show same data base table but not those courses, student already selected.and
then student can subset for applied courses.
But when i select some course and click next, But it show the previous row in course table. but i want selected course row not select when i click . cause completed course not want to select for applying course.
I want to select some row from a database when aply it show the same databases all row except the selected row
i add the same line in the problem line..
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html>
<head>
<title>
CRF Form
</title>
<link rel="stylesheet" href="CSS/admin_style.css" >
</head>
<body>
<div id="header">
<a href="index.php">
<h1>
Welcome to the CRF Form
</h1>
</a>
</div>
<form action="selection.php" method="POST" enctype="multipart/form-data" >
<div id="">
<table width="1000" border="5" align="center">
<tr>
<td colspan="8" align="center" bgcolor="yellow">
<h1>
Slect your completed course
</h1>
</td>
</tr>
<tr bgcolor="orange">
<th>
selection:
</th>
<th>
Course id:
</th>
<th>
Course title:
</th>
<th>
Course credits:
</th>
<th>
Course statust:
</th>
<th>
Delete Post:
</th>
<th>
Edit Post:
</th>
</tr>
<?php
include("includes/connect.php");
$query="select * from course";
$run=mysql_query($query);
while($row=mysql_fetch_array($run)){
$id=$row['id'];
$course_id=$row['course_id'];
$course_title=$row['course_title'];
$course_credits=$row['course_credits'];
$course_status=$row['course_status'];
?>
<tr align="center" bgcolor="pink">
<td>
<input type="checkbox" name="complete[]" value="<?php echo $id; ?>" />
</td>
<td>
<?php echo $course_id; ?>
</td>
<td>
<?php echo $course_title; ?>
</td>
<td>
<?php echo $course_credits; ?>
</td>
<td>
<?php echo $course_status; ?>
</td>
<td>
<a href="delete.php?del=<?php echo $post_id ?>">
Delete
</a>
</td>
<td>
<a href="Edit.php?edit=<?php echo $post_id ?>">
Edit
</a>
</td>
</tr>
<?php } ?>
<tr>
<td align="center" colspan="7">
<input type="submit" name="sub" value="NEXT">
</td>
</tr>
</table>
</form>
</div>
</body>
</html>
this is the selec.php
<html>
<head>
<title>
CRF Form
</title>
<link rel="stylesheet" href="CSS/admin_style.css" >
</head>
<body>
<div id="header">
<a href="index.php">
<h1>
Welcome to the CRF Form
</h1>
</a>
</div>
<div id="">
<table width="1000" border="5" align="center">
<tr>
<td colspan="8" align="center" bgcolor="yellow">
<h1>
Slect your completed course
</h1>
</td>
</tr>
<tr bgcolor="orange">
<th>selection:</th>
<th>Course id:</th>
<th>Course title:</th>
<th>Course credits:</th>
<th>Course statust:</th>
<th>Delete Post:</th>
<th>Edit Post:</th>
</tr>
<?php
include("includes/connect.php");
$check=$_POST['complete'];
foreach($check as $ch){
$select= " id!='".$ch."' and ";//here is the problem
}
$query="select * from course
where $select id!='0'";
$run=mysql_query($query);
while($row=mysql_fetch_array($run)){
$id=$row['id'];
$course_id=$row['course_id'];
$course_title=$row['course_title'];
$course_credits=$row['course_credits'];
$course_status=$row['course_status'];
?>
<tr align="center" bgcolor="pink">
<td>
<input type="checkbox" name="completed" /></input>
</td>
<td><?php echo $course_id; ?></td>
<td><?php echo $course_title; ?></td>
<td><?php echo $course_credits; ?></td>
<td><?php echo $course_status; ?></td>
<td>Delete</td>
<td>Edit</td>
</tr>
<?php } ?>
</table>
</div>
</body>
</html>
I think that you're saying the once the course is selected it shouldn't be displayed on the next page where the student can have a look on the other courses?
If is so then you can use following sql query on the next page where you don't want to display the student's completed course.
SELECT * FROM course WHERE id != $course_id
Let me know if I'm wrong. I didn't comment out as my reputations were low and stackoverflow didn't allow me to.
[EDITED]
This is your complete code.
Your select php file:
//assuming that you are logging in the students with their username or email id, if so then store their username in a session where logging in.
<?php
$user = $_SESSION['username'];
include("includes/connect.php");
if (isset($_POST['submit'])){
$course_id= $_POST['course_id'];
$course_title= $_POST['course_title'];
$course_credits= $_POST['course_credits'];
$course_status= $_POST['course_status'];
$query="SELECT course.id,course.title,course.credits,course.status FROM course WHERE course.username = $user";
$run=mysqli_query($conn,$query);
while($row=mysqli_fetch_array($run)){
$course_id= $_SESSION['course_id'] = $row['course_id'];
$course_title=$row['course_title'];
$course_credits=$row['course_credits'];
$course_status=$row['course_status'];
}
?>
Now in your next php file :
$already_selected_course = $_SESSION['course_id'];
Now the query should look like.
$query = "SELECT course.id,course.title,course.credits,course.status FROM course WHERE course.id != $already_selected_course";
This is it. Note: This solution might contain some errors of brackets etc but the logic is clear.
For better knowledge have a look at my MySQL Complete Video Series here!
I am trying to create a page that displays rpg ranks from a mysql database on a webpage
i went into the database and organized the data by level, so the person with the highest level is shown first and so on, however the database does not contain a table for ranks
I am trying to do that manually in dreamweaver but I don't know how, can I create a counter and have it display in the table?
I managed to get the following:
http://slayersgaming.com/rpgranks2.php
<?php
$dbh=mysql_connect("********", "**********", "*********") or die('Cannot connect to the database because: '. mysql_error());
mysql_select_db("C368969_thcrpgCSGO");
$rpgranks_sql = "SELECT * FROM `thc_rpg` ORDER BY `thc_rpg`.`level` DESC LIMIT 0, 30 ";
$rpgranks_query = mysql_query($rpgranks_sql) or die(mysql_error());
$rsrpgranks = mysql_fetch_assoc($rpgranks_query);
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<p>
<table width="501" height="58" border="0">
<tr>
<td width="240"><h2><strong>Name</strong></h2></td>
<td width="70"><strong>Level</strong></td>
<td width="70"><strong>XP</strong></td>
<td width="70"><strong>Credits</strong></td>
<td width="70"><strong>Rank</strong></td>
</tr>
</table>
<?php do{ ?>
<table width="501" height="58" border="0">
<tr>
<td width="240"><?php echo $rsrpgranks['name'];?></td>
<td width="70"><?php echo $rsrpgranks['level'];?></td>
<td width="70"><?php echo $rsrpgranks['xp'];?></td>
<td width="70"><?php echo $rsrpgranks['credits'];?></td>
<td width="70"> </td>
</tr>
</table>
<?php } while ($rsrpgranks = mysql_fetch_assoc($rpgranks_query)) ?>
</p>
<p> </p>
</body>
</html>
screen cap here: http://oi47.tinypic.com/21exdfs.jpg
This is actually really easy to do. You just need a counter in your do-while loop like this:
<?php
$counter = 1;
do{
?>
<table width="501" height="58" border="0">
<tr>
<td><?php echo $counter; ?></td>
<td width="240"><?php echo $rsrpgranks['name'];?></td>
<td width="70"><?php echo $rsrpgranks['level'];?></td>
<td width="70"><?php echo $rsrpgranks['xp'];?></td>
<td width="70"><?php echo $rsrpgranks['credits'];?></td>
<td width="70"> </td>
</tr>
</table>
<?php
$counter++;
} while ($rsrpgranks = mysql_fetch_assoc($rpgranks_query))
?>
I'm creating a simple website for a business to display their products. On the index page I display the 3 newest products. What I need to do now is have a category page people can go to to view products in a certain category. I tried adapting the code from my index page but the products aren't showing up on my category.php.
I have a product_list.php with the different categories, when one is selected I'm trying to load category.php with the products from the category that was selected.
What I have:
product_list.php
<?php
include "storescripts/connect_to_mysql.php";
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<style type="text/css">
</style>
<meta name="Description" content="Lightweight aluminum boat docks, lifts, and accessories" />
<meta name="Keywords" content="Aluminum boat dock ladder lift water wheels" />
<script src="scripts/swfobject_modified.js" type="text/javascript"></script>
</head>
<title><?php echo $product_name; ?></title>
<link rel="stylesheet" href="style/style.css" type="text/css" media="screen"/>
</style>
<body>
<div align="center" id="mainWrapper">
<?php include_once("template_header.php");?>
<table width="100%" border="0" cellspacing="0" cellpadding="15">
<tr>
<td valign="top" align="center"><table width="100%" border="1">
<tr>
<td align="center"><p>Aluminum Docks</p>
<p><img src="inventory_images/aluminum docks/PN99002-6_24x4_PKG_LG.jpg" width="100" height="64" alt="24X4" /></p></td> // There's a field in my DB called categories, and 'docks' is the value assigned to the products
<td align="center"><p>Floating Docks</p>
<p><img src="inventory_images/floating dock/100225279.jpg" width="100" height="60" alt="Floating Dock" /></p></td>
<td align="center"><p>Frame Docks</p>
<p><img src="inventory_images/frame dock/frameDock.jpg" width="100" height="64" alt="Frame Dock" /></p></td>
<td align="center"><p>Pipe Docks</p>
<p><img src="inventory_images/pipe dock/PN99002_16X4_SECTION_LG.jpg" width="100" height="64" alt="Pipe Dock" /></p></td>
</tr>
<tr>
<td align="center"><p>Boat Lifts</p>
<p><img src="inventory_images/boat lifts/GM1060_LG.jpg" width="100" height="64" alt="Boat Lift" /></p></td>
<td align="center"><p>Boat Lift Accessories</p>
<p><img src="inventory_images/boat lift acceessories/canopy_lg (1).png" width="100" height="64" alt="Boat Lift Accessory" /></p></td>
<td align="center"><p>Rollers & Caddies</p>
<p><img src="inventory_images/rollers and caddies/caddy270 (1).jpg" width="100" height="64" alt="Caddy" /></p></td>
<td align="center"><p>Accessories</p>
<p><img src="inventory_images/accessorries/2step_LG.png" width="100" height="64" alt="Accessory" /></p></td>
</tr>
</table>
</table>
<p> </p>
<?php include_once("template_footer.php");?>
</div>
</body>
</html>
in category.php I'm trying to create a variable called $dynamicList with all the products that have "dock" as a category. But when I echo out $dynamicList nothing is rendered.
<?php
// Run a select query to get my letest 6 items
// Connect to the MySQL database
include "storescripts/connect_to_mysql.php";
$category=$_GET['category'];
$sql = mysql_query("SELECT * FROM products WHERE category='$category' LIMIT 6");
$productCount = mysql_num_rows($sql); // count the output amount
if ($productCount > 0) {
while($row = mysql_fetch_array($sql)){
$id = $row["id"];
$product_name = $row["product_name"];
$price = $row["price"];
$date_added = strftime("%b %d, %Y", strtotime($row["date_added"]));
$dynamicList .= '<table width="100%" border="0" cellspacing="0" cellpadding="6">
<tr>
<td width="17%" valign="top"><img style="border:#666 1px solid;" src="inventory_images/' . $id . '.jpg" alt="' . $product_name . '" width="100" height="64" border="1" /></td>
<td width="83%" valign="top">' . $product_name . '<br />
$' . $price . '<br />
View Product Details</td>
</tr>
</table>';
}
} else {
$dynamicList = "We have no products listed in our store yet";
}
mysql_close();
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<style type="text/css">
</style>
<meta name="Description" content="Lightweight aluminum boat docks, lifts, and accessories" />
<meta name="Keywords" content="Aluminum boat dock ladder lift water wheels" />
<script src="scripts/swfobject_modified.js" type="text/javascript"></script>
</head>
<title><?php echo $category; ?></title>
<link rel="stylesheet" href="style/style.css" type="text/css" media="screen"/>
</style>
<body>
<div align="center" id="mainWrapper">
<?php include_once("template_header.php");?>
<table width="100%">
<tr>
<td valign="top"><p><?php echo $dynamicList;?><br />
</p>
<p> </p>
<p> </p> <h2> </h2></td>
</tr>
</table>
<p> </p>
<?php include_once("template_footer.php");?>
</div>
</body>
</html>
EDIT: $dynamicList is nested in a condition statement. Just write
$dynamicList = '';
before your query
What is the current output on the page? Are the # of rows returned in the query = 0?
You should also sanitize your $category input using mysql_real_escape_string()
WHERE category ='".mysql_real_escape_string($category)."' ...
You must sanitize first the strings using this function:
public static function real_escape($string)
{
if (null != $string) {
$string = (get_magic_quotes_gpc()) ? $string : addslashes($string);
return mysql_real_escape_string($string);
}
return $string;
}
Or better use third party script like phpDataMapper
$sql = mysql_query("SELECT * FROM products WHERE category='$category' LIMIT 6");
should be
$sql = mysql_query("SELECT * FROM products WHERE category='".$category."' LIMIT 6");
This is the only error I can discover for now