I am trying to reconstruct a WAV/MP3 file from raw bases64 encoded data submitted in in a form. I understand th the steps should be something like:
1. Create new file
2. use file_put_content onto the new file with the decoded data
Is this correct? And what is the best/easiest way to do so?
Related
I have included the javascript in my project and FilePond works great on the FrontEnd, as you can see below:
Here is the code in my HTML:
When I submit the form this is what I get for filepond:
Code:
https://snipsave.com/user/viktorgavrilovic/snippet/TpgWPYaBBmWe1N44YO/
Now, how can I save the image to a folder, let's say: C:/temp/?
I know that I have to decode because the data is base64 encoded, here is my PHP so far, with decoded format:
$filepond = $_POST["filepond"];
$json_decoded = json_decode($filepond[0], true);
var_dump($json_decoded);
and this is what I get from the decoded format:
Code:
https://snipsave.com/user/viktorgavrilovic/snippet/u3Th8eqrzvmq6IAWAI/
Could you please tell me what should I do next in order to save the image in a folder and in a MySql DB? Thank you very much!
I have a weird problem. I want to upload some data with WinInet to a PHP script.
When I upload the data at once with HttpSendRequest(), then PHP reads the uploaded data correctly, e.g.
$entityBody = file_get_contents('php://input');
When I upload the data in parts with HttpSendRequestEx() and InternetWriteFile() , then the same data is uploaded, but PHP fails to read the input (empty).
What could be wrong?
Is the PHP script "called" before the entire data is uploaded?
If so, how do I get the data?
Found it, Content-Length header was missing.
I want to send base64 decoded data to php file from ajax, but my half of the data get truncated, not able to send entire data through ajax to php file.
I am sending this: data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAkAAAAJACAYAAABlmtk2AAAgAElEQ…/Hv59f3b//PQ+Q/3vcf35r/vmLQP0RPc/m74Zy4dP//wBHqel8UTBFDwAAAABJRU5ErkJggg==
and converting the base64 image to normal image like jpg
Any Help ?
Just a guess. Don't hurt me Stackoverflow gods. :-) Use JSON, not urlencoding. Make an object literal and then put your data inside. Send the data your PHP file and use json_decode.
var image {image: "data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAkAAAAJACAYAAABlmtk2AAAgAElEQ…/Hv59f3b//PQ+Q/3vcf35r/vmLQP0RPc/m74Zy4dP//wBHqel8UTBFDwAAAABJRU5ErkJggg=="};
I have a dump of our LDAP database, and i'm attempting to extract all images from it using PHP. The images seem to be stored in JFIF format (at least, according to https://www.rfc-editor.org/rfc/rfc2798#page-5). However, i can't figure out how to create a JPEG file from this; I attempted file_put_contents to dump everything in name.jpeg, imagecreatefromstring's output to imagejpeg and some variations on those. However, either I'm not using them correctly, or I'm just attempting this wrong alltogether.
So the question:
Here's a small part of the field:
jpegPhoto:: /9j/4AAQSkZJRgABAQAAAQABAAD//gA+Q1JFQVRPUjogZ2QtanBlZyB2Mi4wICh1c2lu
ZyBJSkcgSlBFRyB2NjIpLCBkZWZhdWx0IHF1YWxpdHkK/9sAQwAIBgYHBgUIBwcHCQkICgwUDQwLCww
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The data is base64 encoded, decode it first and then save it to a file. See http://www.php.net/manual/en/function.base64-decode.php
Ok, I'm hoping I can explain my situation rather than pasting lines and lines of code.
Currently, JSON sends positional info to my PHP file which in turn uses this data to generate an image, saves it and returns the filename via JSON back to browser. Javascript then refreshes the image on screen.
This all works fine at the moment, but I am wanting to optimise the process and look at the possibility of outputting the image file straight after it's created then save afterwards.
My ideal solution would be something like:
header('Content-Type: image/gif');
echo $this->canvas;
// Save user file
$this->canvas->writeImage( $this->userFile = 'user_img.gif' );
$this->canvas->destroy();
// encode everything and send to browser
echo json_encode(array('misc data back to the browser'));
(I still need to send data back to browser via JSON)
And in my HTML I would have the image laid out like this:
<img src='json-processing-script.php' />
But as usual nothing is ever that simple, so I'd like to hear if anyone can make any pointers.
In your example, the json would be added to the gif, messing up your image. If you want to return these two completely different things from your php script, you would have to encode the image, add it to the json and extract it in the javascript to get the source of your image.
See for example this question.