I want my users to be able to make a favourite list.
I have two tables in a database in mySQL. One stores information about businesses and the other stores the unique user ids as well as the ids from the first table that the user has marked a favourite.
Table 1
<pre>
ID | NAME | EMAIL | PHONE |
1 | Joe | a#mail.com | 25634565 |
2 | John | b#mail.com | 43634565 |
3 | Jack | c#mail.com | 65634565 |
4 | James| d#mail.com | 43634565 |
5 | Julie| e#mail.com | 65634565 |
...
</pre>
Table 2
<pre>
USERID | FAV1 | FAV2 | FAV3 | FAV...
2565325489 | 1 | 3 | 5 |
8596854785 | 3 | 2 | NULL |
2356256263 | 5 | NULL | NULL |
...
</pre>
The output I want for a user (in this example the first in table2):
<pre>
Joe | a#mail.com | 25634565 |
Jack | c#mail.com | 65634565 |
Julie| e#mail.com | 65634565 |
</pre>
I have looked into JOIN LEFT and minus query calls, but I just can't make it work. I have a basic understanding of mySQL and PHP, but not a lot.
I would highly appreciate any help with what approach to take.
Ps. If there are better ways to structures my databases, I would love to know.
I'd use a table with two fields - userID and fav - make one entry for each entry. And then...
SELECT table1.name, table1.email, table1.phone FROM table1,table2 WHERE table2.fav = table1.id AND table2.userid = 2565325489
Select * from table1 InnerJoin (Select * from table2) as t4 on table1.ID=t4.FAV1
$result = mysqli_query('SELECT name,email,phone FROM t1 table1 LEFT JOIN table2 t2 ON t1.ID = t2.fav1');
//iterate the results
while ($row = mysqli_fetch_array($result))
{
echo $row['name']." ".$row['email']." "$row['phone'];
}
Related
unfortunately i have to do this in mysql / php . I looked for three days, and there is like 10.000 explantions of this but NONE (and I repeat NONE) works for me. I tried it all. I have to ask, sorry.
I have two tables - articles and control.
table "articles"
------------------
art_id | name |
------------------
1 | aaa |
2 | bbb |
3 | ccc |
4 | ddd |
table "control"
--------------------------------------------
con_id | art_id | data |
--------------------------------------------
1 | 1 | something-a |
2 | 2 | something-b |
3 | 1 | something-a |
4 | 2 | something-c |
5 | 3 | something-f |
art_id exists in both tables. Now what i wanted - for query:
"select * from articles order by art_id ASC" displayed in a table
to have also one cell displaying the count for each of art_id's from table CONTROL...
and so i tried join, left join, inner join - i get errors ... I also tried for each get only one result (for example 2 for everything)... this is semi-right but it displays the array of correct results and it's not even with join!!! :
$query = "SELECT art_id, count(*) as counting
FROM control GROUP BY art_id ORDER BY con_id ASC";
$result = mysql_query($query);
while($row=mysql_fetch_array($result)) {
echo $row['counting'];
}
this displays 221 -
-------------------------------------------------
art_id | name | count (this one from control) |
-------------------------------------------------
1 | aaa | 221 |
2 | bbb | 221 |
3 | ccc | 221 |
and it should be:
for art_id(value1)=2,
for art_id(2)=2,
for art_id(3)=1
it should be simple - like a count of values from CONTROL table displayed in query regarding the "articles" table...
The result query on page for table articles should be:
"select * from articles order by art_id ASC"
-------------------------------------------------
art_id | name | count (this one from control) |
-------------------------------------------------
1 | aaa | 2 |
2 | bbb | 2 |
3 | ccc | 1 |
So maybe i should go with JOIN or with join plus for each... Tried tha too, but then i'm not sure what is the proper thing to echo... all-in-all i'm completely lost here. Please help. Thank you.
So imagine this in two steps:
Get the counts per art_id from the control table
Using your articles table, pick up the counts from step 1
That will give you a query that looks like this:
SELECT a.art_id, a.name, b.control_count
FROM articles a
INNER JOIN
(
SELECT art_id, COUNT(*) AS control_count
FROM control
GROUP BY art_id
) b
ON a.art_id = b.art_id;
Which will give you the results you're looking for.
However, instead of using a subquery, you can do it all in one shot:
SELECT a.art_id, a.name, COUNT(b.art_id) AS control_count
FROM articles a
INNER JOIN control b
ON a.art_id = b.art_id
GROUP BY a.art_id, a.name;
SQL Fiddle demo
SELECT *, (SELECT COUNT(control.con_id) FROM control WHERE control.art_id = articles.art_id) AS count_from_con FROM articles ORDER BY art_id DESC;
If I understood your question right, this query should do the trick.
Edit: Created the tables you have described, and it works.
SELECT * FROM articles;
+--------+------+
| art_id | name |
+--------+------+
| 1 | aaa |
| 2 | bbb |
| 3 | ccc |
| 4 | ddd |
+--------+------+
4 rows in set (0.00 sec)
SELECT * FROM control;
+--------+--------+------+
| con_id | art_id | data |
+--------+--------+------+
| 1 | 1 | NULL |
| 2 | 2 | NULL |
| 3 | 1 | NULL |
| 4 | 2 | NULL |
| 5 | 3 | NULL |
+--------+--------+------+
5 rows in set (0.00 sec)
SELECT *, (SELECT COUNT(control.con_id) FROM control WHERE control.art_id = articles.art_id) AS count_from_con FROM articles ORDER BY art_id ASC;
+--------+------+----------------+
| art_id | name | count_from_con |
+--------+------+----------------+
| 1 | aaa | 2 |
| 2 | bbb | 2 |
| 3 | ccc | 1 |
| 4 | ddd | 0 |
+--------+------+----------------+
You haven't quite explained what you want to accomplish with the print out but here is an example in PHP: (Use PDO instead of mysql_)
$pdo = new PDO(); // Make your connection here
$stm = $pdo->query('SELECT *, (SELECT COUNT(control.con_id) FROM control WHERE control.art_id = articles.art_id) AS count_from_con FROM articles ORDER BY art_id ASC');
while( $row = $stm->fetch(PDO::FETCH_ASSOC) )
{
echo "Article with id: ".$row['art_id']. " has " .$row['count_from_con'].' connected rows in control.';
}
Alternatively with the mysql_ extension:
$result = mysql_query('SELECT *, (SELECT COUNT(control.con_id) FROM control WHERE control.art_id = articles.art_id) AS count_from_con FROM articles ORDER BY art_id ASC');
while( $row = mysql_fetch_assoc($result) )
{
echo "Article with id: ".$row['art_id']. " has " .$row['count_from_con'].' connected rows in control.';
}
This should be enough examples to help you accomplish what you need.
I having two tables
table 1: users
| id | username |
| 1 | john |
| 2 | marry |
| 3 | deep |
| 4 | query |
| 5 | value|
and
table 2:users_2
| table_2_id | user_id |
| 1 | 2,4 |
I need required something like this
| table_2_id | username |
| 1 | marry,query |
anyone can help me for this output in mysql
Is this what you are looking ?
select
`users_2`.`table_2_id` , GROUP_CONCAT(`users`.`username`) as `usernames`
from `users_2`
inner join `users` on FIND_IN_SET(`users`.`id`,`users_2`.`user_id`)
Check output here
http://sqlfiddle.com/#!2/c498bc/3
select a.table_2_id,b.username
from users b,users_2 a
where a.table_2_id=b.id
and b.id in(a.user_id)
group by a.table_2_id
First of all, you should not store a multiple value in a single field. For table users_2, the data should be:
table_2_id user_id
1 2
1 4
After you normalized your table, you can use mysql GROUP_CONCAT() to get the result in the format you mentioned
SELECT
users_2.table_2_id,
GROUP_CONCAT(users.username) AS username
FROM
users_2
JOIN
users ON users.id = users_2.user_id
GROUP BY
users_2.table_2_id
;
I have 4 tables that I need to pull data from. I need to count how many people are signed for a single event and see if a user is applied for an event.
These are my table setups:
TABLE: users
+----+----------+-------+--------+-------+
| id | username | level | class | guild |
+----+----------+-------+--------+-------+
| 1 | example1 | 100 | Hunter | blah |
| 2 | example2 | 105 | Mage | blah2 |
| 3 | example3 | 102 | Healer | blah |
+----+----------+-------+--------+-------+
ID is primary
TABLE: event_randoms
+----+----------+-------+--------+----------+----------+
| id | username | level | class | apped_by | event_id |
+----+----------+-------+--------+----------+----------+
| 1 | random1 | 153 | Hunter | 3 | 3 |
| 2 | random2 | 158 | Healer | 3 | 1 |
| 3 | random3 | 167 | Warrior| 1 | 3 |
+----+----------+-------+--------+----------+----------+
ID is primary
apped_by should be foreign key to users.id
event_id should be foreign key to events.id
TABLE: events
+----+------------+------------+-----------+-----------+-----------+
| id | event_name | event_date | initiator | min_level | max_level |
+----+------------+------------+-----------+-----------+-----------+
| 1 | event1 | date1 | 1 | 100 | 120 |
| 2 | event2 | date2 | 1 | 121 | 135 |
| 3 | event3 | date3 | 1 | 100 | 120 |
| 4 | event4 | date4 | 1 | 150 | 200 |
+----+------------+------------+-----------+-----------+-----------+
ID is primary
TABLE: event_apps
+----+----------+--------------+
| id | event_id | applicant_id |
+----+----------+--------------+
| 1 | 3 | 2 |
| 2 | 4 | 2 |
| 3 | 3 | 1 |
| 4 | 1 | 3 |
+----+----------+--------------+
ID is primary
event_id should be foreign key to events.id
applicant_id should be foreign key to users.id
I will be the first to admit that I am very new to this. I just learned how to use MySQL a few days ago. I can grab stuff from a single table, but I am unsure how to grab from multiple tables.
This is the SQL query I tried
SELECT DD_events.id, event_id, applicant_id, guild, level, class, DD_users.id
FROM DD_events, DD_event_apps, DD_users
WHERE DD_event_apps.event_id = DD_events.id
AND DD_event_apps.applicant_id = DD_users.id
and tried to print_r an array but the array turns up empty.
So a few questions pertain to this:
1: How would I count and display as a number how many people (users and randoms) are signed up for an event?
eg: event 3 should have 4 total (2 users and 2 randoms)
2: How do I see if a particular individual is signed for an event and display text based if they are or not?
eg: user 1 is signed up for event 3 so it would be "Registered" but user 2, who is not signed, would display "Not Registered"
3: I want to display info for who is signed for a particular event in 2 tables, 1 for users and another for randoms.
eg: Event 3 would have 2 users info (username, guild, class, level) under the users table and then 2 random users info (name, class, level, what user applied this person) in the random table.
Any and all help is appreciated even if you can answer 1 part.
I'm thinking this would be your base query:
SELECT
event.id,
app.applicant_id,
usr.guild,
usr.level,
usr.class,
usr.id AS Userid
FROM
DD_events event
JOIN
DD_event_apps app
ON (event.id = app.event_id)
LEFT JOIN
DD_users usr
ON (app.user_id = usr.id)
You can make modifications to this to aggregate it, like so:
SELECT
event.id,
COUNT(app.applicant_id) AS ApplicantCount,
COUNT(DISTINCT usr.guild) AS UniqueGuilds,
COUNT(DISTINCT usr.level) AS UniqueLevels,
COUNT(DISTINCT usr.class) AS UniqueClasses,
COUNT(DISTINCT usr.id) AS UniqueUsers
FROM
DD_events event
JOIN
DD_event_apps app
ON (event.id = app.event_id)
LEFT JOIN
DD_users usr
ON (app.user_id = usr.id)
GROUP BY
event.id
I could write those scripts for you, but I think this provides a good starting point for you to continue from. You'll find that T-SQL is fairly simple when you are trying to get the results you are looking for. Hope this helps!
<?php $query = "SELECT count(*) AS numbuh FROM DD_event_apps WHERE event_id = {$row['id']}";
try
{
// These two statements run the query against your database table.
$stmt = $db->prepare($query);
$stmt->execute();
}
catch(PDOException $ex)
{
// Note: On a production website, you should not output $ex->getMessage().
// It may provide an attacker with helpful information about your code.
die("Failed to run query: " . $ex->getMessage());
}
echo($query);
// Finally, we can retrieve all of the found rows into an array using fetchAll
$count = $stmt->fetchAll();
echo($count['numbuh']); ?>
I'm new to MySQL and PHP. I have two tables, one to hold all the company names and the other table has only the company name below the user:
Table 1
| # | Company name |
--------------------
| 1 | Microsoft |
| 2 | HP |
| 3 | Asus |
| 4 | Apple |
| 5 | Amazon |
| 6 | CCN |
table 2
| # | Company name | User name |
--------------------------------
| 1 | Asus | x1 |
| 2 | Apple | x1 |
| 3 | HP | x2 |
| 4 | Asus | x2 |
| 5 | Apple | x2 |
I need to create a query that achieves the following. First of all the companies are shown which are associated with a specific user (say Asus and Apple for user x1). After that, the remaining companies from table 1 are shown.
For example, the result of the query I'm looking for, for user X1 will display the rows in this way:
| # | Company name |
--------------------
| 1 | Asus |
| 2 | Apple |
| 3 | Microsoft |
| 4 | HP |
| 5 | Amazon |
| 6 | CCN |
How can I achieve this?
It looks like you want to include all companies, but for a given user, list the companies associated with that user first. If that's the case, you do not want to use an INNER JOIN.
Here's some SQL that should work. I've provided reasonable table and field names since you didn't give those. I'm also assuming that you have a reasonably sane table design with no duplicate rows.
SELECT c.company_name,
CASE
WHEN u.company_name IS NULL THEN 'N'
ELSE 'Y'
END AS user_has_company
FROM companies c
LEFT JOIN (
SELECT *
FROM users
WHERE user_name = 'x1'
) u
ON u.company_name = c.company_name
ORDER BY user_has_company DESC, c.company_name
This query will return an extra column - user_has_company. I'd use that to indicate whether the current user is associated with a given company, but you can ignore it if you want.
You will need a JOIN Statement to join another in the SELECT-Statement of table1
Quick example:
SELECT * FROM table2 INNER JOIN table1.id = table2.id WHERE table2.username = 'x1'
You'll find everything you need in the Documentation of JOINs.
http://dev.mysql.com/doc/refman/5.1/en/left-join-optimization.html
If you're just after the MySQL query for this then something like this would work
SELECT company_name,SUM(IF(user_name='x1',1,0)) as ordering
FROM `table2`
GROUP BY company_name
ORDER BY ordering DESC
But you should look at your schema before you go much further. If you have a column (company_name) in one table that refers to another table you should make that column refer to the PRIMARY KEY of the other table, i.e.
Table1
| # | company_name |
--------------------
| 1 | microsoft |
| 2 | hp |
| 3 | asus |
| 4 | apple |
| 5 | amazon |
| 6 | CCN |
table2
| # | company_id | user_name |
--------------------------------
| 1 | 3 | x1 |
| 2 | 4 | x1 |
| 3 | 2 | x2 |
| 4 | 3 | x2 |
| 5 | 4 | x2 |
This is one of the first things you learn in database design/normalisation. You will need to change your query in this case. Something like this:
SELECT company_name,SUM(IF(user_name='x1',1,0)) as ordering
FROM `table1`
LEFT JOIN `table2` ON table2.company_id=table1.id
GROUP BY company_name
ORDER BY ordering DESC
Create your query like this:
$sql = "SELECT b.companyName FROM table1 a INNER JOIN table2 b ON a.companyName = b.companyName WHERE b.userName = 'x1'";
Then, using PHP, use:
$con = mysql_connect("localhost","peter","abc123");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("my_db", $con);
$result = mysql_query($sql);
while($row = mysql_fetch_array($result))
{
echo $row['companyName'];
echo "<br />";
}
mysql_close($con);
Try this query:
SELECT company_name FROM table2 ORDER BY user_name ASC
In the HTML table, using PHP code:
$result = mysql_query(" SELECT company_name, user_name FROM table2 ORDER BY user_name ASC");
echo "<table>
<tr><th>Company Name</th><th>username</th></tr>";
while($row = mysql_fetch_array($result) {
echo "<tr><td>{$row['company_name']}</td><td>{$row['user_name']}</td></tr>";
}
echo "</table>"
I will try to be as explanatory as possible regarding my question. I am using MYSQL/PHP to fetch data from two tables with the structure looking like the following:
table A
+---------+------------+
| userid | username |
+---------+------------+
| 1 | john |
| 2 | doe |
| 3 | lewis |
+---------+------------+
table B
+---------+------------+-----------+
| id |from_userid | to_userid |
+---------+------------+-----------+
| 1 | 1 | 3 |
| 2 | 3 | 2 |
| 3 | 1 | 2 |
| 4 | 2 | 1 |
+---------+------------+-----------+
Am trying to achieve the following:
+---------+------------+----------------------+
| id |sender username| receiver username |
+---------+------------+----------------------+
| 1 | john | lewis |
| 2 | lewis | doe |
| 3 | john | doe |
| 4 | doe | john |
+---------+------------+----------------------+
As you can see, instead of returning the sender or receiver user id, I am returning their username according to Table A.
can I use left or right joins in this scenario? Thanks in advance
Try this
SELECT b.id, sender.username AS sender_username, receiver.username AS receiver_username
FROM tableB AS b
JOIN tableA AS sender ON b.from_userid = sender.userid
JOIN tableA AS receiver ON b.to_userid = receiver.userid
Inner joins would work fine, you just need to do two of them...
Left and right joins are only needed when you want to get all records from one table and some from another table. In this case you have two distinct relationships thus the need for two joins. My MySQL skills are a bit rusty so I don't know if ' or [ are used as separators on the table/field names with spaces.
Select t1.ID, T1.userName as 'Sender userName', T2.username as 'Receiver username'
FROM [Table A] A
INNER JOIN [Table B] T1
on T1.from_userid = A.userID
INNER JOIN [Table B] T2
on T2.to_userid = A.userID