PHP tables consisting of 3 rows loaded from SQL database - php

Question

I have a database loaded with different churches information, I am trying to insert all the information from the database into a PHP table with 3 rows.
I would like the structure of each cell to be:
Church Name
Image
Pastor Name
I can easily insert all data into a table, but I cannot get it to display as 3 rows.
echo("<table>");
while($row = mysql_fetch_array($rs))
{
echo("<tr>");
echo("<td>");
echo("<a href='" . $row['website'] . "'>" . $row['churchName'] . "</a><br>");
echo("<img src=\"" . $row['image'] . "\"><br>");
echo($row['pastorName'] . "<br><br>");
echo("</td>");
echo("<td>");
echo("<a href='" . $row['website'] . "'>" . $row['churchName'] . "</a><br>");
echo("<img src=\"" . $row['image'] . "\"><br>");
echo($row['pastorName'] . "<br><br>");
echo("</td>");echo("<td>");
echo("<a href='" . $row['website'] . "'>" . $row['churchName'] . "</a><br>");
echo("<img src=\"" . $row['image'] . "\"><br>");
echo($row['pastorName'] . "<br><br>");
echo("</td>");
echo("</tr>");
}
echo("</table>");
Doing this causes me to have 3 rows in correct structure, but having duplicate data. I understand that I have not changed the id, but am not sure what I should do

Answer 1

You're repeating the data on the row. If you want to show 3 items per row, you need to add a counter and a statement to draw the table row breaks, as below:
$int_Col = 1;
echo("<table>");
while($row = mysql_fetch_array($rs))
{
if ($int_Col == 1) {
echo("<tr>");
}
echo("<td>");
echo("<a href='" . $row['website'] . "'>" . $row['churchName'] . "</a><br>");
echo("<img src=\"" . $row['image'] . "\"><br>");
echo($row['pastorName'] . "<br><br>");
echo("</td>");
if ($int_Col == 3) {
echo("</tr>");
$int_Col = 1;
} else {
$int_Col++;
}
}
if ($int_Col > 1) {
echo("<td colspan='". (3 - $int_Col) ."'> </td></tr>");
}
echo("</table>");
The last check ($int_Col > 1) should ensure the table is rendered properly with an empty cell - should span the correct amount of cells that were not drawn on the current row.

Answer 2

Just clarify, I think there's two definitions of "rows" here.
MySQL table rows
HTML table rows
I believe you're after getting 3 MySQL table rows into one HTML table row.
Use the following to split the HTML row every 3 MySQL rows:
$i = 0;
while($row = mysql_fetch_array($rs))
{
// whatever you're already doing(ish)
$i++;
if($i % 3 == 0)
{
echo('</tr><tr>');
}
}
You'll need to put some extra checks in in the event that the total number of MySQL rows doesn't divide exactly by 3 because in that case you'll have one or two empty cells to fill at the end of the table.

Answer 3

If I get your code right you are creating 3 rows for every row in the database. mysq_fetch will run the loop for every single row, so the right content of the loop would be:
echo("<tr>");
echo("<td>");
echo("<a href='" . $row['website'] . "'>" . $row['churchName'] . "</a><br>");
echo("<img src=\"" . $row['image'] . "\"><br>");
echo($row['pastorName'] . "<br><br>");
echo("</td>");
echo("</tr>");