Check If In_Array (in Recursive Associative Array) - php

Question

I have an array similar to this:
array(2) {
[0]=>
array(2) {
["code"]=>
string(2) "en"
["name"]=>
string(7) "English"
}
[1]=>
array(2) {
["code"]=>
string(2) "bg"
["name"]=>
string(9) "Bulgarian"
}
}
How do I check if the string Bulgarian is part of the above array, or alternatively if the lang code 'en' is part of the array? It would be great if I didn't have to use foreach to loop through the entire array and compare the string with each element['code'] or element['name'].

Answer 1

// $type could be code or name
function check_in_array($arr, $value, $type = "code") {
return count(array_filter($arr, function($var) use ($type, $value) {
return $var[$type] === $value;
})) !== 0;
}

Answer 2

I know my code used foreach but it is easy to understand and use.
$language=array();
$language[0]['code']='en';
$language[0]['name']='English';
$language[1]['code']='bg';
$language[1]['name']='Bulgaria';
var_dump(my_in_array('Bulgaria', $language));
function my_in_array($search, $array) {
$in_keys = array();
foreach($array as $key => $value){
if(in_array($search, $value)){
$in_keys[]=$key;
}
}
if(count($in_keys) > 0){
return $in_keys;
}else{
return false;
}
}

Answer 3

You can use this function for recursive search
function in_arrayr($needle, $haystack) {
foreach ($haystack as $v) {
if ($needle == $v) return true;
elseif (is_array($v)) return in_array($needle, $v);
}
return false;
}
Or you can use json_encode on your array and search occurence of substring :)

Answer 4

I had a similar problem, so I made this function, it's like in_array, but it can search in array in the array recursively. I think it's correct but I didn't test in a lot of case. (sorry for my english I'm french)
function in_arrayr($needle, $haystack) {
if(is_array($haystack)){
foreach($haystack as $elem){
$a = in_arrayr($needle,$elem)||$a;
}
}
else{
$a = (($needle == $haystack)? true: false);
}
return $a;
}