how to get parameter for an ajax request in php - php

Question

Edit: I solved my prblem, eveyone. I have linked to a wrong javascript page. thats silly. thank u very much though
I have an ajax request GET with parameter random: yes, but when I use PHP to check for the parameter, the parameter doesn't seem to exits
my code is like this:
for ajax
function fetchData() {
new Ajax.Request("webservice.php", {
method: "get",
parameters: {random: "yes"},
onSuccess: displayData,
onFailure: ajaxFailure,
onException: ajaxFailure
});
}
and I write PHP to check the parameter
if ($_GET["random"] == "yes"){
do something
}else if(isset($_REQUEST["poll"]) && $_SERVER["REQUEST_METHOD"] == "GET"){
//this is b/c i have another ajax request with parameters {poll: "favChar"},
do something
}
I get the error of making ajax request. I have check my PHP code. I enter wwww.domainname.com/webservice.php?random=yes and the page output the results correctly.
Can someone help me? Thank u

Answer 1

The easiest way is adding the parameter in the URL:
new Ajax.Request("webservice.php?random=yes", {
// options
});

Answer 2

Create an AJAX obj first: var http = new XMLHttpRequest();
The GET method:
var url = "webservice.php";
var params = "random=yes&param=value";
http.open("GET", url+"?"+params, true);
http.onreadystatechange = function() {//Call a function when the state changes.
if(http.readyState == 4 && http.status == 200) {
alert(http.responseText);
}
}
http.send(null);

Answer 3

According to the documentation, parameters requires a Hash-compatible object, so you might have to convert your plain JavaScript hash, like so:
function fetchData() {
new Ajax.Request("webservice.php", {
method: "get",
parameters: $H({random: "yes"}),
onSuccess: displayData,
onFailure: ajaxFailure,
onException: ajaxFailure
});
}